regents review #1 expressions & equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9)...

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Regents Review #1 Expressions & Equations (x – 4) (2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x – 3 = 2x 5x 7

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Page 1: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Regents Review #1

Expressions &

Equations(x – 4)(2x + 5)

3x3 – 4x2 + 2x – 1

(4a – 9) – (7a2 + 5a + 9)

4x2 + 8x + 1 = 0 (x – 5) 2 = 25

10x3

5x5 x – 3 = 2x 5x 7

Page 2: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Exponential Expressions

Page 3: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Exponential Expressions

1) xy0 2) (2x2y)(4xy3) 3)

x(1) x

8x3y4

3xy3

Any nonzero number raised to the zero power equals 1.

Multiply coefficients and add exponents.

Divide coefficients and subtract exponents.

2

52

2xyy6x

Page 4: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

PolynomialsA polynomial is a sum of terms. Each term is separated by either a + or – sign.

Page 5: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

PolynomialsThe degree of a polynomial with one variable is the highest power to which the variable is raised.

Page 6: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

PolynomialsA polynomial is written in standard form when the degrees (exponents) are listed from highest to lowest.

Page 7: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

PolynomialsWhen adding polynomials, combine like terms.

1) Represent the perimeter of a rectangle as a simplified polynomial expression if the width is 3x – 2 and the length is 2x2 – x + 11.

3x – 2 3x – 2

2x2 – x + 11

2x2 – x + 11

(3x – 2) + (3x – 2) + (2x2 – x + 11) + (2x2 – x + 11)

2x2 + 2x2 + 3x + 3x – x – x – 2 – 2 + 11 + 11

4x2 + 4x + 18

The expression can also be simplified this way.2(3x – 2) + 2(2x2 – x + 11)

Page 8: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

PolynomialsWhen subtracting polynomials, distribute the minus sign before combining like terms.

2) Subtract 5x2 – 2y from 12x2 – 5y

(12x2 – 5y) – (5x2 – 2y)

FROM COMES FIRST

12x2 – 5y – 5x2 + 2y

12x2 – 5x2 – 5y + 2y

7x2 – 3y

Page 9: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

PolynomialsWhen multiplying polynomials, distribute each term from one set of parentheses to every term in the other set of parentheses.

3) (3x – 4)2

4) Express the area of the rectangle as a simplified polynomial expression.

9x2 – 12x – 12x + 16 9x2 – 24x + 16

2x2 – 4x + 1

2x2 -4x 1

x 2x3 -4x2 x

5 10x2 -20x 5

2x3 + 6x2 – 19x + 5x + 5

(3x – 4)(3x – 4) Expand 3x - 4

Page 10: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

PolynomialsWhen dividing polynomials, each term in the numerator is divided by the monomial that appears in the denominator.

42x

2

2

2

3

2

23

3x12x

3x6x

3x12x6x5)

Page 11: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Factoring Polynomials

What does it mean to factor?Create an equivalent expression that is

a “multiplication problem”.

Remember to always factor completely.Factor until you cannot factor anymore!

Page 12: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Factoring

1) Factor out the GCF

2) AM factoring

3) DOTS

1)2x(2x2x4x2

2)3)(x(x65xx2

)4y)(3x4y(3x

16y9x22

42

“Go to Methods”

Binomial difference of two perfect squares

Trinomial ax2 + bx + c , a = 1

Page 13: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

FactoringWhat about ax2 + bx + c when a 1?

Factor 5n2 + 9n – 2

5n2 + 10n – 1n – 2

5n(n + 2) – 1(n + 2) (5n – 1)(n + 2)

GCF is 1, Factor by Grouping!

