mp and mc record

7/30/2019 MP and MC Record

1/102

Exp no: 1

Date :

PROGRAMMING WITH 80858 BIT ARITHMETIC OPERATION

AIM:To write an assembly language program for arithmetic operations of two 8 bit numbers

using 8085 microprocessor kit for the following operations.

A. AdditionB. SubtractionC. MultiplicationD. Division

APPARATUS REQUIRED:

S.No Apparatus Required Quantity1. 8085 Microprocessor kit 1

2. Power supply -

3. Opcode sheet 1

A. ALGORITHM FOR 8-BIT ADDITION:

1. Start the program.2. Load first data in accumulator and move the content from register A to register B.3. Load the second data in accumulator. Initialize the carry value as 00.4. Add the content of A register with B register. If a carry doesnt exist, directly store the

value.5. If carry exists, then increment the carry value and then store the sum in the address

location mentioned.6. Stop the program.


2/102

FLOW CHART FOR 8 BIT ADDTION:

Start

Clear the C register

IFther

e

Load the contents of memory into accumulator

Move the contents of accumulator to B register

Load the contents of memory to accumulator

Add the contents of B-register with accumulator

Increment the C register

Store the contents of accumulator to memory

Move the contents of C register to accumulator

Store the contents of accumulator to memory

Stop

No


3/102

PROGRAM FOR 8-BIT ADDITION:

MEMORY LABEL MNEMONICS OPCODE COMMENTS

4500 START MVI C,00H 0E Move the value to

register C immediately4501 004502 LDA 4200H 3A Load accumulator from

address 4200H4503 00

4504 42

4505 MOV B,A 47 Move the content to the

B register

4506 LDA 4201H 3A Load accumulator from


4508 42

4509 ADD B 80 Add contents of B with

A

450A JNC LOOP1 D2 Jump of control to givenaddress when no carryis found

450B 0E

450C 41

450D INR C 0C Increment register C

450E LOOP1 STA 4202H 32 Store accumulator withcontents of 4202H450F 02

4510 42

4511 MOV A,C 79 Move content of C to A

4512 STA 4203H 32 Store accumulator withcontents of 4203H4513 03

4514 42

4515 STOP HLT 76 Stop the program

B. ALGORITHM FOR 8 BIT SUBTRACTION:

1. Load the first data in accumulator and move the content from accumulator to B register.2. Load the second data in accumulator. Initialize the carry value.3. Subtract the content of accumulator with register B.4. Check whether carry is present or not.5. If present, increment the carry.6. Complement the accumulator content.7. Add immediate by incrementing A register.8. If no carry is present, store the data in accumulator.9. The content present in C register is moved to accumulator.10.Store the result in memory location mentioned.11.Stop the program.


4/102

FLOW CHART FOR 8 BIT SUBTRACTION:


5/102

PROGRAM FOR 8 BIT SUBTRACTION:


4600 START MVI C,00 0E Move the value toregister C

immediately4601 00

4602 LDA 4200H 3A Load accumulator

from address 4200H4603 00

4604 42

4605 MOV B,A 47 Move content of A to

B

4606 LDA 4201H 3A Load accumulatorfrom address 4201H4607 01

4608 42

4609 SUB B 90 Subtract contents of Bwith A

460A JNC LOOP1 D2 Jump of control to

given address when

no carry is found460B 10

460C 46

460D INR C 0C Increment register C

460E CMA 2F Complement occurs

460F INR A 3C Increment of A

4610 LOOP1 STA 4202H 32 Store the content ofgiven address to

accumulator4611 02

4612 42

4613 MOV A,C 79 Move contents of C toA

4614 STA 4203H 32 Store the content of

given address to

accumulator4615 03

4616 42

4617 STOP HLT 76 Stop the program

ALGORITHM FOR 8-BIT MULTIPLICATION:

1. Start the program.2. Load the first data into the accumulator.

3. Move the content of accumulator to the B register.4. Load the second data into the accumulator.5. Move the content of accumulator to the C register.6. Decrement the content of B register by one.7. Add the C register content with accumulator.8. Decrement the content of B register & then repeat the steps 7 & 8.9. Else store the result in the memory location mentioned.10.Stop the program.


6/102

FLOW CHART FOR 8 BIT MULTIPLICATION:


7/102

PROGRAM FOR 8 BIT MULTIPLICATION:


4100 START MVI C,00H 0E Move the content

immediately to reg C4101 004102 LDA 4200H 0A Load accumulator fromaddress 4200H4103 00

4104 41

4105 MOV B,A 47 Move content of A to B

4106 LDA 4201H 0A Load accumulator from


4108 41

4109 MOV C,A 4F Move content of A to C

410A DCR B 05 Decrement register B

410B LOOP ADD C 81 Add content of C with A

410C DCR B 05 Decrement register B410D JNZ LOOP C2 Jump of control to given

address when no zero is

found410E 0B

410F 41

4110 STA 4202H 32 Store the content of given

address to accumulator4111 02

4112 42

4113 HLT 76 Stop the program

ALGORITHM FOR 8 BIT DIVISION:

1. Start the program.2. Load the first data in the accumulator.3. Move the content from memory address to A register and increment the HL pair.4. Move the content from memory address to B register & initialize the C register.5. Compare the 8 bit instructions in A and B registers. Subtract B register from accumulator

& increment the value in C register.

6. Increment the HL pair and move the content in accumulator to memory.7. Stop the program


8/102

FLOW CHART FOR 8 BIT DIVISION:


9/102


10/102

Exp no: 2

Date :

PROGRAM WITH 8085 CONTROL INSTRUCTIONS-

ASCENDING/DESCENDING ORDER

AIM:

To write an assembly language program for the ascending and descending order of 8-bitnumbers using 8085 microprocessor kit.

APPRATUS REQUIRED:

S.NO NAME OF ITEMS QUANTITY

1.

2.

8085-Microprocessor kit

Power supply

1

A. ALGORITHM FOR ASCENDING ORDER:

1. Start the program2. Load the data in memory whose address in C3. Move the memory into C-register then decrement the C-register by 1 and increment H by

1.

4. Load the data in the memory to A.5. Compare the memory with A.

6. Jump on the carry when M is greater A, go to Step 9.7. Move the memory M to D register8. Decrement the address of HL pair and move the D register content to M and increment

the value by H by 1.

9. Move B register and decrement the C-register.10.Jump on Zero to the address 4108,if zero goes to decrement B and go to step1.11. Stop the program.


