met 401 chapter 10 -_economics_of_power_generation_-_a._rezk
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DR. TAIB ISKANDAR & DR. AHMED REZK
Economics of Power Generation
MET401 Power Plant Engineering
2
Introduction
Why do we need economic analysis?
The main purpose of design and operation of a
power plant is to bring the cost of energy
produced to minimum.
Thermal efficiency of a plant is one of the
important factors in determining energy cost.
The most thermally efficient plant is not the
most economics.
3
Types of power plants
Thermal fossil fuels, coal, fuel oil & natural gas. 80% of world electricity.
NuclearGeothermal
Hydraulic Multipurpose plants (generating power, flood control,
etc..)Gas turbine plants
They run for a short time to meet the peak load demand They are used in the combined steam power plant.
• Similar in cycle • Similar in structure• Use steam as a working
fluid
4
Electricity generation in SA
5
Production rate
Electricity production, EAnnual fractional
increase rate, i (%)Eo=electricity
production at year t0
To find time required for electricity production to be doubled, we define tD
as doubling timei
t
it
E
E
ttt
eEE
ttiE
E
Eidt
dE
D
D
D
ttio
oo
o
693.0
2ln
2
)(ln
1
2
12
)(
6
Planning a new power plant
When planning a new power plant there are two considered factors. Total power output to be installed (kWinst)
First demand (kWmax). Growth of demand. Reserve capacity required.
Size of generating units Load variation during 24hr Total capacity of units connected to grid Minimum start up and shut down periods Maintenance program Plant efficiency Price and space per kW vs. unit
500MW plant
Unit 1
Unit 2
Unit 3
7
Load-duration curveskW
ele
ctri
city
Summer Average
Winter Average
Peak loads
8
Electricity supply industry factors
Load factor (m)
Capacity factor / plant factor (n)
8760" 365 * 24year one" 8760x kW
kWh
interval same theduring loadpeak
interval timeaover load average
max
ave
m
m
8760 x kW
kWhr
365 x 24 x kW
kWhr
plant ofcapacity rated
load average
inst
gen
inst
gen
n
n
9
Electricity supply industry factors
Reserve factor (r)
Demand factor (dem)factorcapacity
factor load
kW
kW
max
inst
r
n
mr
connectedkW
kWdem
dem
max
demand connected total
demand maximum actual
10
Electricity supply industry factors
Diversity factor (div)
Use factor (u)peakkW
cbadiv
div
system of loadpeak actual
groupsconsumer invidual of sum
hours operating x kW
kWh
inst
genu
11
Example 1
A steam power plant have a peak load of 65 MW. Connected to it are five loads having maximum demands of 20 MW, 15 MW, 10 MW, 10 MW and 5 MW each. Plant capacity is 90MW and annual load factor is 0.60. Determine,a) the average load on the power plantb) the energy supplied annuallyc) the demand factord) the diversity factore) the use factor if plant only operate 8000 hrs per yearf) What do you think about this plant economically?
12
Power plants location
For thermal power plant Availability of cooling water Availability of fuel Distance from center of load demand Land cost and characteristics Wind direction & water stream Disposal of fuel waste and ashes Staff accommodations Rail and road connections Security
For hydraulic power plant Availability of water and water head
13
Power plant economics
The cost per kWhnet is determined byFixed cost (FC)
Interest (I) Depreciation (D) Taxes and insurance (T)
Operation and maintenance (O&M) covering Salaries and wages Overhauling of equipment Repairs including spare parts, lubricants, miscellaneous,
etc..Fuel costkWhrnet sent out
Depend on capital invest (construction cost)
14
Power plant economics
Total annual cost
Cc – construction cost W – wages R – repairs and maintenance M – miscellaneous. Cf – fuel cost
Annual amount of electricity sent out
Laux = power consumption by auxiliaries n = plant capacity factor
fct CMRWCTDI
C
)(100
n x 100
1 x 8760 x kWkWh instnet
auxL
15
Cost reduction
The costs have a continuous upward mainly
due to monetary inflation, rising fuel prices. It
can be reduced by applying the following: Select equipment with longer life and proper capacity
Run at high load factor
Increase power plant efficiency
Proper maintenance to reduce breakdown
Keep a proper supervision
Simple design (less dependent on highly skilled worker)
16
Example 2
A new housing development is to be added to the lines of a public electrical network There are 2500 apartments each having a connected load of 6 kW, with the commercial load shown. The demand factor of the apartments is 55%. The group diversity factor of the residential load is 2.5, and the peak diversity factor is 1.5, and the commercial – load group diversity factor is 1.6 and the peak diversity factor is 1.1.
Store or serviceConnected load (kW)
Demand factor (d) %
1- laundry3-mosques1-resturant1-bookstore2-drugsstores2-grocery stores1-shoe store1-cloting store1-theater
2512 each
608
10 each5 each
2695
0.660.580.500.680.770.750.690.560.45
Find the maximum demand of each group and the system peak demand.