using sum, difference, and double-angle identities
DESCRIPTION
Chapter 5 Trigonometric Equations. 5.5. Using Sum, Difference, and Double-Angle Identities. 5.5. 1. MATHPOWER TM 12, WESTERN EDITION. Sum and Difference Identities. sin( A + B ) = sin A cos B + cos A sin B sin( A - B ) = sin A cos B - cos A sin B - PowerPoint PPT PresentationTRANSCRIPT
MATHPOWERTM 12, WESTERN EDITION
5.5
5.5.1
Chapter 5 Trigonometric Equations
5.5.2
Sum and Difference Identities
sin(A + B) = sin A cos B + cos A sin B
sin(A - B) = sin A cos B - cos A sin B
cos(A + B) = cos A cos B - sin A sin B
cos(A - B) = cos A cos B + sin A sin B
tan(A B) tanA tanB
1 tan Atan B
tan(A B) tanA tanB
1 tan Atan B
5.5.3
Simplifying Trigonometric Expressions
Express cos 1000 cos 800 + sin 800 sin 1000 as a trig function of a single angle.
This function has the same pattern as cos (A - B),with A = 1000 and B = 800.
cos 100 cos 80 + sin 80 sin 100 = cos(1000 - 800) = cos 200
sin3
cos6
cos3
sin6Express as a single trig function.
This function has the same pattern as sin(A - B), with A
3
and B 6
.
sin3
cos6
cos3
sin6
sin3
6
sin6
1.
2.
5.5.4
Finding Exact Values
1. Find the exact value for sin 750.Think of the angle measures that produce exact values:300, 450, and 600.Use the sum and difference identities. Which angles, used in combination of addition or subtraction, would give a result of 750?
sin 750 = sin(300 + 450) = sin 300 cos 450 + cos 300 sin 450
1
2
2
2
3
2
2
2
2 6
4
5.5.5
Finding Exact Values
2. Find the exact value for cos 150.cos 150 = cos(450 - 300) = cos 450 cos 300 + sin 450 sin300
2
2
3
2
2
2
1
2
6 2
4
sin512
.3. Find the exact value for 3
412
4
312
6
212
sin512
sin(4
6
)
sin4
cos6
cos4
sin6
2
2
3
2
2
2
1
2
6 2
4
5.5.6
Using the Sum and Difference Identities
Prove cos2
sin.
cos
2
sin.
cos2
cos sin2
sin
(0)(cos) (1)(sin)
(1)(sin)
sin
sin
L.S. = R.S.
5.5.7
Using the Sum and Difference Identities
x = 3r = 5
r2 = x2 + y2
y2 = r2 - x2 = 52 - 32
= 16 y = ± 4
Given wherecos , ,
35
02
find the exact value of cos( ).
6
cos( ) cos cos sin sin
6 6 6
cos xr
( )( ) ( )( )35
32
45
12
3 3 4
10
Therefore, cos( ) .
6
3 3 410
5.5.8
Using the Sum and Difference Identities
xyr
A B
23
4
53
Given A and B
where A and B are acute angles
sin cos ,
,
2
3
4
5
find the exact value of A Bsin( ).
( )( ) ( )( )23
45
53
35
8 3 515
Therefore A B, sin( ) . 8 3 515
5sin( ) sin cos cos sinA B A B A B
5.5.9
Double-Angle Identities
sin 2A = sin (A + A)
= sin A cos A + cos A sin A
= 2 sin A cos A
cos 2A = cos (A + A)
= cos A cos A - sin A sin A
= cos2 A - sin2A
The identities for the sine and cosine of the sum of twonumbers can be used, when the two numbers A and Bare equal, to develop the identities for sin 2A and cos 2A.