11/102

FLOW CHART FOR ASCENDING ORDER:


12/102

PROGRAM FOR ASCENDING ORDER:

ADDRESS OPCODE LABEL MNEMONICS COMMENTS

4100 06 START MVI B,05H Move the contentimmediately to reg B4101 05

4102 05 DCR B Decrement the reg B

4103 0E LOOP1 MVI C,05H Move the content

immediately to reg c4104 05

4105 0D DCR C Decrement the reg C

4106 21 LXI H,4200Load the content

immediately to HL pair4107 00

4108 42

4109 7E LOOP2 MOV A,M Move the content to A410A 23 INX H Increment the HL pair

410B BE CMP M Compare the contents

410C DA JC LOOP3

Jump carry to loop3410D 14

410E 41

410F 56 MOV D,M Move the content to D

4110 77 MOV M,A Move the content to memory

4111 2B DCX H Decrement the HL pair

4112 72 MOV M,D Move the content to memory

4113 23 INX H Increment the HL pair4114 0D LOOP3 DCR C Decrement the reg C

4115 C2 JNZ LOOP2

Jump non zero to loop24116 09

4117 41


4119 C2 JNC LOOP1

Jump no carry to loop1411A 03

411B 41

411C 76 STOP HLT Halt the process


13/102

B. ALGORITHM FOR DESCENDING ORDER:

1. Start the program2. Load the data in memory whose address in C3. Move the memory into C-register then decrement the C-register by 1 and increment H by

1.4. Load the data in the memory to A.5. Compare the memory with A.6. Jump on no carry when M is greater A, go to Step 9.7. Move the memory M to D register8. Decrement the value of HL pair and move the D register content to M and increment the

value by H by 1.

9. Move B register and decrement the C-register.

10.Jump on Zero to the address 4108,if zero goes to decrement B and go to step1.11.Stop the program.


14/102

FLOW CHART FOR DESCENDING ORDER:


15/102

PROGRAM FOR DESCENDING ORDER:

ADDRESS OPCODE LABEL MNEMONICS COMMENTS4100 06 START MVI B,05H Move the content

immediately to reg B4101 05


4103 0E LOOP1 MVI C,05H Move the content

immediately to reg c4104 05

4105 0D DCR C Decrement the reg C

4106 21 LXI H,4200Load the content


4108 424109 7E LOOP2 MOV A,M Move the content to A

410A 23 INX H Increment the HL pair

410B BE CMP M Compare the contents

410C D2 JNC LOOP3

Jump non carry to loop3410D 14

410E 41

410F 56 MOV D,M Move the content to D

4110 77 MOV M,A Move the content to memory

4111 2B DCX H Decrement the HL pair4112 72 MOV M,D Move the content to memory

4113 23 INX H Increment the HL pair

4114 0D LOOP3 DCR C Decrement the reg C

4115 C2 JNZ LOOP2

Jump non zero to loop24116 09

4117 41


4119 C2 JNC LOOP1

Jump no carry to loop1411A 03411B 41

411C 76 STOP HLT Halt the process


16/102

Exp no: 3

Date :

PROGRAM WITH 8085 CONTROL INSTRUCTIONS

AIM:To write an assembly language program for the Maximum/Minimum instructions using

8085 microprocessor kit.

APPRATUS REQUIRED:


1.

2.


Power supply

1

A. ALGORITHM FOR SEARCHING MINIMUM NUMBER:

1. Start the program2. Load the address of the first element of the array in the HL register fair(pointer).3. Move the count to B register.4. Increment the pointer.5. Get the first data in accumulator.6. Decrement the count.

7. Increment the pointer.8. Compare the content of memory address by HL pair with that of accumulator.9. If carry=1 go to step 2 or If carry=0 go to step 10.10.Move the content of memory addressed by HL to accumulator.11.Decrement the count.12.Check whether ZF=0 go to step 7 or If ZF=1 go to next step.13.Store the smallest data in memory.14.Stop the program.


17/102

FLOW CHART FOR SEARCH THE MINIMUM NUMBER:


18/102

PROGRAM FOR SEARCHING MINIMUM NUMBER


4100 21 START LXI H,4500

Load the contentimmediately to HL pair

4101 00

4102 45

4103 46 MOV B,M Move the content to reg B


4105 7E MOV A,M Move the content to A


4107 23 L2 INX H Increment the HL pair

4108 BE CMP M Compare the memory to A

4109 DA JC L1

Jump carry to L1410A 0D410B 41

410C 7E MOV A,M Move the content to reg A

410D 05 L1 DCR B Decrement the reg B

410E C2 JNZ L2

Jump non zero to L2410F 07

4110 41

4111 32 STA 4504

Store the value to A4112 04

4113 45

4114 76 STOP HLT Halt the process

B. ALGORITHM FOR SEARCHING MAXIMUM NUMBER:

1. Start the program2. Load the address of the first element of the array in the HL register fair (pointer).3. Move the count to B register.4. Increment the pointer.5. Get the first data in accumulator.6. Decrement the count.7. Increment the pointer.8. Compare the content of memory address by HL pair with that of accumulator.9. If carry=0 go to step 2 or If carry=0 go to step 10.10.Move the content of memory addressed by HL to accumulator.11.Decrement the count.12.Check whether ZF=0 go to step 7 or If ZF=1 go to next step.13.Store the smallest data in memory.14.Stop the program.


19/102

FLOW CHART FOR SEARCH THE MAXIMUM NUMBER


20/102

PROGRAM FOR SEARCHING MAXIMUM NUMBER:


4100 21 START LXI H,4500Load the content


4102 45

4103 46 MOV B,M Move the content to reg B


4105 7E MOV A,M Move the content to A


4107 23 L2 INX H Increment the HL pair

4108 BE CMP M Compare the memory to A

4109 D2 JNC L1Jump non carry to L1410A 0D

410B 41

410C 7E MOV A,M Move the content to reg A

410D 05 L1 DCR B Decrement the reg B

410E C2 JNZ L2

Jump non zero to L2410F 07

4110 41

4111 32 STA 4504

Store the value to A4112 04

4113 45

4114 76 STOP HLT Halt the process


21/102

Exp no: 4

Date :


AIM:To write an assembly language program for the Code conversion using 8085

microprocessor kit.

APPRATUS REQUIRED:


1.

2.


Power supply

1

a. ALGORITHM FOR BCD TO BINARY:

1. Start the program.2. Get the BCD data in A register and move to B register.3. Mask the lower nibble of BCD data in A register.4. Rotate the upper nibble to lower nibble position and save in B register.5. Clear the accumulator.6. Move 0AH to C register.

7. Add B register to A register.8. Decrement C register If ZF=0 go to step 7 If ZF=1 go to next step.9. Save the product in B register.10.Get the BCD data in A register.11.Add the units (A reg) to product (B reg).12.Store the binary value in memory.13.Stop the program.


