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  • 8/9/2019 Well Test Mod Sol

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    Model Solutions to Examination

    1

    Date:

    1. Complete the sections above but do not seal until the examination is finished.

    2. Insert in box on right the numbers of the questions attempted.

    3. Start each question on a new page.

    4. Rough work ing should be confined to lef t hand pages.

    5. This book  must be handed in entire with the top corner sealed.

    6. Additional book s must bear the name of the candidate, be sealed and be affixed to

    the first book  by means of a tag provided

    Sub ject:

    INSTRUCTIONS TO CANDIDATES

    8 Pages

    PLEASE READ EXAMINATION REGULATIONS ON BACK COVER

    No.  Mk.

    N   A  M   

    E  :   

    R  E  G  

    I    S    T   R  

    A  T   

    I    O  N    N   O  . :   

    C   O  U   

    R  S    E  

    :   

    Y   E  A  R  :   

    S    I    G  N   

    A  T   U   

    R  E  :   C   o  m  

     p  l   e  t   e   t   h  i   s   s  e  c  

    t   i   o  n   b  u  t    d   o   n  o  

    t   

    s  e  a  l    u  n  

    t   i   l    t   h  e   e  x  

    a  m  

    i   n  a  t   i   o  n   

    i   s   f   i   n  i   s  h  e  d   

    Reservoir Engineering - Well Test Analysis

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    Model Solutions to Examination

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    ANSWER 1

    The general solution is:

    P tD Dxf  = π

    Convert dimensionless variables to actual real variables:

    PPi Pff kh

    qt

    kt

    x

    Pi Pkh

    q

    kt

    x

    D Dxf  t f 

    ff t f 

    =   − =

    − =

    ( ) 

    ( )

    2

    2

    2

    2

    πµ ϕµ

    πµ

    πϕµ

    C

    C

    Now rearrange for Pff:

    ( )

    ( )

    Pi Pq

    kh

    kt

    x

    Pi Pq

    kh

    kt

    x

    ff t f 

    ff t f 

    − =

    − =

    µ

    π

    π

    ϕµ

    µ

    π

    π

    ϕµ

    2

    2

    2

    2

    C

    C

    This can be easily rearranged to the following:

    P Piq

    kh

    xtff 

    t f 

      = −   

        

        −µ

    ππ

    ϕµ2 2

    2

    C

    Which is the equation of a straight line:

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    y = mx + c

    m = -C

    q

    kh

    xt f 

    µπ

    πϕµ2 2

      

         

    Thus, if a plot of Pff, measured by the downhole pressure transducer,

    against   t , the square root of the flowing time, is made, the gradient

    m, can be evaluated.

    P Pq

    kh

    xtff 

    t f 

      =   

        

        −1 22

    µπ

    πϕµ C

    Pff - measured by pressure transducer

    t - recorded over flow period

    Pi - (not important) but measured by RFT or early DST 

    Plot Pff v t 

    Evaluate gradient through data, m

    mq

    kh

    xt f   = −

        

         

    µπ

    πϕµ2 2C

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    Model Solutions to Examination

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    q - held constant through test and recorded at surface

    µ - known from PVT test data

    h - known from geological modelling

    φ - known from petrophysics/core tests etc

    t C   - known from rock mechanical testing of cores

    k - known - as given in question

    = =   −   

        

       xf 

    q

    m kh

    u t

    µπ

    πϕ2 C

    The analysis of the plot of Pff v   t  should be carefully carried out, i.e.

    select appropriate data that is not affected by early time effects e.g.

    wellbore storage, or late time effects e.g. influenced by boundaries to

    flow.

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    ANSWER 2

    a) Gas material balance is given by:

    Mg = M

    gi - M

    gp  (1)

    i.e. current mass of gas = initial mass - produced mass

    in reservoir of gas in reservoir of gas

    From equation of state:

    (PV = ZnRT)

    Mg = V

    g  ρg

    MW P

    ZRT 

    .=

    Mass = volume x density MW = molecular weight of gas

    Define G = Volume of gas at standard conditions

    = = =  . . ..

