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SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT- DISCRETE ENERGY LEVELS "LASER FUNDAMENTALS" Second Edition By William T. Silfvast

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Page 1: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

SOLUTION SET

Chapter 3

PARTICLE NATURE OF LIGHT­DISCRETE ENERGY LEVELS

"LASER FUNDAMENTALS"

Second Edition

By William T. Silfvast

Page 2: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

/ - --- ----- ------ ------····--- -----------------·--····--- ------ -····-

Cll 3

1. Using the Bohr theory, carry out the derivation of the electron orbit radius r ( eqn. 3 .4. and the orbital energy En (eqn. 3.8) for the hydrogen atom.

Fr b ~ ( 3, 2.) ( "3, 3)

h' ~ l ..... Jii - r .~l!i

~er~

n i ~ '- Y TT C:o p f'"tt M W

Y"he. e ~

1. '"l.

- n 1. (]. rr -i1 ) tc - r:~ h n ': ~ u n .. - V\'te rr el. - (j' W'ee ..

-::·--

Page 3: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

2. Compute the wavelengths for the followin . . . CH 3 the Bohr theory: g trans1t1ons in the hydrogen atom using ;

!

(a) n == 2 to n == I· '

(b) n == 3 ton== I· '

( c) n == 4 to n == 2 · ' ( d) n == 5 to n == 3 · '

( e) n == 6 to n == 4.

F='ro...._ ( 3. II) * ~ R It ( {2 - ~~):: ~. 0% 77 H'xto ~~· -~) M'

l Oi) Yh :. 1. it\' Vii .:- I J_ -:: ( ~ - l ,_ \ ~ H -J A4.f I 2 }

"Ll ::: (. 2 I )7 x I 0 - '7 M =. 12 I I s 7 V\ l.N\

(b) l ~ ( J. - J_ ) Ru 'A ,.,_ ~...._ fl

)\

)\ 53 = L 2 ~ 2t_ x 10-(pWt = ~, 2.::. .:~~ -. • rr .ti• -uwa ·- n t

_I -::. ( f._ - ~.) f< H

"~

Page 4: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

CH 3 3. Compute the ionization potential for five-times ionized carbon (C5+) and also com­

pute the wavelength of the transition from n = 3 ton = 2 for that species.

E ::: -~'-Ea - - ?! '- Eo

I '2.. -I

b~ Et> .:= ts. >'fse V a. "1.. cl. ~ ::. ~

b s-+ ( ) l ) ).,_ n -{-o"' j..J - .); lcR C. / s f r o ..._ 5. I '-I :

, r I

D 'f"' .

-v.. -:: c - ~ '"2 2-o ( J_ - J_~) - -jl

~~'- h 2). 3

ie ( \ ~J \ "i? 0 - --- (. h 2.. l ....

r\~'--

\ I (< H ~~ l +'- - ~~)

I.~ 2 .3 s-x '° -8' ~ :: I ~.. 2 3 s- rt t11 -_:.:_ ______________ __

Page 5: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

CH3

4~ In the isoelectronic scaling of hydrogen-like species , what is the lowest- atomic number element that would have a possible X-ray laser transition at a wavelength shorter than 4.4 nm? (Here, consider the transition from n = 3 ton = 2 as the laser transition.)

F_...o w... 1·0~o b f.e ~ 3 : I· \ \ - - \. ~ ~ ~H ( ~ - ~) - ~-- /.oei'7x1D

1 1>t-'(i·- ~-)

N () w ~} (.. <. L/. '1 fl IM.

J_ ( lo ~b. 3 V\ IA\_ J ~ '-7, '7- ~ ~ ~ ' .'---=

, r I

-i:- , ·~ a. q \ ~ trv e ,.. ) (4. yt.4.>(, r~ ""'; e ¥"'

l ~ \ 3 -

Page 6: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

ll+ 3

5. Solve the Schrodinger equation for the energy eigenvalue of the ground state of th~ hydrogen atom, assuming a solution of the form 'lj;1 (r) = ce-ar (eqn. 3.38).

, r I

, I I

Page 7: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

lH 3 6. Write out the wave function for the hydrogen atom for n = 3, l = 2, and m = +1

using (3.65) and (3.66).

