mathpower tm 10, western edition chapter 2 number patterns 2.5 2.5.1

8
MATHPOWER TM 10, WESTERN EDITION hapter 2 Number Patterns 2.5 2.5.1

Upload: hannah-evans

Post on 26-Dec-2015

219 views

Category:

Documents


5 download

TRANSCRIPT

Page 1: MATHPOWER TM 10, WESTERN EDITION Chapter 2 Number Patterns 2.5 2.5.1

MATHPOWERTM 10, WESTERN EDITION

Chapter 2 Number Patterns2.5

2.5.1

Page 2: MATHPOWER TM 10, WESTERN EDITION Chapter 2 Number Patterns 2.5 2.5.1

An Arithmetic Sequence is a sequence where each termis formed from the preceding term by adding a constantto the preceding term.

Consider the sequence -3, 1, 5, 9.This sequence is found by adding 4 to the previous term.The constant term which is added to each term to produce the sequence is called the Common Difference.

2.5.2

Arithmetic Sequences

Page 3: MATHPOWER TM 10, WESTERN EDITION Chapter 2 Number Patterns 2.5 2.5.1

t 1 t 2 t 3 t 4

Sequence

Sequence expressed using the common

difference

Sequence expressed in general

terms

-3 + (1)4

-3 + 4 + 4

-3 + (2)4

-3 + 4 + 4 + 4

-3 + (3)4

Continuing with this pattern, the general term is derived as:

tn = a + (n - 1) d

-3 1 5 9

-3

a a + d a + 2d a + 3d

-3 + 4

2.5.3

Arithmetic Sequences

Page 4: MATHPOWER TM 10, WESTERN EDITION Chapter 2 Number Patterns 2.5 2.5.1

tn = a + (n - 1) d

GeneralTerm

FirstTerm

Number or Position of the Term

Common Difference

2.5.4

The General Arithmetic Sequence

Page 5: MATHPOWER TM 10, WESTERN EDITION Chapter 2 Number Patterns 2.5 2.5.1

Given the sequence -5, -1, 3, …:a) Find the common difference.

d = t2 - t1

= (-1) - ( -5) = 4

Note: The common differencemay be found by subtractingany two consecutive terms.

b) Find t10 . tn = a + (n - 1) d

c) Find the general term . tn = a + (n - 1) d

d) Which term is equal to 63?

tn = a + (n - 1) d63 = - 5 + 4n - 472 = 4n18 = n t18 = 63

a = -5n = 10d = 4tn = ?

a = -5n = ?d = 4

a = -5n = ?d = 4tn = 63

t10 = -5 + (10 - 1) 4 = -5 + (9) 4t10 = 31

= -5 + (n - 1) 4 = -5 + 4n - 4 tn = 4n - 9

63 = -5 + (n - 1) 42.5.5

Finding the Terms of an Arithmetic Sequence

Page 6: MATHPOWER TM 10, WESTERN EDITION Chapter 2 Number Patterns 2.5 2.5.1

Find the number of terms in 7, 3, -1, - 5 …, -117 . tn = a + (n - 1) d

A pile of bricks is arranged in rows. The number of bricksin each row forms a sequence 65, 59, 53, …, 5. Which row contains 11 bricks? How many rows are there?

tn = a + (n - 1) d tn = a + (n - 1) d

a = 7n = ?d = -4tn = - 117

a = 65n = ?d = - 6tn = 11

-117 = 7 + (n - 1) (-4) -117 = 7 - 4n + 4 -117 = -4n + 11 -128 = -4n 32 = n

11 = 65 + (n - 1) (-6)-60 = -6n 10 = n

a = 65n = ?d = - 6tn = 5

5 = 65 + (n - 1) (-6)-66 = -6n n = 11

2.5.6

Finding the Number of Terms of an Arithmetic Sequence

The 10th row contains 11 bricks.

There are 11 rows in this pile.

There are 32 terms inthe sequence.

Page 7: MATHPOWER TM 10, WESTERN EDITION Chapter 2 Number Patterns 2.5 2.5.1

Arithmetic means are the terms that are between two given terms of an arithmetic sequence.

Insert five arithmetic means between 6 and 30.

6 _ _ _ _ _ 30 7 terms altogether

tn = a + (n - 1)d

Therefore, the terms are:

a = 6n = 7d = ?tn = 30

30 = 6 + (7 - 1)d30 = 6 + 6d24 = 6d 4 = d

6, , 30 10, 14, 18, 22, 262.5.7

Arithmetic Means

Page 8: MATHPOWER TM 10, WESTERN EDITION Chapter 2 Number Patterns 2.5 2.5.1

Pages 74 - 761 - 43 odd46, 47, 49, 5052, 53, 56, 57 2.5.8

Suggested Questions: