12x1 t09 03 permutations i (2010)

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The Basic Counting Principle

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Page 1: 12X1 T09 03 permutations I (2010)

The Basic Counting Principle

Page 2: 12X1 T09 03 permutations I (2010)

The Basic Counting Principle

If one event can happen in m different ways and after this another

event can happen in n different ways, then the two events can

occur in mn different ways.

Page 3: 12X1 T09 03 permutations I (2010)

The Basic Counting Principle

If one event can happen in m different ways and after this another

event can happen in n different ways, then the two events can

occur in mn different ways.

e.g. 3 dice are rolled

Page 4: 12X1 T09 03 permutations I (2010)

The Basic Counting Principle

If one event can happen in m different ways and after this another

event can happen in n different ways, then the two events can

occur in mn different ways.

e.g. 3 dice are rolled

(i) How many ways can the three dice fall?

Page 5: 12X1 T09 03 permutations I (2010)

The Basic Counting Principle

If one event can happen in m different ways and after this another

event can happen in n different ways, then the two events can

occur in mn different ways.

e.g. 3 dice are rolled

(i) How many ways can the three dice fall?

666 Ways

Page 6: 12X1 T09 03 permutations I (2010)

The Basic Counting Principle

If one event can happen in m different ways and after this another

event can happen in n different ways, then the two events can

occur in mn different ways.

e.g. 3 dice are rolled

(i) How many ways can the three dice fall?

666 Ways

iespossibilit 6 has die1st the

Page 7: 12X1 T09 03 permutations I (2010)

The Basic Counting Principle

If one event can happen in m different ways and after this another

event can happen in n different ways, then the two events can

occur in mn different ways.

e.g. 3 dice are rolled

(i) How many ways can the three dice fall?

666 Ways

iespossibilit 6 has die1st the

iespossibilit 6 has die 2nd the

Page 8: 12X1 T09 03 permutations I (2010)

The Basic Counting Principle

If one event can happen in m different ways and after this another

event can happen in n different ways, then the two events can

occur in mn different ways.

e.g. 3 dice are rolled

(i) How many ways can the three dice fall?

666 Ways

iespossibilit 6 has die1st the

iespossibilit 6 has die 2nd the

iespossibilit 6 has die 3rd the

Page 9: 12X1 T09 03 permutations I (2010)

The Basic Counting Principle

If one event can happen in m different ways and after this another

event can happen in n different ways, then the two events can

occur in mn different ways.

e.g. 3 dice are rolled

(i) How many ways can the three dice fall?

666 Ways

iespossibilit 6 has die1st the

iespossibilit 6 has die 2nd the

iespossibilit 6 has die 3rd the

612

Page 10: 12X1 T09 03 permutations I (2010)

(ii) How many ways can all three dice show the same number?

Page 11: 12X1 T09 03 permutations I (2010)

(ii) How many ways can all three dice show the same number?

116 Ways

Page 12: 12X1 T09 03 permutations I (2010)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit 6 has die1st the

Page 13: 12X1 T09 03 permutations I (2010)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit 6 has die1st the

ypossibilit 1only has now die 2nd the

Page 14: 12X1 T09 03 permutations I (2010)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit 6 has die1st the

ypossibilit 1only has now die 2nd the

ypossibilit 1only has now die 3rd the

Page 15: 12X1 T09 03 permutations I (2010)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit 6 has die1st the

ypossibilit 1only has now die 2nd the

ypossibilit 1only has now die 3rd the6

Page 16: 12X1 T09 03 permutations I (2010)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit 6 has die1st the

ypossibilit 1only has now die 2nd the

ypossibilit 1only has now die 3rd the6

(iii) What is the probability that all three dice show the same

number?

Page 17: 12X1 T09 03 permutations I (2010)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit 6 has die1st the

ypossibilit 1only has now die 2nd the

ypossibilit 1only has now die 3rd the6

(iii) What is the probability that all three dice show the same

number?

216

6same the3 all P

Page 18: 12X1 T09 03 permutations I (2010)

(ii) How many ways can all three dice show the same number?

116 Ways

iespossibilit 6 has die1st the

ypossibilit 1only has now die 2nd the

ypossibilit 1only has now die 3rd the6

(iii) What is the probability that all three dice show the same

number?

