power of random processes - binghamtonws2.binghamton.edu/fowler/fowler personal page/ee521... ·...
TRANSCRIPT
1/40
Power ofPower ofRandom ProcessesRandom Processes
2/40
Power of a Random Process
Recall : For deterministic signals…instantaneous power is x2(t)
For a random signal, x2(t) is a random variable for each time t. Thus there is no single # to associate with “instantaneous power”. To get the Expected Instantaneous Power (i.e., on average) we compute the statistical (ensemble) average of x2(t):
3/40
Power of a Random Process
Avg. Power of x(t) : PX(t) = E{ x2(t)}
This is also called the “mean square value”of the process
In general, can depend on time.But we’ll see it doesn’t for WSS(& stationary) processes
Often drop the“Average” terminology
4/40
Relationship of Power to ACFRecall: RX(t, t+τ ) = E { x(t) x(t+τ) }
Clearly, setting τ =0 makes this equal to PX(t) ⇒ PX(t) = RX(t, t)
If the Process is WSS (or SS) RX(t,t) = RX(0)
PX = RX(0)
τ
RX(τ)PX (Power of process)
For WSS or SS
5/40
Power vs. Variance
Note: If the WSS process is Zero Mean, then:
Power & Variance are Equal for Zero mean Process
{ }WSSfor)0(
)]()([2
22
xR
txtxE
x
x
−=
−=σRecall Variance:
PX
22 xP xx +=σ“DC” Power
“AC” Power
2xXP σ=
6/40
Power Spectral Density of a Random Process
Recall: PSD for Deterministic Signal x(t) :
∫−
−
∞→
=
=
2/
2/
2
)()(where
)()( lim
T
T
tjT
T
Tx
dtetxX
TX
S
ωω
ωω
7/40
Power Spectral Density of a Random Process
For a random Process: each realization (samplefunction) of process x(t) has different FT and therefore a different PSD.
We again rely on averaging to give the “Expected”PSD or “Average” PSD…
But… Usually just call it “PSD”.
8/40
Define PSD for WSS RPWe define PSD of WSS process x(t) to be :
This definition isn’t very useful for analysis so we seek an alternative form
The Wiener-Khinchine Theorem provides this alternative!!!
⎪⎭
⎪⎬⎫
⎪⎩
⎪⎨⎧
=∞→ T
XES T
Tx
2)()( lim
ωω
<Compare this to PSD for Deterministic Signal>
9/40
Weiner- Khinchine Theorem
Let x(t) be a WSS process w/ ACF RX(τ) and w/PSD SX(ω) as defined in ( )… Then RX(τ) and SX(ω) form a FT pair :
SX(ω) = F{ RX(τ) }
or Equivalently
RX(τ) ↔ SX(ω)
10/40
Proof of WK theoremBy definition : ∫
∞
∞−
−= dtetxX tjTT
ωω )()(
For Real x(t):
21)(
2
2/
2/
2/
2/1
2
2/
2/21
2/
2/1
2
12
21
)()(
)()(
)()()(
dtdtetxtx
dtetxdtetx
XXX
ttjT
T
T
T
tjT
T
tjT
T
TTT
−−
− −
−
−−
∫ ∫
∫∫
=
⋅=
−=
ω
ωω
ωωω
11/40
Proof of WK theorem(cont’d)
Thus :
Move E {.} inside integrals :
21)(
2/
2/
2/
2/12
12)(1lim)( dtdtettRT
S ttjT
T
T
Tx
Tx
−−
− −∞→ ∫ ∫ −= ωω
⎪⎭
⎪⎬⎫
⎪⎩
⎪⎨⎧
= −−
− −∞→ ∫ ∫ 21
)(2
2/
2/
2/
2/1
12)()(1lim)( dtdtetxtxT
ES ttjT
T
T
TT
xωω
12/40
Proof of WK theorem(cont’d)
We were almost there… BUT we have one-too-manyintegrals.
For convenience define: φ(t2 - t1) = RX(t2 - t1) e-jω(t2- t1)
∫ ∫− −∞→
−=2/
2/21
2/
2/12 )(
T1)( lim
T
T
T
TTx dtdtttS φω
13/40
Proof of WK theorem(cont’d)
Change of Variables = Change of AxesChange of Variables = Change of Axes
Instead of integrating “Row-by-Row” as in we integrate “Diagonal-by-Diagonal”.
