Skema Set 1 P2

SECTION A

Question 1 Part Mark Answer Note

(a)

(b)(i)

(b)(ii)

(c)

1

1

1

1

Name the container X correctly Lead container / concrete container

Underlining thee correct phrase in the box correctly

a beta particle

Give the reason correctly

Negatively charge

Give the reason correctly

The mass of ray P < ray Q // The speed f ray P > ray Q

Total 4

Question 2

Question 3

Section Marks Answer Catatan

(a) 1 There is no net flow of heat between two objects and

they have same temperature

(b) 1 45 0C

(c) 1

1

The heat from block P transfer to the water

Until the rate of heat transfer between P and water

become equal

(d)

1

1

E = mcӨ

= 0.3 x 900 x 55

= 14 850 J

6

marks

Question 4 No 4

4 a)

1M

1M

v = 5 x 0.8

= 4 ms -1

4 b) 1M

1M

The wave are circular

Wavelength remains unchanged

4 c) 1M Diffraction

No 2

2 a)

1M Quantity matters in a material //An object at rest tends to

remain at rest // an object in motion tends to stay in motion

2 b) 1M The car

2 c) 1M Mass // Inertia is smaller

2 d) 1M

1M

v2 = u

2 + 2as

02 = 15

2 + 2a(375)

- 0.3 ms -2

Skema Set 1 P2

4 d) 1M

1M

Waves pass through an aperture or round a small obstacle

Waves spread out.

Question 5

Q 5 / S 5

(a)(i) 1 Density is the mass per volume

(b)(i)

(ii)

(iii)

1

1

1

Level of the boat is higher in the sea than in the river.

Water displaced in the sea is less than in the river.

Density of sea water is higher than river water.

(c)(i)

(ii)

1

1

The lower the density of water, the greater /higher the

volume of water displaced.

Weight of the boat = Weight of the water displaced

(d) 1 Archimedes’ principle // Bouyancy’s law

(e) 1

2

Ballast tank filled by sea water

Weight of submarine > upthrust

Maximum

1 mark

(Any one

mark)

Tot/Jum : 8

QUESTION 6

Part Mark Answer Note

(a)

(b)

(c)

(c)

(d)

1

1

1

1

1

1

1

1

Name the current I1 correctly Base current

Name the current I2 correctly

Collector current

State two observations correctly

I1 < I2 // I1 = 0 and I2 = 0

The small changing of I1 give the large changing of I2 or I1 is directly

proportional to I2

Give the reason correctly

The mass of ray P < ray Q // The speed f ray P > ray Q

Complete the circuit correctly

The two resistors in series

One of the resistor in base circuit

State the correct function of the two resistors

As the voltage divider

Total 8

Skema Set 1 P2

QUESTION 7

Part Mark Answer Note

(a)(i)

(a)(ii)

(a)(iii)

(b)(i)

1

1

1

1

1

Complete the ray diagram in Diagram 7.2 correctly

Two reflected rays are shown (diagram)

Angle of incidence = Angle of reflection (diagram)

State the phenomenon involved correctly

Reflection

State the problem that happens correctly

The driver in car P cannot see car Q // field of view very small

Name the curve mirror correctly

Convex mirror

Skema Set 1 P2

Part Mark Answer Note

(b)(ii)

(b)(iii)

(a)(iii)

(b)(i)

(c)(i)

(c)(ii)

1

1

1

1

1

1

1

Complete the ray diagram in Diagram 7.3 correctly

Two reflected rays are shown (diagram)

Angle of incidence = Angle of reflection (diagram)

State the solution of the problem in (a) (iii) correctly

The convex mirror increase the field of view

State the problem that happens correctly

The driver in car P cannot see car Q // field of view very small

Name the curve mirror correctly

Convex mirror

Give the correct answer

Unchanged

Give the reason correctly

The characteristics of image of a convex mirror not depends on the focal

length

Skema Set 1 P2

Total 10

Question 8

Bhg Markah Jawapan Catatan

(a) 1 Isotope that are not stable

Isotop yang nukleusnya tidak stabil

(b) 1

1

D

The reading of ratemeter is highest

Bacaan meter kadar paling tinggi

(c) (i) 1

1

226

88 Ra 222

86 Rn + 4

2 He

Symbol alfa betul - 1

Persamaan seimbang

-1

(c) (ii) 1

1

1

1

100% → 50% → 25% → 12.5%

Sodium-24 : 3T = 45

T = 15 hours

Cobalt-60 : T = 15.9/3 = 5.3 years

Radium-226 : T = 4860/3 = 1620 years

(d) 1

1

1

Sodium-24

Half life is short @ activity decreases faster

Setengah hayat pendek @ keaktifan cepat

berkurang

Emmits beta rays @ can penetrate ground but

can’t penetrate pipe

Memancarkan sinar beta @ boleh menembusi

tanah tetapi tidak boleh menembusi paip

Skema Set 1 P2

12 markah

SECTION B

Question 9

Bhgn. Markah Jawapan Catatan

Soalan 9

(a)(i)

