series circuits parallel circuits lecture week equivalent ...€¦ · lecture week 4 •series...
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Series Circuit Series Circuits….How do I determine the current through each resistor?
-Current is the same for all resistors
How do I determine the voltage drop through each resistor?
-Voltage is different for all resistors
Series Equivalent Resistance:
𝑹𝒆𝒒 = 𝑹𝟏 + 𝑹𝟐 + 𝑹𝟑 + …𝑹𝒏
Image: Science Buddies Staff, “Squishy Circuits Project 2: Add Even More Lights,” [Online document], 11/21/15, [2/15/16], Available: http://www.sciencebuddies.org/science-fair-projects/project-ideas/Elec_p074/electricity-electronics/squishy-circuits-project-2
V
V
EQUIVALENT
CIRCUIT
VReq
𝐼
Series Circuit - Equivalent Circuit
𝑹𝒆𝒒 = 𝑹𝟏 + 𝑹𝟐 + 𝑹𝟑 + …𝑹𝒏
CURRENT THROUGH ALL RESISTORS IS THE SAME AND
EQUAL TO THE CIRCUIT CURRENT OF THE EQUIVALENT
CIRCUIT
𝑰 =𝑽
𝑹𝒆𝒒
(1) Calculate the Equivalent Resistance (Req).
(2) Use Ohm’s Law to determine the circuit current.
(3) Then use Ohm’s Law to determine the voltage drop across each resistor.
𝑽 = 𝑰𝑹𝟏
Parallel Equivalent Resistance
V
EQUIVALENT
CIRCUIT
𝟏
𝑹𝒆𝒒=
𝟏
𝑹𝟏+
𝟏
𝑹𝟐+
𝟏
𝑹𝒏
𝑰 =𝑽
𝑹𝒆𝒒
(1) Equivalent Resistance (Req)
(2) Current through each Resistor using Ohm’s Law
(3) Voltage drop across each resistor
𝑽 = 𝑽𝟏 = 𝑽𝟐 = 𝑽𝟑
-ALL RESISTORS IN PARALLEL EXPERIENCE THE SAME VOLTAGE DROP
-EQUAL TO THE SUPPLY VOLTAGE OR POWER SUPPLY
-CIRCUIT CURRENT IS SPLIT THROUGH EACH RESISTOR!!!
https://www.youtube.com/watch?v=Oph5JN-ayZ8
𝐼
𝑰 = 𝑰𝟏 + 𝑰𝟐 + 𝑰𝟑
Parallel Resistance: Example
1 K 1 K
I
EE 1305 Name Lab/Team # Date
Calculations:
Problem Statement: Assuming you have two 1 k resistors in parallel, (a) determine the equivalent resistance, (b) the circuit current, (c) the current through each resistor, and (d) add up the currents through each resistor and compare to the circuit current.
Equations/Unit Conversions Figures
1
𝑅𝑒𝑞=
1
𝑅1+
1
𝑅2+
1
𝑅3+ … 𝑉 = 𝐼𝑅
𝑉 = 𝐴
1
𝑅𝑒𝑞=
1
𝑅1+
1
𝑅2
𝑅𝑒𝑞 =𝑅1𝑅2
𝑅1 + 𝑅2
𝑅𝑒𝑞 =1 𝑘 1 𝑘
(1 𝑘+ 1 𝑘)
= 0.5 𝑘
(a)
5VReq = 0.5 k
Parallel Resistance: Example con’t
EE 1305 Name Lab/Team # Date
Calculations 𝑉 = 𝐼𝑅𝑒𝑞
𝐼 =𝑉
𝑅𝑒𝑞=5 𝑉
0.5 𝑘
1 𝑘
103ඍ𝐴
𝑉= 0.01 𝐴
(b)
(c)𝐼 =
𝑉
𝑅1𝑘=5 𝑉
1 𝑘
1 𝑘
103ඍ𝐴
𝑉= 0.005 𝐴
Current through each resistor is 0.005A
(d) 𝐼 = 0.005 𝐴 ∗ 2 = 0.01 𝐴
Adding up the currents gives me the same current as the circuit current.
1 K 1 K
I
5VReq = 0.5 k
I
Shorthand Notation/Equivalent Circuits: Example
Combination of R3 and R5 Combination of R4 and R3||R5Combination of R1 and R2
What’s Next in Week 5?
Will introduce…
LAB• Module 1 – Angle Sensor
LECTURE
• Ohm’s law and its applications: Voltage Divider Method
Please bring laptops to all labs.
P1. Calculate the equivalent resistance for the resistors in series. Use the equivalent resistance to determine the current flowing through each resistor. Make sure to show the unit conversion V = AΩ when setting up your current (I) calculation. Show all units and unit conversions for each calculation.
P2 The circuit below includes 3 resistors in parallel, R1 = 1kΩ, R2 = 2 kΩ, and R3 = 4 kΩ. (a) Determine the equivalent resistance (Req), (b) use Ohm’s Law to determine the circuit current, (c) use Ohm’s Law to determine the current through each resistor.
P3. (a) Simplify the circuit and determine the equivalent resistance. (b) Determine the circuit current, and(c) Determine the power consumed by the equivalent resistance and the power supplied by the 12 V source. (d) Does conservation of power exist in the circuit? Label each step and include units and unit conversions for full credit.
Group Problem:(a) Write the equivalent resistance (Req) using the
shorthand notation for the three resistors. (b) Assume R1 = 1 kΩ, R2
= 1 kΩ, and R3 = 500 Ω, compute the equivalent resistance of the
circuit. (c) Compute the total current I consumed by the circuit (d)
Use Ohm’s law to compute the voltage drop across R3. SHOW ALL
UNITS AND UNIT CONVERSIONS USING THE PROBLEM SOLVING FORMAT
PRACTICED IN CLASS FOR UNIT CONVERSIONS.
What’s Next in Week 5?
Will introduce…
LAB• Module 1 – Angle Sensor
LECTURE
• Ohm’s law and its applications: Voltage Divider Method
Please bring laptops to all labs.