22/102

FLOW CHART FOR CODE CONVERSION: (BCD TO BINARY)


23/102

PROGRAM FOR BCD TO BINARY:


4100 3A START LDA 4500

Load the content to A4101 00

4102 45

4103 47 MOV B,A Move content to reg B

4104 E6 ANI OF And the content immediatelywith accumulator4105 0F

4106 5F MOV E,A Move content to reg E

4107 78 MOV A,B Move content to reg A

4108 E6 ANI FO And the content immediately

with accumulator4109 F0410A 0F RRC Rotate A to right with carry

410B 0F RRC Rotate A to right with carry

410C 0F RRC Rotate A to right with carry

410D 0F RRC Rotate A to right with carry

410E 57 MOV D,A Move content to reg D

410F A7 XRA A XOR function with A

4110 26 MVI H,OAMove immediately to reg H

4111 0A

4112 84 L1 ADD H Add the reg H

4113 15 DCR D Decrement the reg D

4114 C2 JNZ L1

Jmp non zero to L14115 12

4116 41

4117 83 ADD E Add to reg E

4118 82 STA 4501

Store the content to A4119 01

411A 45

411B 76 STOP HLT Halt the process


24/102

b. ALGORITHM FOR BINARY TO BCD

1. Start the program.2. Clear D &E register to account for hundreds and tens.3. Load the BINARY data in A register4. Compare A register with 64H If carry flag set go to step 8 otherwise go to next step.5. Subtract 64H from A register.6. Increment E register.7. Go to step 4.8. Compare A register with 0AH If carry flag set go to step 11 otherwise go to next step.9. Subtract 0AH from A register.10.Increment D register11.Go to step 8.

12.Combine the units and tens to form 8 bit result.13.Save the units, hundreds and tens in memory.14.Stop the program.


25/102


26/102

PROGRAM FOR BINARY TO BCD:


4100 31 START LXI SP,4700Load the data to stack

pointer4101 004102 47

4103 21 LXI H,4500

Load the data to HL4104 00

4105 45

4106 7E MOV A,M Move the data to A

4107 CD CALL SUB R1Call the sub function SUBR1

4108 0B

4109 41

410A 76 HLT Halt the process410B 21 SUB R1 LXI H,4600

Load the data to HL410C 00

410D 46

410E 06 MVI B,64HMove the data to regB

410F 64

4110 CD CALL SUB R2Call the sub function SUB

R24111 1A

4112 41

4113 06 MVI B,0AHMove the data to regB

4114 0A

4115 CD CALL SUB R2Call the sub function SUB

R24116 1A

4117 41

4118 77 MOV M,A Move the data to M

4119 C9 RET Return

411A 36 SUB R2 MVI M,FFHMove the data to M

411B FF

411C 34 L1 INR M Increment memory register

411D 90 SUB B Subtract reg B from A

411E D2 JNC L1 Jump no carry to L1411F 1C

4120 41

4121 80 ADD B Add A to B

4122 23 INX H Increment reg H

4123 C9 RET Return


27/102

Exp no: 5Date :

PROGRAMMING WITH 808516 BIT ARITHMETIC OPERATION

AIM:

To write an assembly language program for arithmetic operations of two 16 bit numbers

using 8085 microprocessor kit for the following operations.

A. AdditionB. SubtractionC. MultiplicationD. Division

APPARATUS REQUIRED:

S.No

Apparatus Required Quantity

1. 8085 Microprocessor kit 1

2. Power supply -

3. Opcode sheet 1

A. ALGORITHM FOR 16-BIT ADDITION:

1. Start the program

2. Load the first 16-bit data from memory into HL register pair3. Move the first 16-bit data from HL register pair to DE register pair4. Load the second 16-bit data from memory into HL register pair5. Initialize the C register as 00H6. Move content of L register into accumulator7. Add the content of E register to content of accumulator8. Move content of accumulator(result of lower 8-bit addition) into L register9. Move content of H register into accumulator10.Add the content of D register to content of accumulator with carry11.If carry zero means go to step 1312.Increment C register

13.Move content of accumulator(result of higher 8-bit addition) into H register14.Store the output from HL register pair to memory15.Move content of C register into accumulator16.Store the carry result in another memory location17.Stop the program


28/102


29/102

PROGRAM FOR 16 BIT ADDITION:

ADDRESS LABEL MNEMONICS OPCODE OPERAND COMMENTS

8500 LHLD 90008503 XCHG

8504 LHLD 9002

8507 MVI C,00

8509 MOV A,L

850A ADD E

850B MOV L,A

850C MOV A,M

850D ADC D

850E JNC STEP1

8511 INR C

8512 STEP1 MOV H,A

8513 SHLD 9100

8516 MOV A,C

8517 STA 9102

851A HLT

B. ALGORITHM FOR 16-BIT SUBTRACTION:


2. Load the first 16-bit data from memory into HL register pair3. Move the first 16-bit data from HL register pair to DE register pair4. Load the second 16-bit data from memory into HL register pair5. Initialize the C register as 00H6. Move content of L register into accumulator7. Subtract the content of E register from content of accumulator8. Move content of accumulator(result of lower 8-bit subtraction) into L register9. Move content of H register into accumulator10.Subtract the content of D register from content of accumulator with borrow11.If carry zero means go to step 1312.Increment C register

13.Move content of accumulator(result of higher 8-bit subtract) into H register14.Store the output from HL register pair to memory15.Move content of C register into accumulator16.Store the carry result in another memory location17.Stop the program


30/102

FLOW CHART FOR 16-BIT SUBTRACTION:

Get the lower byte of first number

Get the lower byte of second number

Subtract lower byte of second number

from lower byte of first number

Get the higher byte of first number

Get the higher byte of second number

Subtract higher byte of second number

and borrow from previous subtraction

Store the result

Stop


31/102

PROGRAM FOR 16 BIT SUBTRACTION:

ADDRESS LABEL MNEMONICS OPCODE OPERAND COMMENTS

8500 LHLD 9000

8503 XCHG

8504 LHLD 9002

8507 MVI C,00

8509 MOV A,L

850A SUB E

850B MOV L,A

850C MOV A,M

850D SBB D

850E JNC STEP18511 INR C

8512 STEP1 MOV H,A

8513 SHLD 9100

8516 MOV A,C

8517 STA 9102

851A HLT

C. ALGORITHM FOR 16- BIT MULTIPLICATION:

1. Start the program.2. Move the content of accumulator to the B register.3. Load the HL register into the accumulator.4. Exchange the content of accumulator to the C register.5. Load the HL register to the next accumulator.6. Load the register pair immediately to the H register.7. Multiply the register with SP.8. Increment B register.9. Move the HL register to memory.

10.Compare the OR register pair with E.11.Store the HL register to memory.12.Move the content of the memory to register B.13.Move the content of all memory.14.Stop the program.


32/102

FLOW CHART16 BIT MULTIPLICATION:

PROGRAM FOR 16 BIT MULTIPLICATION:

Get the lower byte of first number

Get the lower byte of second number

Subtract lower byte of second number

from lower byte of first number

Get the higher byte of first number

Get the higher byte of second number

Subtract higher byte of second number

and borrow from previous subtraction

Store the result

Stop


33/102


4100 LXI D,0000

4101

4102

4103 LXI SP,FFFF4104

4105

4106 LXI B,2222

4107

4108

4109 LXI H,0000

410A

410B

410C L2 DAD SP

410D JNC L1

410E410F

4110 INX D

4111 L1 DCX B

4112 MOV A,C

4113 ORA B

4114 JNZ L1

4115

4116

4117 SHLD 4500

4118

4119

411A XCHG

411B SHLD 4502

411C

411D

411E HLT

ALGORITHM FOR 16 BIT DIVISION:1. Start the program.2. Initialize BC to store quotient.

