penggunaan kalkulator saintifik
DESCRIPTION
math ting4TRANSCRIPT
PENGGUNAAN
KALKULATOR
SAINTIFIK
TOPICS:
Standard Form ( Form 4)
Quadratic Expression and Equation. ( Form 4)
Simultaneous Linear Equation ( Form 3)
Matrices ( Form 5 )
Number Bases ( Form 5 )
STANDARD FORM
•TO ROUND OFF THE NUMBER WITH THE GIVEN SIGNIFICANT FIGURE
Round off 70615 correct to three significant figures.
Bundarkan 70615 betul kepada tiga angka bererti
A. 70 600 C. 70 610
B. 70 620 D. 70 700
MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan
70615 = Answer Tekan ENG sehingga kuasa 10 menjadi
00
2. Round off 0.002496 correct to three significant figures.
Bundarkan 0.002496 betul kepada tiga angka bererti
A 0.02 C 00.00249
B 0.03 D 0.00250
MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan
0.002496 = Answer Tekan Shift ENG sehingga kuasa 10
menjadi 00
6.27 EXP ( - ) 4 Answer Tekan Shift ENG
sehingga kuasa 10 menjadi 00
To Convert Standard Form into Single Number
41027.6
A. 0.0000627 C. 62 700
B. 0.000627 D. 6 270 000
1.
5108.1
A. 180000 C. 18000
B. 1800 D. 1800000
1.8 EXP 5 = Answer
2.
Taip soalan 0.0000203 = Answer
Express 0.0000203 in standa Inrd form
1. Express 0.0000203 in standard form
A C
B D
51003.2 71003.2 61003.2 8103.20
Convert Single Number Into Standard Form
State 7560000 in standard form.
A C
B D
5 10 x 7.56-5 10 x 7.56
-6 10 x 7.566 10 x 7.56
MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan
7560000 = Answer
Operational in Standard Form
MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan
6.35 EXP (-) 5 – 3.2 EXP ( - 6) = Answer
65 102.31035.6
A C
B D
51012.3 61012.3
51003.6 61003.6
004.0
1004.3 14
A C
B D
131060.7 141060.7
151060.7 161060.7
MODE 5 X Scί 2 Scί 0 ~ 9 3 Taip soalan
3.04 EXP (14) ÷ 0.04 = Answer
QUADRATIC EQUATION
* FACTORISATION OF QUADRATIC EXPRESSION
MODE 3 X EQN 1 Tekan arrow menghala ke
kanan Degree ? 2 a? 10 = b ? 1 = c ? (-) 2 = Answer
X = 0.4 Tekan a b/c 2 5 = X = - 0.5
Tekan a b/c =
Factorise 210 2 xx
A C
B D
)2)(110( xx)1)(25( xx
)210)(1( xx
)1)(25( xx
1 2
2
1
( x - ) ( x + ) 5
2
2
1
Paper 2 : Solve the quadratic equations:
Selesaikan persamaan kuadratik:
x
xx
2
11123
Answer/Jawapan :
[4 marks/markah]
2x2 + 5x – 12 = 0
( 2x – 3 ) (x + 4) = 0
x = 3 x = -4
2 1 2
Simultaneous Linear Equation.
p - 4q = 8
3p + 2q = 17
MODE 3 X EQN 1 Unknowns ? 2
a1 ? 1= b1 ? (-) 4 = c 1 ? 8 = a 2 ? 3 = b 2 ? 2 =
c 2 ? 17 = Answer x = 6 = y = - 0.5 @ - 2
1
Answer : p = 6 , q = - 2
1
Matrices
(b) Using matrices, calculate the values of x and y that satisfy
the following matrix equation.
2
1
35
24
y
x
MODE 3 X EQN 1 Unknowns ? 2
a1 ? (-) 4 = b1 ? 2 = c 1 ? 1 = a 2 ? ( - ) 5 =
b 2 ? 3 = c 2 ? 2 = x = 0.5 @ = y = 1.5 @ 2
3
Answer : x = , y = 2
3
2
1
2
1
NUMBER BASES ( F 5)
Convert Base 2 to Base 10 and Vice versa
Express as a number in base ten.
