try out for the second grade student print

8/3/2019 Try Out for the Second Grade Student Print

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UNIVERSITAS NEGERI MAKASSAREka Irianti

095204116

Class C Education

English

Language TestingTry Out For The Second Grade of

Senior High School Of SMA Negeri 1Galesong Utara

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TABLE OF CONTENTS

TABLE OF CONTENTS .......................................................................ii

CHAPTER I INTRODUCTION................................................................1

A. Background

................................................................................................................1

B. Content of Test

................................................................................................................

1

C. Place of Tryout

................................................................................................................

2

CHAPTER II TEST SPECIFICATION (BLUEPRINT).................................3

A. The Test Constraction

................................................................................................................

4

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B. Answer Keys

................................................................................................................

12

C. Scoring Rubric

................................................................................................................

12

CHAPTER III RESULTS OF ANALYSIS..................................................13

A. Data Presentation

...............................................................................................................13

B. Frequency Distribution

...............................................................................................................

14

C. Central Tendency

...............................................................................................................

15

D. Standard Deviation

...............................................................................................................

16

E. Reliability

...............................................................................................................

17

F. Validity

...............................................................................................................

19

G. Item Analysis

...............................................................................................................

29

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CHAPTER IV CONCLUSION.................................................................46

APPENDIX..........................................................................................48

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CHAPTER I

INTRODUCTION

A. BACKGROUND

Language testing is a kind of test that particularly tests the

language competence. It has an objective to measure the

achievement of the student in learning language or to check what

students can do with language. Language test also may be designed

chiefly as a device to reinforce learning and to motivate students in

their learning activity. In language testing, there are some items

must be tested, it divide into language skills and language areas.

Language skills are consist of listening, speaking, reading and writing

test, while language areas are consist of grammar and vocabulary

test. It can be in the form of essay question or in multiple choices, it

depends on the learning and testing objective.

Test of language ability may be inaccurate or unreliable in sense

that repeated measures may give different result. These measures

may also be invalid in the sense that the other abilities are mix in. To

be useful, the test must be provided with reliable and valid

measurements for certain purposes. To assess the reliability and

validity of test, we must do some kinds of analysis in order to get the

objectivity of test of question before we use the test item for the

student. That is why, in this small research, I try to assess the

reliability and validity of a test by using multiple choices test.

B. CONTENT OF TEST

This try out uses multiple choices instruments to assess the

reliability and validity of the test that consist of six items will be tested.

They are four language skills, listening, speaking, reading and reading,

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also two language areas, such as grammar and vocabulary. Each items

of test care consist of five number of question so the total question of

this try out section is 30. It is the ideal number of test that required in

language testing.

C. PLACE OF TRY OUT

SMA Negeri 1 Galesong Utara is the place that had taken to

execute this try out on 10 December 10 th 2011. There are 30 students

are tested in this section, they are from Science class of Second Grade

Senior High. The test was done successful with the result of test will be

discussed and analyzed in the next chapter.

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CHAPTER II

TEST SPECIFICATION (BLUEPRINTS)

SUBJECT : ENGLISH

SEMESTER/CLASS : I/ XI

EXACT 1

SCHOOL : SMA

NEGERI 1 GALESONG UTARA

NO Basic CompetenceObjective/Indicators Domain TechniqueItems

1 Listening The students areable to:

identify some

basic verbs in

the

monologue.

postulate

viewpoint of

the given

topics.

C1,C2,C3 MC 1-5

2 Reading The students areable to:

grasp the

meaning of a

simple text.

C1,C2 MC 6-10

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get some

general to

specific

information

from the

text.

3 Vocabulary The students areable to find the

appropriate word to

complete the text.

C1,C2 MC 11-15

4 Speaking The students areable to identifiy the

expression of:

Disappointed

Pleasure

Pain

Givingopinion

Giving advice

C1,C2,C3 MC 16-20

5 Grammar The students areable to:

Write simple

present tense

sentences.

Relative

pronoun.

Conditional

sentence

C1,C2 MC 21-25

6 Writing The students areable to:

put the

C1,C2 MC 26-30

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jumbled into

meaningful

sentences.

construct

incorrect

order

sentences

into readable

paragraphs.

A. TEST CONSTRUCTION

Listening section

1.

a. Unforgettable.

b. You're right.

c. I think so.d. Yes, I was there.

2.

a. Green

b. Bluec. Red

d. Black

3.

2

Man : which color do you think suits me better,

green or blue?

Woman : Neither, I have always thought red suits you

Woman : Im not feeling well, but I have to finish all

my documents.

Man : What about your holiday in Bali?

Woman :


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a. Good job

b. Its fantastic

c. You must take a rest

d. Thats what was the friends is for

Listening script for number 4 to 5

4. When was Albert Einstein born?

a. the early 1800

b. the end 1800

c. the early I900

d. the end 1900

1. According to the speaker, he died in the age of

a. 70

b. 74

c. 64

d. 94

Reading section

3

Albert Einstein was born near the 1800 in Omni Germany.

He graduated from university ostrich in Switzerland at ages

26, that was also when he did his famous work in physics.For the next ten years he lived in Germany. He also had

travel a lot to talk with other scientist. Then in early 1930 he

had to leave Germany because of Hitler and NAZI party. He

moved to United State. From that time until hi is dead, he


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Text 1

The following text is for questions 6 to 10

2. Which of the following statements do you agree with?

a. The farmer lived happily with his wife.

b. The farmers wife took care of the bird.

c. The bird was very thankful to the farmer.

d. The farmers wife was a very kind woman.

1. The farmers new hut was .

a. built by the birds

b. a gift from the bird

c. decorated luxuriously

d. build of perfumed wood

3

The Farmer and the Bird

A farmer came across the bird with a broken wing. He picked it up,

took it home and look after it lovingly, even though his wife complained

bitterly about his wasting too much time on the creature.

After some time, the wing mended and, because they did not want

the farmer to have kept on arguing with his wife all the time, it decided to

go back to its nest.

When the farmer discovered that the bird was gone, he was so

upset that he went out to look for it. Eventually, he found it again, and

was greeted happily by the whole family of the bird. As the sign of their

thanks for his care and attention, the birds gave him a little box, and told

him not to open it until he got home.

To his surprise, the farmer found the box full of precious stones.

When his wife saw them, she decided that she too deserved a reward,

and she went to see the birds. The birds gave her a little casket; but this

one was full of devils. The devil jumped on her as soon as she opened thecasket and chased her away.


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1. What do we learn from the text?

a. A gift shows kindness.

b. Sufferings bring happiness.c. Arguing makes you distressed.

d. A good deed deserves a reward.