Find two numbers whose product = ac and whose sum = b

ac = (5)(-2) = -10 b = 9 The numbers are -1 and 10

Rewrite the polynomial with 4 terms

Factor out the GCF of each group

Write the factors as 2 binomials

Create two groups5n2 + 10n – 1n – 2

Page 14: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

FactoringWhen factoring completely, factor until you cannot factor anymore! 12x10x2x 23 1) 44 81y16x 2)

)9y3y)(4x3y)(2x(2x 22

)9y)(4x9y(4x 2222 6)5x2x(x2

2)3)(x2x(x

The factored form of the polynomial expression is equivalent to the standard form of the polynomial expression.

Page 15: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

EquationsWhat types of equations (in one variable) do we need to know how to solve?

1) Equations with rational expressions (fractions)2) Quadratic Equations3) Square Root Equations4) Literal Equations (solving for another variable)

Remember: When solving any type of equation, always use properties of equality and check solution(s).

Page 16: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Rational Equations (proportions)

5(3x – 2) = 10(x + 3)15x – 10 = 10x + 30 5x – 10 = 30 5x = 40 x = 8

Always check solution(s) to any equation

1023x

53x

511

511

1022

511

102)3(

53

88

Page 17: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Rational EquationsHow do we solve a rational equation with more than one fraction?

Option 1: Combine fractions and create a proportion

Option 2: Multiply by the LCD (least common denominator)

7103x

55x

Example: Solve for x.

Page 18: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Rational Equations

7103x

55x

7103x

55x

22

FOO

7103x

10102x

17

10105x

7103x

55x

(7)103x

55x

101010

12x

70105x703x102x

10(7)1(3x)5)2(x

5x + 10 = 70

Create a Proportion Multiply by the LCD

Page 19: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Quadratic Equations1) ax2 + c = 0 Ex: 2x2 – 32 = 0 2x2 = 32 x2 = 16 x = x = 4 or x = {4,-4}

16

2) ax2 + bx + c = 0Ex: x2 – 5x = -6

Isolate x2 and take the square root.

Set the equation equal to zero.Factor.Set each factor equal to zero and solve.Zero Product Property

x2 – 5x + 6 = 0

(x – 2)(x – 3)= 0

x – 2 = 0 x – 3 = 0 x = 2 x = 3 x = {2,3}

Page 20: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Quadratic EquationsHow do we solve a quadratic equation that cannot be factored?

Example: Find the roots of x2 – 2x – 5 = 0.

)1(2

)5)(1(4)2()2( 2 x

2

242x

2

622x

1

611x

}61,6{1 x

61x

Use the quadratic formula:a

acbbx

2

42

a = 1, b = -2, c = -5

626424

Page 21: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Quadratic EquationsThe equation can also be solved by completing the square.Find the roots of x2 – 2x – 5 = 0.

x2 – 2x – 5 = 0x2 – 2x = 5x2 – 2x _____ = 5 _______x2 – 2x + 1 = 5 + 1

(x – 1)(x – 1)

1)1(2

2

22

22

b

(x – 1)2 = 6

61)(x 2

61x61x

Page 22: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Square Root Equations Solve 3193x5

403x5

83x

2283x 643x

321.x

Isolate the

Square both sides of the equation to eliminate the

Page 23: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Literal EquationsWhen solving literal equations, isolate the indicated variable using properties of equality.

candxa,oftermsinyforSolve

cyxay

xac

xax)y(a

xac

y

y(a + x) = cFactor out the variable that you are solving for.

Page 24: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Literal Equations

bh21

A

bh2A

bbh

b2A

hb

2A

bandAoftermsinhforSolve

Multiply both sides of the equation by 2 to eliminate the fractional coefficient.

Page 25: Regents Review #1 Expressions & Equations (x – 4)(2x + 5) 3x 3 – 4x 2 + 2x – 1 (4a – 9) – (7a 2 + 5a + 9) 4x 2 + 8x + 1 = 0 (x – 5) 2 = 25 10x 3 5x 5 x

Now it’s your turn to review on your own!

Using the information presented today and the study guide posted on halgebra.org,

complete the practice problem set.

Regents Review #2 Friday, May 15th

Be there!