3. Load the dividend.4. Transfer the content to the register pair DE.5. Load the divisor.6. Move the content of H to accumulator.7. If dividend is less than the divisor then store the result.8. Store quotient in 16 bit address.9. Stop the program.


34/102

FLOW CHART16 BIT DIVISION:

Start St

PROGRAM FOR 16 BIT DIVISION:

Get the divisor in A reg, move to B reg and get the dividend in A reg

Clear C register for Quotient

Compare B register and A register

If

Subtract the content of B

register from a register

Stop

No

Yes

Increment the Quotient (C register)

Store the reminder (A

register) in memory

Move the content of C

register to A register and

store it in memory

Start


35/102


4100 START LXI H, 4500H

4101

4102

4103 LXI B, 4502H

41044105

4106 LXI D, 4504H

4107

4108

4109 L1 MOV A, L

410A SUB C

410B MOV L, A

410C MOV A, H

410D SBB B

410E MOV H, A

410F JC L24110

4111

4112 INX D

4113 JMP L1

4114

4115

4116 L2 DAD B

4117 SHLD 4506

4118

4119

411A XCHG

411B SHLD 4508H

411C

411D

411E HLT

Exp no: 6

Date :


36/102

PROGRAMMING FOR ARITHMETIC OPERATIONS USING 8086

ARITHMETIC OPERATION

AIM:

To perform arithmetic operations like addition, subtraction, multiplication and division

using 8086.

1. ADDITION:2. SUBTRACTION.3. MULTIPLICATION.4. DIVISION

APPARATUS REQUIRED:

S.No Apparatus Required Quantity

1. 8085 Microprocessor kit 1

2. Power supply -

3. Opcode sheet 1

A. ALGORITHM FOR 16 BIT ADDITIONS;

1. Start the program.2. Load the first data in AX register.3. Load the second data in BX register.

4. Clear CL register.5. Add the two data and get sum in AX register.6. Store sum in memory.7. Check for carry.8. Increment CL register.9. Stores carry in memory.10.Stop.


37/102

FLOWCHART:

Load the first data in AXregister

Load the second data in

Bx register

Clear CL register

Is

CF=

Store carry in memory

Increment CL

YES

NO

Start

Sto


38/102

PROGRAM FOR 16 BIT ADDITIONS IN 8086:

Memory

Address

Hex.

Code

Mnemonic Instruction Comments

Label Opcode Operand

1000 C7 START MOV AX ,#1234 Load the data in AX reg

1001 C0

1002 34

1003 12

1004 C7 MOV BX,#5678 Load the data in BX reg

1005 C3

1006 78

1007 56

1008 01 ADD AX,BX Add two data and get sum inAX reg1009 D8

100A 89 MOV [1200],AX Move the sum value to memory

100B 06

100C 02

100D 11

100E F4 STOP HLT Halt the process


39/102

B. ALGORITHM FOR 16 BIT SUBTRACTIONS:

1. Start the program.2. Load the minuend in AX register.3. Get the subtrahend in BX register.4. Clear CL register to account for sign.5. Subtract the content of BX from AX.6. Check for carry. If cy=1 go to next step.7. Increment CL register.8. Store the sign bit in memory.9. Stop.


40/102

FLOWCHART:

Get minuend in AXregister

Get subtrahend in BX

register

Clear CL register

Is

CF=

Store difference in

memory

Increment CL

YES

NO Complement AX

Add 01 to AX

Store

Start

Sto


41/102

PROGRAM FOR 16 BIT SUBTRACTIONS IN 8086:

Memory

Address

Hex.

Code

Mnemonic Instruction Comments


1000 C7 START MOV AX ,#1234 Load the data in AX reg

1001 C0

1002 34

1003 12

1004 C7 MOV BX,#5678 Load the data in BX reg

1005 C3

1006 78

1007 56

1008 01 ADD AX,BX Add two data and get sum in

AX reg1009 D8

100A 89 MOV [1200],AX Move the sum value to

memory100B 06

100C 02

100D 11

100E F4 STOP HLT Halt the process


42/102

C. ALGORITHM FOR 32 BIT MULTIPLICATIONS:

1. Load address of data in BX register2. Clear CX register to account for carry3. Get D1LW in AX & D2 LW in BP4. Multiply MX&BP to get product1 in AX&BX5. Save P1UW in SI register6. Get D1UW in AX register7. Multiply AX&BP to get product2 in AX&DX8. Check for array9. Increment CX10.Save P2UW in DI register11.Multiply AX&BP12.Add P3LW to SI register13.Add CX & P3LW14.Clear CX register15.Check for carry16.Increment CX register17.Save third & fourth word of product in memory18.Stop


43/102

FLOWCHART:

Save P1LW in SI

Get P1UW in

Add D2 LW to SI

`

Multiply AX & BP

Load the address of data

in BX register

Get D1 LW in AX

register

Start

Get D2 LW in

BP

Save AX

A


44/102

Is

Increment CX

Save P2

in DI

Get D2UW in

Add P3LW to SI

Is

CF=1

Increment CX

Add CX & P3UW

Clear CX

Save SI as

Multiply AX & BX


45/102

Multiply AX & BP to get

Add DI & AX to get third

Add CX previous carry to get fourth

product of final product

Get D1UW in

Stop

Save the data


46/102

PROGRAM FOR 32 BIT MULTIPLICATION IN 8086

Memory

Address

Hex.code Mnemonic Instruction Comments

Label Opcode

1000 C7 START MOV AX,#0004H Move the data in reg AX

1001 C01002 04

1003 00

1004 C7 MOV BX,#0005H Move the data in reg BX

1005 C3

1006 05

1007 00

1008 F7 MUL BX Multiply AX and BX

1009 E3

100A 89 MOV [1102],AX Load the data from AX reg

to address100B 06

100C 02100D 11

100E 89 MOV [1104],BX Load the data from BX reg

to address100F 16

1010 04

1011 11

1012 F4 STOP HLT Halt the process


47/102

D. ALGORITHM FORDIVISION OF 32 BIT DATA BY 16 BIT DATA :

1. Load the address of data in SI register.2. Get lower word of dividend in AX register.3. Get upper word of dividend in DX register.4. Get divisor in BX register.5. Perform division to get quotient in AX and divider in DX.6. Save quotient and remainder.7. Stop.