    VG

    g

    G M W P

    Z RT

    ZRT

    MW Pg

    sc sc

    sc sc

    ρρ

    at standard conditions ZSC

     = 1

    = =  .V G P TZ

    T Pg

    sc

    sc

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    Model Solutions to Examination

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    This equation can be written, taking account of gas material balance

    equation (1) as:

    VG G P T

    T Pg

    i p sc z

    sc

     ( )

    =  −

    Also, by the same argument:

    VG P T

    T PZigi

    i sc

    sc i

      = T = constant reservoir pressure

    For volumetric depletion

    V V

    G G P Tz

    T P

    G P T

    T P

    g gi

    i p sc

    sc

    i sc zi

    sc i

     

    ( )

    =

    =  −

    =

    = − =

    = =  −

    = = −

     ( )

     ( )

     

    G GZ

    PG

    Z

    P

    P

    Z

    G G

    G

    P

    Z

    P

    Z

    P

    Z

    P

    G ZG

    i p i

    i

    i

    i p

    i

    i

    i

    i

    i

    i

    i i

    p

    Thus, plotting - against Gp

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    where P = measured reservoir pressure

    Z = compressibility of gas at P

    Gp = cumulative gas produced at standard conditions

     yields a straight line:

    Pi

    Zi

    P

    Z

    0

    The data points can be plotted, as above, and the line

    extrapolated to = 0.

    At this point, Gp = G

    i i.e. the initial gas-in-place.

    (b) In most situations the plot will not be valid since

    depletion will not be entirely volumetric. The expansion of rock

    and connate water will lead to errors in the process, sometimes

    of 100%.

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    Model Solutions to Examination

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    This is most apparent in abnormally pressured reservoirs where

    over-pressure results in gas compressibility and rock and water

    compressibility being of similar magnitude. Under such

    circumstances, these effects cannot be ignored.

    The modification is as follows:

    Vg = V

    gi - ∆V

    g

    ∆Vg = V

    pi (S

    wcC

    w+C

    f) ∆P

    here Vpi is the initial pore volume∆P is the pressure depletion

    Swc

     is the connate water solution

    Cw is the water compressibility

    Cf is the formation compressibility

    Vgi

     = Vpi

     (1-Swc

    )

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    = = −−

      +

    = = −   ∆

    −( )  +

     

    =  −

    =

    => −

     ( )

     ( )

    ( )

      ,( )

     

    ( )

    V VV

    SS C C P

    V VP

    S

    S C C

    From before VG G P T

    T P

    VG P T

    T P

    G G

    g gi

    gi

    wc

    wc w f  

    g gi

    wc

    wc w f  

    g

    i p sc z

    sc

    gi sc zi

    sc i

    i p

    1

    1

    1

    ZZP

    G ZP

    PS

    S C C

    P

    Z

    P

    SS C C

    G G

    G

    P

    Z

    P

    Z

    P

    SS C C

    P

    Z

    P

    G ZG

    ii

    i wc

    wc w f  

    wc

    wc w f  

    i p

    i

    i

    i

    wc

    wc w f  i

    i

    i

    i i

    p

    = −   ∆−

      +  

    => −   ∆−

      +

     

     =

      −

    => −   ∆−

      +

     

     = −

    11

    11

    11

    ( )

      ( )( )

     ( )

    ( )

    This will give a straight line only when Cf is constant. This is rarely

    the case, since Cf is a pressure dependent quantity. Selection of C

    f is

    therefore a difficult and important decision if this modified plot is to

    be of benefit.

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    Model Solutions to Examination

    11

    (c) The problems with water influx are significant. Not only does

    influx affect the material balance

    Vg = V

    gi - W

    e,

    but there are additional effects of gas trapping in the invaded region

    of the reservoir/aquifer system.

    The management of such fields demands that both reservoir and

    aquifer behaviour are understood. The nature of gas sales is to

    arrange long term contracts with specified Daily Contracted

    Quantities of gas, which are, additionally, subject to swing factors i.e.the delivery must be able to meet demand above the DCQ, or below,

    depending on seasoned variation. In designing such contracts, it is,

    therefore, crucially important to fully understand reservoir and

    aquifer characteristics, as failure to meet contracts can prove a costly

    business.

    The DCQ is based on the peak production rate of the reservoir, again

    accounting for saving factor. The Annual Contract Quantity = 365

    DCQ i.e. saving is balanced. The reservoir model must be able to

    predict future performance. In this situation of Water influx, the

    material balance equation can be conveniently coupled to an analysis

    method which has well testing theory as its routes. The reservoir

    becomes “the well”, while the aquifer becomes “the reservoir”.

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    Variable rate solution of this familiar problem is required to model the

    aquifer performance.

