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penentuan tekanan uap murni (pers antoine )

aselonitri

A 14.272

B 2945.47C 224

t 0 C 75

In Pi Sat = A B ! "# C 4.421$$

P1 sat %$.20&%574&5

'itrometana

A 14.204

B 2972.47C 209

t 0 C 75

In Pi Sat = A B ! "# C $.7$7%5&

P2 sat = 42.007%429&1

1 = 0.& 1 = 0

2 = 0.4 2 = 0

P=P2sat #( P1 sat P2 sat) 1 &&.72725 P=P2sat #( P1 sat P2 sat) 1

1 = 1 .P1 sat ! P 0.74%1%2 1 = 1 .P1 sat ! P 0

1 = 0.2 1 = 0.%

2 = 0.% 2 = 0.2

P=P2sat #( P1 sat P2 sat) 1 50.247&5 P=P2sat #( P1 sat P2 sat) 1

1 = 1 .P1 sat ! P 0.$$11%7 1 = 1 .P1 sat ! P 0.%%79$

1 = 0.4 1 = 1

2 = 0.& 2 = 0

P=P2sat #( P1 sat P2 sat) 1 5%.4%745 P=P2sat #( P1 sat P2 sat) 1

1 = 1 .P1 sat ! P 0.5&905% 1 = 1 .P1 sat ! P 1



ta*el +ata

P

0 0 42.007%4

42.007%4 0.2 0.$$11%7 50.247&5

0.4 0.5&905% 5%.4%745

0.& 0.74%1%2 &&.72725

0.% 0.%%79$ 74.9&705

1 1 %$.20&%&

74.9&705

%$.20&%&

0 0.2 0.4 0.& 0.%

0

0.2

0.4

0.&

0.%

1

1.2



1 1.2



penentuan tekanan uap murni (pers antoine )

Benen

A 1$.%59

B 277$.7%

C 5$.0%t 0 C $7$.15

In Pi Sat = A B ! "# C 5.19$2$$

P1 sat 1%0.0497540$1&

"oluen

A 14.010

B $10$.01

C 5$.$&t 0 C $7$.15

In Pi Sat = A B ! "# C 4.$0&52&

P2 sat = 74.1%2$29&12

1 = 0.& 1 = 0

2 = 0.4 2 = 0

P=P2sat #( P1 sat P2 sat) 1 1$7.702% P=P2sat #( P1 sat P

1 = 1 .P1 sat ! P 0.7%4515 1 = 1 .P1 sat ! P

1 = 0.2 1 = 0.%

2 = 0.% 2 = 0.2

P=P2sat #( P1 sat P2 sat) 1 95.$55%1 P=P2sat #( P1 sat P

1 = 1 .P1 sat ! P 0.$77&$% 1 = 1 .P1 sat ! P

1 = 0.4 1 = 1

2 = 0.& 2 = 0

P=P2sat #( P1 sat P2 sat) 1 11&.529$ P=P2sat #( P1 sat P

1 = 1 .P1 sat ! P 0.&1%041 1 = 1 .P1 sat ! P



ta*el +ata

P

0 0.000000 74.1%2$$

sat) 1 74.1%2$$ 0.2 0.$77&$% 95.$55%1

0.4 0.&1%041 11&.529$

0 0.& 0.7%4515 1$7.702%0.% 0.90&&1& 15%.%7&$

1 1.000000 1%0.049%

sat) 1 15%.%7&$

0.90&&1&

sat) 1 1%0.049%

1

20

40

&0

%0

100

120

140

1&0

1%0

200



0 0.2 0.4



Column /

Column /



0.& 0.% 1 1.2



Peritunan BB3 "

p = 70

t te*ak = 7&.4$5&00527

in alpa = 0.&77904&927

alpa = 1.9&974&1%1%

1 = 0.&

2 = 0.4

p2 sat = 44.25204752&

ln p2 sat = $.7%9901&422

t it = 7&.4$55957%4

selisi t it + t te*ak= 4.74$&900& asil olsik

ln P1 sat = 4.4&%4020%%9

p1 sat = %7.21724&199

i = 0.74757&$9&



6 "