1. What is the main information discussed in the third paragraph??

a. The bird welcomed the farmer.

b. The farmer got a little casket from the birds.

c. The farmer was so angry and went out to find the bird.

d. The farmer was happy having got a box of precious stones.

1. the bird was gone, he was so upset( paragraph 3)The underlined word refers to .

a. The bird

b. The farmer

c. The casket

d. The farmers wife

Vocabulary section

Text 2

The following text is for questions 11 to 15

Fill in the blank words on the text above by choose one of the best answerbelow:

a. Because

b. On the other hand

c. Consequently

d. Nevertheless

1

(11) , both jogging and (12), carried to extremes, can behazardous. Many confused joggers over do and (13)suffer from uncleand foot damage. Fad dieting, fortunately, becomes only a temporarymeans of shedding a few pounds while the body is deprived of the balancednutrition it

(14)

, so most dieters cannot

(15)

on fad diets. Above


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1. a. Diet

b. Dieting

c. Feed

d. Feeding

1.

a. Ultimately

b. Decided

c. Suggested

d. Mostly

1.

a. Offers

b. Requires

c. Pure

d. Essential

1.

a. Produceb. Serves

c. Preserve

d. Preserving

Speaking Section

1. Ajeng : how about your vacation?

Dini : it was I dont want to go there again.

Ajeng : oh, Im sorry to hear that.

What is the best expression to complete the dialogue above?

a. Great

b. Very satisfied

c. Terrible

d. Good

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Man : Do you think that free education for poor people will be an effective

policy?Woman : because this is what they really need.

a. I think this will help them a lotb. I dont think that this is goodc. I think they will be spoiledd. I dont think that its necessary

1. Man : Do you have any complain about the service?Woman : No, with it.Man : oh, I see.

a. I am disappointedb. Im happy enoughc. I disagreed. I agree

1. Joy : Danny : whats wrong?Joy : I cut my finger when I try to slice this union, and it very hurt me.

a. Upss!

b. Ouch, it hurts!c. Its good.d. Its horrible.

1. Donny : what should I do? Im so confused.Willy : . to come to the talk show tomorrow. You wont regret it, Iguarantee.

a. Youd better not b. Watch outc. take my adviced. you dont have

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Grammar Section

1. Where is my dictionary? it was on my desk

Perhaps somebody it.

a. Takes

b. Has taken

c. Is taking

d. Would take

1. He usually in blue ink.

a. Will write

b. Has written

c. Write

d. Writes

1. Josh lived in a big house has a pool in his back yard.

a. That

b. Who

c. Which

d. Whom

1. If you I will be angry.

a. dont want to write the letter

b. were not writing the letter

c. will write the letter

d. will not write the letter

1. Mita : What a lovely dress!

Armin: if I had money. I would buy it for you.

We may conclude that .

a. Tono will buy the dress for Mita.

b. Tono bought the dress for Mita.

c. Tono cant afford to buy the dress for Mita.

d. Tono can buy the dress for Mita.

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Writing Section

Text 3

For question number 26 to 30

1. Bees have three pairs of leg and four wings. Like all insect, they

have a head, chest, and abdomen. They have mouthparts and a

tongue for collecting nectar. They carry nectar in an organ called a

honey stomach. Moreover bees have special wings that let them flylike a helicopter. They can fly backward, forward, sideways, or stay

in one place in the air.

2. Bees are insect; there are about 20.000 species or kinds of bees.

They live everywhere in the world except in High Mountain, in the

Arctic and Antarctic, and on some small islands in the ocean.

3. In addition, bees have three regular eyes and two compound eyes.

Their compound eyes have many lenses. Furthermore, bees can see

colors and patterns. This helps find flowers.

4. Some bees are small as 0.08 inch (2 millimeters). However, some

bees are big as 1.6 inches (4 centimeters). Bees come in manycolors; black, gray, yellow, red, green, or blue. Most bees live alone.

They are called solitary bees. Meanwhile some bees live in group

called colonies. They are social bees.

1. Arrange the four paragraphs above into the right form.

a. 1-2-3-4

b. 4-3-2-1

c. 3-4-2-1

d. 2-1-4-3

1. The topic of the passage is

a. Animals

b. Insect

c. Bee

d. Nectar

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1. Which of the following is probably NOT a colour of bee?

a. Blackb. White

c. Red

d. Yellow

1. Where in the passage does the author list the parts of the bees body?

a. 1

b. 2

c. 3

d. 4

1. Which of the following place that bee cannot live?a. Forest

b. Antarctica

c. Africa

d. Low-land

A. ANSWER KEYS

1. A 16. C2. C 17. A

3. C 18. B4. B 19. B5. B 20. C6. C 21. A7. D 22. D8. D 23. A9. D 24. A10.B 25. C

11. B 26. D

3

QuestionNumber

Rubric Score

1-30

Right answer

Wrong answer

No answer

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0

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14.B 29. A15.C 30. B

A. SCORING RUBRIC

CHAPTER III

TEST ANALYSIS

A. DATA PRESENTATION

List of the score below is the result of language testing of thefirst grade of SMA Negeri 1 Galesong Utara.

Table 1. List of the Students Score

No. Name of the Students Score

1 Rini Rustia Nur 21

2 Qariatul Wahyuni 21

3 Fitriani 21

4 Susilawati 17

5 Khairunnisa 17

6 Rahmi 17

7 Nur Yusri Hidaya 17

8 Nurhana Ayunita 16

9 Aisyah 16

10 Risnawati Rahman 1611 Rosmita 16

12 Tenriani 15

13 Nurul Mujriah 14

14 Nasrianti 13

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15 Nur Insyana 13

16 St. Umrah Syarih 13

17 Murniati 13

18 St. Nurintang 12

19 Sakinah 12

20 Ratu Tri Putri 12

21 Irsandi 12

22 Malikal Mulki 12

23 Sri wahyuni 12

24 Rahmi Fajriani 12

25 Ruslianto 12

26 Fatmawati 12

27 Midayini 11

28 Hikmawati 11

29 Astuti Bahar 11

30 Yuliana 10

B. FREQUENCY DISTRIBUTION

Table 2. Frequency Distribution of scores

No. Raw Score Final Score Tally Frequency

Percentag

e

1 21 70 /// 3 10

2 17 57 //// 4 13.3

3 16 54 //// 4 13.3

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4 15 50 / 1 3.3

5 14 47 / 1 3.3

6 13 43 //// 4 13.3

7 12 40 //// //// 9 30

8 11 37 /// 3 10

9 10 33 / 1 3.3

Total 30 30 100

The distribution of the scores illustrated above can be presented in

another way as in the following frequency polygon:

Students Score Frequency

C. MEASURES OF CENTRAL TENDENCY

1. Mode

The mode score of this testing is 40, as nine testees have

scored this mark.

