qfl2144 rmn aula2

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NMR EXPERIMENT NMR EXPERIMENT When magnetically active nuclei are placed into an external magnetic field, the magnetic fields align themselves with the external field into two orientations. During the experiment, electromagnetic radiation of a specific frequency is applied. By sweeping the magnetic field, an energy difference between field, an energy difference between spin states will occur that has the same energy as that f the applied radio frequency and plot of frequency versus energy absorption can be generated. This is the NMR spectrum

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Page 1: QFL2144 RMN AULA2

NMR EXPERIMENTNMR EXPERIMENT

When magnetically active nuclei are placed into an external magnetic field, the magnetic fields align themselves with the external field into two orientations. During the experiment, electromagnetic radiation of a specific frequency is applied. By sweeping the magnetic field, an energy difference between field, an energy difference between spin states will occur that has the same energy as that f the applied radio frequency and plot of frequency versus energy absorption can be generated. This is the NMR spectrum

Page 2: QFL2144 RMN AULA2

∆E

- 1/2

= kBo = hν

The Energy Separation Depends on BThe Energy Separation Depends on Boo

Bo

∆E

+ 1/2

= kBo = hνdegenerate

at Bo = 0

increasing magnetic field strength

Page 3: QFL2144 RMN AULA2

Classical Instrumentation:Classical Instrumentation:The ContinuousThe Continuous--Wave NMR Wave NMR

typical before 1965;

field is scanned

Page 4: QFL2144 RMN AULA2

A Simplified 60 MHzA Simplified 60 MHz

NMR SpectrometerNMR Spectrometer

Transmitter

RF Detector

Recorder

RF (60 MHz)Oscillator

absorptionsignal

Receiver

Probe

SN~ 1.41 Tesla (+/-) a few ppm

MAGNETMAGNET

Page 5: QFL2144 RMN AULA2

Modern Instrumentation: Modern Instrumentation: the Fourierthe Fourier--Transform NMRTransform NMR

requires a computer

FT-NMR

Page 6: QFL2144 RMN AULA2

PULSED EXCITATIONPULSED EXCITATION

OBROADBAND

N

ν1

ν2

CH2 C CH3

BROADBANDRF PULSE

All types of hydrogen are excitedsimultaneously with the single RF pulse.

contains a range of frequencies

S

ν3

(ν1 ..... νn)

Page 7: QFL2144 RMN AULA2

Espectro de RMN de HidrogênioEspectro de RMN de HidrogênioEspectro de RMN de HidrogênioEspectro de RMN de Hidrogênio((ProtonProton NMR Spectrum)NMR Spectrum)

Page 8: QFL2144 RMN AULA2

The NMR Spectrum� The vertical axis shows the intensity of Rf

absorption.

� The horizontal axis shows relative energy at which the absorption occurs (in units of parts per million the absorption occurs (in units of parts per million = ppm)

� Tetramethylsilane (TMS) in included as a standard zero point reference (0.00 ppm)

� The area under any peak corresponds to the number of hydrogens represented by that peak.

Page 9: QFL2144 RMN AULA2

CH2 C

O

CH3

NMR Spectrum of PhenylacetoneNMR Spectrum of Phenylacetone

EACH DIFFERENT TYPE OF PROTON COMES AT A DIFFERENT PLACE - YOU CAN TELL HOW MANY DIFFERENT TYPES OF PROTONS THERE ARE BY INTEGRATION.

Page 10: QFL2144 RMN AULA2

DIAMAGNETIC SHIELDING

Why should the proton nuclei in different compounds behave differently in the nmr experiment? The answer to this question lies with the electron(s) surrounding the proton in covalent compounds and ions. Since electrons are charged particles, they move in response to the external magnetic field (Bo) so as to generate a secondary field that to generate a secondary field that opposes the much stronger applied field. This secondary field shields the nucleus from the applied field, so Bo must be increased in order to achieve resonance (absorption of rf energy). Thus Bo must be increased to compensate for the induced shielding field.

When an atom is placed in a magnetic field, its electrons circulate about the direction of the applied magnetic field. This circulation causes a small magnetic field at the nucleus which opposes the externally applied field. The magnetic field at the nucleus (the effective field) is therefore generally less

than the applied field by a fraction σ .B = Bo (1-σ)

Page 11: QFL2144 RMN AULA2

1. Número de sinais: Quantos tipos diferentes de hidrogênios na molécula.

Hidrogênios magneticamente equivalentes ressoam no mesmo campo aplicado.

Hidrogênios são magneticamente equivalente também quimicamente equivalente.

