partial fraction expansion
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ELEC361: Signals And SystemsDr. Aishy Amer, Concordia University, Electrical and Computer Engineering
Review: Partial Fraction ExpansionPartial fractions are several fractions whose sum equals a given fraction
Purpose: Working with transforms requires breaking complex fractions into simpler fractions to allow use of tables of transforms
1111
)1)(1()1(5)1(6
15
16
15
16
1111
2
2
−−
=−+++−
=−
++
•
−+
+=
−−
•
ss
ssss
ss
ssss
2
Review:Partial Fraction Expansion
32)3()2(1
++
+=
+++
sB
sA
sss
( ))3()2(
2)3()3()2(
1++
+++=
+++
sssBsA
sss
32
21
)3()2(1
++
+−
=++
+ssss
s
1=+ BA 123 =+ BA
Expand into a term for each factor in the denominator.Recombine right hand side
Equate terms in s and constant terms. Solve.Each term is in a form so that inverse Laplace transforms can be applied.
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Review:Partial Fraction Expansion: Different terms of 1st degree
To separate a fraction into partial fractions when its denominator can be divided into different terms of first degree, assume an unknown numerator for each fraction
561
11)1()111(
)1)(1()()(
)1)(1()1()1(
)1()1()1()111(
2
2
==⇒⎭⎬⎫
−=−=+
−−
=−+−++
=−+
++−=
−+
+=
−−
BAABBA
ss
ssABsBA
sssBsA
sB
sA
ss
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Review: Partial Fraction Expansion: Repeated terms of 1st degree
When the factors of the denominator are of the first degree but some are repeated, assume unknown numerators for each factor
If a term is present twice, make the fractions the corresponding term and its second powerIf a term is present three times, make the fractions the term and its second and third powers
2114
321
)()2()1()1(43)()()(
)1()1()1()1(
)1()1()1()1(43
2
22
33
2
323
2
===⇒⎪⎭
⎪⎬
⎫
=++=+
=
+++++=
++++=++=
=+
++
+++=
++
++
+=
+++
CBACBA
BAA
CBAsBAAsCsBsAsssN
sDsN
sC
ssBsA
sC
sB
sA
sss
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Review: Partial Fraction Expansion: Different quadratic terms
When there is a quadratic term, assume a numerator of the form Bs + C
05.05.0120
0)2()()(1
)1()1()2(1)2()1()2)(1(
1
2
2
22
===⇒⎪⎭
⎪⎬
⎫
=+=++
=+
++++++=
++++++=
+++
++
=+++
CBACACBA
BACAsCBAsBA
sCsBsssAss
CBssA
sss
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Review:Partial Fraction Expansion: Repeated quadratic terms
When there is repeated quadratic term, assume two numerator of the form Bs + C and Ds+E
05.0025.025.0
1240324
0235022
0)1()1()2)(1(
)2)(1()2(1)2()2()1()2)(1(
1
2
222
22222
=−==−==
⇒
⎪⎪⎪
⎭
⎪⎪⎪
⎬
⎫
=++=++++
=+++=++
=+
++++++++
++++++=
+++
+++
++
+=
+++
EDCBA
ECAEDCBA
DCBACBA
BAsEsDssssC
sssBsssAss
EDsss
CBssA
sss