2. Median

The medium score in this testing is 43.

3. Mean

To get the mean score of the testing, we had to do some step

below;

Table 3. Frequency Distribution of scores

No. X F Fx

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1 7.0 3 21.0

2 5.7 4 22.8

3 5.4 4 21.6

4 5.0 1 5.0

5 4.7 1 4.7

6 4.3 4 17.2

7 4.0 9 36.0

8 3.7 3 11.1

9 3.3 1 3.3

Tot

al

43.1 30 fx = 142.7

X = fx = 142.7 = 4.7566666667 = 4.76

N 30

X = 4.76

We can see that in this particular test section there is a fairly

correspondence among the mode (4.0), median (4.3), and mean 4.76).

A. STANDARD DEVIATION

Table 4. Standard Deviation

N0 x d (x X) d2

1 7.0 2.24 5.01762 7.0 2.24 5.01763 7.0 2.24 5.0176

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4 5.7 0.94 0.88365 5.7 0.94 0.88366 5.7 0.94 0.8836

7 5.7 0.94 0.88368 5.4 0.64 0.40969 5.4 0.64 0.409610 5.4 0.64 0.409611 5.4 0.64 0.409612 5.0 0.24 0.057613 4.7 -0.06 0.003614 4.3 -0.46 0.211615 4.3 -0.46 0.211616 4.3 -0.46 0.211617 4.3 -0.46 0.211618 4.0 -0.76 0.5776

19 4.0 -0.76 0.577620 4.0 -0.76 0.577621 4.0 -0.76 0.577622 4.0 -0.76 0.577623 4.0 -0.76 0.577624 4.0 -0.76 0.577625 4.0 -0.76 0.577626 4.0 -0.76 0.577627 3.7 -1.06 1.123628 3.7 -1.06 1.123629 3.7 -1.06 1.123630 3.3 -1.46 2.1316

Total 142.7 0 31.834

d2 = 31.834

SD = 31.834

30

= 1.06113

SD = 1.03

F. RELIABILITY

N

oX Y X2 Y2 XY

1 11 10 121 100 110

2 10 11 100 121 110

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3 11 10 121 100 110

4 9 8 81 64 72

5 9 8 81 64 72

6 8 9 64 81 72

7 8 9 64 81 72

8 9 7 81 49 63

9 7 9 49 81 63

1

0

6 10 36 100 60

1

1

9 7 81 49 63

1

2

5 10 25 100 50

1

3

8 6 64 36 48

1

4

3 10 9 100 30

1

5

5 8 25 64 40

1

6

7 6 49 36 42

1

7

7 6 49 36 42

18 4 8 16 64 32

1

9

5 7 25 49 35

2

0

4 8 16 64 32

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2

1

7 5 49 25 35

22

4 8 16 64 32

2

3

7 5 49 25 35

2

4

7 5 49 25 35

2

5

7 5 49 25 35

2

6

7 5 49 25 35

2

7

7 4 49 16 28

2

8

5 6 25 36 30

2

9

7 4 49 16 28

3

0

5 5 25 25 25

X= 208 Y= 219 X2 = 1566 Y2 = 1721 XY =

1536

N = Number of students taking the test

x= sum of variable x/ genap

y= sum of variable y/ganjil

xy= sum of multiplication of variable x and variable y

x2 = sum of square x

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y2 = sum of square y

Nxy (x)(y) (30x1536) (208x219)

528

[Nx2 (x)2][ Ny2 - (y)2] [(30x1566)-(208)2][(30x1721)-

(219)2] [3716][3669]

528 0.143692.43

The result of calculation is then analyzed using Spearman-Brown to seethe reliability of the test.

2rhh1+ rhh

2 x 0.14 0.281+ 0.14 1.14

0.25

To interpret the test realibiility (rn), Sudijono (2003:209) provides

criteria. If the result of calculation (rn) is the same or greater than 0.70, the

evaluated test is highly reliable. Conversely, if the result calculation is

smaller than 0.70, the evaluated test is not highly reliable. Therefore, the

result of calculation is not reliable (rn = 0.25).

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G. VALIDITY

TesteesTest Item

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 X

Rini Rustia

Nur 1 1 1 0 1 1 1 0 0 1 1 0 1 1 0 1 1 0 1 0 0 1 0 1 1 1 1 1 1 1 2

Qariatul

Wahyuni 1 1 1 0 1 1 1 0 0 1 1 0 1 1 0 1 1 1 1 0 0 1 1 1 0 1 0 1 1 1 2

Fitriani

1 1 1 0 1 1 1 0 0 1 1 0 1 1 0 1 1 0 1 0 0 1 0 0 0 1 1 1 1 1 2Susilawati

0 1 1 0 0 0 1 0 0 1 1 0 1 0 0 1 1 1 1 0 0 1 1 1 1 1 1 0 0 1 1

Khairunnisa0 1 1 0 0 1 1 0 0 1 1 0 1 0 0 1 1 1 1 0 0 0 1 1 1 1 1 0 0 1 1

Rahmi0 1 0 0 0 1 1 1 0 1 1 0 1 0 0 1 1 1 1 0 1 1 0 1 1 0 1 1 0 0 1

Nur Yusri

Hidaya 1 1 1 1 1 0 1 1 0 1 0 0 1 0 0 1 1 1 1 0 0 1 1 0 0 0 0 1 0 1 1

Nurhana

Ayunita 0 1 1 0 0 0 1 0 0 1 1 0 1 0 0 1 1 1 1 0 0 0 1 1 1 1 1 0 0 1 1

Aisyah0 1 0 0 0 1 1 1 0 1 0 1 1 0 0 1 1 0 1 0 1 1 0 1 1 0 1 1 0 0 1

0

Risnawati

Rahman 0 1 1 0 1 1 0 1 0 1 0 0 0 0 1 1 1 0 0 0 0 1 1 1 0 1 1 1 0 1 1

Rosmita0 1 1 0 0 0 1 0 0 1 1 0 1 0 0 1 1 1 1 0 0 0 1 1 1 1 1 0 0 1 1

Tenriani0 1 0 1 1 1 1 1 0 1 0 0 1 0 0 1 0 1 1 0 0 0 0 0 1 1 0 1 0 1 1

Nurul

Mujriah 0 0 1 0 1 0 0 1 0 1 1 0 0 0 0 1 1 0 1 0 1 0 1 0 0 1 1 1 0 1 1

4Nasrianti

0 1 0 0 1 0 0 1 0 0 1 1 0 0 0 0 0 1 0 1 0 1 0 1 1 1 0 1 0 1 1

Nur Insyana0 0 0 1 0 0 0 1 1 1 0 0 1 0 0 1 1 1 1 0 0 1 1 0 0 0 0 1 0 1 1

6

St. Umrah

Syarih 0 1 1 0 0 0 0 0 0 1 1 0 1 0 0 0 1 1 1 0 0 1 0 0 0 1 1 1 1 0 1

Murniati0 1 1 0 0 0 1 0 0 1 0 0 1 0 0 1 1 1 1 0 0 1 0 0 1 0 1 1 0 0 1

8

St.

