trigonometric substitutions - mcmaster universityppoudel/teaching/fall-16/homework/lecture 32... ·...

16
TRIGONOMETRIC SUBSTITUTIONS We showed in class that the area enclosed by the circle x 2 + y 2 = a 2 equals πa 2 . It involved computing integrals of the form Z a 0 p a 2 - x 2 dx Exercise 1. Find the area enclosed by the ellipse x 2 a 2 + y 2 b 2 =1 The following table is a list of trigonometric substitutions that we use for certain radical expressions. Table 1. Table of Trigonometric Substitutions Type Expression Substitution Identity 1 a 2 - x 2 x = a sin θ, - π 2 θ π 2 1 - sin 2 θ = cos 2 θ 2 a 2 + x 2 x = a tan θ, - π 2 <θ< π 2 1 + tan 2 θ = sec 2 θ 3 x 2 - a 2 x = a sec θ, 0 θ< π 2 or π θ< 3π 2 sec 2 θ - 1 = tan 2 θ 1

Upload: others

Post on 02-Sep-2019

1 views

Category:

Documents


0 download

TRANSCRIPT

TRIGONOMETRIC SUBSTITUTIONS

We showed in class that the area enclosed by the circle x2 + y2 = a2 equals πa2. It involved

computing integrals of the form ∫ a

0

√a2 − x2 dx

Exercise 1. Find the area enclosed by the ellipse

x2

a2+y2

b2= 1

The following table is a list of trigonometric substitutions that we use for certain radical

expressions.

Table 1. Table of Trigonometric Substitutions

Type Expression Substitution Identity

1√a2 − x2 x = a sin θ, −π

2≤ θ ≤ π

21− sin2 θ = cos2 θ

2√a2 + x2 x = a tan θ, −π

2< θ <

π

21 + tan2 θ = sec2 θ

3√x2 − a2 x = a sec θ, 0 ≤ θ < π

2or π ≤ θ < 3π

2sec2 θ − 1 = tan2 θ

1

2 TRIGONOMETRIC SUBSTITUTIONS

Exercise 2. (Type 1)

∫ √4− x2x2

dx

Note that the radical term is of Type 1 i.e. radical of the form√

22 − x2.Therefore we need to use the substitution x = 2 sin θ, and proceed from there.

Exercise 3. (Type 2)

∫1

x2√x2 + 4

dx

Just because it has a radical expression does not necessarily mean that you need to use the

substitution from the table. For instance:

Exercise 4.

∫x√

x2 + 9dx

TRIGONOMETRIC SUBSTITUTIONS 3

Exercise 5. (Type 3)

∫1√

x2 − 1dx

So there are integrals where you need to do substitution first before computing the integrals

Exercise 6.

∫ √3

2

0

x3

(4x2 + 1)32

dx

4 TRIGONOMETRIC SUBSTITUTIONS

There are certain integrals where you need to solve by completing the squares first

Exercise 7.

∫ √5 + 4x− x2 dx

Exercise 8.

∫x2 + 1

(x2 − 2x+ 2)2dx