p = 70

t te*ak = 79.5&7%$70%%9

in alpa = 0.&&&027$1&5

alpa = 1.94&4%9155

81 = 0.&

82 = 0.4p1 sat = 9&.501&9&$411

ln p1 sat = 4.5&95&05%&9

t it = 79.5&7%$9740%

selisi t it + t te*ak= 2.&51%%90$00& asil olsik

ln P2 sat = 4.5&95&05021

p2sat = 9&.501&%%1&15

i = 0.%27157$271



Peritunan BB3 " Benen

p = 120 ln P =

t te*ak = $44.&027 "1 sat =

in alpa = 0.9%%979 t"2 sat =

alpa = 2.&%%4%9 " ratarata =

1 = 0.$$

2 = 0.&7p2 sat = 77.0&1$$

ln p2 sat = 4.$44&02

t it = $44.&027

selisi t it + t te*ak= &.900%

ln P1 sat = 4.$44&02

p1 sat = 77.0&1$$

i = 0.211919



4.7%7492 Benen "oluen

$5%.%$49

$%9.%27% A 1$.%594 A 14.010

$74.$$1$ B 277$.7%0 B $10$.01

C 5$.0% C 5$.$&



Peritunan BB3 " Benen

p = 120 ln P = 4.7%7492

t te*ak = $%5.9124 "1 sat = $5%.%$49

in alpa = 0.%4&42& t"2 sat = $%9.%27%

alpa = 2.$$1$01 " ratarata $74.$$1$

1 = 0.$$

2 = 0.&7p1 sat = 107.&527

ln p1 sat = 4.&7%91

t it = $%5.9124

selisi t i 2.07005

ln P2 sat = 4.&7%909

p2 sat = 107.&52&

i = 0.29&045



Benen "oluen

A 1$.%594 A 14.010

B 277$.7%0 B $10$.01

C 5$.0% C 5$.$&



Assumin :aoult;s la< to *e -ali+ prepare a P8 +iaram >or a temperature o> $

, (90?C) an+ a t8 +iaram >or a pressure o> 90 kPa >or one o> te >ollo<in s8ste

(a) Benene(l)!et8l*enene(2) (*) lCloro*utane(l)!loro*enene(2).

(a) Benzene(l)/ethylbenzene(2);

BUBL P

Benen til Benen

A 1$.%594 A 14.0045

B 277$.7%0 B $279.47

C 5$.0% C 59.95

" $&$.15

ln P1 sat 4.91$7

P1 1$&.14%0

ln p2 sat $.1%%$

P2 24.247$

1 0.20 1 0 "a*el

2 0.%0 2 0 1

P 4&.&275 P 24.247$2 0

1 0.5%$9%212$ 1 0 0.2

0.4

1 0.40 1 0.& 0.&

2 0.&0 2 0.4 0.%

P &9.007& P 91.$%77$ 1

1 0.7%917&94&7 1 0.%9$%71

1 0.%0 1 1

2 0.20 2 0

P 11$.7&79 P 1$&.14%

1 0.957$7404&4 1 1

DEW P

P 47.%$%5&$&0&%

1 0.210%2$05$$

(b) l-Chlorobutane(l)/chlorobenzene(2).

P 90 Benen til Bene

ln P 4.499% A 1$.%594 A

"1 sat $49.4$70 B 277$.7%0 B

"2 sat 404.9%70 C 5$.0% C

" rata2 $77.2120ln P1 sat 5.$01% " $75 "

P1 sat 200 7052 ln P1 sat 5 24$0 ln P1 sat

0 0.

0

20

40

&0

%0

100

120

140

1&0



$.15

ms@

1 p

0 24.247$2

0.5%$9%2 4&.&275

0.7%9177 &9.007&

0.%9$%71 91.$%77$

0.957$74 11$.7&79

1 1$&.14%

14.0045

$279.47

59.95

$7$ " $71

5 1%92 ln P1 sat 5 1$4&

2 0.4 0.& 0.% 1 1.2

Column I

Column I



179.$19& P1 sat 1&9.%009

$.52%& ln p2 sat $.4&1$

$4.0774 P2 sat $1.%57&

0.$9 1 0.42

0.&1 2 0.5%

0.77 1 0.%0

1 "1

0 404.9%70

0.74 $75

0.77 $7$

0.%0 $71

0.%2 $&9

0.%5 $&7

1 $49.4$70

0.4 0.& 0.% 1 1.2

Column I

Column I



Assumin :aoult;s la< to *e -ali+ prepare a P8 +iaram >or a temperature o> $&$.15

, (90?C) an+ a t8 +iaram >or a pressure o> 90 kPa >or one o> te >ollo<in s8stems@

(a) Benene(l)!et8l*enene(2) (*) lCloro*utane(l)!loro*enene(2).

(b) l-Chlorobutane(l)/chlorobenzene(2)

BUBL P

loro*utana Cloro*enena

A 1$.9&00 A 1$.992&B 2%2&.2&0 B $295.12

C 49.05 C 55.&

" $&$.15

ln P1 sat 4.9&20

P1 142.%%4&

ln p2 sat $.27%5

P2 2&.5$&1

1 0.20 1 0 "a*el

2 0.%0 2 0 1 1P 49.%05% P 2&.5$&0& 0 0

1 0.57$7&7$01 1 0 0.2 0.57$7&7

0.4 0.7%2121

1 0.40 1 0.& 0.& 0.%%9%29

2 0.&0 2 0.4 0.% 0.955&$1

P 7$.0755 P 9&.$4521 1 1

1 0.7%2120&%2 1 0.%%9%29

1 0.%0 1 1

2 0.20 2 0P 119.&149 P 142.%%4&

1 0.955&$0%4& 1 1

DEW P

P 51.%%&0120&

1 0.217%79$1%

(b) l-Chlorobutane(l)/chlorobenzene(2).