    Fetkovich showed that results derived by a quasi-semi-steady state

    solution to the problem generated acceptable results, saving on

    computation time.

    With the material balance and Fetkovich model, the production of the

    system can be predicted. The aquifer inner boundary pressure is the

    gas reservoir average pressure, so required depletion rates can be

    modelled.

    The timing of decline will be when:

    P Pg− −

    =  swing i.e. the gas reservoir average pressure is equal to that

    required to meet the maximum gas output. Both this and the peak

    production rate must be well designed to honour the gas contract.

    Production problems include the trapping of gas in the region of water

    influx. As water invades the reservoir it displaces gas to a residual

    concentration Sgr which becomes lost in terms of production.

    The water influx will then be impeded due to relative permeability

    effects and pressure maintenance may be affected.

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    Model Solutions to Examination

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    A major benefit in the management of such fields is to have good

    aquifer description which may be achieved by better data gathering

    from the aquifer i.e. core sampling. Many characteristic will be

    different between reservoir and aquifer not least of which is

    permeability, which will be greater in the aquifer due to increased

    periods of diagenesis.

    With good aquifer data, simulation becomes more valuable, helping the

    management process.

    ANSWER 3

    a) Several factors influence well test design.

    Assuming wellbore storage, an estimate of CD, which can be deter

    mined from very early time data (for constant compressibility (in

    single phase) and skin (an estimate can be determined from anearlier well test or from corey time data using type curve matching)

    can give an indication of the time needed to reach the semi-log

    straight line. So, to be able to set good estimates of k and S, the

    straight line on the semi-log plot must be reached (out of wellbore

    storage affected region) and at least 1 log cycle of data should be

    measured in this region (MTR).

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    In a bounded reservoir, if the geometry of the drainage region (and

    - average drainage area) is the objective of the test, then time to

    reach the boundaries has to be allocated to the test (reservoir limit

    test). In this case, m* is calculated from slope in SSS depletion. In

    Cartesian plot m  q

    cth* = −

    φ A  and can be determined. C

    A Dietz

    shape factor necessary for the MBH correction. If CA is already

    known, the well test only needs to reach the SSS zone. The radius at

    investigation r 4 t  4kt

    ci

    = =α φµ 

      gives an indication of the distance that

    the pressure disturbance traveled, so if the distance to boundaries

    (faults, etc) is known (from geophysics, etc), an estimation of time

    taken to reach boundaries can also be performed.

    For this, relevant data is compressibility of oil, total compressibility

    (great uncertainty), estimates of k and S, oil viscosity, porosity,

    thickness of formation, and flow rates.

    b) A software package can import data in real time and perform an

    early time analysis to determine the existence of wellbore storage,

    and from type curve matching or derivative (log-log) analysis set CD,

    and type curve matching an estimate of K and S can be made and CD

    stated before, this can give management an indication of time

    necessary to reach MTR region. Analysis of log - log (p’ vs t) plot can

    give a real time indication of when the MTR region is reached(derivative plateau) and depending on objective of test, the real time

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    Model Solutions to Examination

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    analysis can continue for the design of the testing in the LTR as

    stated before, with some knowledge of the distance to the boundaries.

    If this distance is not known, then testing should be extended to

    “feel” them : normally performed after well is drilled.

    c) Flow rate is dependent on type of fluid and associated conditions,

    such as:

    - In oil wells, qo is normally limited by test separator capacity

    - In gas wells (exploration), gas rate can be limited by the capacity of

    the flaring system

    - In High Pressure, high temperature wells, rate can be limited bythe maximum allowable temperature at the wellhead (rating of

    elastomers seals).

    Production software performing a nodal analysis taking in consideration

    all this (separator, chokes, tubing lift performance and reservoir in

    flow - needs k and S estimates) can give a good indication of the well-test flow rate or ranges at allowable rates.

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    ANSWER 4

    a) This is a very useful plot. Allows the identification of 3 flow

    regimes (this diagnostic role is a very important application of the

    derivative response) and also allows a precise identification of the

    boundaries (in time) of those regimes (another important role of the

    log-log derivative diagnostic plot).

    MTR) In this case, the existence of the derivative plateau

    indicates the existence of a middle time region (MTR) in radial flow.

    ETR) After a transition period that may be shorter or longer

    (depends on geometry of system and well location within it). A periodof half slope is reached, indicating the existence of linear flow.