FLOWCHART

Get lower word of

dividend in AX register

Get upper word of

dividend in DX register

Divide AX and DX with BX

Save quotient in

Save remainder in

memory

Start

Sto


48/102

PROGRAM FOR DIVISION OF 32 BIT BY 16 BIT DATA :

Exp no: 7

Date :

MemoryAddress

Hex.code Mnemonic Instruction CommentsLabel Instruction

1000 C7 START MOV AX,#0004H Move the data in reg AX

1001 C0

1002 04

1003 00

1004 C7 MOV BX,#0005H Move the data in reg BX

1005 C3

1006 05

1007 00

1008 F7 MUL BX Multiply AX and BX

1009 E3

100A 89 MOV [1102],AX Load the data from AX reg

to address100B 06

100C 02

100D 11

100E 89 MOV [1104],BX Load the data from BX reg

to address100F 16

1010 04

1011 11

1012 F4 STOP HLT Halt the process


49/102


AIM:To write an assembly language program for the below given instructions using 8086

microprocessor kit.

A. Maximum/MinimumB. Code conversion

APPRATUS REQUIRED:


1.

2.


Power supply

1

A. ALGORITHM FOR MINIMUM NUMBERS IN AN ARRAY:

1. Start2. Load starting address of array in SI register3. Load number of byte in array in CL register4. Increment array pointer5. Get first byte of array in AL register6. Decrement byte count

7. Increment array pointer8. Get next byte in BL register9. Compare AL and BL10.Checks carry flag11.Move BL and AL12.Check zero flag13.Save smallest data14.Stop


50/102

FLOWCHART:

Start

Load address of array inSI register

Load address of result

in DI register

Set CL as byte count

Increment array pointer

Decrement byte count


Get byte in BL register

Get first byte of array in AL

register

Compare al and BL register

Is

A

B

C

YES

NO


51/102

A

Move BL and AL

Decrement CL

IS

Store AL in memory

Stop

B

C

NO

YES


52/102

PROGRAM FOR SEARCHING OF MINIMUM NUMBER IN AN ARRAY

Memory

Address

Hex.

Code

Mnemonic InstructionComments


1000 BE MOV SI,1100 set SI register as

1001 11 pointer

1002 00

1003 BF MOV DI,1200 set DI register as

1004 12 pointer for result

1005 00

1006 8A MOV CL,[SI]

1007 0C

1008 46 INC SI increment address

1009 84 MOV AL,[SI] pointer

100A 04

100B FE DEC CL

100C C9

100D 46 AGAIN INC SI makes SI to point to

100E 8A MOV BL,[SI] next data

100F 1C get next data in BL

1010 3A CMP AL,BL register

1011 C3

1012 72 JC AHEAD if cy=1 then AL is

1013 02 less than BL

1014 8A MOV AL,BL

1015 C3

1016 FE AHEAD DEC CL decrement count

1017 C9

1018 75 JNC AGAIN if count is not zero

1019 F3 repeat search101A 88 MOV [DI],A store smallest data

101B 05 in memory

101C F4 HLT


53/102

B. ALGORITHM FOR MAXIMUM NUMBER IN AN ARRAY

1. Start2. Load the starting address of array in SI register3. Load the address of result in DI register4. Load number of bytes in the array in CL register5. Increment array pointer6. Get first byte of array in AL register7. Get next byte of array in BL register8. Checks carry flag9. Move BL and AL10.Decrement byte count11.Check zero flag12.Store largest data13.Stop


54/102

FLOW CHART:

Start

Set CL as byte count


Set SI register as array pointer

Set DI register as result pointer

Decrement byte count

B

Get the first byte of

array in AL register

Decrement the byte count

Get the next byte of array in

BL

Compare AL AND BL register

iscf=0

YES

NO

A

C


55/102

IS

STORE AL IN MEMORY

STOP

B

NO

YES

DECREMENT BYTE COUNT

MOVE BL AD AL

A

C


56/102

PROGRAM FOR SEARCHING OF MAXIMUM NUMBER IN AN ARRAY

Memory

Address

Hex.

Code



1000 BE START MOV SI,1100 set SI register as

1001 11 pointer

1002 00

1003 BF MOV DI,1200 set DI register as

1004 12 pointer for result

1005 00

1006 8A MOV CL,[SI] set CL as count for

1007 0C element

1008 46 INC SI increment address

1009 84 MOV AL,[SI] pointer

100A 04

100B FE DEC CL

100C C9

100D 46 AGAIN INC SI makes SI to point to

100E 8A MOV BL,[SI] next data

100F 1C get next data in BL

1010 3A CMP AL,BL register

1011 C3

1012 72 JNC AHEAD if cy=1 then BL as

1013 02 current largest

1014 8A MOV AL,BL

1015 C3

1016 FE AHEAD DEC CL decrement count

1017 C9

1018 75 JNC AGAIN if count is not zero

1019 F3 repeat search101A 88 MOV [DI],AL store largest data

101B 05 in memory

101C F4 HLT


57/102

Exp no:8 STRING MANIPULATION

AIM:To write and execute a program to perform the string manipulation multibyte addition using

8086 microprocessor.

APPARATUS REQUIRED:

S. NO Apparatus required Quantity

1. 8086 microprocessor kit 1

2. Power supply 1

ALGORITHM:

1. XOR the BX register with AX register.

2. XOR the BX register with BX register.

3. Move the data 05 to CL register.

4. Move the content of 1200 to SI register.

5. Move the content of SI register to BL register.

6. Add the content of BX register with AX register and the result is stored in AX register.

7. Execute the loop1 instruction.8. Move the AX register to SI register.

9. Stop the program.


58/102

FLOW CHART:

YES

NO

XOR the content of BX register

with BX register

Move the 05 value to CL

Move the content of 1200 to SI

register

Move the content of SI to BLregister

Increment the SI value

LOOP

START

XOR the content of BX register

with AX register

A


59/102


60/102

PROGRAM:

ADDRESS OPCODE LABEL INSTRUCTION OPERAND COMMENTS

1000 31,CD XOR AX,BX XOR the content of AXregister with BX register

1002 31,0B XOR BX,BX XOR the content of BXregister with BX register

1004 C6,C1,05 MOV CL,05 Move the data 05 to CL

register

1007 C7,C6,00,12 MOV SI,1200 Move the content of1200 to SI register

100B 8A,1C LOOP 1 MOV BL,[SI] Move the content of SI

register to BL register100D 01,08 ADD AX,BX Add the content of BX

register with AX

register

100F 46 INC SI Increment SI register

1010 F2,F9 LOOP LOOP 1 Go to loop 1

1012 89,04 MOV [SI],AX Move the content of AX

register to SI register

1014 F4 HLT Stop the program


61/102

Exp no:9 EVEN OR ODD

AIM:

To write and execute an assembly language for finding whether the given number is even or

odd.