Let: τ = t2 – t1 t2 = (τ + λ)/2λ = t1 + t2 t1 = (λ – τ)/2
14/40
Proof of WK theorem(cont’d)
t1
t2τ = t2 – t1λ = t2 + t1
15/40
Proof of WK theorem(cont’d)
21
21
21
21
21
J
11
22
=
−
=
∂∂
∂∂
∂∂
∂∂
=
λτ
λτ
tt
tt
Use Jacobian result for 2-D change of variables
From Calculus III
16/40
Proof of WK theorem(cont’d)
∫ ∫∞→
=?
?
?
?21)(
T1)( lim λττφω ddS
Tx
Q: As τ ranges over -T≤τ≤Thow does λ range?
A: For each τ, λ must be restricted to stay inside original square – see Figure on next Chart
J
17/40
Proof of WK theorem(cont’d)
t1
t2τ = t2 – t1λ = t2 + t1Note: φ(t2 – t1) Doesn’t ChangeIn The DirectionOf t2 + t1 Axis
T/2– T/2
– T/2
T/2τ = 2
τ = 4 τ = 6
τ = T
18/40
Proof of WK theorem(cont’d)
τ = t2 – t1t2 = τ + t1
t1= t2 - τ
λ = (τ + t1) + t1 = 2t1 + τ
λ = t2 + (t2 - τ) = 2t2 - τ
When τ > 0 we need (From Axes Figure):t2 ≤ T/2 λ ≤ T - τt1 ≥ -T/2 λ ≥ -T + τ
λ = t2 + t1
Works out similarly for τ < 0
19/40
Proof of WK theorem(cont’d)
So… τλτφωτ
τ
ddT
ST
T
T
TTx 2
1)(1)( lim ∫ ∫−
−
+−∞→ ⎥⎥⎦
⎤
⎢⎢⎣
⎡=
= T - τ
{ })(
)(
1)(lim
τR
d
dT
x
T
TT
ℑ=
=
⎟⎠⎞
⎜⎝⎛ −=
∫
∫
∞
∞−
−∞→
ττφ
τττφ
<End of Proof>
20/40
Some Properties of PSD & ACF
(1) The PSD is an even function of ω for a real process x(t) proof : since each sample function is real valued then we know that ⏐x(ω)⏐is even.
⇒ ⏐x(ω)⏐2 is even: (even x even = even)⇒ So is SX(w) ( this is clear from )
21/40
Some Prop. of PSD & ACF(2) SX(ω) is real-valued and ≥ 0.
proof : again from ( ) – since ⏐x(w)⏐2 is real-valued & ≥ 0, so is SX(w)
(3) RX(τ) is an even function of τ
Also follows from IFT{ Real & Even } = Real & Even <Property of the FT>
)()}()({
)}()({)(
ττσσ
ττ
x
x
RxxE
txtxER
=+=
−=−
22/40
Graphical View of Prop #3For WSS, ACF does not depend on absolute time only relative time
t- τ t+ττ τ
t
t
t
t
Doesn’t matter if you look forward by τ or look backward by τ
23/40
Computing Power from PSD
From it’s name – Power Spectral Density – we know what to expect :
∫∞
∞−
= ωωπ
dSP xx )(21
So let’s Prove this !!!!
Well … this part is not obvious!!
24/40
Computing Power from PSDWe Know: { }
∫∞
∞−
−
=
ℑ=
ωωπ
ωτ
ωτ deS
SR
jx
xx
)(21
)()( 1
PX = RX(0)
.!Q.E.D)(21
)(21
1
0
∫
∫∞
∞−
∞
∞− =
=
⎥⎥⎦
⎤
⎢⎢⎣
⎡=
ωωπ
ωωπ
ω
dS
deSP
x
jxX
25/40
Units of PSD Function
∫∞
∞−=
πωω
2)( dSP xx )(ωxS
Watts Hz [ Watts / Hz ]
26/40
Using Symmetry of SX(w)
⎥⎥⎦
⎤
⎢⎢⎣
⎡= ∫
∞
0
)(212 ωωπ
dSP xx
Integrate only from 0 → ∞
Double to account for the -∞ → 0 part of integral
27/40
PSD for DT Processes
SX(Ω) = DTFT { RX[m] }
Periodic in Ω with period 2π
ΩΩ= ∫−
dSP xx
π
ππ)(
21
Not much changes – mostly, just use DTFT instead of CTFT!!
