s-1 1.please complete the information sheet on your desk. 2.introduction 3.syllabus a.angel (1 st...

S-1

1. Please complete the information sheet on your desk.

2. Introduction

3. Syllabusa. Angel (1st BALJEM, 6th CAMMAL)

b. Cheating

c. Assignments

d. Passes Matthews

Angel

http://schoolwires.henry.k12.ga.us/16502022291322713/site/default.asp

http://angel.henry.k12.ga.us/

Describing Motion: Kinematics in One Dimension

AP Physics

Chapter 2


AP Physics

Section 2-1 Reference Frames and Displacement


IA1a -

Students should understand the general relationships among position, velocity, and

acceleration for the motion of a particle along a straight line

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Describing Motion: Kinematics in One Dimensionunderstand the general relationships among position, velocity, and acceleration

Mechanics – study of

motion, force, energy

Kinematics – how objects move

Dynamics – why objects move

Translational Motion – move without rotation

2-1

Reference Frames (Frames of Reference)

Are we moving?

Compared to what?

Usually with “respect to the Earth”

Unless otherwise specified

All other cases, must specify the frame of reference

Typically done with coordinate grid and x and y axis (only x or y for 1D motion)

2-1


Positive – up and right

Negative – down and left

2-1


S-2

A really ugly dog wanders back and forth on his chain.

He walks 10 m to the right.

Then 5 m to the left.

Then 7 m to the right.

Then 2 m to the left.

Then 4 more meters to the left.

What was his displacement and distance traveled?

http://www.bing.com/images/search?q=ugly+dog&id=84E8BE533DF811DBFDE9723539C9D06ED0602E3E&FORM=IGRE1

Defining Motion

Position – relative to frame of reference (x or y)

Displacement – change in position (meters)

x = x2-x1

Not distance

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Distance vs. Displacement

2-1


Distance – scalar (magnitude)

Displacement – vector (magnitude and direction)

Must give a direction

East/West, up/down

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2-1

Distance Time Graph Gizmo


http://www.explorelearning.com/index.cfm?method=cResource.dspView&ResourceID=260

AP Physics

Section 2-2 Average Velocity


Average Speed – distance per unit time (scalar)

Average Velocity – displacement per unit time (vector)(meters/second)

x = displacement

t = change in time

2-2

t

xv


2-2

Distance Time Velocity Graph Gizmo


http://www.explorelearning.com/index.cfm?method=cResource.dspView&ResourceID=301

AP Physics

Section 2-3 Instantaneous Velocity


Instantaneous Velocity – the average velocity during an infinitesimally short time interval

We will only calculate situations with constant velocity or constant acceleration

Calculus is required if acceleration is not constant

2-3

t

xv

0t

lim


Slope of any displacement time graph is the instantaneous velocity

2-3


Using the graph

calculate the

average velocity

between t0=2

and t=5

APP-Matt-09

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AP Physics

Section 2-4 Acceleration


Average Acceleration – change in velocity per unit time (vector) (meters/second2)

v is final velocity

v0 is initial velocity (or at time 0)

Sign of a indicates direction of vector

Deceleration is just negative acceleration2-4

0

0

tt

vv

t

va


Acceleration is the slope of the velocity time graph

2-4


AP Physics

Section 2-5 Motion at Constant Acceleration

Describing Motion: Kinematics in One Dimensionunderstand the special case of motion with constant acceleration


IA1b -

Students should understand the special case of motion with constant acceleration.

2-4


We are limited to calculations when acceleration is a constant

We will use the mathematical definition of displacement, velocity, and acceleration to derive 4 Kinematic equations.

Memorize these equations – you will use them a lot

2-5



Assume

t0 = 0, it drops out of equations

We rework the definition of acceleration to get our first working equation

2-5atvv

t

vva

tt

vva

0

0

0

0



For the second equation we first rework the definition of average velocity to solve for displacement

2-5

tvxx

t

xxv

0

0



We define average velocity as the average of the initial and final velocity (only possible with constant acceleration)

2-5

20vv

v


Now we combine the last three equations

2-5

221

00

000

00

0

2

2

attvxx

tatvv

xx

tvv

xx

tvxx


For the third equation we start by using a version of the definition of velocity

2-5

tvxx 0


Combine with our average velocity definition

2-5

tvv

xx

tvxx

20

0

0



Solve the definition of acceleration for time

2-5

a

vvt

t

vva

0

0


Combine and you get

2-5a

vvxx

a

vvvvxx

tvv

xx

2

2

2

20

2

0

000

00

Finally, solve for final velocity

2-5

axvv

a

vvxx

2

220

2

20

2

0


The 4th equation is not found in your book, but is in most others

2-5

tvvxx

tvv

xx

tvxx

)(

2

021

0

00

0


AP Physics

Section 2-6 Solving Problems


1. Determine what the object is your are solving for.

2. Draw a diagram. Determine the positive and negative direction for motion.

3. Write down any known quantities.

4. Think about “The Physics” of the problem.

5. Determine what equation, or combination of equations will work under theses Physics conditions.

2-6


6. Make your calculations.

7. See if your answer is reasonable.

8. Determine what units belong with the number, and what the direction should be if it is a vector.

2-6


A car slows down uniformly from a speed of 21.0 m/s to rest in 6.00s. How far did it travel in this time?