P 90 Cloro*utana Cloro*enena

ln P 4.499% A 1$.9&00 A 1$.992&

"1 sat $47.%0$0 B 2%2&.2&0 B $295.12

"2 sat 402.71%2 C 49.05 C 55.&



" rata2 $75.2&0&

ln P1 sat 5.29&1 " $75 " $7$

P1 sat 199.5544 ln P1 sat 5.2%92 ln P1 sat 5.2$5&

ln p2 sat $.&%44 P1 sat 19%.1771 P1 sat 1%7.%472

P2 sat $9.%219 ln p2 sat $.&7&0 ln p2 sat $.&110

1 0.$1 P2 sat $9.4%%4 P2 sat $7.00$0

2 0.&9 1 0.$2 1 0.$5 1 0.70 2 0.&% 2 0.&5

1 0.70 1 0.7$

" $&9 " $&7 "a*el

ln P1 sat 5.12&& ln P1 sat 5.0710 1 1

P1 sat 1&%.4$&2 P1 sat 159.$$24 0 0

ln p2 sat $.47%5 ln p2 sat $.4110 0.$2 0.70

P2 sat $2.4110 P2 sat $0.294& 0.$5 0.7$

1 0.42 1 0.4& 0.$9 0.7&

2 0.5% 2 0.54 0.42 0.79 1 0.79 1 0.%2 0.4& 0.%2

1 1

0 0.2 0.4

$20.0000

$$0.0000

$40.0000

$50.0000

$&0.0000

$70.0000

$%0.0000

$90.0000

400.0000

410.0000



p2&.5$&0&

49.%05%

7$.0755

9&.$4521

119.&149

142.%%4&

0 0.2 0.4 0.& 0.% 1 1.2

0

20

40

&0

%0

100

120

140

1&0

Col

Col



" $71

ln P1 sat 5.1%14

P1 sat 177.9$74

ln p2 sat $.5452

P2 sat $4.&455

1 0.$92 0.&1

1 0.7&

"1

402.71%2

$75

$7$

$71

$&9$&7

$47.%0$0

0.& 0.% 1 1.2

Column IColumn I



mn I

mn I



metanol +an metil asetat

metanol /"I3 AS"A"

A 1&.59$% A 14.4015B $&44.$ B 27$9.17

C $$.$9 C 50.0$

" $1%.15 1 2.%19&$4

ln P1 sat $.79&0 2 1.0011&1

P1 44.52$0 P &7.722%2

ln p2 sat 4.1%5$ 1 0.0$2$&%

P2 &5.712& 2 0.9&7&$2

1 0.0&

2 0.94 A 1.10707&in 1 1.0$&5&9

1 2.%1952&

selisi 0.00010%

in 2 0.0011&

2 1.0011&1

selisi 1.000%



a. B3P P *. 6e< P

" $4$.15 81 0.05 1

1 0.05 82 0.95 2

2 0.95 1 2.5$549 in 1

in 1 0.%57$75 2 1 1

1 2.$5&9&& P 42.1%714 in 2

in 2 0.002$75 1 0.010425 2

2 1.002$7% 2 0.9%9575 D1.2 1=0P1 sat 79.%

P2 sat 40.5 1!2

P 47.9707% in 1 0.9$0295 In 1!2

1 2.5$525%

selisi 0.0002$2 In 1!2 =

in 2 0.00010$ 0.&7%2215

2 1.00010$ 0.&7%2215

selisi 0.00010$ 1.&2%2215

1

2

. D



0 1 1

1 2 0

0.95 in 1 0

2.5%571 1 1

0 in 2 0.95

1 2 2.5%571

5.094%0& D1.2 1=1 0.7&202$

0.507519 A 0.95

0.&7%222

1= 1.019&2%

A(121)