(ii)

1

1

1

1

1

1

Area per unit square // P = F / A

200 / 0.2

= 1000 N m-2

800 / 0.8

= 1000 N m-2

Pressure at P = Q =R

Force is directly proportional to the surface area

Define symbols used

With unit

Accept without unit

(b) 1

1

1

1

Pressure is applied to the toothpaste (tube)

The toothpaste carry and apply the pressure of the

equal magnitude to the whole tube

Pascal’s Principle

(c)

1,2

3,4

modification explanation

piston of bigger cross-

sectional area

Can support greater

force (weight)

Low density material Lightweight // easy to

carry

Accept any

reasonable

Skema Set 1 P2

5,6

7,8

9,10

Non-compressible

liquid

Piston can be lifted up

Longer handle Less effort needed to

press the small piston

Apply released valve

between small and

main reservoir

Liquid can flows into

small reservoir

modification

Question 10

Q10/S10

Sect. Mark

(a)(i)

(b)

1

6

1 State the definition of current correctly

The rate of charge flows.

1 State the correct comparison of the type of circuit connection

Diagram 10.1 connected in series and Diagram 10.2 connected in parallel.

2 State the correct comparison of the ammeters reading

The reading of ammeter in Diagram 10.2 is greater than in Diagram 10.1.

3 State the correct comparison of the voltmeters readings

The reading of voltmeter in Diagram 10.1 > Diagram 10.2.

4 State the correct comparison of the effective resistance

The effective resistance in Diagram 10.2 < Diagram 10.1.

5 State the correct relation between the effective resistance and the current flows Effective resistance increases, the current flows decreases.

6 State the correct relation between type of circuit connection and effective

resistance.

Circuit connected in parallel, the effective resistance decreases.

(c) 3 1 State the correct happens of the ammeter reading

The ammeter reading increased

2 State the correct happens of voltmeter reading

The voltmeter reading decreased.

Skema Set 1 P2

3 State the correct reason

Effective resistance in the circuit decreased.

(d) 10

State the correct extra device attached and correct reason

1 Attach one fuse to the live wire in the consumer unit/ fuse box.

2 To break/switch off the circuit when large current before the wire become

hotter and produce fire.

State the correct choosing of wire/cable and correct reason

3 Using the insulating wires // thicker wires

4 To prevent short circuit // To reduce resistance, improve efficiency.

State the correct adjustment of each lamp and the correct reason

5 Attach switch for each lamp.

6 To allows each lamp to be switched on and off independently.

State the correct modification of connection of metal fitting lamp and give the

correct reason

7 Connect the metal fitting lamp to the earth wire/cable.

8 To flows electron (extra) to earth to avoid lethal shock.

State the correct using of bulbs and give the correct reason

9 Using only 240 V light bulb.

10 To ensure the bulbs light up with normal brightness.

Total : 20

SECTION C Question 11

Bhg Mrk Jawapan Catatan

Soalan 11

(a) 1 Aerofoil / airfoil

(b)

(i)

( ii )

1

2

3

1

The shape of cross section of the wing causes the speed of

airflow

Above the wings to be higher than the speed of airflow

below

When the speed of moving air is higher ,the pressure is

lower

Hence air pressure below the wings is higher compare to

above the wings

Bernoulli’s principle

Skema Set 1 P2

( c) 1

2

3

4

5

6

7

8

9

10

A shape of cross section which is upper side is longer than

the bottom

To produced the speed of airflow Above the wings to be

higher than the speed of airflow below

The larger the area of the wing

The larger the lift force

The less density of the wing materials

Less weight // produce more upward resultant force

The higher the difference in speed of air

The higher the difference in pressure

The most suitable choice is P

Because it has

A shape of cross section which is upper side is longer than

the bottom

The larger the area of the wing

The less density of the wing materials

The higher the difference in speed of air

(d)(i)

(ii)

(iii)

1

2

1

2

1

P= F/A

F=PA

F=500 x 40

F = 20000N

Resultant force = 20000 – 900(9.8)

= 11180N

Upward

F =ma

a=F/m

a=12.42ms-2

Total 20

Question 12

Section Mark Answer

12(a) 1 Electric to sound

(b) 1

1

1

1

Current flows and soft iron core is magnetised

Hammer hit the gong

Contacts open

Soft iron core loses its magnetism

(c) 1

1

1

1

1

Size of the hammer is big

Surface area contact is big

Larger distance between the hammer and the gong

The force applied on the gong is greater

The number of turns of the coil is greater

Skema Set 1 P2

1

1

1

1

1

The strength of the magnetism is greater

High curvature of the gong

The area of air molecule vibrate is greater

Q

Size of the hammer is big, Larger distance between

the hammer and the gong, The number of turns of

the coil is greater, High curvature of the gong

(d)(i)