1. Object – car

2. Diagram

2-6



1. Object – car

2. Diagram

3. Know

v0=21.0m/s

v=0m/s

t=6.00s2-6


A vicious killer poodle is standing still when he sees you across the 25 m long room.

You have 0.67 seconds to avoid her attack.

A. What is the poodles initial velocity?

B. What is the poodles acceleration?

C. What is the poodles final attack velocity?

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5. Physics – car is going through negative acceleration in 1D, acceleration is constant

6. Equation – needs v0, v, t, x (define x0=0)

So

2-6

tvvxx )( 021

0



5. Physics – car is going through negative acceleration in 1D, acceleration is constant

6. Equation – needs v0, v, t, x (define x0=0)

Solve

2-6

mssmx 63)6)(/210(21


A car is behind a truck going 25m/s on the highway. The car’s driver looks for an opportunity to pass, guessing that his car can accelerate at 1.0m/s2. He gauges that he has to cover the 20 m length of the truck, plus 10 m clear room at the rear of the truck and 10 m more at the front of it. In the oncoming lane, he sees a car approaching, probably also traveling at 25 m/s. He estimates that the car is about 400 m away. Should he attempt to pass?

2-6


1. Object – car2. Diagram3. Known quantitiesCar relative truck Car relative to App. Car App. Car

v0=0m/s 25m/s 25m/s a=1m/s2 1m/s2 0m/s2 x=40m 360m

(why?)

4. Physics – car must travel 40 m to pass truck, approaching car can travel maximum of 400-40 m in that same period of time, or their paths overlap 2-6


5. Time for car to pass

2-6st

sm

m

a

xt

atx

attvxx

94.8/1

)40(222

221

221

00


5. How far did the other car get in that time?

2-6

mx

smx

vtx

st

5.223

)94.8)(/25(

94.8


Practice Page

2-6

A lonely rabbit is standing 30 m from a really cute bunny that is hopping away at a constant 10 m/s. If the rabbit starts from rest, and can accelerate at 5 m/s2,

A. How long will it take to reach the bunny

B. How far will he have traveled

C. How much faster than the bunny will he be running

3rd AP Physics ID: APPhysics-Matthews-2011

5th AP Physics ID: APP-Matt-09

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AP Physics

Section 2-7 Falling Objects


We will ignore air friction

We will learn the why later.

Acceleration due to gravity at earths surface is 9.80 m/s2 directed downward (-9.80m/s2)

Symbol g represents acceleration due to gravity

Still use motion equations but

x is replaced with y

a is replaced with g2-7


Two common misconception

1. Acceleration and velocity are always in the same direction

a. No, as an object is thrown upward, velocity is +y, acceleration is –y

2. Acceleration is zero at the highest point.

a. No, at the highest point, the velocity is zero, but acceleration is always -9.80m/s2

b. The object changes velocity, it must have an acceleration 2-7


A cat is dropped off a cliff that is 145 m tall.

A. What is his acceleration?

B. What is his initial velocity?

C. What is his final velocity?

D. How long is he in the air?

E. Did he land on his feet?

S-5

A really large mouse sees a cat 100 m away. If he starts from rest and takes 28 s to catch the cat, what is his acceleration? Assume that the cat is moving away at a constant 20 m/s.

S-6

Important concepts from video

1. y velocity at the top – 0m/s

2. Displacement at the bottom – 0m

3. Acceleration – always -9.80m/s2

2-7


Truck and Soccer Ball

http://physics.doane.edu/physicsvideolibrary/FlashVideos/ProjectileMotion/verttruck2.html

http://physics.doane.edu/physicsvideolibrary/FlashVideos/ProjectileMotion/verttruck2.html

Practice

2-7

Evil Ralphie is throwing sheep off a cliff. Bad Ralphie! He throws the first sheep upward at 22 m/s. Then 6 seconds later he throws a second sheep downward. The cliff is 180 m tall and both sheep land (gently and on their feet) at the same time. What was the initial velocity of the second sheep?

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s-1 1.please complete the information sheet on your desk. 2.introduction 3.syllabus a.angel (1 st...

Documents

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