sles investigate some of the approximations to π which have been used
DESCRIPTION
TOPIC 1 Real and Complex Number Systems I (4 weeks)TRANSCRIPT
SLEs
Investigate some of the approximations to π which have been used.
11 Mathematics CTopics - Semester 1• Real and Complex Number Systems I• Vectors and Applications I• Matrices and Applications I• Introduction to Groups• Structures and Patterns I• Real and Complex Number Systems II
Topics - Semester 2• Vectors and Applications II• Structures and Patterns II• Matrices and Applications II• Dynamics I• Periodic and Exponential Functions I
TOPIC 1
Real and Complex Number Systems I
(4 weeks)
Structure of the Real Number System including:• rational numbers• irrational numbers
Simple manipulation of surds
Subject Matter
Unit 1
Real and Complex Number Systems I
Real
Rational (a/b) Irrational (a/b)
Integers Non-integers SurdsTranscendental
(…-2,-1,0,1,2,…) (¼,-3.453,43/17,…) (5,5.17,-17…) (π ,e)
Real numbers are any numbers which can be placed on the real number line.
Rational numbers are any numbers which can be expressed as a ratio p where p and q are integers qAll integers, terminating decimals or recurring decimals are rational
-5 -4 -3 -2 -1 0 1 2 3 4 5
i
Get real!
i
Get real!Get rational!
Model
Express each of the following as fractions:(a) 0.454545….(b) 0.14676767…..
(a) 0.454545….
Let x = 0.454545…. 100x = 45.454545…. 100x – x = 45 99x = 45 x = 45/99 = 5/11
(b) 0.14676767…..
Let x = 0.14676767….. 10000x = 1467.676767….. 100x = 14.676767….. 9900x = 1453 x = 1453/9900
Page 16 Ex 1.3
Surds
5.223
22754
26
236
625.623672..
3
25333
425
425
41
ge
baabba
ba
80
516
54
surdaasWrite
335
53353254
5932534516
45751280
Simplify
335
53353254
5932534516
45751280
Simplify
)53)(53()(
)32)(53()(
b
aSimplify
MODEL
4553539
)53)(53()(
1552336
)32)(53()(
b
a
Page 21 Ex 1.4
2325
234
23
)(
)(
)(
:
c
b
a
atorsmindenorationalwithfollowingtheofeachExpress
223
22
23
23)(
a
7)23(4
29)23(4
2323
234
234)(
b
722137
2232515
29)23)(25(
2323
2325
2325)(
c
Page 26 Ex 1.5
Inequalities
ModelModel Solve and graph
32
7321
532)(
xxc
xb
xa
482532)(
xxxa
102022121
7321
xxx
xb
10
011
22223232
00
32
0xwhensolutionnotherefore1x0therefore
x
xbutxxxxxxxx
xConsiderxConsider
xxc
Page 34 Ex 1.6
1 (second column)3(first column)
Graphing Inequalities
• Solve and graph
• x – 10 < 4x – 2 ≤ 2x + 8
x – 10 < 4x – 2 ≤ 2x + 8 x – 10 < 4x – 2 and 4x – 2 ≤ 2x + 8 -3x < 8 and 2x ≤ 10 x > -2 ⅔ and x ≤ 5
Page 34 Ex 1.6
2 c-j
Absolute Value
-3 = 32-8 = -6 = 64-2 - 5-9 = 2 – 4 = -2
Page 34 Ex 1.6 4
Graphing Absolutes
Solve and graph:(a) 2x+4 = 10(b) x-3 ≥ 4(c) 3-x < 4(d) 3x-2≤ 1
(a) 2x+4 = 10 2x+4 = -10 or 2x+4 = 10 2x = -14 or 2x = 6 x = -7 or x = 3
(b) x-3 ≥ 4 x-3 ≤ -4 or x-3 ≥ 4 x ≤ -1 or x ≥ 7
(c) 3-x < 4 3-x > -4 and 3-x < 4 -x > -7 and -x < 1 x < 7 and x > -1
(d) 3x-2 1 3x-2 -1 and 3x-2 1 3x 1 and 3x 3 x and x 13
1
Page 34 Ex 1.6 5a-c,7,8
Solve and graph | 16+4x | ≤ 5-7x (P35 No 9h)
If the question said:| 16+4x | ≤ 3 then you would say:i.e. 16 + 4x ≥ -3 and 16 + 4x ≤ 3
Solve and graph | 16+4x | ≤ 5-7x (P35 No 9h)
| 16+4x | ≤ 5-7xi.e. 16 + 4x ≥ -(5-7x) and 16 + 4x ≤ 5 - 7x 16 + 4x ≥ -5 + 7x and 16 + 4x ≤ 5 - 7x 21 ≥ 3x and 11x ≤ -11 x ≤ 7 and x ≤ -1
Page 34 Ex 1.6 9
Page 3 Ex 1.1
Symbol Meaning
is an element ofb M means that b is an element of the set M where M = {a,b,c,…}
for all2x is even x where x is a positive integer
: such that {x: x is even} means the set of all x such that x is even
there existsA : bA means there exists a set A such that b is an element of A
* A defined binary operatione.g. x*y = 2x+y – 3 4*5 = 2x4 + 5 – 3 = 10
Laws of Addition on the set of integers (J)
• Closure Law
• The sum of any two integers results in another number which is also an integer.
a,b ∈ J, a + b = c where c ∈ J
• Commutative Law
• The order in which numbers are added does not alter their sum.
a,b ∈ J, a + b = b + a
• Associative Law
• No matter how numbers are associated in addition, it does not alter their sum.
a,b,c ∈ J, (a + b) + c = a + (b + c)
• Identity Law of Addition
• 0 is the identity element for addition.• When 0 is added to any number, the sum is the
same as that number.
a ∈ J, a + 0 = 0 + a = a
• Additive Inverse Law
• For every integer, a, there exists another unique number, -a, such that they add to give 0 (the identity element)
a ∈ J, -a ∈ J a + -a = 0
Page 7 Ex 1.2