APPARATUS REQUIRED:

S.NO APPARATUS REQUIRED QUANTITY

1 8086 Microprocessor kit 1

2 Power supply 1

ALGORITHM:

1. Start the program.

2. Clear the CX register.

3. Clear the D register.

4. Move the content 06 to CL register.

5. Move the content 1300 to SI register.

6. Move the SI value to AL register.

7. Shift AL register by one.

8. Jump if carry to LI.

9. Increments BL register value.

10. Jump to loop 2.

11. Increment DL value.12. Increment SI value.

13. Go to loop 3.

14. Move the content from DL to SI and BL to SI.

15. Increment SI value.

16. Stop the program.


62/102

FLOW CHART:

Start

Clear the CX register

Clear the DL register

Clear the BL register

Move the data 06 to CL

Move the content of 1300 to

SI register

Move the SI value to AL

register

B

A


63/102

YES

NO

YES

NO

Increment the BL register

Increment the DL value


Jump

carr

Jump if

carr

A

D

D

Loop

C

B


64/102


Move the content of DL to (SI)

Move the content of BL to (SI)

Stop

C


65/102

PROGRAM:

ADDRESS OPCODE LABEL INSTRUCTION OPERAND COMMENT

1000 C7,C1,00,00 MOV CX,00 Clear the CX register

1004 C6,C2,00 MOV DL,00 Clear the DL register

1007 C6,C3,00 MOV CL,06 Move the data 06 to CLregister

100A C6,C1,06 MOV SI,1300 Move the content of 1300 SI register

100E C7,C6,06,13 L3 MOV AL,[SI] Move the content of SI to

AL register

1010 D2,EB SHR AL Shift AL register by one

1012 72,05 JC 101C Jump if carry to L2

1014 FE,C3 INC BL Increment BL register by o

1016 E9,1E,10 JMP 101B Jump to L11019 FF,C2 INC DL Increment DL by one

101B 46 L1 INC SI Increment SI value

101C E2,FO L2 LOOP 100E Go to loop 3

101E 88,14 MOV [SI],DL Move the content DL to SI

1020 46 INC SI Increment SI value

1021 88,1C MOV [SI],DL Move the content DI to SI

1023 F4 HLT Stop the program


66/102

Exp no: 10

Date :

PROGRAMMING FOR 8 BIT ARITHMETIC OPERATION USING 8051

AIM:

To write an assembly language program for 8- bit addition, subtraction, multiplication and

division using 8051.

APPARATUS REQUIRED:

1. 8051 microcontroller2. Power supply

ALGORITHM FOR 8 BIT ADDITIONS:

1. Start the program2. Get the 1st operand in accumulator3. Add 2nd operand with 1st operand in accumulator4. Move data from accumulator to data pointer5. Store the result in memory6. Stop

FLOW CHART:

Get the 1st operand

in A

Add the immediate data with content of A

register

Store the result in memory

Sto

Start


67/102

PROGRAM FOR 8-BIT ADDITION OF 8051

Memory

AddressHex. Code



4100 74 MOV A,#34 Get 1st operand in A register

4101 34

4102 24 ADD A,#62 Add operand in A register

4103 62

4104 90 MOV DPTR,#4500

4105 45

4106 004107 F0 MOV X@DPTR,A Store the result in memory

4108 80 SJMP 4108

4109 FE


68/102

ALGORITHM 8 BIT SUBTRACTION IN 8051:

1. Start the program2. Get the 1st operand in accumulator3. Subtract 2nd operand from 1st operand in accumulator4. Move data from accumulator to data pointer5. Store the result in memory6. Stop

FLOWCHART:

Get the 1st operand in A

re ister

Subtract 2nd operand from A

Store the result in memory

Start

Stop


69/102

PROGRAM FOR 8-BIT SUBTRACTION OF 8051:

Memory

Address Hex. Code

Mnemonic Instruction

CommentsLabel Opcode Operand

4100 74 MOV A,#12 Get 1st operand in A register

4101 12

4102 94 SUBB A,#08 Subtract 2nd

operand from

4103 68 accumulator

4104 90 MOV DPTR,#4500 Move to data pointer

4105 45

4106 00

4107 F0 MOV X@DPTR,A Store the result in memory

4108 80 SJMP 4108

4109 FE

ALGORITHM FOR MULTIPLICATION:

1. Start the program2. Get the two numbers3. Multiply two numbers4. Store the result5. Stop the program


70/102

FLOW CHART FOR MULTIPLICATION

PROGRAM FOR MULTIPLICATION:

ADDRESS LABEL MNEMONICS OPCODE

4100 START MOV A,#04 74,04

4102 MOV B,# 02 75, F0,02

4105 MUL A,B A4

4106 MOV DPTR,#4500 90,45,00

4109 MOVX @ DPTR,A F0

410A INC DPTR A3

410B MOV A ,B E5,F0

410D MOV X,@DPTR,A F0

410E HERE SJMP HERE 80, FE

Start

Get the

Multiply two numbers

Store the

Sto


71/102

ALGORITHM FOR DIVISION:

1. Start the program2. Get the two numbers3. Divide two numbers4. Store the result5. Stop the program

FLOW CHART FOR DIVISION:

Start

Get two inputs

Divide

two

Store the

results

Sto


72/102


73/102

Exp no :11

Date:

1S AND 2S COMPLEMENT USING 8051

AIM:

To write an assembly language program for 1s and 2s complement using 8051.

ALGORITHM:

1. Start the program.

2. Move the value to a register.

3. Compliment the value of a register.

4. The result is stored in the address of 4500.

5. Move the content of a to DPTR.

6. Increment the a value.

7. Increment the DPTR value.

8. Move the content of a to DPTR.

9. Jump to the next process.


74/102

PROGRAM:

ADDRESS OPCODE LABEL MNEMONICS OPERAND COMMENTS

4100 MOVE A, #DPTR Move the content of

DPTR value to A4101

4102CPL A Compliment the value of

A

4103MOV DPTR, #4200 Move the value from

4200 to DPTR4104

4105

4106MOV X @DPTR, A Move the A value to

DPTR

4107INC A Increment the A Value

4108INC DPTR Increment the DPTR

Value

4109MOV X @DPTR, A Move the content of A

value to DPTR

410ASJMP 410A Short jump

410B


75/102

FLOW CHART:

Start

Get divide in A

Get divide in B

Divide by B

Store result in memory

Stop


76/102

PROGRAM:

ADDRESS OPCODE LABEL MNEMONICS OPERAND COMMENTS

4100 MOV A, #08 Move the

content to A

register4101

4102 MOV B, #02 Move the

content to B

register4103

4104

4105 DIV A,B Divide thecontent of B

from A


77/102

Exp no: 12

Date :

INTERFACING AND PROGRAMMING OF STEPPER MOTOR

CONTROL USING 8085

AIM:To interface stepper motor with 8085.

APPARATUS REQUIRED:

1. 8085 microcontroller kit2. Stepper motor control kit3. Power supply

ALGORITHM:

1. Start the program2. Set count for four stepping sequence.3. Set control word.4. Set output data for a sequence.5. Wait for one millisecond.6. Decrement count value.7. Stop.


78/102

FLOW CHART:

Start

Initialize ports

Set count for 4 stepping

sequence

Output data for a

Wait for 1 millisecond

Is

Count=0?

Yes

No


79/102

PROGRAM FOR INTERFACING OF STEPPER MOTOR WITH 8085:

Memory

Address

Hex.

