most likely macrostate the system will find itself in is the one with the maximum number of...
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Most likely macrostate the system will find itself in is the one with the maximum number of microstates.
E1
1(E1)
E2
2(E2)
Total microstates =
Ω (𝐸1,𝐸2 )=Ω1(𝐸1)Ω2(𝐸2)
To maximize :
E1
1(E1)
E2
2(E2)
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Most likely macrostate the system will find itself in is the one with the maximum number of microstates.
E1
1(E1)
E2
2(E2)TkdE
d
dE
d
B
1lnln
2
2
1
1
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Using this definition of temperature we need to describe real systems
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Boltzmann Factor (canonical ensemble)
TkBeP
)(
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𝑓 ′ (�⃑� )𝑑𝑣𝑥𝑑𝑣 𝑦𝑑𝑣 𝑧∝𝑒− 𝑚𝑣2
2𝑘𝐵𝑇 𝑑𝑣 𝑥𝑑𝑣 𝑦𝑑𝑣𝑧
𝑓 ′ (�⃑� )𝑑𝑣𝑥𝑑𝑣 𝑦𝑑𝑣 𝑧∝𝑒−𝑚(𝑣𝑥
2+𝑣𝑦2+𝑣 𝑧
2 )2𝑘𝐵𝑇 𝑑𝑣 𝑥𝑑𝑣 𝑦𝑑𝑣𝑧
𝑓 ′ (�⃑� )𝑑𝑣𝑥𝑑𝑣 𝑦𝑑𝑣 𝑧∝𝑒−𝑚𝑣 𝑥
2
2𝑘𝐵𝑇 𝑑𝑣 𝑥𝑒−𝑚𝑣𝑦
2
2𝑘𝐵𝑇 𝑑𝑣 𝑦𝑒−𝑚𝑣𝑧
2
2𝑘𝐵𝑇 𝑑𝑣 𝑧
∝𝑔 (𝑣 𝑥 )𝑑𝑣𝑥
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Integrating over the two angular variables we can get the probability that the speed of a particle is between and :
𝑓 ′ (�⃑� )𝑣2 sin𝜃 𝑑𝑣𝑑𝜃 𝑑𝜑∝𝑒− 𝑚𝑣2
2𝑘𝐵𝑇 𝑣2sin 𝜃 𝑑𝑣𝑑𝜃𝑑𝜑
⇒ 𝑓 (𝑣 )𝑑𝑣∝𝑒− 𝑚𝑣2
2𝑘𝐵𝑇 𝑣2 𝑑𝑣
For to be a proper probability distribution/density function:
∫0
∞
𝑓 (𝑣 )𝑑𝑣=1
⇒ 𝑓 (𝑣 )𝑑𝑣= 4√𝜋 ( 𝑚
2𝑘𝐵𝑇 )3 /2
𝑣2𝑒− 𝑚𝑣2
2𝑘𝐵𝑇 𝑑𝑣
Maxwell-Boltzmann speed distribution
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0 10 20 30 40 50 60 70 80 90 1000
0.02
0.04
0.06
0.08
0.1
0.12
T = 10
0 10 20 30 40 50 60 70 80 90 1000
0.005
0.01
0.015
0.02
0.025
0.03
0.035
0.04
T = 100
0 10 20 30 40 50 60 70 80 90 1000
0.002
0.004
0.006
0.008
0.01
0.012
T = 1000
⇒ 𝑓 (𝑣 )𝑑𝑣= 4√𝜋 ( 𝑚
2𝑘𝐵𝑇 )3 /2
𝑣2𝑒− 𝑚𝑣2
2𝑘𝐵𝑇 𝑑𝑣
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⟨𝑣 ⟩=∫0
∞
𝑣𝑓 (𝑣 )𝑑𝑣=√ 8𝑘𝐵𝑇𝜋𝑚
⟨𝑣2 ⟩=∫0
∞
𝑣2 𝑓 (𝑣 )𝑑𝑣=3𝑘𝐵𝑇𝑚
=𝑣𝑟𝑚𝑠2
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⇒𝑑𝑝=𝑛𝑚𝑣 2 𝑓 (𝑣 )𝑑𝑣 sin𝜃 cos2𝜃 𝑑𝜃
The pressure on the wall due to all the particles in the gas is:
𝑝=𝑛𝑚∫0
∞
𝑣2 𝑓 (𝑣)𝑑𝑣 ∫0
𝜋/2
sin 𝜃 cos2𝜃𝑑𝜃
¿𝑛𝑚 ⟨𝑣2 ⟩ 13
¿𝑛𝑚3𝑘𝐵𝑇𝑚
13
¿𝑛𝑘𝐵𝑇=𝑁𝑉𝑘𝐵𝑇
⇒𝑝𝑉=𝑁𝑘𝐵𝑇
Only till to include only those particles hitting the wall from the left
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Efficiency of a Carnot engine
𝑝𝐴 ,𝑉 𝐴 ,𝑇 h
𝑝𝐵 ,𝑉 𝐵 ,𝑇 h
𝑝𝐶 ,𝑉 𝐶 ,𝑇 𝑙
𝑝𝐷 ,𝑉 𝐷 ,𝑇 𝑙
⇒ Δ𝑄h=𝑅𝑇 h ln𝑉 𝐵
𝑉 𝐴p
V
⇒ Δ𝑄𝑙=𝑅𝑇 𝑙 ln𝑉 𝐷
𝑉 𝐶
⇒ Δ𝑄=0⇒𝑇h𝑉 𝐵
𝛾−1=𝑇 𝑙𝑉 𝐶𝛾−1
⇒ Δ𝑄=0⇒𝑇 𝑙𝑉 𝐷
𝛾−1=𝑇h𝑉 𝐴𝛾−1
Isotherm 1
Adiabat 1
Adiabat 2
Isotherm 2
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0.5 1 1.5 2 2.5 30
0.5
1
1.5
2
2.5
Pr_b
v(1) v(2) v(3)
Calculates the relevant area for the Maxwell constructions(v(2)-v(1))*Pr_b - integral(Prfunc,v(1),v(2))
integral(Prfunc,v(2),v(3)) - (v(3)-v(2))*Pr_b
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P (
bar)
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