Nurintang 1 1 0 0 0 1 0 1 0 1 0 1 0 0 0 1 0 1 1 0 1 0 0 0 1 0 0 0 0 1 1

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9Sakinah

0 1 0 0 0 0 1 0 0 1 0 1 1 0 0 1 0 1 1 0 0 1 0 0 1 0 1 1 0 0 1

0

Ratu Tri

Putri 0 0 0 1 0 0 0 1 0 1 0 0 1 0 0 1 1 1 1 0 0 0 1 0 0 1 0 1 0 1 1

Irsandi0 0 1 0 0 1 1 0 0 1 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 1 0 0 1

Malikal Mulki0 1 1 0 1 1 0 0 0 1 0 0 0 1 0 1 1 0 0 0 0 1 0 0 0 1 1 1 0 0 1

Sri wahyuni0 0 1 0 0 1 1 0 0 1 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 1 0 0 1

4

Rahmi

Fajriani 0 0 1 0 0 1 1 0 0 1 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 1 0 0 1

Ruslianto0 0 1 1 0 0 1 0 0 1 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 1 0 0 1

6Fatmawati

0 1 1 0 0 0 0 0 0 1 1 0 0 0 1 0 1 0 1 0 0 0 1 0 0 1 1 1 0 1 1

Midayini0 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 1 0 1 0 0 0 1 0 0 1 1 1 0 1 1

8Hikmawati

0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 1 1 1 1 0 1 1 0 0 0 0 1 1 1 1 1

9Astuti Bahar

0 0 0 0 0 0 0 0 1 1 1 0 0 0 1 0 1 0 1 0 0 0 1 0 0 1 1 1 0 1 1

0Yuliana

0 0 0 1 1 0 0 0 0 0 0 1 0 0 0 0 1 0 1 0 0 0 1 0 0 1 1 1 0 1 1

X 5 19 18 6 10 13 17 10 3 27 18 6 20 4 3 24 22 16 27 1 5 19 14 10 16 18 23 25 5 2044

Mp18.4

15.63

15.22

13.17

1615.69

15.7

14.5

1214.6

14.94

12.33

10.17

18.85

1315.36

14.91

14.69

14.33

13 1414.79

14.57

1714.56

14.94

14.13

1417.4

14.85

Mt

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

14

.1

3

SD

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

1.

03

P0.17

0.63

0.6

0.2

0.33

0.43

0.57

0.33

0.1

0.9

0.6

0.2

0.67

0.13

0.1

0.8

0.73

0.53

0.9

0.03

0.17

0.63

0.47

0.33

0.53

0.6

0.77

0.83

0.17

0.67

Q0.83

0.37

0.4

0.8

0.67

0.57

0.43

0.67

0.9

0.1

0.4

0.8

0.33

0.87

0.9

0.2

0.27

0.47

0.1

0.97

0.83

0.37

0.53

0.67

0.47

0.4

0.23

0.17

0.83

0.33

Rpbi1.87

1.92

1.22

-0.47

1.27

1.31

1.75

0.25

-0.68

1.41

0.96

-036

-5.47

1.79

-0.36

2.38

1.25

0.61

0.57

-0.2

-0.03

0.83

0.4

1.95

0.45

0.96

0-0.29

1.43

0.99

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1. Determining the proportion of

testees correctly answering the

analyzed item:

1) p1= x = 5 = 0.17

N 30

2) p2= x = 19 =0.63

N 30

3) p3= x = 18 = 0.60

N 30

4) p4= x = 6 = 0.20

N 30

5) p5= x = 10 = 0.33

N 30

6) p6= x = 13 = 0.43N 30

7) p7= x = 17 = 0.57

N 30

8) p8= x = 10= 0.33

N 30

9) p9= x = 3 = 0.10

N 30

10)p10= x = 27 = 0.90

N 30

11)p11= x = 18 = 0.60

N 30

12)p12= x = 6 = 0.20

N 30

13)p13= x = 20 = 0.67

N 30

14)p14= x = 4 = 0.13

N 30

15)p15= x = 3 = 0.1

N 30

16)p16= x = 24 = 0.8

N 30

17)p17= x = 22 =0.73

N 30

18)p18= x = 16 = 0.53

N 30

19)p19= x = 27 = 0.9

N 30

20)p20= x = 1 = 0.03

N 30

21)p21= x = 5 = 0.17N 30

22)p22= x = 19 = 0.63

N 30

23)p23= x = 14= 0.47

N 30

24)p24= x = 10 = 0.33

N 30

25)P25= x = 16 = 0.53

N 30

26)p26= x = 18 = 0.6

N 30

27)p27= x = 23 = 0.77

N 30

28)p28= x = 25 = 0.83

N 30

29)p29= x = 5 = 0.17

N 30

30)p30= x = 20 = 0.67

N 30

4


29/60

1. determining the proportion of

testees incorrectly answer the

analyzed item;