Code



4100 21 START LXI H,LOOK UP

4101 1A

4102 41

4103 06 MVI B,04

4104 04

4105 7E REPT MOV A,M

4106 D3 OUT 0C0H Out data

4107 C0

4108 11 LXI D,0303H Move immediate data4109 03

410A 03

410B 00 DELAY NOP

410C 1B DCX D Decrement DE pair

410D 7B MOV A,E

410E B2 ORA D

410F C2 JNZ DELAY If non zero jump to delay

4110 0B

4111 41

4112 23 INX H Increment HL pair

4113 05 DCR B Decrement B

4114 C2 JNZ REPT If it is non zero jump to Rept

4115 05

4116 41

4117 C3 JMP START Jump to start

4118 00

4119 41

411A DB LOOKUP

411B 09 To rotate in forward direction

411C 05411D 06

411E 0A


80/102

Exp no:13

Date: INTERFACING 8253 TIMER WITH 8085

AIM:

To interface 8253 interface board to 8085 p and verify the operation of 8253 in six

different modes.

APPARATUS REQUIRED:

8085 p kit, 8253 interface board, DC regulated power supply, VXT parallel bus, CRO.

FLOW CHART:

Stop

Move immediately 00 to

accumulator

Out the (A) port

Move immediately CC to A

register

Out the A port value

Move immediately 90 to A


Move immediately 88 to A

re ister

Out the A value to DAT register


Start


81/102

PROGRAM:

Address Opcodes Label Mnemonic Operands Comments

4100 3E 36 START: MVI A,36 Channel 0 in mode 3

4102 D3 CE OUT CE Send Mode control word

4104 3E 0A MVI A,0A LSB of count

4106 D3 C8 OUT C8 Write count to register

4108 3E 00 MVI A,00 MSB of count

410A D3 C8 OUT C8 Write count to register

410C 76 HLT Stop the program


82/102

Exp no:14

Date :

PROGRAMMING FOR INTERFACE EXPERIMENTS

AIM:

To study the value of analog to digital conversion and digital to analog conversion.

A. ADC INTERFACING WITH 8085B. DAC INTERFACING WITH 8085

APPARATUS REQUIRED:

1. 8085 microprocessor kit2. ADC, DAC interface card

A. ALGORITHM FOR ADC INTERFACE:

1. Start the program2. Initialize the count value3. Move the data immediately to the accumulator4. Store the data in specified address5. Display the data with LED glowing ON/OFF6. Stop the program


83/102

FLOWCHART:

Start

Initialize the value

Set the mode for count

Transfer the data to output address

Check it with LED

Stop

Display


84/102

PROGRAM FOR ADC INTERFACE:

Memory

address

Label Mnemonics Hexade

cimal

code

Comments

Op code Operand

4100 Start MVI A,10 3E Move the data immediately to the

accumulator

4101 10

4102 OUT E0 D3 Display to port

4103 E0

4104 MVI A,18 3E Move the data immediately to the

accumulator

4105 18

4106 OUT E0 D3 Display to port

4107 E0

4108 MVI A,01 3E Move the data 00 immediately to

the accumulator

4109 01

410A OUT D0 D3 Display to port

410B D0

410C XRA A AF Clear the accumulator content

410D XRA A AF Clear the accumulator content

410E XRA A AF Clear the accumulator content

410F MVI A,00 3E Move the data 00 immediately to

the accumulator4110 00

4111 OUT D0 D3 Display to port

4112 D0

4113 HLT 76 Halt the program


85/102

B. ALGORITHM FOR DAC INTERFACE:

A. SQUARE WAVE GENERATOR:B. SAW TOOTH WAVEFORMC. TRIANGULAR WAVEFORM

A. ALGORITHM FOR SQUARE WAVE GENERATOR:

1. Start the program2. Clear the accumulator3. Load minimum value to the accumulator

4. Display data in output port address5. Call subroutine SQR6. Delay program SQR7. Assign first count to C register8. Assign second count to B register9. Decrement the second count10. If count is zero, decrement the count else go to step 911. If carry is zero go to step 812.Return to main program


86/102

Clear the accumulator content

Load the data in output port

Display the output

Call the subroutine

Load the maximum value in acc

Display the data in the output

Call the subroutine

Delay the SQR

Assign I count to C reg

Assign II count to B reg

Decrement II count

Count=

Decrement I count

Count=

Stop

Start


87/102

PROGRAM FORSQUARE WAVE GENERATOR:

Memory

address


cimal

code

Comments

Op code Operand

4101 MVI A,00 3E Move the data immediately to theaccumulator

4102 00

4103 OUT C0 D3 Display to port

4104 C0

4105 CALL SQR CD Call the subroutine

4106 12

4107 41

4108 MVI A,FF 3E Move the data immediately to theaccumulator

4109 FF

410A OUT C0 D3 Display to port410B C0

410C CALL SQR CD Call the subroutine

410D 12

410E 41

410F JMP LOOP1 C3 Jump to specified location

4110 01

4111 41

4112 MVI C,03 0E Move the data immediately to theaccumulator

4113 03

4114 MVI B,FF 06 Move the data immediately to theaccumulator

4115 FF

4116 DCR B 05 Decrement the B register4117 JNZ LOOP4 C2 Jump to specified location if no

zero exists

4118 16

4119 41

411A DCR C 0D Decrement the B register

411B JNZ LOOP3 C2 Jump to specified location if nozero exists

411C 14

411D 41411E RET 76 Return to main program


88/102

B. ALGORITHM FOR SAW TOOTH WAVEFORM:


2. Load initial data as accumulator3. Display the first data in output port address4. Decrement the content of accumulator5. If the data is zero jump to loop1

FLOWCHART:

Load the initial value in the acc

Display the data in accumulator to output port address

Increment the content of accumulator

Checkthe

data is

Start


89/102

PROGRAM FOR SAW TOOTH WAVEFORM:

C. ALGORITHM FOR TRIANGULAR WAVEFORM:

1.Start the program2.Load the initial data in the accumulator3.Write the data from the accumulator to the output port address4.Increment the content of accumulator5.If zero flag is reset, jump to loop16.Move the data FF to accumulator7.Write the data from the accumulator to the output port address8.Decrement the content of accumulator9.Jump to loop3 if no zero exist

Memory

address


cimalcode

Comments

Op code Operand

4050 LOOP1 MVI A,00 3E Move the data immediatelyto the accumulator

4051 00

4052 LOOP2 OUT C0 D3 Write the data from A to portaddress

4053 C0

4054 INR A 3C Increment the Accumulator

4055 JNZ LOOP2 C2 Jump to specified location if

no zero occurs

4056 52

4057 40

4058 JMP LOOP1 C3 Jump to specified location

4059 50

405A 40


90/102

FLOW CHART:

Load the initial data to accumulator

Dis la 1st content in out ut ort

Initialize the 2nd content of accumulator

If

Dis la accumulator content in o/ ort

Decrement 1st value

If

Yes

Yes

No

No

Start


91/102

PROGRAM FOR TRIANGULAR WAVEFORM:

.