216

6same the3 all P

36

1

Page 19: 12X1 T09 03 permutations I (2010)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the

five exits. Thus, the probability of any given mouse leaving by a

particular exit is

Four mice, A, B, C and D are put into the maze and behave

independently.

(i) What is the probability that A, B, C and D all come out the same

exit?

5

1

1996 Extension 1 HSC Q5c)

Page 20: 12X1 T09 03 permutations I (2010)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the

five exits. Thus, the probability of any given mouse leaving by a

particular exit is

Four mice, A, B, C and D are put into the maze and behave

independently.

(i) What is the probability that A, B, C and D all come out the same

exit?

5

1

1996 Extension 1 HSC Q5c)

5

1

5

1

5

11exit same theuse all P

Page 21: 12X1 T09 03 permutations I (2010)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the

five exits. Thus, the probability of any given mouse leaving by a

particular exit is

Four mice, A, B, C and D are put into the maze and behave

independently.

(i) What is the probability that A, B, C and D all come out the same

exit?

5

1

1996 Extension 1 HSC Q5c)

5

1

5

1

5

11exit same theuse all P

1door any through gocan mouseFirst P

Page 22: 12X1 T09 03 permutations I (2010)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the

five exits. Thus, the probability of any given mouse leaving by a

particular exit is

Four mice, A, B, C and D are put into the maze and behave

independently.

(i) What is the probability that A, B, C and D all come out the same

exit?

5

1

1996 Extension 1 HSC Q5c)

5

1

5

1

5

11exit same theuse all P

1door any through gocan mouseFirst P

5

1door samethrough

gomust miceOther

P

Page 23: 12X1 T09 03 permutations I (2010)

Mice are placed in the centre of a maze which has five exits.

Each mouse is equally likely to leave the maze through any of the

five exits. Thus, the probability of any given mouse leaving by a

particular exit is

Four mice, A, B, C and D are put into the maze and behave

independently.

(i) What is the probability that A, B, C and D all come out the same

exit?

5

1

1996 Extension 1 HSC Q5c)

5

1

5

1

5

11exit same theuse all P

1door any through gocan mouseFirst P

5

1door samethrough

gomust miceOther

P

125

1

Page 24: 12X1 T09 03 permutations I (2010)

(ii) What is the probability that A, B and C come out the same

exit and D comes out a different exit?

Page 25: 12X1 T09 03 permutations I (2010)

(ii) What is the probability that A, B and C come out the same

exit and D comes out a different exit?

5

1

5

1

5

41exitdifferent uses exit, same use DABCP

Page 26: 12X1 T09 03 permutations I (2010)

(ii) What is the probability that A, B and C come out the same

exit and D comes out a different exit?

5

1

5

1

5

41exitdifferent uses exit, same use DABCP

1door any through gocan D P

Page 27: 12X1 T09 03 permutations I (2010)

(ii) What is the probability that A, B and C come out the same

exit and D comes out a different exit?

5

1

5

1

5

41exitdifferent uses exit, same use DABCP

1door any through gocan D P

5

4

choose todoors 4 has mouseNext

P

Page 28: 12X1 T09 03 permutations I (2010)

(ii) What is the probability that A, B and C come out the same

exit and D comes out a different exit?

5

1

5

1

5

41exitdifferent uses exit, same use DABCP

1door any through gocan D P

5

4

choose todoors 4 has mouseNext

P

5

1door samethrough

gomust miceOther

P

Page 29: 12X1 T09 03 permutations I (2010)

(ii) What is the probability that A, B and C come out the same

exit and D comes out a different exit?

5

1

5

1

5

41exitdifferent uses exit, same use DABCP

1door any through gocan D P

5

4

choose todoors 4 has mouseNext

P

125

4

5

1door samethrough

gomust miceOther

P

Page 30: 12X1 T09 03 permutations I (2010)

(iii) What is the probability that any of the four mice come out the

same exit and the other comes out a different exit?

Page 31: 12X1 T09 03 permutations I (2010)

(iii) What is the probability that any of the four mice come out the

same exit and the other comes out a different exit?