1) q1 = 1 - p1 = 1 0.17=

0.83

2) q2 = 1 p2 = 1 0.63=

0.37

3) q3 = 1 p3 = 1 0.6= 0.4

4) q4 = 1 p4 = 1 0.2= 0.8

5) q5 = 1 p5 = 1 0.33=

0.67

6) q6 = 1 p6 = 1 0.43=

0.57

7) q7 = 1 p7 = 1 0.57=

0.43

8) q8 = 1 p8 = 1 0.33=

0.67

9) q9 = 1 p9 = 1 0.1= 0.9

10)q10 = 1 p10 = 1 0.9=

0.1

11)q11 = 1 p11 = 1 0.6=

0.4

12)q12 = 1 p12 = 1 0.2=

0.8

13)q13 = 1 p13 = 1 0.67=

0.3314)q14 = 1 p14 = 1 0.13=

0.87

15)q15 = 1 p15 = 1 0.1=

0.9

16)q16 = 1 p16 = 1 0.8=

0.2

17)q17 = 1 p17 = 1 0.73=

0.27

18)q18 = 1 p18 = 1 0.53=0.47

19)q19 = 1 p19 = 1 0.9=

0.1

20)q20 = 1 p20 = 1 0.03=

0.97

21)q21 = 1 p21 = 1 0.17=

0.83

22)q22 = 1 p22 = 1 0.63=

0.37

23)q23 = 1 p23 = 1 0.47=

0.53

5


30/60

24)q24 = 1 p24 = 1 0.33=

0.67

25)q25 = 1 p25 = 1 0.53=

0.47

26)q26 = 1 p26 = 1 0.6 =

0.4

27)q27 = 1 p27 = 1 0.77=

0.23

28)q28 = 1 p28 = 1 0.83=

0.17

29)q29 = 1 p29 = 1 0.17=

0.83

30)q30 = 1 p30 = 1 0.67=

0.33

6


31/60

1. Calculating the mean score of the total score:

Mt = 424 = 14.13

30

2. Calculating the mean score of testees correctly answering the analyzed

item:

1. Mp1 = 21+21+21+17+125

= 18.4

2. Mp2 =21+21+21+17+17+17+17+16+16+16+16+15+13+13+13+12+12+1

2+1219

= 15.63

3. Mp3 =21+21+21+17+17+17+16+16+16+14+13+13+12+12+12+12+12+1

218

= 15.22

4. Mp4 = 17+15+13+12+12+106

= 13.17

5. Mp5 = 21+21+21+17+16+15+14+13+12+1010

= 16

6. Mp6 = 21+21+21+17+17+16+16+15+12+12+12+12+1213

= 15.69

7. Mp7 =21+21+21+17+17+17+17+16+16+16+15+13+12+12+12+12+1217

= 15.7

8. Mp8 = 17+17+16+16+15+14+13+13+12+1210

= 14.5

7


32/60

9. Mp9 = 13+12+113

= 12

10. Mp10 =21+21+21+17+17+17+17+16+16+16+16+15+14+13+13+13+12+

12+12+12+12+12+12+12+12+12+1127

= 14.6

11. Mp11 =21+21+21+17+17+17+16+16+14+13+13+12+12+12+12+12+12+1

118

= 14.94

12. Mp12 = 16+13+12+12+11+106

= 12.33

13. Mp13 =21+21+21+17+17+17+17+16+16+16+15+13+13+13+12+12+12+12+12+122

0

= 10.17

14. Mp14 = 21+21+21+124

= 18.75

15. Mp15 = 16+12+113

= 13

16. Mp16 =21+21+21+17+17+17+17+16+16+16+16+15+14+13+13+12+12+1

2+12+12+12+12+12+12+1124

= 15.36

17. Mp17 =21+21+21+17+17+17+17+16+16+16+16+14+13+13+13+12+12+1

2+12+11+11+1022

= 14.91

8


33/60

18. Mp18 =

21+17+17+17+17+16+16+15+13+13+13+13+12+12+12+1116

= 14.69

19. Mp19 =21+21+21+17+17+17+17+16+16+16+15+14+13+13+13+12+12+

12+12+12+12+12+12+12+11+11+1010

= 14.33

20. Mp20 = 131

= 13

21. Mp21 = 17+16+14+12+115

= 14

22. Mp22 =21+21+21+17+17+17+16+16+13+13+13+13+12+12+12+12+12+1

2+1119

= 14.79

23. Mp23 = 21+17+17+17+16+16+16+14+13+12+12+12+11+1014

= 14.57

24. Mp24 = 21+21+17+17+17+16+16+16+16+1310

= 17

25. Mp25 = 21+17+17+17+16+16+16+15+13+13+12+12+12+12+12+1216

= 14.56

26. Mp26 =21+21+21+17+17+16+16+16+15+14+13+13+12+12+12+12+11+

1018

= 14.94

9


34/60

27. Mp27 =21+21+17+17+17+16+16+16+16+14+13+13+12+12+12+12+12+

12+12+12+11+11+1023

= 14.13

28. Mp28 =21+21+21+17+17+16+16+15+14+13+13+13+13+12+12+12+12+

12+12+12+12+12+11+11+1025

= 14

29. Mp29 = 21+21+21+13+115

= 17.4

30. Mp30 =21+21+21+17+17+17+16+16+16+15+14+13+13+12+12+12+12+

11+11+1020

= 14.85

5. Calculating the standard deviation of the total score SD: 1.03

d2

= 31.834

SD = 31.834

30

= 1.06113

SD = 1.03

10


35/60

11


36/60

6. Calculating the rpbi

rpbi = Mp-MtSDpq

rpb1 = 18.4-14.131.030.170.83

= 4.15 x 0.45

= 1.87

rpb2 = 15.63-14.131.030.630.37

= 1.47 x 1.3

= 1.92

rpb3 = 15.22-14.131.030.60.4

= 1.06 x 0.45

= 1.22

rpb4 = 13.17-14.131.030.20.8

= -0.93 x 0.5

= -0.47

rpb5 = 16-14.131.030.330.67

= 1.82 x 0.7

= 1.27

rpb6 = 15.69-14.131.030.430.57= 1.51 x 0.87

= 1.31

rpb7 = 15.7-14.131.030.570.43

= 1.52 x 1.15

= 1.75

rpb8 = 14.5-14.131.030.330.67

= 0.36 x 0.7

= 0.25

rpb9 = 12-14.131.030.10.9

= -2.07 x 0.33

= -0.68

rpb10 = 14.6-14.131.030.90.1

= 0.47 x 3

= 1.41

rpb11 = 14.94-14.131.030.60.4

= 0.79 x 1.22

= 0.96

rpb12 = 12.33-14.131.030.20.8

= -0.75 x 0.5

= -0.36

rpb13 = 10.17-14.131.030.670.33

= -3.85 x 1.42

= -5.47

rpb14 = 18.85-14.131.030.130.87

= 4.58 x 0.39

= 1.79

rpb15 = 13-14.131.030.10.9

= -1.1 x 0.33

= -0.36

rpb16 = 15.36-14.131.030.80.2

= 1.19 x 2

= 2.38

rpb17 = 14.91-14.131.030.730.27

= 0.76 x 1.65

= 1.25

rpb18 = 14.69-14.131.030.530.47

= 0.54 x 1.13

= 0.61

rpb19 = 14.33-14.131.030.90.1

= 0.19 x 3

= 0.57

12


37/60

rpb20 = 13-14.131.030.030.97

= -1.1 x 0.18

= -0.2

rpb21 = 14-14.131.030.170.83

= -0.13 x 0.2

= -0.03

rpb22 = 14.79-14.131.030.630.37

= 0.64 x 1.3

= 0.83

rpb23 = 14.57-14.131.030.470.53

= 0.43 x 0.94

= 0.4

rpb24 = 17-14.131.030.330.67

= 2.79 x 0.7

= 1.95

rpb25 = 14.56-14.131.030.530.47

= 0.42 x 1.06

= 0.45

rpb26 = 14.94-14.131.030.60.4

= 0.79 x 1.22

= 0.96

rpb27 = 14.13-14.131.030.770.23

= 0 x 1.83

= 0

rpb28 = 14-14.131.030.830.17

= -0.13 x 2.21

= -0.29

rpb29 = 17.4-14.131.030.170.83

= 3.17 x 0.45

= 1.43

rpb30 = 14.85-14.131.030.670.33

= 0.7 x 1.42

= 0.99

13


38/60

H. ITEM ANALYSIS

1. Item difficulty

TesteesTest Item

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 X

Rini Rustia

Nur 1 1 1 0 1 1 1 0 0 1 1 0 1 1 0 1 1 0 1 0 0 1 0 1 1 1 1 1 1 1 2

Qariatul

Wahyuni 1 1 1 0 1 1 1 0 0 1 1 0 1 1 0 1 1 1 1 0 0 1 1 1 0 1 0 1 1 1 2

Fitriani1 1 1 0 1 1 1 0 0 1 1 0 1 1 0 1 1 0 1 0 0 1 0 0 0 1 1 1 1 1 2

Susilawati0 1 1 0 0 0 1 0 0 1 1 0 1 0 0 1 1 1 1 0 0 1 1 1 1 1 1 0 0 1 1

Khairunnisa0 1 1 0 0 1 1 0 0 1 1 0 1 0 0 1 1 1 1 0 0 0 1 1 1 1 1 0 0 1 1

Rahmi0 1 0 0 0 1 1 1 0 1 1 0 1 0 0 1 1 1 1 0 1 1 0 1 1 0 1 1 0 0 1

Nur Yusri

Hidaya 1 1 1 1 1 0 1 1 0 1 0 0 1 0 0 1 1 1 1 0 0 1 1 0 0 0 0 1 0 1 1

Nurhana

Ayunita 0 1 1 0 0 0 1 0 0 1 1 0 1 0 0 1 1 1 1 0 0 0 1 1 1 1 1 0 0 1 1

Aisyah0 1 0 0 0 1 1 1 0 1 0 1 1 0 0 1 1 0 1 0 1 1 0 1 1 0 1 1 0 0 1

0

Risnawati

Rahman 0 1 1 0 1 1 0 1 0 1 0 0 0 0 1 1 1 0 0 0 0 1 1 1 0 1 1 1 0 1 1

Rosmita 0 1 1 0 0 0 1 0 0 1 1 0 1 0 0 1 1 1 1 0 0 0 1 1 1 1 1 0 0 1 1

Tenriani0 1 0 1 1 1 1 1 0 1 0 0 1 0 0 1 0 1 1 0 0 0 0 0 1 1 0 1 0 1 1

Nurul

Mujriah 0 0 1 0 1 0 0 1 0 1 1 0 0 0 0 1 1 0 1 0 1 0 1 0 0 1 1 1 0 1 1

4Nasrianti

0 1 0 0 1 0 0 1 0 0 1 1 0 0 0 0 0 1 0 1 0 1 0 1 1 1 0 1 0 1 1

Nur Insyana0 0 0 1 0 0 0 1 1 1 0 0 1 0 0 1 1 1 1 0 0 1 1 0 0 0 0 1 0 1 1

6

St. Umrah

Syarih 0 1 1 0 0 0 0 0 0 1 1 0 1 0 0 0 1 1 1 0 0 1 0 0 0 1 1 1 1 0 1

Murniati0 1 1 0 0 0 1 0 0 1 0 0 1 0 0 1 1 1 1 0 0 1 0 0 1 0 1 1 0 0 1

14


39/60

8

St.

Nurintang 1 1 0 0 0 1 0 1 0 1 0 1 0 0 0 1 0 1 1 0 1 0 0 0 1 0 0 0 0 1 1

9Sakinah

0 1 0 0 0 0 1 0 0 1 0 1 1 0 0 1 0 1 1 0 0 1 0 0 1 0 1 1 0 0 1

0

Ratu Tri

Putri 0 0 0 1 0 0 0 1 0 1 0 0 1 0 0 1 1 1 1 0 0 0 1 0 0 1 0 1 0 1 1

Irsandi0 0 1 0 0 1 1 0 0 1 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 1 0 0 1

Malikal Mulki0 1 1 0 1 1 0 0 0 1 0 0 0 1 0 1 1 0 0 0 0 1 0 0 0 1 1 1 0 0 1

Sri wahyuni

0 0 1 0 0 1 1 0 0 1 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 1 0 0 1

4

Rahmi

Fajriani 0 0 1 0 0 1 1 0 0 1 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 1 0 0 1

Ruslianto0 0 1 1 0 0 1 0 0 1 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 1 0 0 1

6Fatmawati

0 1 1 0 0 0 0 0 0 1 1 0 0 0 1 0 1 0 1 0 0 0 1 0 0 1 1 1 0 1 1

Midayini0 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 1 0 1 0 0 0 1 0 0 1 1 1 0 1 1

8Hikmawati

0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 1 1 1 1 0 1 1 0 0 0 0 1 1 1 1 1

