05 - layout strategy

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Layout Strategy Dr. Keong Leong Management Department UNLV

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  • Layout Strategy

    Dr. Keong LeongManagement Department

    UNLV

  • When you complete this class you should be able to: Explain the strategic importance of

    layout decisions Develop a good layout for a process-

    oriented facility Balance production flow in a

    repetitive or product-oriented facility using the assembly line balancing technique

    Key Learning Outcome

  • Outline

    Global Company Profile: McDonalds The Strategic Importance of Layout

    Decisions Process-Oriented and Repetitive Layout Assembly Line Balancing

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    McDonalds New Layout

    Redesigning all 30,000 outlets around the world Three separate dining areas

    Linger zone with comfortable chairs and Wi-Ficonnections

    Grab and go zone with tall counters Flexible zone for kids and families

    Facility layout is a source of competitive advantage

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    McDonalds

    Savings of $100,000,000 per year in food costs

    New Kitchen Layout

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Facility Layout Strategy

    The objective of layout strategy is to develop a cost-effective layout that will meet a firms competitive needs

    Location or arrangement of everything within & around a facility to achieve: Higher utilization of space, equipment, and people Improved flow of information, materials, or people Improved employee morale and safer working

    conditions Improved customer/client interaction Flexibility

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Surgery

    Radiology

    ER Triage Room

    ER Beds Pharmacy

    Emergency room admissions

    Billing/exit

    Laboratories

    Patient A - broken leg

    Patient B - erratic heart pacemaker

    Figure 9.3Figure 9.3

    Process-Oriented Layout

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Minimize cost = Xij Cijn

    i = 1

    n

    j = 1

    where n = total number of work centers or departments

    i, j = individual departmentsXij = number of loads moved from

    department i to department jCij = cost to move a load between

    department i and department j

    Process-Oriented Layout

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Process Layout Example

    Arrange six departments in a factory to minimize the material handling costs. Each department is 20 x 20 feet and the building is 60 feet long and 40 feet wide. Construct a from-to matrix Determine the space requirements Develop an initial schematic diagram Determine the cost of this layout Try to improve the layout Prepare a detailed plan

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    DepartmentDepartment AssemblyAssembly PaintingPainting MachineMachine ReceivingReceiving ShippingShipping TestingTesting(1)(1) (2)(2) Shop (3)Shop (3) (4)(4) (5)(5) (6)(6)

    Assembly (1)Assembly (1)

    Painting (2)Painting (2)

    Machine Shop (3)Machine Shop (3)

    Receiving (4)Receiving (4)

    Shipping (5)Shipping (5)

    Testing (6)Testing (6)

    Number of loads per weekNumber of loads per week

    50 100 0 0 20

    30 50 10 0

    20 0 100

    50 0

    0

    Figure 9.4Figure 9.4

    Process Layout Example

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Process Layout Example

    Room 1Room 1 Room 2Room 2 Room 3Room 3

    Room 4Room 4 Room 5Room 5 Room 6Room 66060

    4040

    Receiving Shipping TestingDepartment Department Department

    (4) (5) (6)

    Figure 9.5Figure 9.5

    Assembly Painting Machine ShopDepartment Department Department

    (1) (2) (3)

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    100100

    5050

    2020

    5050

    5050

    20201010

    100100

    3030

    Interdepartmental Flow GraphInterdepartmental Flow Graph

    1 2 3

    4 5 6

    Figure 9.6Figure 9.6

    Process Layout Example

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Cost = $50*20 + $100*40 + $20*60(1 and 2) (1 and 3) (1 and 6)

    + $30*20 + $50*40 + $10*20(2 and 3) (2 and 4) (2 and 5)

    + $20*60 + $100*20 + $50*20(3 and 4) (3 and 6) (4 and 5)

    = $13,200

    Cost = Xij Cijn

    i = 1

    n

    j = 1

    Process Layout Example

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Room 1Room 1 Room 2Room 2 Room 3Room 3

    Room 4Room 4 Room 5Room 5 Room 6Room 66060

    4040

    Receiving Shipping TestingDepartment Department Department

    (4) (5) (6)

    Figure 9.8

    Painting Assembly Machine ShopDepartment Department Department

    (2) (1) (3)

    Process Layout Example

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    3030

    5050

    1010

    5050

    202020205050 100100

    100100

    Revised Interdepartmental Flow GraphRevised Interdepartmental Flow Graph

    2 1 3

    4 5 6

    Figure 9.7Figure 9.7

    Process Layout Example

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Cost = $50*20 + $100*20 + $20*40(1 and 2) (1 and 3) (1 and 6)

