statics part 1

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    FLUID STATICS

    FLUIDS ARE AT REST OR MOVING IN SUCH A MANNER THAT THERE IS NO

    RELATIVE MOTION BETWEEN ADJACENT PARTICLES

    NO SHEAR STRESSES IN THE FLUID AT REST

    PRESSURE IS THE ONLY FORCE DEVELOPED

    PRESSURE AT A POINT

    Pressure normal force per unit area at a given point acting on a given

    plane within the fluid mass of interest

    How the pressure at a point varies with the orientation of the plane passing

    through the point ?

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    sxPs

    x

    y

    z

    zxPy

    yxPz

    x

    y

    z

    2

    zyx

    g

    FORCES ON AN ARBITRARY WEDGE SHAPED ELEMENT OF FLUID

    THE PRESSURE AT A POINT IN A FLUID AT REST, OR IN MOTION, IS

    INDEPENDENT OF DIRECTION AS LONG AS THERE ARE NO SHEARING

    STRESSES PRESENT PASCALS LAW

    s

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    s

    zsin

    s

    ycosSinsz Cossy

    yy amF

    yxy a2

    zyxSinsxPzxP

    yxy ayPP2

    zz amF

    z

    xz

    a2

    zyx

    2zyxgCossxPyxP

    ga2

    zPP zxz

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    Taking the limit x, y, z approch zero while maintaining

    zys PPP

    IN THE ABSENCE OF SHEARING STRESSES, PRESSURE AT ANY POINT INA FLUID IS INDEPENDENT OF DIRECTION PASCALS LAW

    PASCAL BLAISE 1623 1662 39 YEARS

    1642 - invented the first mechanical adding machine

    Pascal proved by experimentation in 1648 that the level of the mercury column in a

    barometer is determined by an increase or decrease in the surrounding atmospheric

    pressure rather than by a vacuum, as previously believed.

    His methodology reflected his emphasis on empirical experimentation as opposed toanalytical, a priori methods, and he believed that human progress is perpetuated by

    the accumulation of scientific discoveries resulting from such experimentation.

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    y

    z

    x

    zx2

    y

    y

    PP

    zx

    2

    y

    y

    PP

    yx

    2

    z

    z

    PP

    yx2

    z

    z

    PP

    zy

    2

    x

    x

    PP

    zy2

    x

    x

    PP

    BASIC EQUATION FOR THE PRESSURE FIELD

    How does the pressure in a fluid in which there are no shearing

    stresses vary from point to point ?

    j

    i

    K

    z,y,xP

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    T.O.H.......xx

    )x(f

    2

    1x

    x

    )x(f)x(fxxf

    2

    2

    2

    Neglecting all higher order terms

    zyx

    y

    PFy

    T.O.H.....2

    y

    y

    P

    2

    1

    2

    y

    y

    P

    PP

    2

    2

    2

    2yy

    2

    y

    y

    PPP

    2y

    y

    zx

    2

    y

    y

    PPzx

    2

    y

    y

    PPFy

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    By Newtons Second Law,

    m a = Surface forces (pressure) + Body forces (weight)

    a

    mF

    azyxkzyxzyxP

    akP

    General equation of motion for a fluid no shearing stress

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    PRESSURE VARIATION IN A FLUID AT REST

    dz

    dp

    For liquids or gases at rest the pressure gradient in the vertical

    direction at any point in a fluid depends only on the specific weight of

    the fluid at that point

    akp

    PZ

    0a;z

    p;0

    y

    p;0

    x

    p

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    INCOMPRESSIBLE FLUID

    dz

    dp

    2

    1

    2

    1

    z

    z

    p

    p

    dzdp

    )zz(pp 1221

    This pressure distribution HYDROSTATIC DISTRIBUTION

    hghPP 21

    Hgofmm76081.910006.13

    10325.101

    g

    PPh

    3

    21

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    PAB

    = h + Po

    PRESSURE IN A HOMOGENOUS, INCOMPRESSIBLE FLUIDAT REST

    depends on the depth of the fluid relative to somereference plane

    not influenced by the size of shape of the tank in which

    the fluid is held

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    F1 = (A1/A2)F2

    A1

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    COMPRESSIBLE FLUID

    dz

    dp2z

    1z

    2p

    1p

    dzdp Gases are compressible

    gTR

    pg

    dz

    dp2z

    1z

    2p

    1pT

    dz

    R

    g

    p

    dp

    2z

    1z1

    2

    T

    dz

    R

    g

    p

    pln zfT

    For isothermal condition

    o

    12

    1

    2

    TR

    )zz(g

    p

    pln

    o

    12

    1

    2

    TR

    )zz(gexp

    p

    p

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    STANDARD ATMOSPHERE

    T = 150 C (288.15 K)

    p = 101.33 kPa (abs)

    = 1.225 kg/m3

    = 12.014 N/m3

    = 1.789 10-5 Pa.s

    FOR TROPOSPHEREm/K0065.0

    zTT a

    Airplanes

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    2z

    1z1

    2

    T

    dz

    R

    g

    p

    pln

    zfT

    m/K0065.0

    zTT a

    2z

    1z

    a1

    2

    zT

    dz

    R

    g

    p

    pln

    zTln1

    R

    g

    p

    pln a

    1

    2

    Rg

    a1

    2 zTlnp

    pln

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    Graphical Representation of Pressure

    ABSOLUTE PRESSURES POSITIVE

    GAGE PRESSURES POSITIVE & NEGATIVE

    Pabs = Patm Pgage

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    BAROMETER

    vaporatm php

    For mercury at 20o C,

    papvapor 158585.0

    hpatm

    Evangelista Torricelli - 1644

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    PIEZOMETER TUBE

    Simple and accurate

    Suitable only for pressure

    greater than atmospheric

    pressure

    Pressure measured to bereasonably small height will

    be large

    Capillarity effects are negligible

    for large bore tube ie.,diameters greater than 30 mm

    atmA phP

    0hh

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    U-TUBE MANOMETER02211 hhpa

    1122a hhp

    If A contains gas,

    22 hpa

    Capillarity effects are

    negligible for large bore

    tube ie., diameters

    greater than 30 mm

    DIFFERENTIAL U TUBE MANOMETER

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    DIFFERENTIAL U-TUBE MANOMETER

    3322b11a hhphp

    Capillarity effects cancel

    INCLINED TUBE MANOMETER

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    INCLINED TUBE MANOMETER

    3322b11a hsinlphp

    113322 sin hhlpp baIf A and B contain gas

    sin22

    ba ppl

    Amplification issin1

    sin

    1sin

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    Pressure Gage

    Pressure gages