125

4exitdifferent uses DP

Page 32: 12X1 T09 03 permutations I (2010)

(iii) What is the probability that any of the four mice come out the

same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

Page 33: 12X1 T09 03 permutations I (2010)

(iii) What is the probability that any of the four mice come out the

same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

125

4exitdifferent uses BP

Page 34: 12X1 T09 03 permutations I (2010)

(iii) What is the probability that any of the four mice come out the

same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

125

4exitdifferent uses BP

125

4exitdifferent uses CP

Page 35: 12X1 T09 03 permutations I (2010)

(iii) What is the probability that any of the four mice come out the

same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

125

4exitdifferent uses BP

125

4exitdifferent uses CP

125

44exitdifferent uses mouseany P

Page 36: 12X1 T09 03 permutations I (2010)

(iii) What is the probability that any of the four mice come out the

same exit and the other comes out a different exit?

125

4exitdifferent uses DP

125

4exitdifferent uses AP

125

4exitdifferent uses BP

125

4exitdifferent uses CP

125

44exitdifferent uses mouseany P

125

16

Page 37: 12X1 T09 03 permutations I (2010)

(iv) What is the probability that no more than two mice come out the

same exit?

Page 38: 12X1 T09 03 permutations I (2010)

(iv) What is the probability that no more than two mice come out the

same exit?

same use 3same all1exit same use 2 than more no PPP

Page 39: 12X1 T09 03 permutations I (2010)

(iv) What is the probability that no more than two mice come out the

same exit?

same use 3same all1exit same use 2 than more no PPP

125

16

125

11

Page 40: 12X1 T09 03 permutations I (2010)

(iv) What is the probability that no more than two mice come out the

same exit?

same use 3same all1exit same use 2 than more no PPP

125

16

125

11

125

108

Page 41: 12X1 T09 03 permutations I (2010)

Permutations

Page 42: 12X1 T09 03 permutations I (2010)

Permutations A permutation is an ordered set of objects

Page 43: 12X1 T09 03 permutations I (2010)

Permutations A permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such

Objects

Page 44: 12X1 T09 03 permutations I (2010)

Permutations A permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such

Objects (i.e. use all of the objects)

Page 45: 12X1 T09 03 permutations I (2010)

Permutations A permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such

Objects

If we arrange n different objects in a line, the number of ways we

could arrange them are;

(i.e. use all of the objects)

Page 46: 12X1 T09 03 permutations I (2010)

Permutations A permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such

Objects

If we arrange n different objects in a line, the number of ways we

could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

(i.e. use all of the objects)

Page 47: 12X1 T09 03 permutations I (2010)

Permutations A permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such

Objects

If we arrange n different objects in a line, the number of ways we

could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

(i.e. use all of the objects)

1 n

2object for

iespossibilit

Page 48: 12X1 T09 03 permutations I (2010)

Permutations A permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such

Objects

If we arrange n different objects in a line, the number of ways we

could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

(i.e. use all of the objects)

1 n 2 n

2object for

iespossibilit

3object for

iespossibilit

Page 49: 12X1 T09 03 permutations I (2010)

Permutations A permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such

Objects

If we arrange n different objects in a line, the number of ways we

could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

(i.e. use all of the objects)

1 n 2 n 1

2object for

iespossibilit

3object for

iespossibilit

objectlast for

iespossibilit

Page 50: 12X1 T09 03 permutations I (2010)

Permutations A permutation is an ordered set of objects

Case 1: Ordered Sets of n Different Objects, from a Set of n Such

Objects

If we arrange n different objects in a line, the number of ways we

could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

! n

(i.e. use all of the objects)

1 n 2 n 1

2object for

iespossibilit

3object for

iespossibilit

objectlast for

iespossibilit

Page 51: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

Page 52: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

!9 tsArrangemen

Page 53: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

!9 tsArrangemen With no restrictions, arrange 9 people

gender does not matter

Page 54: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

!9 tsArrangemen With no restrictions, arrange 9 people

gender does not matter 362880

Page 55: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

!9 tsArrangemen With no restrictions, arrange 9 people

gender does not matter 362880

(ii) boys and girls alternate?

Page 56: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

!9 tsArrangemen With no restrictions, arrange 9 people

gender does not matter 362880

(ii) boys and girls alternate?

(ALWAYS look after any restrictions first)

Page 57: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

!9 tsArrangemen With no restrictions, arrange 9 people

gender does not matter 362880

(ii) boys and girls alternate?

1 tsArrangemen

boy a be

MUSTperson first

(ALWAYS look after any restrictions first)

Page 58: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

!9 tsArrangemen With no restrictions, arrange 9 people

gender does not matter 362880

(ii) boys and girls alternate?