1

1

I =12

10

0.83 A (with unit)

(ii)

1

1

1

PI = 10080

10x

= 12.5 W

I = 240

5.12/ 0.052 A (accept e.c.f)

TOTAL 20 M

section A

1 (a) (i) Refractive index, type of transparent material / n 1

(ii) Refracted angle / r 1

(iii) Incident angle/ i 1

(b) n r /

0 sin r

rsin

1

1.49 19.0 0.3256 3.07

1.92 16.5 0.2840 3.52

2.42 12.5 0.2164 4.62

2.91 10.0 0.1736 5.76

3.50 7.5 0.1305 7.66

Skema Set 1 P2

1. columns n , r , sin r, rsin

1

2. all the units of n , r , sin r, rsin

1are correct

3. all the value of r +/ - 0.5 0

4. Value of r , constant at 1 decimal place

5 Value of sin r , constant at 4 decimal places

6. Value of rsin

1 constant at 2 decimal places

7. All the value of r ,sin r, rsin

1are correct

7

(c) score

1. n at y-axis and rsin

1 at x-axis

2. the units at both axis is correct

3. both axis has initial scale and not ganjil

4. 5 points ploted are correct

5. 3 points plotted are correct

6. smooth line

7. the minimum size is 5 x 4 ( from origin to the last point)

score marks

7 5

5-6 4

3-4 3

2 2

1 1

5 (d) Directly proportional 1

Total 16

2 (a) Straight line from I= 0.40 A

Straight line to Y axis at V = 0.74

0.72 V (with unit)

1

1

1

(b) increase 1

(c) constant 1

(d) (i)

Show a triangle (enough size)

Substitution

1st

2nd

Skema Set 1 P2

(ii)

0.60

0.88

r= 0.68Ω

E = V + Ir

= .0.72 + 0.4 X 0.68 ( V = 0.72V and I =0.68 A)

= 0.9921 V ( 4 decimal point)

3rd

1st &2

nd

3rd

(e) eye position must be perpendicular to scale of ammeter/voltmeter./

The connection must tied

1

Total 12

Section B

Question

Soalan

Answer

Jawapan

Marks

Markah

3. (a)

(b)

(c) (i)

(ii)

State a suitable inference

Acceleration is influenced by the mass

1

State a relevant hypothesis

When the mass increased, the acceleration will be decreased.

1

State the aim of experiment

To investigate the relationship between the acceleration and the mass.

1

State the suitable manipulated variables and responding variable

(Quantity that can be measured)

Manipulated variable : mass

Responding variable : acceleration

1

Skema Set 1 P2

(iii)

(iv)

(v)

State the constant variable

Force applied

1

State the complete list of apparatus and materials

5 Trolleys, ticker timer, ticker tape, a rubber band, a wooden runway,

12 V a.c power supply.

1

Draw the functional arrangement of the apparatus

Trolley rubber band

Ticker

Timer

Ticker tape

Friction compensated runway

Power supply

1

State the method to control the manipulated variable

The apparatus is set up as shown in the diagram.

The ticker-timer is switched on and a trolley is pulled using a rubber

band. The extension of the rubber band is ensured to be of the same

length

1

State the method to measure the responding variable

Acceleration of the trolley is calculated using the ticker-tape , a = ( v-u

) / t

1

Repeat the experiment at least 4 times with the values

Procedure 2 and Procedure 3 are repeated using 2, 3, 4 and 5 trolleys.

(Note : Based on SPM standard , at least five manipulated values

required.)

1

State how the data tabulated with the title MV and RV

Mass / num. of trolley acceleration / cm s-2

1

2

3

4

5

1

State how the data is analysed, plot a graph RV against MV

acceleration / cm s-2

Mass / num. of trolley

1

Total

12

Question

Soalan

Answer

Jawapan

Marks

Markah

4. (a)

(b)

Inference

The rotation speed of the motor influeced on number of battery

1

Hypothesis

If the current increase , then the speed of rotation increase.

1

Aim

To investigate the relationship between the current and distance/speed

1

Skema Set 1 P2

(c) (i)

(ii)

(iii)

Variables

manipulated :current

responding : distance of the rode fixed :strength of magnet/ rod mass

1

1

List of apparatus and materials

2 bar magnet ,iron rod,batteries,ammeter, metere rule

1

Arrangement of the apparatus

1

(iv)

(v)

Procedure of the experiment which include the method

of controlling the manipulated variable and the method of

measuring the responding variable.

The current 0.5 A record from the ammeter. Measured the distance of rod movement .

The experiment is repeated 4 times with the difference current, I = 1.0

A ,

1.2 A, 1.4A ,1.6A and 1.8A

1

1

1

(vi) Tabulate the data

Current,I/A 0.5 1.0 1.2 1.4 1.6 1.8

Distance of the rod/cm

1

(vii) Analyse the data

Distance/cm

Current,I/A

1

Total 12