part a3a - addition give the general formula for adding 2 complex numbers z1 = a + bi and z2 = c +...
TRANSCRIPT
PART A3A - ADDITION
Give the general formula for adding 2 complex numbers z1 = a + bi and z2 = c + di
Give a simple example demonstrating the addition
Show how to add 2 complex numbers graphically. It is not necessary to provide any numbers. This is easily done when you use the complex plane and draw the complex numbers as vectors. Resources: Dave’s Short Course, Wikipedia (look up Complex numbers), Parallelogram method, Head to Tail method.
Your method should allow someone who is given z1 and z2to “eye-ball”/sketch where z1 + z2 will be.
z1
z2
A3B – DIVISION ALGEBRAICALLY
Give the general formula/explanation for dividing 2 complex numbers z1 = a + bi and z2 = c + di
Give an appropriately worked out example of division.
A3B GRAPHICAL DIVISION: POLAR FORM
Instead of expressing a complex number as z = a + bi, we can define it in terms of the angle θ it makes with the x-axis going counter-clockwise and its radius (also called modulus, radius, or distance from the origin)
Now z can be expressed as (r, θ)
or z = r(cos θ + i sin θ)
REPRESENTING DIVISION GRAPHICALLY Division is a very similar operation to multiplication (meaning it involves a rotation and scaling).
• Search online for a definition of division in polar form.
• Take 2 simple complex vectors in the first quadrant (radii = 1, 2, 3, … and angles such as 90, 60, 45, 30, etc)
• Divide them algebraically: z1/z2 (you can use the same example you have for the first part of the problem)
• Convert that answer to polar form to understand what dividing by Z2 does to Z1
• Draw an appropriate picture demonstrating your understanding of division in polar coordinates.
www.desmos.com/calculator change window setttings to Polar and plot points by typing (1,1) or (-2,3). Use Word to draw the lines with arrows
(2,0) or (2, 0⁰)
(-2,3) or (√13, 124⁰) (0,3) or (3, 90⁰)
(1,1) or (√2, 45⁰)
CONVERTING TO POLAR COORDINATESa) (2,0) or z = 2 + 0i
b) (0,3) or z = 0 + 3i
c) (1,1) or z = 1 + i
d) (-2, 3) or z = -2 + 3i