    + $30*40 + $50*20 + $10*40(2 and 3) (2 and 4) (2 and 5)

    + $20*60 + $100*20 + $50*20(3 and 4) (3 and 6) (4 and 5)

    = $10,600

    Cost = Xij Cijn

    i = 1

    n

    j = 1

    Process Layout Example

    Lower Cost Layout

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Assembly Line Balancing

    Objective is to minimize the imbalance between machines or personnel while meeting required output

    Starts with the precedence relationships Determine cycle time Calculate theoretical minimum number of

    workstations Balance the line by assigning specific tasks to

    workstations Calculate efficiency

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Cycle time = Production time available

    Demand per day

    Minimum number of work stations

    Task timesCycle time

    Efficiency =

    =

    Task times(Actual number of work stations)*(Largest cycle time)

    Assembly Line Balancing

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    This means that tasks B and E cannot be done until task A has been completed

    Performance Task Must FollowTime Task Listed

    Task (minutes) BelowA 10 B 11 AC 5 BD 4 BE 12 AF 3 C,DG 7 FH 11 EI 3 G,HTotal time 66

    Copier Example

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    Performance Task Must FollowTime Task Listed

    Task (minutes) BelowA 10 B 11 AC 5 BD 4 BE 12 AF 3 C,DG 7 FH 11 EI 3 G,HTotal time 66

    I

    GF

    C

    D

    H

    B

    E

    A10

    1112

    5

    4 3

    711 3

    Figure 9.13

    Copier Example

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    I

    GF

    C

    D

    H

    B

    E

    A10

    1112

    5

    4 3

    711 3

    Performance Task Must FollowTime Task Listed

    Task (minutes) BelowA 10 B 11 AC 5 BD 4 BE 12 AF 3 C, DG 7 FH 11 EI 3 G, HTotal time 66

    480 available mins per day

    40 units required

    Cycle time =Production time available per day

    Units required per day= 480 / 40= 12 minutes per unit

    Minimum number of

    workstations= Time for task i

    Cycle time

    n

    i = 1

    = 66 / 12= 5.5 or 6 stations

    Copier Example

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    I

    GF

    C

    D

    H

    B

    E

    A10

    1112

    5

    4 3

    711 3

    Copier Example

    PerformancePerformance Task Must FollowTask Must FollowTimeTime Task ListedTask Listed

    TaskTask (minutes)(minutes) BelowBelowAA 1010 BB 1111 AACC 55 BBDD 44 BBEE 1212 AAFF 33 C, DC, DGG 77 FFHH 1111 EEII 33 G, HG, HTotal time Total time 6666

    480 available mins per day

    40 units requiredCycle time = 12 mins

    Minimum workstations = 5.5 or 6

    Line-Balancing Heuristics

    Choose the available task with the least number of following tasks

    5. Least number of following tasks

    Choose the available task with the shortest task time

    4. Shortest task time

    Choose the available task for which the sum of following task times is the longest

    3. Ranked positional weight

    Choose the available task with the largest number of following tasks

    2. Most following tasks

    Choose the available task with the longest task time

    1. Longest task time

    Table 9.4

    Primary Rule

    Secondary Rule

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    480 available mins per day

    40 units requiredCycle time = 12 mins

    Minimum workstations = 5.5 or 6

    PerformancePerformance Task Must FollowTask Must FollowTimeTime Task ListedTask Listed

    TaskTask (minutes)(minutes) BelowBelowAA 1010 BB 1111 AACC 55 BBDD 44 BBEE 1212 AAFF 33 C, DC, DGG 77 FFHH 1111 EEII 33 G, HG, HTotal time Total time 6666Station

    1

    Station 2

    Station 4

    Station 5

    Station 3

    Station 6

    Figure 9.14

    Copier Example

    5

    I

    GF

    H

    C

    D

    B

    E

    A10 11

    12

    4

    3 7

    11

    3

  • (Principles of Operations Management, Heizer & Render, 7th Edition)

    480 available mins per day

    40 units requiredCycle time = 12 mins

    Minimum workstations = 5.5 or 6

    Efficiency = Task times

    (actual number of workstations) x (largest cycle time)

    = 66 minutes / (6 stations) x (12 minutes)= 91.7%

    Copier Example

    I

    GF

    C

    D

    H

    B

    E

    A10

    1112

    5

    4 3

    711 3