    Following this period, another transition is reached, when the far

    boundaries of the system start to affect the pressure response.

    When the period of unit slope is reached, the pressure response is

    dominated by the bounded reservoir model, being semi-steady-state

    depletion beyond that. This transition period is also affected by the

    distance to the reservoir boundaries, and if they are reached or not at

    the same time. A possible geological interpretation could be a bounded

    fluvial channel

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    Model Solutions to Examination

    17

    Unit slope period other

    boundaries are reached

    (SSS depletion)

    Linear flow peridRadial flow perid

    For the correct unique interpretation, input needs to be received from

    other disciplines such as geology, geophysics, Petrophysics, etc →

    multidisciplinary task!

    b) Not counting a possible wellbore storage dominated period that

    would be analysed in the log-log plot, the following specialist plots arenecessary.

    Semilog-plot →  to perform the analysis of the MTR region (derivative

    plateau), giving the best estimates of k and S. Flow in the MTR region

    (radial) is a straight line in a semilog plot.

    I assume the flow periods were already defined in the log-log

    derivative plot.

    Linear flow plot ( ) →  after the MTR period analysis, the relevant

    parameters are stored (k,S) and the linear flow plot can give estimates

    of the geometry of the system, L1, L

    2 and W

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    L1

    L2

    W

    Cartesian flow plot _ in SSS regime, pwf

     vs t is a straight line at slope

    −   qc hAt φ 

     and assuming that ct is known, an estimate of the connected

    pore volume can be achieved. This allows the estimation of reserves.

    Also the extrapolation of the pressure to t=0 yields a relation with the

    Dietz shape factor of the drainage area.

    ANSWER 5

    i) The lack of uniqueness can be overcome by the input of geologists,

    geophysicists, petrophysicists, etc, giving information about the

    depositional environment, likely geological structure, faulting, layering

    (cores, WFTs) etc.

    ii) In some situations, these can be overcome using the Hawkins

    equation. AC>υ the resistivity or equivalent logs can help.

    iii) Analysis of cores (permeameter) or WFT measurements can allow

    the estimation of vertical profiles for the permeability and identify

    layering, etc.

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    Model Solutions to Examination

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    iv) This can be overcome using an approximation such as:

    Q

    qsq

    tp t

    tp =Q

    qs

    Where Q is cumulative production, qs is surface rate and T p is a

    production time accounting for variation in the rate during the test.

    The limitation is that before shut in a stabilised rate qs should exist.

    This can overcome some variability in the rate (uncertainty). The

    continuous development of more precise flowmeters (multiphase) can

    also help in reducing uncertainty.

    v) A material balance using the pressure decline and estimated

    reserves from geology can help in identifying if there is some

    pressure support from an aquifer.

    b)

    i) Lack of uniqueness is an important issue but assuming that there is

    some previous geological or geophysical study, the effects of it can be

    reduced. In new exploration areas this problem can be more serious,

    where data input from other disciplines is still reduced (lack of

    information).

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    ii) This is also important because when designing a stimulation

    treatment to reduce or overcome the damaged region (acidising,

    fracturing), the knowledge of the depth of damage would help in

    optimising this.

    iii) As long as WFT data (MDT) and/or cores are available, this shouldbe a minor problem.

    iv) This is very important as the transient well test analysis normally

    assumes constant and known rate. If this is not the case, then the

    analysis is incorrect. Maybe that’s why such a large effort is being put

    on the development of accurate and reliable multiphase flowmeters.

    v) This can be very important because in the exploration & appraisal

    stage of a field, especially offshore, the knowledge of whether there

    is aquifer support or not would be extremely valuable in optimising the

    development cost. (Accounting for water injection support or not and

    all the related facilities).

    c) The fact that when there are no measurements of initial Pi by W

    Ft

    or MDT, some error can be introduced if the pressure transducer is

    not at perforation depth. Pi = Ptranducer

      + ρh and this ρh may notbe well

    known if there is some cushion fluid going down through valve.

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    Model Solutions to Examination

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    → The calculation of the wellbore storage coefficient assumes

    constant single phase compressibility. This can lead to serious errors

    in estimating CD because prior to shut-down most oil wells would be in

    Z phase flow.

    → Very important limitation →  deferred production while test isbeing performed (no production at all during buildups) →maybe the

    largest limitation of well testing from the managers point of view!

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