practice sheet (1)

Upload: ritik12041998

Post on 03-Jun-2018

216 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/12/2019 Practice Sheet (1)

    1/6

    Practice sheet

    Single Answer Questions

    1. A versatile reducing agent which can reduce any reducible group is an organic compound is

    (a) 4NaBH (b) 2 5/Na C H OH (c) 2 /H Pt (d) 2 6 /B H THF

    2. A nonlinear molecule is

    (a) 2 2H C C CH= = (b) H C C C N

    (c) 2H C C CH C CH= = (d) 2N O!. "ercentage o# chlorine is chlorophyll is

    (a) 5$ (b) 25 (c) 1$.! (d) $

    4. %lucose OH

    an endiolOH #ructose. An endiol is a molecule processing both a &'& bond with two

    groups altac*ed to the carbon atoms. +he endiol is a

    (a) ,tereoisomer o# glucose

    (b) stereoisomer o# #ructose(c) tautomer o# glucose

    (d) tautomer o# glucose and #ructose.

    5.

    N

    N

    NH2

    N

    N

    CH3

    ..

    .

    .

    .

    . ..

    ..1

    2

    34

    56

    7

    8

    9

    +he least basic - atom is

    (a) 1/! (b) 6 (c) (d)

    6. 0hich o# the #ollowing has a lower "*a than a carboylic acid

    (a) "henol (b) "uloroglucircol

    (c) 23 43 6 trimethylphenol (d) 23 43 6trimethylphenol

    . A cyclic hydrocarbon has a #ormula 5 1$C H . t #orms eight monobrominated specier (including stereoisomers) its

    #ormula is

    (a) (b) .

    (c) (d) .

    . 23 4heptadiene eists as stereoisomers.

    (a) 2 (b) ! (c) 4 (d) 5

    . n the complete combustion o# inclasse gas what change o# hybridi7ation does a c atom undergo

    (a)!Sp Sp (b) ! 2Sp Sp (c) ! 2Sp dSp (d) 2Sp Sp

    1$. 0hich o# the #ollowing cannot be the name o# !H C CN

  • 8/12/2019 Practice Sheet (1)

    2/6

    (a) Acetonitrile (b) 8ethyl cyanide (c) 8ethanenitrile (d) 9thanenitrile

    11. rder o# bond length o# & in the #ollowing:

    H3COH,H

    HC = O and H C

    O

    Ois

    (a) ; ; (b) ; ; (c) ; ; (d) ; ;

    12. 8olecular #ormula o# an aromatic compound o# #ormula !C H O is a phenol3 an ether and an aldehyde3 number o#

    structural isomers possible with bonding between

  • 8/12/2019 Practice Sheet (1)

    3/6

    1. &on#ormation o# butane viewed along the 1 2C C with dihedral angles oand 6$oare

    (a) An eclipsed3 s*ew3 partially eclipsed and anti(b) An eclipsed and anti

    (c) 9clipsed and s*ew

    (d) 9clipsed partially eclipsed and anti

    1. &on#ormational enantiomers have to be necessarily

    (a) anti #orms (b) 9clipsed #orms

    (c) partially eclipsed #orms (d) ,*ew (gauche) #orms

    2$. ?witterions are species having a >ve charge at one end and a

  • 8/12/2019 Practice Sheet (1)

    4/6

    25.

    CH2 O C C4H9

    O

    CH O C

    O

    C4H9

    CH2 O C

    O

    C4H9

    H2O

    NaOH(a!

    a s"a# $

    B is

    (a) A Cihydric alcohol with 80'62(b) A trihydric alcohol with 80'6$

    (c) A trihydric alcohol with 80'2

    (d) A trihydric alcohol with 80'2

    26.-- + HO CH2 CH2 OH + HOOC COOH + HO CH2 CH2 OH + COOHCOOH +-----

    -H2C CH2 O C

    O

    C

    O

    O

    n

    + H2O

    0hich is not true about this reaction

    (a) t is an esteri#ication

    (b) t is an condensation

    (c) t is a polymeri7ation(d) +he 8w o# the product is an integral multiple o# the sum o# the molecular weights o# the reactants.

    2. A secondary al*yl halide reacts with 2 5C H ONa which is both a sting base and a power#ul nucleophile is yield

    (a) an ether (b) an al*ene (c) either o# the above (d) both o# the above

    2.

    %&'C na)e is

    (a) 4ethenylheptane (b) 4Dinycheptane(c) !ethenylheptane (d) !(1propye)1haene

    2. +owards aromatic electrophilic substitution the most reactive among the #ollowing is

    (a) 2PhNH (b) 2.PhNH HCl (c) 2PhNO (d) !PhNHCOCH

    !$. OH

    CH3C*

    lCl3

    OH

    CH3

    +

    OH

    CH3

    NH2NH2

    CH3

    +he di##erence is because o#

    (a) +he acidic nature o# phenol (b) +he acidic nature o# aniline

    (c) +he basic nature o# aniline (d)

  • 8/12/2019 Practice Sheet (1)

    5/6

    !1. Among an anide3 amine and an imide3 the increasing order o# basic nature is

    (a) Amide inside amine (b) Amine inside amide

    (c) inside amide amine (d) amine amide inside

    !2. 6 5 2 6 5 2C H CH CH NH and C H CH CH NH = = are

    (a) "osition isomers (b) chain isomers (c) 8etames (d) tantomers

    Match the following81.

    COLUMN I COLUMN II

    &an undergo

    A ! 2 !H C CO CH CO CH " &yclisation

    E @@

    ! 2 !

    (

    CH C OCH CH F earrangement

    & @@ @@

    ! 2 2 2

    ((

    CH CH CH CH CH C OH 9nolisation

    C

    C6H5

    CH3

    C

    OH

    C

    OH

    C6H5

    CH3

    , 9limination

    + eduction

    82.

    COLUMN I COLUMN II

    A C

    C6H5

    CH3

    NOH " Ginear structure

    E C

    H

    C C

    CH3

    Cl

    H

    F ptical activity

    & C

    Cl

    C C

    CH3

    H

    H

    %eometrical isomerism

    C C

    H

    C CCH3

    H

    H3C

    , "lanarity

    + esonance ,tabilisation

  • 8/12/2019 Practice Sheet (1)

    6/6

    ANSWER KE!

    1.& 2.& !.C 4.C 5.C

    6.& .& .& .A 1$.&

    11.C 12.& 1!.& 14.C 15.C

    16.E 1.& 1.& 1.C 2$.C

    21.& 22.E 2!.& 24.C 25.&

    26.C 2.C 2.C 2.A !$.E

    !1.& !2.C

    81. A3 + E,3 + &"3 + CF

    82. A3 + E" &"3 F C"3 ,