Y\ = > _f_ ::.. '- VV\ -:::: + I Pl-: t. i+ t

f,,.b ...._ C 5. ,,') 'f. -= c f,, e.- .. L ti)<') \6l 'R.} vYI.

L~ Lvi - 1 .. t • LS"'=-rio '1 - .,., • • • s--

- -- q,./I.,_

Page 8: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

Cll 3

7. Obtain the possible term designations for a hydrogen atom in which the electron is in the 3d level.

S-:::. )/ L. )= z. :::; '.j: Si',,. 'I I l..

T 1. w;.. l., 5"'/i.

$ ~ 1/1- r-~ 3/l..

Page 9: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

Cll 3

8. Give the electron configuration for a lithium atom in its ground state, and write ~ut the term designation for that state.

\ s 't 2S L; ~ I"-~ IA .,._e)_ srd:4

1~~ 2 s I s -:.;:. r"L ) ;: 0 =:; s '>~

"2 $_,. I

L :r =)

Page 10: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

9. List the electron configurations for the following elements in their ground states: aluminum, fluorine, calcium, germanium, and krypton.

Page 11: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

L.#3

10. Determine the number of states and write out the term designations (eqn. 3.76) for those states that result from an outer electron configuration of 2s4p.

2S '-IF

'2.S 9 .-2 =- () s =- v'L Yp ==? 1 :: I S = I/?..

L :. I s--' ~~~~~--.ltllw,i::U

I + \ - L 7 .J:.L+~ - --

I +-- l) - ~ -

I - I - () =? -

L ~ I S =D

T::. L-+ s ::- I + o = I ~

J 1:> '-.

3 [:> (

'3 (=> 0

I /-;;;;

I

Page 12: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

11. You are told that a short-wavelength laser is measured to have a wavelength of 30.38 nm and occurs on an H-like transition fro.m n = 4 ton =~-In what element does the laser action occur? Justify your answer. 2..

v=

:t: 'L::

, t- --, '

I'-/ :z_l. G./)X/{)

1, ~? )( l'O /';::;-

&,, f S°"" X ID 1 'I - /~, {)L/(/ -

L-/ I OD ~ ~

Page 13: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

lH 3

12. The element magnesium (Mg) is vaporized to produce a gas of magnesium atoms. An electrical current is passed through the gas in order to excite the atoms to levels . above the ground state. Give the complete ground-state electron configuration. Make an energy-level diagram and provide the labels of the ground state and all of the excited energy levels associated with the same n quantum number as that of the ground state. Allow only one of the outer electrons to be excited .

\I

's 0

.R=-o

1. ::. I

£=6 .,R :: 2

____ :-o~ _.. ____ > Di

l -t-__........._._,...,, DI

Page 14: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

CH3

13. Obtain the spectroscopic designation and diagram the energy levels for the follow­ing three electronic configurations:

' - ~ \)2.

f p~

'

's ()

ls2 2s2, ls2 2s2p, ls2 2s3d.

' sl. 2 s sci --=y

~D 3

lD~

~D,

>pio

lp,o

~p~

s -= l/i.. - I/ z_ ) = o) o

CS] s=V2. ~=-D 5 ~ 'Ii .t. == I

S - l .+ J. :: I L -:: o +I = I J"::. 2 > I> D - 2 2 ) --

s = vi. l::.. o s ~ 'I, )_ = 2.

S=

J:: I

Page 15: SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT …silfvast.creol.ucf.edu/LaserFundamentals/SolutionSet/Chapter3.pdf · SOLUTION SET Chapter 3 PARTICLE NATURE OF LIGHT DISCRETE ENERGY

14. Determine the number of energy levels and· the term designations for those levels of an atom in a state in which the two outer electrons are 2s and 2p.

$ ~ 'tz. .P:... i)

5 ': 'I-,_ .). =- '

CH3

('-1. ..j..l=1 :) - "2 "'2..

L -:. D + I = I J;: 2, 'j ()

s ?!) I "2.,1)(.J

s ::. l _.L::D L:: D 4 l =- l .J: J "l- "2.

~ I I ':lo ' I I

'-I ~ ra.te$