Need only look at -π ≤ Ω < π
28/40
Big Picture of PSD & ACFi.e. High Frequencies have Largepower contentProcess exhibits
Rapid fluctuations
Narrow ACF Broad PSD
Less CorrelatedSample-to-sample
i.e. High Frequencieshave Smallpower contentProcess exhibits
Slow fluctuations
Broad ACF Narrow PSD
More CorrelatedSample-to-sample
<<See “Big Picture: Filtered RP” Charts in “V-3 RP Examples” >>
29/40
White NoiseThe term “White Noise” refers to a WSS process whose PSD is flat over all frequencies
C-T White Noise
ω
SX(ω)
Convention to use this form (i.e. w/ division by 2)
White Noise Has Broadest Possible PSD
N /2
ωω ∀=2
)( NXS
30/40
C-T White Noise
NOTE : C-T white noise has infinite Power :
Can’t really exist in practice but still a veryuseful Model for Analysis of Practical Scenarios
∫∞
∞−
∞→ωd2/N
31/40
C-T White NoiseQ : what is the ACF of C-T white Noise ?A: Take the IFT of the flat PSD :
{ }
)(
2/)( 1
τδ
τ
2N
N
=
ℑ= −xR
x(t1) & x(t2) are uncorrelatedfor any t1 ≠ t2
Delta function !Narrowest ACFRX(τ)
Area = N /2τ
PX = RX(0) = N /2δ(0) → ∞Infinite Power.. It Checks!
Also….
32/40
D-T White NoisePSD is:SX(Ω) = N /2 ∀ Ω
…but focus on Ω∈[-π,π]
ACF is:RX[m] = IDTFT {N /2 }
= N /2 δ [m]
Delta sequence
x[k1] & x[k2] are uncorrelated for any k1 ≠ k2
Ω
SX(Ω)
-π π
N /2 Broadest Possible PSD
Narrowest ACF
m
RX[m]
-3 1-2 -1 2 3
N /2
33/40
D-T White Noise
Note:
D-T White Noise has Finite Power(unlike C-T White Noise)
2221
2]0[
NN
N
=Ω=
==
∫−
π
ππ
dP
RP
x
xx watts
watts
34/40
Examples of PSDExample 1: “BANDLIMITED WHITE NOISE”This looks like white noise within some bandwidth but its PSD is zero outside that bandwidth – hence the name.
Thus:
⎟⎠⎞
⎜⎝⎛=
BSx π
ωω4
rect2/)( N
B
BBdPB
Bx
N
NN
=
+⋅⋅== ∫−
)22(2/212/
21 2
2
πππ
ωπ
π
π
And…
SX(ω)
ω-2πB 2πB
N /2
35/40
Example: BL White NoiseThe ACF (using FT pair for rect and sinc) is:
RX(τ) = N B sinc (2πBτ)
Again we see PX = N B , since RX(0) = N B
Note: For τ > 1/2B …x(t) & x(t + τ) are Approximately Uncorrelated
RX(τ)
-32B
-22B
-12B
1 2B
22B
32B
N B
τ
36/40
Example #2 of PSDExample 2 : “SINUSOID WITH RANDOM PHASE”
x(t) = A cos (ωCt + θ)
We examined this RP before: RX(τ) = A2 cos (ωCτ)2
So using FT Pair for a Cosine gives the PSD:
SX(ω) = (πA2)/2 [δ (ω + ωC) + δ (ω – ωC)]
ω
SX(ω)
- ωc ωc
Area = (πA2)/2Area = (πA2)/2
37/40
Example #2 of PSDNote : Can get PX in two ways:
221
2
2
2
)(.2
)0(.1
Ax
Ax
dS
R
=
=
∫∞
∞−ωωπ
⇒ PX = A2
2
<Sifting Property>
38/40
Example #3 of PSDExample 3: “FILTERED D-T RANDOM PROCESS”
< See Also: Class Notes on “Filtered RPs” >
D-T Filterx [k]
Zero mean ⇒ RX[m] = σ2δ[m] (Input ACF) White noise
⇒ SX(Ω) = σ² ∀Ω (Input PSD)
y[k] = x[k] + x [k +1]
SX(Ω)
Ω
σ²
39/40
Example #3 of PSDFor this case we showed earlier that for this filter output the ACF is :
RY[m] = σ² { 2δ[m] + δ[m-1] + δ[m+1] }
So the Output PSD is:
SY(Ω) = σ² [2 + e-jΩ + e-jΩ]
= 2σ² [cos (Ω) + 1]
Use the result for DTFT of δ[m] and also time-shift property
= 2 cos (Ω) By Euler
40/40
Example #3 of PSD
General Idea…Filter Shapes Input PSD:Here it suppresses High Frequency power
-2π -π π 2π
Sy(Ω)
Ω
4σ²Replicas Replicas
SY(Ω) = 2σ² [cos (Ω) + 1]
Remember: Limit View to [-π,π]