tutormansor wordpress com latihan matematik tingkatan 4 04 mathematic reasoning answer
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ANSWER / JAWAPAN
CHAPTER 04 MATHEMATICAL REASONING (MATHEMATICS FORM 4)
BAB 04 PENAKLUKAN MATEMATIK (MATEMATIK TINGKATAN 4)
HAK CIPTA TERPELIHARA MAY 2013
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Latihan Matematik Tingkatan 4
Exercise Mathemtics Form 4
Bab 04 MATHEMATICAL REASONING
Chapter 04 PENAALUKAN MATEMATIK
JAWAPAN / ANSWER
Question: http://goo.gl/Ny39Z
EXERCISE 1
1. _
(a) TRUE
(b) If is a multiple of 3, then x divisible by 3 / Sekiranya x adalah gandaan 3, maka x boleh dibahagi dengan 3.
If x is divisible by 3, then x is a multiple of 3 / Sekiranya x boleh dibahagi dengan 3, maka x
adalah gandaan 3.
(c) Premise 2: y is less than zero / y lebih kecil daripada kosong.
2. _
(a) Statement / Kenyataan
(b) Conclusion / Konklusi : p is 4 cm / p adalah 4 cm
(c) 10+
3. _
(a) 52 = 10 1
4= 0.25
(b) Premise 2: x is an angle in a semicircle / x adalah sudut dalam sebuah separa bulatan.
(c) SOME / SEBAHAGIAN
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ANSWER / JAWAPAN
CHAPTER 04 MATHEMATICAL REASONING (MATHEMATICS FORM 4)
BAB 04 PENAKLUKAN MATEMATIK (MATEMATIK TINGKATAN 4)
HAK CIPTA TERPELIHARA MAY 2013
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4. _
(a) Some even numbers are divisible by 4 / Sebahagian nombor genap boleh dibahagi dengan 4
(b) _
(i) FALSE / SALAH
(ii) TRUE / BETUL
(c) Conclusion / Konklusi : 0
5. _
(a) STATEMENT because there has equal sign. Ignore the true or false.
KENYATAAN sebab ada symbol sama dengan. Abaikan betul atau salah.
(b) OR / ATAU
(c) Premise 1: A quadrilateral has 4 sides / Segi empat mempunyai 4 sisi.
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ANSWER / JAWAPAN
CHAPTER 04 MATHEMATICAL REASONING (MATHEMATICS FORM 4)
BAB 04 PENAKLUKAN MATEMATIK (MATEMATIK TINGKATAN 4)
HAK CIPTA TERPELIHARA MAY 2013
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3
EXERCISE 2
1. _
(a) Implication 1: If > , then > / Sekiranya > , maka > . Implication 2: If > , then > / Sekiranta > , maka > .
(b) _
(i) Some / Sebahagian
(ii) All / Semua
2. _
(a) _
i) Conclusion / Konklusi : 3.
ii) Premise 2: 2 is a factor of 4 / 2 adalah faktor bagi 4.
(b) OR / ATAU
3. _
(a) Conclusion / Konklusi : 2 1 where = 1, 2, 3, 4,
(b) Premise 1: Acute angle is less than 90 / Sudut akut kurang daripada 90.
4. _
(a) Implication 1: If tan = 1 then = 45 / Sekiranya tan = 1, maka = 45. Implication 2: If = 45, then tan = 1 / Sekiranya = 45, maka tan = 1.
(b) If 1 > 0, then < 0 / Sekiranya 1 > 0 maka < 0.
(c) TRUE / BETUL
5. _
(a) Concluison / Konklusi : n is an odd number / n adalah nombor ganjil.
(b) Premise 1 : Isosceles triangle has two sides of equal length. / Segitiga sama kaki mempunyai dua
sisi yang sama panjang.
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ANSWER / JAWAPAN
CHAPTER 04 MATHEMATICAL REASONING (MATHEMATICS FORM 4)
BAB 04 PENAKLUKAN MATEMATIK (MATEMATIK TINGKATAN 4)
HAK CIPTA TERPELIHARA MAY 2013
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4
(c) STATEMENT because there has equal sign.
KENYATAAN kerana mempunyai tanda sama dengan.
DIAGNOSTIC TEST
1. _
(a) _
i. NOT STATEMENT / BUKAN KENYATAAN
ii. STATEMENT / KENYATAAN
(b) _
i. >
ii. >
(c) ALL / SEMUA
(d) Conlusion / Konklusi: 5 has two factors / 5 mempunyai dua factor
2. _
(a) _
i. TRUE / BETUL
ii. FALSE / SALAH
(b) If = 0, then = 0 or = 0 / Sekiranya = 0, maka = 0 atau = 0. If = 0 or = 0, then = 0 / Sekiranya = 0 atau = 0, maka = 0.
(c) Premise 2 : The circumference of circle not 10. / Ukur lilit bulatan P bukan 10.
3. _
(a) Some of odd number are prime numbers. / Sebahagian nombor ganjil adalah nombor perdana.
(b) 3 + (2) = 5 or 16 is a perfect square.
(c) Premise 1: The sum of interior angles of pentagon is 540./ Hasil tambah sudut dalaman bagi pentagon ialah 540.
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ANSWER / JAWAPAN
CHAPTER 04 MATHEMATICAL REASONING (MATHEMATICS FORM 4)
BAB 04 PENAKLUKAN MATEMATIK (MATEMATIK TINGKATAN 4)
HAK CIPTA TERPELIHARA MAY 2013
https://tutormansor.wordpress.com/
5
4. _
(a) Antecedent: Triangle has two equal sides.
Consequent: It is an isosceles triangle.
(b) _
i. If < 6, then < 4. FALSE
ii. If , then = . TRUE
(c) 2 + 7 = 0, 1, 2,
(d) If = , then M is a subset to N.
5. _
(a) _
i. TRUE / BETUL
ii. FALSE / SALAH
(b) ALL / SEMUA
(c) Premise 1: A natural number is greater than zero.
(d) 2 is an odd number if and only if is an odd number.