2110111
MODE 2 X Base 3 BIN Taip =
DEC Answer 2110111
A 1310 C 5510
B 3110 D 11010
Express 126 as a number in base two.
A 1111102 C 11111102
B 11101102 D 11111112
MODE 2 X Base 3 DEC Taip 126 = BIN Answer
Convert Base 8 to Base 10 and Vice versa
Express 1548 as a number in base ten.
A 80 C 864
B 108 D 1925
MODE 2 X Base 3 OCT Taip 154 = DEC Answer
Express 342810 as a number in base eight.
A 544 C 2742
B 428 D 6544
8
8 8
8
MODE 2 X Base 3 DEC Taip 3428 = OCT Answer
Convert Base 8 to Base 2 and Vice versa
Express 4028 as a number in base two.
A 1100102 C 10000102
B 1100100102 D 1000000102
MODE 2 X Base 3 OCT Taip 402 = BIN Answer
Express 10 110 1012 as a number in base eight.
A 2358 C 2658
B 2648 D 5518
MODE 2 X Base 3 BIN Taip 10110101 =
OCT Answer
Operational in Base Two
100102 + 1112 =
A 111012 C 101012
B 110012 D 100012
MODE 2 X Base 3 BIN Taip 10010 + 111 = Answer
GURU YANG BIASA
MEMBERITAHU
GURU YANG BAIK
MEMBERI PENJELASAN
GURU YANG TERBAIK
GURU YANG BAGUS
MEMBERI TUNJUK AJAR
MEMBERI INSPIRASI
SEKIAN
TERIMA KASIH
USAGE OF SCIENTIFIC
CALCULATOR
SELF PRACTICE
Exercises :
1- Round off 6 284 correct to 2 significant figures.
A 6 200 C 6 290
B 6 280 D 6 300
2- Round off 0.00035118 correct to 3 significant figures.
A 0.000351 C 0.003512
B 0.0003511 D 0.0003521
3- Round off 0.0368 correct to two significant figures.
A. 0.003 C. 0.036
B. 0.04 D. 0.037
4. Express as single number.
A. 0.007564 C. 0.000007564
B. 0.00007564 D. 0.0000007564
5.
A 6 x 10 C 6 x 10
B 6 x 10 D 6 x 10
6. Express 558000 in standard form.
A 5.58 x 10 C 5.58 x 10
B 5.58 x 10 D 5.58 x 10
610564.7
000 000 5
03.0
34
8
9
3
4
5
6
7. Factorise 7x2 + 26x –8
8. Factorise 3x2 – 7x –20
7. Solve equation x2 - 3x + 2 = 2(x - 1)
10 . 2h - 2m = 7
4h + 6m = -1
Answer : h = m =
11. 3 v + 4 w = - 6
v – 2w = 8
Answer : v = w =
12. Using matrices, calculate the value of k dan
m which satisfy the following matrix equation :
=
85
21
m
k
11
1
13. Express 67 as a number in base two.
A 1000111 B 1001011
C 1000011 D 1000010
14. Express 1010111 as a number in base ten
A 86 B 87
C 88 D 89
15. Express 275 as a number in base ten.
A 198 B 187
C 189 D 178
16. Express 157 as a number in base eight.
A 234 B 235 C 236 D 237
17. Express 110102 as a number in base eight.
A 268 B 328
C 1228 D 11018
2
10
2
2 2
2
8
8 888
18. 11101 + 1110
A 100011 B 111001
C 101111 D 101011
19. 110112 – 1012 =
A. 10102 C. 101102
B. 11102 D. 100102
20. 100102 - 11012 =
A. 1012 C. 10112
B. 1112 D. 11112
2 2
2
2
2
2