9Astuti Bahar

0 0 0 0 0 0 0 0 1 1 1 0 0 0 1 0 1 0 1 0 0 0 1 0 0 1 1 1 0 1 1

0Yuliana

0 0 0 1 1 0 0 0 0 0 0 1 0 0 0 0 1 0 1 0 0 0 1 0 0 1 1 1 0 1 1

UG 4 13 10 3 8 8 11 8 1 14 10 2 12 3 1 14 13 10 13 1 3 10 9 10 9 11 10 11 3 1328

LG1 6 8 3 2 5 6 2 2 13 8 4 8 1 3 10 9 6 14 0 2 9 5 0 7 7 13 14 2 7

17

LG =

UG =

IF = UG + L G ID = UG + LGN n

15


40/60

IF 1 = 1 + 430

= 530

= 0.17 = 17%The item is difficult

IF 2 = 1 3 + 630

= 1930

= 0.63 = 63%The item is desirable

IF 3 = 1 0 + 830

= 1830


IF 4 = 3 + 330

= 630


IF 5 = 8 + 230

= 1030


IF 6 = 8 + 530

= 1330


IF 7 = 1 1 + 630

= 1730


IF 8 = 8 + 230

= 1030


IF 9 = 1 + 2

30= 3

30= 0.1 = 10%

The item is difficult

IF 10 = 1 4 + 1330

= 2730

= 0.9 = 90%The item is easy

IF 11 = 1 0 + 830

= 1830


IF 12 = 2 + 430

= 630


IF 13 = 1 2 + 830

= 2030


IF 14 = 3 + 130

= 430


IF 15 = 1 + 330

= 430

16


41/60


IF 16 = 1 4 + 1030

= 24

30= 0.8 = 80%

The item is easy

IF 17 = 1 3 + 930

= 2230


IF 18 = 1 0 + 6

30= 16

30= 0.53 = 53%

The item is desirable

IF 19 = 1 3 + 1 430

= 2730


IF 20 = 1 + 030

= 130


IF21 = 3 + 230

= 530


IF 22 = 1 0 + 930

= 1930


IF 23 = 9 + 530

= 1430

= 0.47 = 47%


IF 24 = 1 0 + 030

= 1030


IF 25 = 9 + 730

= 16

30= 0.53 = 53%


IF 26 = 1 1 + 730

= 1830

= 0.6= 60%The item is desirable

IF 27 = 1 0 + 1330

= 2330


IF 28 = 1 1 + 1 430

= 2 530


IF 29 = 3 + 230

= 530


IF 30 = 13 + 7

17


42/60

30= 20

30= 0.67 = 67%


2. Item Discrimination

ID 1 = 1 - 415

= -315

= -0.2

ID 2 = 13 - 615

= 715

= 0.47

ID 3 = 10 - 815

= 215

= 0.13

ID 4 = 3 - 315

= 015

= 0

ID 5 = 8 - 215

= 615

= 0.4

ID 6 = 8 - 515

= 315

= 0.2

ID 7 = 1 1 - 615

= 515

= 0.33

ID 8 = 8 - 215

= 615

= 0.4

ID 9 = 1 - 215

= -115

= -0.07

ID 10 = 1 4 1315

= 115

= 0.07

ID 11 = 1 0 - 815

= 215

= 0.13

ID 12 = 2 - 415

= -215

= -0.13

ID 13 = 1 2 - 815

= 415

= 0.27

ID 14 = 3 - 115

= 215

= 0.13

ID 15 = 1 - 315

= -215

= -0.13

18


43/60

ID 16 = 14 - 1015

= 415

= 0.27

ID 17 = 13 - 915

= 415

= 0.27

ID 18 = 10 - 615

= 415

= 0.13

ID 19 = 13 - 1415

= -115

= -0.07

ID 20 = 1 - 015

= 115

= 0.07

ID 21 = 3 - 215

= 115

= 0.07

ID 22 = 1 0 - 915

= 115

= 0.07

ID 23 = 9 515

= 415

= 0.27

ID 24 = 10 - 015

= 1015

= 0.67

ID 25 = 9 - 715

= 215

= 0.13

ID 26 = 1 1 - 715

= 415

= 0.27

ID 27 = 10 1315

= -315

= -0.2

ID 28 = 11 - 1415

= -315

= -0.2

ID 29 = 3 - 215

= 115

= 0.07

19


44/60

ID 30 = 13 - 715

= 615

= 0.27

Table 7: The Indices of facility and Discrimination

20


45/60

21

Item UG LG IF ID Remark

1 4 1 0.17 -0.20 Improper

2 13 6 0.63 0.47 Proper

3 10 8 0.60 0.13 Improper4 3 3 0.20 0.00 Improper

5 8 2 0.33 0.40 proper

6 8 5 0.43 0.20 Improper

7 11 6 0.57 0.33 Improper

8 8 2 0.33 0.40 proper

9 1 2 0.10 -0.07 Improper

10 14 13 0.90 0.07 Improper

11 10 8 0.60 0.13 Improper

12 2 4 0.20 -0.13 Improper

13 12 8 0.67 0.27 proper

14 3 1 0.13 0.13 Improper

15 1 3 0.13 -0.13 Improper

16 14 10 0.80 0.27 proper

17 13 9 0.73 0.27 proper

18 10 6 0.53 0.13 Improper

19 13 14 0.90 -0.07 Improper

20 1 0 0.03 0.07 Improper

21 3 2 0.17 0.07 Improper

22 10 9 0.63 0.07 Improper

23 9 5 0.40 0.27 Improper

24 10 0 0.33 0.67 Proper

25 9 7 0.53 0.13 Improper

26 11 7 0.60 0.27 proper

27 10 13 0.77 -0.20 Improper

28 11 14 0.83 -0.20 Improper


46/60

22


47/60

3. Full Item Analysis

1 UG LG UG + LGA* 4 2 6B 3 2 5C 6 10 16D 2 1 3O 0 0 0

Total 15 15 30

IF=UG+LGN=430=0,13

ID=UG-LGN=230=0,07

2 UG LG UG + LGA 1 4 5

B 1 4 5C* 13 7 20D 0 0 0O 0 0 0

Total 15 15 30

IF=UG+LGN=2030=0,67

ID=UG-LGN=630=0,2

3 UG LG UG + LGA 3 5 8B 2 1 3C* 10 9 19D 0 0 0O 0 0 0

Total 15 15 30

IF=UG+LGN=1930=0,63

ID=UG-LGN=130=0,03

4 UG LG UG + LGA 1 4 5B* 3 2 5C 7 6 13D 4 3 7

23


48/60

O 0 0 0Total 15 15 30

IF=UG+LGN=530=0,17

ID=UG-LGN=130=0,03

5 UG LG UG + LGA 1 3 4B* 8 2 10C 6 9 15D 0 1 1O 0 0 0

Total 15 15 30

IF=UG+LGN=1030=0,33

ID=UG-LGN=630=0,2

6 UG LG UG + LGA 0 3 3B 7 6 13C* 8 6 14D 0 0 0

O 0 0 0Total 15 15 30

IF=UG+LGN=1430=0,47

ID=UG-LGN=230=0,07

7 UG LG UG + LGA 3 6 9B 1 1 2C 0 0 0

D* 11 7 18O 0 1 1Total 15 15 30

IF=UG+LGN=1730=0,57

ID=UG-LGN=430=0,13

24


49/60

8 UG LG UG + LGA 0 4 4B 4 2 6C 2 6 8

D* 8 3 11O 1 0 1

Total 15 15 30

IF=UG+LGN=1130=0,37

ID=UG-LGN=530=0,17

9 UG LG UG + LG

A 5 3 8B 7 6 13C 2 3 5D* 1 3 4O 0 0 0

