the effect of a catalyst on reaction rate
TRANSCRIPT
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Enthalpy Changes of Neutralisation
By: Beatrice Valencia
Class: IGCSE Year 1
Chandra Kusuma School 2013
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Introduction:
When an alkali neutralizes an acid, a salt and water are formed.
Aqueous hydrogen ions (H+(aq)) from the acid react with the hydroxideions(OH-(aq)) from the alkali, forming water. The identity of the salt will of
course depend on the nature of the acid and alkali used. For hydrochloric
acid and sodium hydroxide:
H+(aq)+Cl-(aq) + Na+(aq)+OH-(aq) Na+(aq)+Cl-(aq)+H2O(I)
Hydrochloric acid Sodium Hydroxide Sodium Chloride
Notice in this equation the Na+ and Cl- ions are unchanged. The only
chemical reaction occurring is between H+ and OH- ions:H+(aq) + OH-(aq) H2O(I)
The combination of H+ and OH- ions in this way release energy.
Purpose: to measure the enthalpy changes when the process of giving of
heat(exothermic)
No. Materials
1 Hydrochloric acid
2 Sodium Hydroxide3 Nitric acid
4 Sulphuric acid
5 Measuring cylinder
6 Dropper
7 Beakers
8 Thermometer
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Procedure/ Method :
1) Hydrochloric acid with sodium hydroxide
Picture Observation
Measure 25cm3 of 2.0
mol dm-3 hydrochloric
acid into a polystyrene
beaker.
Record its temperature.
Put 25cm3 of 2.0 dm-3
sodium hydroxide
solution in a measuring
cylinder and take its
temperature.
Now pour this into the
acid, stir and take the
final temperatue.
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Data:
Temp. HCL: 29o
Temp.NaOH: 33o
Temp.Final: 41o
Question #1 :A. What was the temperature rise? (If the acid and alkali were not at the same
temperature initially, use the mean of their initial temperatures as the starting
temperature.)
29+33/2=31o
B. How much energy was delivered to the 50cm3 of final solution during thereaction? (Assume the specific heating capacity of the polystyrene cup is
negligible and that the specific heating capacity of the solution is 4.2JK-1
g-1
.)Q=mc.t
=50g. 4.2J/kg=2.1Kj
= 2.1 kJ/0.05mol=42kJ/mol
C. How many moles of water were formed by the reaction you have just carried out?25cm3=0.025 dm3
Mole HCL=2mol/dm3 x 0.025 dm3 =0.05mol
Mole of NaOH,NaCl,H2O=0.05
D. Work out the enthalpy change of neutralisation for this reaction in kilojoules permole of water formed.
NaOH + HCL NaCL + H2O
2) Nitric acid and sodium hydroxide
Picture Observations
Measure 25cm3of 2.0 mol
dm-3nitric acid into a
polystyrene beaker.
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Record its temperature.
Put 25cm3of 2.0 dm-3
sodium hydroxide
solution in a measuring
cylinder and take its
temperature.
Now pour this into the
acid, stir and take the final
temperatue.
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Question:1. Write an ionic equation to represent the reaction that has occurred.
H+(aq) + NO3 -(aq) Na+(aq) + OH-(aq)2. Work out the enthalpy change of neutralisation for this reaction.3. Compare the values you have obtained for the enthalpy changes of neutralisation
of the three reactions and explain the way the values compare.
Q=mc.t
=50g. 4.2J. 10,5=2205kJ
= 2205 kJ/0.05mol=44.1kJ/mol
4. How do the values for the first two reactions in this table compare with your ownexperimental results for the same reactions? Account for any errors in your
results.
The enthalpy change in experiment 2 is greater than experiment 1
5. Do the values for the first three reactions in the table agree with the explanationyou have given in question 4?
%error= [Theory-Lab/Theory]/theory x 100%
= [-57.9 42]/-57.9 x 100% HCL with NaOH
= 172.5%
%error= [Theory-Lab/Theory]/theory x 100%
= [-57.6 44.1]/-57.6 x 100% HNO3 with NaOH
= 176.5%
6. Suggest why the enthalpy change of neutralisation for the reaction involvingethanoic acid is slightly lower than the values for the first three reactions, and
why the enthalpy change of neutralisation for the reaction involving hydrogen
sulphide is substantially lower. (The dissociation constants, Ka, for hydrochloric
acid, hydrobromic acid and nitric acid are very large; that of ethanoic acid is 1.7 x
10-5 mol dm-3 and that of hydrogen sulphide is
8.9 x 10 -8mol dm-3.)
Because the dissociation constant is larger so its make the enthalpy of HCL is
larger than the ethanoic acid
3) Sulphuric acid and sodium hydroxide
Picture Observations
Measure 25cm3of 2.0mol dm-3sulphuric acid
into a polystyrene
beaker.
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Record its temperature.
Put 25cm3of 2.0 dm-3
sodium hydroxide
solution in a measuringcylinder and take its
temperature.
Now pour this into the
acid, stir and take the
final temperatue.
Question:
1. Compare the temperature rises for the two experiments and explain theirrelative values.