problem of the day - calculator
DESCRIPTION
Problem of the Day - Calculator. 2. Let f be the function given by f(x) = 2e4x . For what value of x is the slope of the line tangent to the graph of f at (x, f(x)) equal to 3?. A) 0.168 B) 0.276 C) 0.318 D) 0.342 E) 0.551. Problem of the Day - Calculator. 2. - PowerPoint PPT PresentationTRANSCRIPT
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Problem of the Day - Calculator
Let f be the function given by f(x) = 2e4x . For what value of x is the slope of the line tangent to the graphof f at (x, f(x)) equal to 3?
2
A) 0.168B) 0.276C) 0.318D) 0.342E) 0.551
![Page 2: Problem of the Day - Calculator](https://reader036.vdocument.in/reader036/viewer/2022062806/56814f51550346895dbcf755/html5/thumbnails/2.jpg)
Problem of the Day - Calculator
Let f be the function given by f(x) = 2e4x . For what value of x is the slope of the line tangent to the graphof f at (x, f(x)) equal to 3?
2
A) 0.168B) 0.276C) 0.318D) 0.342E) 0.551
(Graph derivative and find where y = 3)
![Page 3: Problem of the Day - Calculator](https://reader036.vdocument.in/reader036/viewer/2022062806/56814f51550346895dbcf755/html5/thumbnails/3.jpg)
You have learned to analyze visually the solutions of differential equations using slope fields and to approximate solutions numerically using Euler's Method.
You have solved equations of the form
y' = f(x) and y'' = f(x)
Now you will learn to solve using the separation of variables method.
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Separation of Variables Method
Rewrite equation so that each variable occurs on only one side of the equation.
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Growth and Decay
Application of separation of variables where
rate of change of y is proportional to y
Cekt
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Find the particular solution for t = 3 if the rate of change is proportional to y and t = 0 when y = 2, and t = 2 when y = 4.
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Find the particular solution for t = 3 if the rate of change is proportional to y and t = 0 when y = 2, and t = 2 when y = 4.
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At t = 3
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Let P(t) represent the number of wolves in a population at time t years, when t > 0. The population P(t) is increasing at a rate directly proportional to 800 - P(t), where the constant of proportionality is k.
a) If P(0) = 500, find P(t) in terms of t and k.b) If P(2) = 700, find k.c) Find lim P(t). t ⇒∞
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Let P(t) represent the number of wolves in a population at time t years, when t > 0. The population P(t) is increasing at a rate directly proportional to 800 - P(t), where the constant of proportionality is k.
a) If P(0) = 500, find P(t) in terms of t and k.
implies
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a) If P(0) = 500, find P(t) in terms of t and k.
P'(t) = k(800 - P(t))
-ln|800 - P| = kt + Cln|800 - P| = -kt + C|800 - P| = ekt + C|800 - P| = ekt eC|800 - P| = Cekt.
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a) If P(0) = 500, find P(t) in terms of t and k.
|800 - P| = Cekt
800 - 500 = Ce0
300 = C
P(t) = 800 - 300e-kt
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b) If P(2) = 700, find k.
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b) If P(2) = 700, find k.
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c) Find lim P(t). t ⇒∞
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c) Find lim P(t). t ⇒∞
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