rotational inertia by: russell and malachi brown and zachary beene

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Rotational Inertia By: Russell and Malachi Brown and Zachary Beene

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Page 1: Rotational Inertia By: Russell and Malachi Brown and Zachary Beene

Rotational Inertia

By: Russell and Malachi Brown and Zachary Beene

Page 2: Rotational Inertia By: Russell and Malachi Brown and Zachary Beene

Rotational Inertia, I is:Measure of an object’s resistance to changes in rotation.

The moment of inertia, I, of a point mass with respect to an axis is defined as the product of the mass times the distance from the axis squared.

I = mr2

Page 3: Rotational Inertia By: Russell and Malachi Brown and Zachary Beene

The moment of inertia of any extended object is built up from that basic definition. An object can be thought of as a sum of particles, each having a mass of dm. Integration is used to sum the moment of inertia of each dm to get the inertia of body.

𝐼=∑ 𝑟2𝑑𝑚=∫𝑟 2𝑑𝑚System of Particles

Continuous Object

Page 4: Rotational Inertia By: Russell and Malachi Brown and Zachary Beene

Here is an example of a rod’s moment of inertia being integrated.(about an axis in the center)

The center of the rod is Length of 0, so the two ends are –L/2 and L/2. The dm in the original equation is replaced with M/L*dr, because M/L is the proportional mass per length.

Page 5: Rotational Inertia By: Russell and Malachi Brown and Zachary Beene

For simplicity, here are the equations for inertia of common objects (already integrated).

Page 6: Rotational Inertia By: Russell and Malachi Brown and Zachary Beene

Parallel axis theoremThe moment of inertia about any axis parallel to the axis through the center of mass is given by:

Page 7: Rotational Inertia By: Russell and Malachi Brown and Zachary Beene

Here’s an example using a rod.The moment of inertia of a rod about its center is given by the equation

I = (1/12)mL2

To find the moment of inertia of a rod about its end is given by:

I = Icm + md2

I = (1/12)mL2 + m(L/2)2

I = (1/12)mL2 + mL2/4I = (1/3)mL2