tugas mtk2
DESCRIPTION
tugas matematika teknik 2 by irawanTRANSCRIPT
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Tugas Matematika Teknik Kimia II
Ahmad Irawan 122013001
9/16/15 Tugas MTK II
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1. Find The reaction constant and reaction order Ir the rection equation −r A=K CA
n
Jawab:
Waktu (s)Konsentrasi
(mol/L) - rA Log Ca (x) Log rA (y) x^2 xy0 10 0,1256 1 -0,90101 1 -0,90101
20 8 0,0919 0,903089987 -1,03668 0,815571525 -0,9362240 6 0,0614 0,77815125 -1,21183 0,605519368 -0,9429960 5 0,0476 0,698970004 -1,32239 0,488559067 -0,92431
120 3 0,0233 0,477121255 -1,63264 0,227644692 -0,77897180 2 0,0132 0,301029996 -1,87943 0,090619058 -0,56576300 1 0,005 0 -2,30103 0 0
Total 4,158362492 -10,285 3,22791371 -5,04926
Mencari Nilai a dan b
a=∑ x∑ y−N∑ xy¿¿¿
b=∑ x∑ xy−∑ y∑ x2
¿¿¿
¿−2,300872335
y=ax+b
y=1,4 x+2,3
log−r A=log k+n logC A
log−r A=1,4 logC A+2,3 jadi, nilai n dan k adalahn=2,3k=101,4=25,1188
0 0.2 0.4 0.6 0.8 1 1.2
-2.5
-2
-1.5
-1
-0.5
0
Log Ca
Log
rA
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Gambar 1. Grafik Persamaan ReaksiIsoterm Langmuir
No. C0 Ce 1/Ce = x Qs Data 1/qS = y x^2 xy
1 5 0,56 1,785714
0,299106
3,3432944
3,1887745
5,970168
2 10 0,76 1,315789
0,576964
1,7332105
1,7313007
2,280539
3 15 0,91 1,098901
1,010004
0,9900949
1,2075834
1,088016
TOTAL 4,200404
6,0665969
6,1276586
9,338719
Mencari Nilai a dan b
a=∑ x∑ y−N∑ xy¿¿¿
b=∑ x∑ xy−∑ y∑ x2
¿¿¿
¿−2,77502
y=3,426258 x−2,77502atau 1qs
=3,426258C e
+2,77502
1qmaks
=2,77502makaqmaks=−0,36036
1qmaks b
=3,426258maka b=−0,80993
qs Data 1/qs (model) qs model % kesalahan (%)
0,2991062 3,343294402 0,29910617 1,8559E-14
0,576964 1,733210535 0,57696395 5,77275E-14
1,0100042 0,990094904 1,01000419 4,3969E-14
Kesalahan Rata-rata 4,00852E-14
Mencari 1/qs (model) menggunakan rumus 1qs
=3,426258C e
+2,77502 nilai Ce disubtitusikan ke
dalam persamaan tersebut.
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Mencari nilai qsmodel=
1
( 1qs ) % kesalahan
qsdata−qsmodelqsdata
×100%
1 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.90
0.5
1
1.5
2
2.5
3
3.5
4
Langmuir
1/Ce
1/qs
Gambar 2. Grafik Isoterm Langmuir
Isoterm FreundlichNo
. C0 Ce qs Data % Efisiensi Penyerapan Log Ce = x Log qs =
y x^2 xy
1 5 0,56 0,296 88.8% -0,251812 -0,52871 0,063409 0,133135
2 10 0,76 0,616 92.4% -0,119186 -0,21042 0,014205 0,025079
3 15 0,91 0,939333 93.93% -0,040959 -0,02718 0,001678 0,001113
TOTAL -0,411957 -0,76631 0,079292 0,159327
Mencari Nilai a dan b
a=∑ x∑ y−N∑ xy¿¿¿
b=∑ x∑ xy−∑ y∑ x2
¿¿¿
¿0,071490836
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qs=K f CS1/n
log qs=logK f+( 1n ) logC sy=ax+b
y=2,380788605 x+0,071490836
log qs=2,380788605 logC s+0,071490836
Sehingga diperoleh harga (1/n) dan Kf sebagai berikut:
( 1n )=2,380788605danK f=100,071490836=1,178937646
qs Data qs model % Kesalahan (%)0,296 0,296469254 -0,158531739
0,616 0,613384994 0,424513887
0,939333 0,941839788 -0,266868935
kesalahan rata-rata -0,000295596
Untuk mencari nilai qs model menggunakan persamaan qs=K f CS1/n dengan mensubtitusikan
nilai 1/n dan Kf
Untuk mendapatkan % kesalahan menggunakan rumus % kesalahanqsdata−qsmodel
qsdata×100%
-0.3 -0.25 -0.2 -0.15 -0.1 -0.05 0
-0.6
-0.5
-0.4
-0.3
-0.2
-0.1
0
Freundlich
Log Ce
Log
qs
Gambar 3. Grafik Isoterm Freundlich
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