Memory

address


cimal

code

Comments

Op code Operand

4060 LOOP3 MVI A,00 3E Move the data immediately to theaccumulator

4061 00

4062 LOOP1 OUT C0 D3 Write the data from A to portaddress

4063 C0

4064 INR A 3C Increment the Accumulator

4065 JNZ LOOP1 C2 Jump to specified location if nozero occurs

4066 62

4067 40

4068 MVI A,FF 3E Move the data immediately to theaccumulator

4069 FF

406A LOOP2 OUT C0 D3 Write the data from A to portaddress

406B C0

406C DCR A 3D Decrement the Accumulator

406D JNZ LOOP2 C2 Jump to specified location if nozero occurs

406E 6A

406F 40

4070 JMP LOOP1 C3 Jump to specified location

4071 50

4072 40


92/102

Exp no:15

Date :

PROGRAMMING FOR INTERFACE EXPERIMENTS

AIM:To control the traffic light using 8085 microprocessor and interface of 8279

APPARATUS REQUIRED:8085 trainer kit, 8279 interface board, DC power supply.

B. ALGORITHM FOR INTERFACING 8279 WITH 8085 TO DISPLAY THECHARACTER C

1. Start the program2. Get mode and display set3. By immediate address mode get value in A-register4. Count value in display5. Write content in display RAM6. Out the character7. Stop


93/102

FLOW CHART:

Start

Move the value in

Clear the dis la

Get the values of

Out the counter value

Stop

Display the character


94/102

PROGRAM FOR INTERFACING OF 8279 WITH 8085:

Memory

AddressHex. Code



4100 3E MVI A,00 Mode & Display set

4101 004102 D3 OUT C2 Out control word C2

4103 C2

4104 3E MVI A,CC Clear display RAM

4105 CC

4106 D3 OUT C2

4107 C2

4108 3E MVI A,90 Write display RAM

4109 CC

410A D3 OUT C2

410B C2

410C 3E MVI A,6C Display C

410D 6C

410E D3 OUT C0

410F C0

4110 3E MVI A,FF

4111 FF

4112 D3 OUT C0 Out the content

4113 C0

4114 D3 OUT C0

4115 C0

4116 D3 OUT C0

4117 C0

4118 D3 OUT C0

4119 C0

411A D3 OUT C0

411B C0

411C 76 HLT


95/102

Exp no:16

Date: Interfacing 8251 with 8085

AIM:

To interface 8251 with 8085

APPARATUS REQUIRED:

8085 p kit, 8251 interface board, DC regulated power supply, VXT parallel bus.

B (1).ALGORITHM FOR INTERFACING OF 8251 WITH 8085:

1. Start the program.2. At transmitter side move the data to accumulator.3. Out the data to port CE.4. Move the data from port to A.5. AND 04 with the content of accumulator.6. If it is non zero jump on to LOP.7. REST 1.

8. For reception move the data to accumulator.9. out data to various port.10.Input data from port.11.If it is non zero jump on to LOP1.12.AND data with accumulator.13.Store the result in 4150.14.RESET 1.


96/102

Start

Out the data to port CE

Out data to various Port

RESET 1

If

AND 04 with the content of

N

In transmitter sidemove the data to

Move the data fromport to A

Yes

In receiver side move

data to accumulator

Out data to port

AND 02 with A

If

N

Yes

FLOW CHART:

Store result

Stop


97/102

PROGRAM FOR INTERFACING OF 8251 WITH 8085

TRANSMITTER PROGRAM:

Memory

Address

Hex.

Code



4100 3E START MVI A,36 Move data to accumulator.

4101 364102 D3 OUT OCE H Out the data

4103 CE

4104 3E MVI A,0A

4105 0A

4106 D3 OUT OC8 H Out the data to port

4107 C8

4108 3E MVI A,00 Clear accumulator

4109 00

410A D3 OUT OC8 H

410B C8410C 3E MVI A,4E

410D 4E

410E D3 OUT OC2 H Out the data to port

410F C2

4110 3E MVI A,37

4111 37

4112 D3 OUT OC2 H

4113 C2

4114 DB

4115 C2 LOP IN OC2 H Cut the data from port

4116 E6 ANI 04 And immediate data 04 with A

4117 04

4118 CA JZ LOP Jump on zero to LOP

4119 14

411A 41

411B 3E MVI A,41 H

411C 41

411D D3 OUT OC0 H

411E CO

411F CF RST 1 Reset


98/102

RECEIVER PROGRAM:

Memory

Address

Hex.

Code



4200 3E MVI A,36 Move 36 to accumulator

4201 36

4202 D3 OUT OCE H

4203 CE

4204 3E MVI A,0A

4205 0A

4206 D3 OUT C8 H

4207 C8

4208 3E MVI A,00

4209 00

420A D3 OUT OC8 H

420B C8

420C 3E MVI A,4E

420D 4E

420E D3 OUT OC2 H

420F C2

4210 3E MVI A,374211 37

4212 D3 OUT OC2 H

4213 C2

4214 DB

4215 C2 LOP1: IN OC2 H

4216 E6 ANI 02 AND 02 with accumulator

4217 02

4218 CA JZ LOP1 Jump on zero to LOP 1

4219 14

421A 42

421B DB IN OC0 H


99/102

Memory

Address

Hex.

Code



421C CO

421D 32 STA 4150 Store in 4150

421E 50

421F 41

4220 CF RST 1


100/102

Exp no:17

Date:

INTERFACING 8255 WITH 8085

AIM:

To interface programmable peripheral interface 8255 with 8085 and study its

characteristics in mode 0, mode 1 and BSR mode.

APPARATUS REQUIRED:

8085 p kit, 8255 interface board, DC regulated power supply, VXT parallel bus.

I/O MODES:

MODE 0SIMPLE I/O MODE:

PROGRAM:

ADDRESS OPCODES LABEL MNEMONICS OPERAND COMMENTS

4100 START: MVI A,90 Initialize port A as

input

and port B as output4101

4102 OUT C6 Send Mode Control

Word4103

4104 IN C0 Read from port A

4105

4106 OUT C2 Display the data in port

B4107

4108 STA 4200 Store the data readfrom port A in 4200

4109

410A

410B STOP: HLT Stop the program


101/102


102/102

Sub program:

ADDRESS OPCODES LABEL MNEMONICS OPERAND COMMENTTS

450E JMP 4200 Go to 4200

450F4560

BSR MODE(Bit Set Reset mode)

PROGRAM:

ADDRESS OPCODES LABEL MNEMONICS OPERAND COMMENTS

4100 START: MVI A,01 Set PC0

4101

4102 OUT C6 Send Mode

Control Word41034104 MVI A,07 Set PC3

4105

4106 OUT C6 Send ModeControl Word4107

4108 STOP: HLT Stop the

program

mp and mc record

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