# de sinais? CH CH CH# de sinais? CH4 CH3CH3

Page 12: QFL2144 RMN AULA2

CCH3H3C

CH3C CH3

Número de sinais?

umum

CH3

CH3um

dois

Page 13: QFL2144 RMN AULA2

H3C C

CH3

Br

CH3CH3CH2-Br

umdois

CH3CH2CH2-Br CH3CHCH3

Cl

doistrês

Page 14: QFL2144 RMN AULA2

CH3CHCH2CH3 Cl-CH2CH2CH2-Cl

Br

Cl-CH2CH2CH2-Cl

quatro dois

Page 15: QFL2144 RMN AULA2

O Deslocamento QuímicoO Deslocamento QuímicoO Deslocamento QuímicoO Deslocamento Químico(The Chemical Shift)(The Chemical Shift)

Page 16: QFL2144 RMN AULA2

PEAKS ARE MEASURED RELATIVE TO TMSPEAKS ARE MEASURED RELATIVE TO TMS

Si CH3CH3

CH3

CH

tetramethylsilane“TMS”

reference compound

Rather than measure the exact resonance position of a peak, we measure how far downfield it is shifted from TMS.

TMS

shift in Hz

0

CH3

n

Highly shieldedprotons appearway upfield.

Chemists originallythought no other compound wouldcome at a higherfield than TMS.

downfield

Page 17: QFL2144 RMN AULA2

The shift observed for a given protonin Hz also depends on the frequencyof the instrument used.

Higher frequencies= larger shifts in Hz.

HIGHER FREQUENCIES GIVE LARGER SHIFTSHIGHER FREQUENCIES GIVE LARGER SHIFTS

TMS

shift in Hz

0n

downfield

= larger shifts in Hz.

Page 18: QFL2144 RMN AULA2

parts permillion

THE CHEMICAL SHIFTTHE CHEMICAL SHIFTThe shifts from TMS in Hz are bigger in higher field instruments (300 MHz, 500 MHz) than they are in the lower field instruments (100 MHz, 60 MHz).

We can adjust the shift to a field-independent value,the “chemical shift” in the following way:

chemicalshift

= δδδδ = shift in Hz

spectrometer frequency in MHz= ppm

This division gives a number independent of the instrument used.

A particular proton in a given molecule will always come at the same chemical shift (constant value).

Page 19: QFL2144 RMN AULA2

Chemical Shift (δδδδ)� The chemical shift (δδδδ) in units of ppm is defined as:

δδδδ = distance from TMS (in hz)

radio frequency (in Mhz)

� A standard notation is used to summarize NMR spectral data. For example p-xylene:

δδδδ 2.3 (6H, singlet)δδδδ 7.0 (4H, singlet)

� Hydrogens in identical chemical environments (equivalent hydrogens) have identical chemical shifts.

Page 20: QFL2144 RMN AULA2

All different types of protons in a moleculehave a different amounts of shielding.

They all respond differently to the applied magnetic field and appear at different places in the spectrum.

PROTONS DIFFER IN THEIR SHIELDINGPROTONS DIFFER IN THEIR SHIELDING

This is why an NMR spectrum contains useful information(different types of protons appear in predictable places).

UPFIELDDOWNFIELD

Highly shielded protons appear here.

Less shielded protonsappear here.

SPECTRUM

It takes a higher fieldto cause resonance.

Page 21: QFL2144 RMN AULA2

Overview of where protons appear in an NMR spectrum

aliphaticC-H

CH on Cnext to pi bonds

C-H where C is attached to anelectronega-tive atom

alkene=C-H

benzeneCH

aldehydeCHO

acidCOOH

2346791012 0

X-C-HX=C-C-H

Page 22: QFL2144 RMN AULA2

3 - 4Alkyl Halide (RCH2X)

0.8 – 1.7Alkyl (C – H)

δ (ppmType of Hydrogen

10 - 12Carboxylic Acid (RCOOH)

6 - 8Aromatic (e.g. benzene)

4 - 6Alkene (R2C=CH2)

3 - 4Alkyl Halide (RCH2X)

Page 23: QFL2144 RMN AULA2

� Circulation of electrons within molecular

orbitals results in local magnetic fields that

oppose the applied magnetic field.

� The greater this “shielding” effect, the greater

the applied field needed to achieve resonance,

and the further to the right (“upfield”) the NMR

signal.

Page 24: QFL2144 RMN AULA2

Structure Effects on Shielding� Electron donating groups increase the electron density

around nearby hydrogen atoms resulting in increased shielding, shifting peaks to the right.

� Electron withdrawing groups decrease the electron density around nearby hydrogen atoms resulting in decreased shielding, (deshielding) shifting peaks to the left.

Page 25: QFL2144 RMN AULA2

Three major factors account for the resonance positions (on the ppm scale) of most protons.

1. Deshielding by electronegative elements.

2. Anisotropic fields usually due to π-bonded electrons in the molecule.

3. Deshielding due to hydrogen bonding.

Page 26: QFL2144 RMN AULA2

� electrons shield nucleus

� electronegativity: withdraws electrons to

deshield nucleus

� downfield (deshielding) = left side of

spectrum

� upfield (shielding) = right side of spectrum

� delta values increase from right to left!