Total 15 15 30

IF=UG+LGN=430=0,13

ID=UG-LGN=-230=0,07

10 UG LG UG + LGA 0 0 0B* 14 15 29C 1 0 1D 0 0 0O 0 0 0

Total 15 15 30

IF=UG+LGN=2930=0,97

ID=UG-LGN=-130=-0,03

11 UG LG UG + LGA 1 0 1B* 10 11 21C 1 1 2

25


50/60

D 3 3 6O 0 0 0

Total 15 15 30

IF=UG+LGN=2130=0,7

ID=UG-LGN=-130=-0,03

12 UG LG UG + LGA* 2 2 4B 13 13 26C 0 0 0D 0 0 0O 0 0 0

Total 15 15 30

IF=UG+LGN=430=0,13

ID=UG-LGN=030=0

13 UG LG UG + LGA* 12 8 20B 0 1 1C 3 6 9

D 0 0 0O 0 0 0Total 15 15 30

IF=UG+LGN=2030=0,67

ID=UG-LGN=430=0,13

14 UG LG UG + LGA 0 0 0

B* 3 1 4C 5 0 5D 7 14 21O 0 0 0

Total 15 15 30

IF=UG+LGN=430=0,13

26


51/60

ID=UG-LGN=230=0,07

15 UG LG UG + LGA 10 8 18

B 4 2 6C* 1 5 6D 0 0 0O 0 0 0

Total 15 15 30

IF=UG+LGN=630=0,2

ID=UG-LGN=-430=-0,13

16 UG LG UG + LGA 0 0 0B 0 5 5C* 14 10 24D 1 0 1O 0 0 0

Total 15 15 30

IF=UG+LGN=2430=0,8

ID=UG-LGN=430=0,13

17 UG LG UG + LGA* 13 9 22B 1 0 1C 1 5 6D 0 0 0O 0 1 1

Total 15 15 30

IF=UG+LGN=2230=0,73

ID=UG-LGN=430=0,13

18 UG LG UG + LGA 0 4 4

27


52/60


53/60

IF=UG+LGN=530=0,17

ID=UG-LGN=130=0,03

22 UG LG UG + LGA 0 0 0B 0 1 1C 5 5 10D* 10 9 19O 0 0 0

Total 15 15 30

IF=UG+LGN=1930=0,63

ID=UG-LGN=130=0,03

23 UG LG UG + LGA* 8 5 13B 2 8 10C 5 1 6D 0 1 1O 0 0 0

Total 15 15 30

IF=UG+LGN=1330=0,43

ID=UG-LGN=330=0,1

24 UG LG UG + LGA* 9 0 9B 5 7 12C 1 4 5D 0 4 4O 0 0 0

Total 15 15 30

IF=UG+LGN=930=0,3

ID=UG-LGN=930=0,3

29


54/60

25 UG LG UG + LGA 2 1 3B 2 2 4C* 10 8 18D 1 4 5O 0 0 0

Total 15 15 30

IF=UG+LGN=1830=0,6

ID=UG-LGN=230=0,07

26 UG LG UG + LGA 0 0 0B 2 6 8

C 2 1 3D* 11 8 19O 0 0 0

Total 15 15 30

IF=UG+LGN=1930=0,63

ID=UG-LGN=330=0,1

27 UG LG UG + LG

A 1 1 2B 4 1 5C* 10 13 23D 0 0 0O 0 0 0

Total 15 15 30

IF=UG+LGN=2330=0,77

ID=UG-LGN=-330=-0,1

28 UG LG UG + LGA 4 0 4B* 11 14 25C 0 0 0D 0 1 1O 0 0 0

Total 15 15 30

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IF=UG+LGN=2530=0,83

ID=UG-LGN=-330=0,1

29 UG LG UG + LGA* 3 2 5B 4 2 6C 1 0 1D 7 11 18O 0 0 0

Total 15 15 30

IF=UG+LGN=530=0,17

ID=UG-LGN=130=0,03

30 UG LG UG + LGA 0 1 1B* 13 7 20C 0 0 0D 2 7 9O 0 0 0

Total 15 15 30

IF=UG+LGN=2030=0,67

ID=UG-LGN=630=0,2

CHAPTER IV

CONCLUSION

Based on the result of analysis items had explained above, we can conclude that it must

be consider using the test in the real test. The result shows that the contents of test were lack bothin reliability and validity. The result of reliability analysis shows the score 0.25, based on the

theory the score is in the category not reliable or unreliable. The result of validity analysis also

out of valid category, most items was invalid. Then about the full item analysis, in terms of

difficulty, discriminant, and full items, the analysis show that most of items were desirable for

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students. In the item of discriminant, the item of the try out is lack on property, exactly only ten

items which is proper.

Besides that, as the main objective of the test is want to test the six point of language

skills such as listening, reading, writing, speaking, vocabulary, grammar. But the result showsthat most of students had lacked on all the skills and area to be known and understand. Whereas

we know that it is important to make student success in all English skills and areas. The result of

the test the highest score is 21 and score 10 as the lowest score.

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Item Answer Validity

(rpb)

IF ID Remark

1 A 1.87 0.17 -0.20 ---

2 C 1.92 0.63 0.47 -++

3 C 1.22 0.60 0.13 -+-

4 B -0.47 0.20 0.00 ---

5 B 1.27 0.33 0.40 -++

6 C 1.31 0.43 0.20 -+-

7 D 1.75 0.57 0.33 -++

8 D 0.25 0.33 0.40 -++

9 D -0.68 0.10 -0.07 ---

10 B 1.41 0.90 0.07 ---

11 B 0.96 0.60 0.13 ++-

12 A -0.36 0.20 -0.13 ---

13 A -5.47 0.67 0.27 -++

14 B 1.79 0.13 0.13 ---

15 C -0.36 0.13 -0.13 ---

16 C 2.38 0.80 0.27 --+

17 A 1.25 0.73 0.27 -++

18 B 0.61 0.53 0.13 ++-

19 B 0.57 0.90 -0.07 +--

20 C -0.2 0.03 0.07 ---

21 A -0.03 0.17 0.07 ---

22 D 0.83 0.63 0.07 -+-

23 A 0.4 0.40 0.27 +++

24 A 1.95 0.33 0.67 -++

25 C 0.45 0.53 0.13 ++-

26 D 0.96 0.60 0.27 -++

27 C 0 0.77 -0.20 ---


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try out for the second grade student print

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