0.95(121) P a %1.$&&$1

0.951.91

1.91

0.%5&959

0.14$041



E1 0.45

E2 0.$5

E$ 0.2

,1 1.7795

,2 0.%%95

,$ 0.4575F te*ak 0.5

- it 0.0$129

- selisi 0.4&%71



*enen toluen etil *enen

A 1$.%59 A 14.010 A 14.0045

B 277$.7% B $10$.01 B $279.47

C 5$.0% C 5$.$& C 59.95

t $%$.15 t $%$.15 t $%$.15

In P1 sat 5.4557%%&44% in P2 sat 4.&00752 in p$ sat $.%57&25

P1 sat 2$4.1094274% p2 sat 99.55914 p$ sat 47.$5275

1 0.$$

2 0.$$

$ 0.$$

P *ulp 125.7$70$5&%

P +e< 709.4$279109

P 90

,1 2.&01215%&0%

k2 1.10&212&427

k$ 0.52&141721$

F te*ak 0.7

- it 0.004$$50&&7

3 0.$

1 0.40474$7527

2 0.$$97%7$71%

$ 0.259%0$9422

1 0.1555979105

2 0.$071&27991

$ 0.49$790%014



*enen toluen etil *enen

A 1$.%59 A 14.010 A 14.0045

B 277$.7% B $10$.01 B $279.47

C 5$.0% C 5$.$& C 59.95

t $%$.15 t $%$.15 t $%$.15

In P1 sat 5.4557%9 in P2 sat 4.&00752 in p$ sat $.%57&25

P1 sat 2$4.1094 p2 sat 99.55914 p$ sat 47.$5275

1 0.$$

2 0.$$

$ 0.$$

P *ulp 125.7$7

P +e< 709.4$2%

P 120

,1 1.950912

k2 0.%29&59

k$ 0.$94&0&

F te*ak 0.1

- it 0.005041

3 0.9

1 0.5%7%97

2 0.27%5$2

$ 0.1$%&12

1 0.$01$45

2 0.$$5719

$ 0.$512&5



aeton Aetonitril *enen

A 14.$91& A 14.725% A

B 2795.%2 * $271.24 B

C 4$.15 $1.$ C

" $40 " $40 t

In P1 sat 4.97$$0% in P2 sat 4.12%975 In P1 sat

P1 sat 144.5041 p2 sat &2.1142 P1 sat

1 0.75 1

2 0.25 2

P *ulp 12$.90&& P *ulp

P +e< 192.&7&2 P +e<

P 115 P

,1 1.25&557 ,1

k2 0.54012$ k2

F te*ak 0.& F te*ak

- it 0.00$1%7 - it

3 0.4 3

1 0.%1&7 1

2 0.1%&4%% 2

1 0.&4995 1

2 0.$452&9 2



etil *enen etanol

1$.%59 A 14.0045 A 1&.&7&

277$.7% B $279.47 B $&74.47

5$.0% C 59.95 C 4&.7

$7$.15 t $7$.15 t $&0

5.19$2$$ in P2 sat $.5$$&51 In P1 sat 4.94752

1%0.049% p2 sat $4.24%77 P1 sat 140.%25$

0.5 1 0.25

0.5 2 0.75

107.149$ P *ulp %&.01204

$&0.1141 P +e< 5&$.$124

75.9975 P %1.0&4

2.$&9154 ,1 1.7$7212

0.450&57 k2 0.%$5&4%

0.5$ F te*ak 0.42

0.004$$2 - it 0.004%29

0.47 3 0.5%

0.&%&452 1 0.$$1&2$

0.$17%% 2 0.&7$20&

0.2%974& 1 0.190%94

0.705$7 2 0.%05&1



1propanol Cloro*utana C

A 1&.0&92 A 1$.9&00

B $44%.&& B 2%2&.2&0

C &9.0& C 49.05

t $&0 t $9%.15

in P2 sat 4.215&91 In P1 sat 5.%&4154

p2 sat &7.74094 P1 sat $52.1%$9

1 0.5

2 0.5

P *ulp 215.7411

P +e< 704.$741

P 175.0045

,1 2.01242%

k2 0.45$121

F te*ak 0.41

- it 0.00$1

3 0.59

1 0.711057

2 0.292042

1 0.$5$$$$

2 0.&4451$



loro*enena

A 1$.992&

B $295.12

C 55.&

t $9%.15

in P2 sat 4.$7$21&

p2 sat 79.29%24



aeton Aetonitril

A 10.0% A 11.&$

B 2572 B &254

1 0.005 1 0.9&2 0.995 2 0.04

In ama1 0.92072$25 In ama2 0.00002$25

ama 1 2.511105%907 ama 2 1.00002$250$

" te*ak 404.5%&10029

in p1 sat $.722%%5907 in p2 sat $.%277727&

p1 sat 41.$%$&51$1$ p2 sat 0.02175%0221

P *u*lle 0.54124$$%%2 C 1901.995077&

P +e< 0.54124$$%2$ p1 sat! p2 sat 1901.9950994

In P1 sat!p2 sat 7.550&5%&&&& " it 2.1%$47005

P1 sat!p2 sat 1901.9950994 selisi 2.1%$47005

P 0.54124$$%%5

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