Page 27: QFL2144 RMN AULA2

DESHIELDING BY DESHIELDING BY DESHIELDING BY DESHIELDING BY ELECTRONEGATIVE ELEMENTSELECTRONEGATIVE ELEMENTS

Page 28: QFL2144 RMN AULA2

C HClChlorine “deshields” the proton,that is, it takes valence electron density away from carbon, whichin turn takes more density fromhydrogen deshielding the proton. electronegative

element

DESHIELDING BY AN ELECTRONEGATIVE ELEMENTDESHIELDING BY AN ELECTRONEGATIVE ELEMENT

NMR CHART

δδδδ- δ+δ+δ+δ+

δδδδ- δ+δ+δ+δ+

highly shieldedprotons appearat high field

“deshielded“protons appear at low field

deshielding moves protonresonance to lower field

Page 29: QFL2144 RMN AULA2

Electronegativity Dependence Electronegativity Dependence

of Chemical Shiftof Chemical Shift

Compound CH3X CH3F CH3OH CH3Cl CH3Br CH3I CH4 (CH3)4Si

Dependence of the Chemical Shift of CH3X on the Element X

Element X

Electronegativity of X

Chemical shift δδδδ

F O Cl Br I H Si

4.0 3.5 3.1 2.8 2.5 2.1 1.8

4.26 3.40 3.05 2.68 2.16 0.23 0

deshielding increases with theelectronegativity of atom X

TMSmostdeshielded

Page 30: QFL2144 RMN AULA2

CHCl3 CH2Cl2 CH3Cl

7.27 5.30 3.05 ppm

mostdeshielded

The effect increases withgreater numbersof electronegative7.27 5.30 3.05 ppm

-CH2-Br -CH2-CH2Br -CH2-CH2CH2Br

3.30 1.69 1.25 ppm

mostdeshielded

The effect decreaseswith incresing distance.

of electronegativeatoms.

Page 31: QFL2144 RMN AULA2

ANISOTROPIC FIELDSANISOTROPIC FIELDSDUE TO THE PRESENCE OF PI BONDS

The presence of a nearby π bond greatly affects the chemical shift.

Benzene rings have the greatest effect.

Page 32: QFL2144 RMN AULA2

Circulating ππππ electrons

Ring Current in BenzeneRing Current in Benzene

Deshielded

H H

Secondary magnetic field

generated by circulating ππππelectrons deshields aromatic

protons

Bo

Deshielded

H H fields add together

Page 33: QFL2144 RMN AULA2

C=C

HH

ANISOTROPIC FIELD IN AN ALKENEANISOTROPIC FIELD IN AN ALKENE

protons aredeshielded

shifteddownfield

Deshielded

fields add

C=C

H H

Bo

secondarymagnetic(anisotropic)field lines

Page 34: QFL2144 RMN AULA2

HC

ANISOTROPIC FIELD FOR AN ALKYNEANISOTROPIC FIELD FOR AN ALKYNE

Bo

secondarymagnetic(anisotropic)field

H

C

C

hydrogensare shielded

Shielded

fields subtract

Page 35: QFL2144 RMN AULA2

HYDROGEN BONDINGHYDROGEN BONDINGHYDROGEN BONDINGHYDROGEN BONDING

Page 36: QFL2144 RMN AULA2

HYDROGEN BONDING DESHIELDS PROTONSHYDROGEN BONDING DESHIELDS PROTONS

O H O R

HHO

R

The chemical shift dependson how much hydrogen bondingis taking place.

Alcohols vary in chemical shiftfrom 0.5 ppm (free OH) to about5.0 ppm (lots of H bonding).

O H

R

O R 5.0 ppm (lots of H bonding).

Hydrogen bonding lengthens theO-H bond and reduces the valence electron density around the proton- it is deshielded and shifted

downfield in the NMR spectrum.

Page 37: QFL2144 RMN AULA2

O

C

O

R

H

H

C

O

O

R

Carboxylic acids have stronghydrogen bonding - theyform dimers.

With carboxylic acids the O-H

SOME MORE EXTREME EXAMPLESSOME MORE EXTREME EXAMPLES

With carboxylic acids the O-Habsorptions are found between10 and 12 ppm very far downfield.

O

OO

H

CH3

In methyl salicylate, which has stronginternal hydrogen bonding, the NMRabsortion for O-H is at about 14 ppm,way, way downfield.

Notice that a 6-membered ring is formed.

Page 38: QFL2144 RMN AULA2

NMR Correlation ChartNMR Correlation Chart-OH -NH

TMS

HCHCl3 ,

DOWNFIELD UPFIELD

DESHIELDED SHIELDED

12 11 10 9 8 7 6 5 4 3 2 1 0

CH2FCH2ClCH2BrCH2ICH2OCH2NO2

CH2ArCH2NR2

CH2SC C-HC=C-CH2

CH2-C-

O

C-CH-C

C

C-CH2-CC-CH3

RCOOH RCHO C=C

H

δδδδ (ppm)