Identities for sin 2x and cos 2x:
sin 2x = 2sin x cos x cos 2x = cos2x - sin2xcos 2x = 2cos2x - 1cos 2x = 1 - 2sin2x
5.5.10
Double-Angle Identities
Express each in terms of a single trig function.
a) 2 sin 0.45 cos 0.45
sin 2x = 2sin x cos xsin 2(0.45) = 2sin 0.45 cos 0.45 sin 0.9 = 2sin 0.45 cos 0.45
b) cos2 5 - sin2 5
cos 2x = cos2 x - sin2 x cos 2(5) = cos2 5 - sin2 5 cos 10 = cos2 5 - sin2 5
Find the value of cos 2x for x = 0.69.
cos 2x = cos2 x - sin2 xcos 2(0.69) = cos2 0.69 - sin2 0.69 cos 2x = 0.1896
A group of Friars opened a florist shop to help with their belfry payments. Everyone liked to buy flowers from the Men of God, so their business flourished. A rival florist became upset that his business was suffering because people felt compelled to buy from the Friars, so he asked the Friars to cut back hours or close down. The Friars refused. The florist went to them and begged that they shut down.
5.5.11
Double-Angle Identities
Verify the identity tan A
1 cos 2 A
sin 2A.
1 (cos2 A sin2 A)
2sin Acos A
1 cos2 A sin2 A)
2 sinAcos A
sin2 A sin2 A
2sin Acos A
2sin 2 A
2sin Acos A
sin A
cos A
tan A
tan A
L.S = R.S.
5.5.12
Double-Angle Identities
Verify the identity tan x
sin 2x
1 cos 2x.
2sin x cos x1 2 cos 2 x 1
2sin x cos x2cos2 x
sin xcos x
tan x
tan x
L.S = R.S.
5.5.13
Double-Angle Equations
Find A given cos 2A =
22
where 0 A 2.
y = cos 2A
2 A
A 8
,78
,98
,15
8
2
8
78
98
158 y
2
2
For cos A = 22
where 0 A 2, A
4
and 74
.
2 A 4
2n,74
2n.4
,74
,94
,15
4
5.5.14
Double-Angle Equations
Find A given sin 2A =-
12 where 0 A 2.
76
,
A 712
,1112
,1912
,2312
116
,19
6,
236
y = sin 2A
y 1
2712
1112
1912
2312
2 A
For sin A =-
12 where 0 A 2, A=
76
and11
6.
2 A 76
2n,11
6 2n.
Graph the function f (x) 2 tanx
1 tan2 x
Using Technology
and predict the period.
The period is
Rewrite f(x) as a single trig function: f(x) = sin 2x
5.5.15
Prove
2tanx
1 tan2 x sin2x .
Identities
2sin x
cos xsec 2 x
2sin x
cos x1
cos 2 x
2sin x
cos x
cos 2 x
1
2sin xcos x
2sin xcos x
L.S. = R.S.5.5.16
Applying Skills to Solve a Problem
The horizontal distance that a soccer ball will travel, when
kicked at an angle , is given by d 2v0
2
gsincos ,
where d is the horizontal distance in metres, v0 is the initialvelocity in metres per second, and g is the acceleration dueto gravity, which is 9.81 m/s2.
a) Rewrite the expression as a sine function.Use the identity sin 2A = 2sin A cos A:
d 2v0
2
gsincos
d v0
2
gsin2
5.5.17
b) Find the distance when the initial velocity is 20 m/s.
Applying Skills to Solve a Problem [cont’d]
d v0
2
gsin2
d (20)2
9.81sin2
Dis
tan
ce
Angle
From the graph, the maximumdistance occurs when = 0.785398.
The maximum distance is 40.7747 m.The graph of sin reaches itsmaximum when
2
.
Sin 2 will reach a maximum when
2
2
or 4
.
5.5.18
Suggested Questions:Pages 272-274A 1-16, 25-35 odd
B 17-24, 37-40, 43, 47, 48
5.5.19
Again they refused. So the florist then hired Hugh McTaggert, the biggest meanest thug in town. He went to the Friars' shop beat them up, destroyed their flowers, trashed their shop, and said that if they didn't close, he'd be back. Well, totally terrified, the Friars closed up shop and hid in their rooms. This proved that Hugh, and only Hugh, can prevent florist friars.