1 tsArrangemen

boy a be

MUSTperson first

(ALWAYS look after any restrictions first)

!5

boys thearranging

of waysofnumber

Page 59: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

!9 tsArrangemen With no restrictions, arrange 9 people

gender does not matter 362880

(ii) boys and girls alternate?

1 tsArrangemen

boy a be

MUSTperson first

(ALWAYS look after any restrictions first)

!5 !4

boys thearranging

of waysofnumber

girls thearranging

of waysofnumber

Page 60: 12X1 T09 03 permutations I (2010)

e.g. In how many ways can 5 boys and 4 girls be arranged in a line

if;

(i) there are no restrictions?

!9 tsArrangemen With no restrictions, arrange 9 people

gender does not matter 362880

(ii) boys and girls alternate?

1 tsArrangemen

boy a be

MUSTperson first

(ALWAYS look after any restrictions first)

!5 !4

boys thearranging

of waysofnumber

girls thearranging

of waysofnumber

2880

Page 61: 12X1 T09 03 permutations I (2010)

(iii) What is the probability of the boys and girls alternating?

Page 62: 12X1 T09 03 permutations I (2010)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

Page 63: 12X1 T09 03 permutations I (2010)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

126

1

Page 64: 12X1 T09 03 permutations I (2010)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

126

1

(iv) Two girls wish to be together?

Page 65: 12X1 T09 03 permutations I (2010)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

126

1

(iv) Two girls wish to be together?

!2 tsArrangemen

arranged becan girls

the waysofnumber the

Page 66: 12X1 T09 03 permutations I (2010)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

126

1

(iv) Two girls wish to be together?

!2 tsArrangemen

arranged becan girls

the waysofnumber the

!8 others 7 girls) (2

objects 8 arranging

of waysofnumber

Page 67: 12X1 T09 03 permutations I (2010)

(iii) What is the probability of the boys and girls alternating?

362880

2880alternate girls & boys P

126

1

(iv) Two girls wish to be together?

!2 tsArrangemen

arranged becan girls

the waysofnumber the

!8 others 7 girls) (2

objects 8 arranging

of waysofnumber

80640

Page 68: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n)

Page 69: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n) (i.e. use some of the objects)

Page 70: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n)

If we have n different objects in a line, but only want to arrange k of

them, the number of ways we could arrange them are;

(i.e. use some of the objects)

Page 71: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n)

If we have n different objects in a line, but only want to arrange k of

them, the number of ways we could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

(i.e. use some of the objects)

Page 72: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n)

If we have n different objects in a line, but only want to arrange k of

them, the number of ways we could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

(i.e. use some of the objects)

1 n

2object for

iespossibilit

Page 73: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n)

If we have n different objects in a line, but only want to arrange k of

them, the number of ways we could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

(i.e. use some of the objects)

1 n 2 n

2object for

iespossibilit

3object for

iespossibilit

Page 74: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n)

If we have n different objects in a line, but only want to arrange k of

them, the number of ways we could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

(i.e. use some of the objects)

1 n 2 n 1 kn

2object for

iespossibilit

3object for

iespossibilit

kobject for

iespossibilit

Page 75: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n)

If we have n different objects in a line, but only want to arrange k of

them, the number of ways we could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

1231

1231121

knkn

knknknnnn

(i.e. use some of the objects)

1 n 2 n 1 kn

2object for

iespossibilit

3object for

iespossibilit

kobject for

iespossibilit

Page 76: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n)

If we have n different objects in a line, but only want to arrange k of

them, the number of ways we could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

1231

1231121

knkn

knknknnnn

(i.e. use some of the objects)

1 n 2 n 1 kn

2object for

iespossibilit

3object for

iespossibilit

kobject for

iespossibilit

!!

kn

n

Page 77: 12X1 T09 03 permutations I (2010)

Case 2: Ordered Sets of k Different Objects, from a Set of n Such

Objects (k < n)

If we have n different objects in a line, but only want to arrange k of

them, the number of ways we could arrange them are;

n tsArrangemen ofNumber

1object for

iespossibilit

1231

1231121

knkn

knknknnnn

(i.e. use some of the objects)

1 n 2 n 1 kn

2object for

iespossibilit

3object for

iespossibilit

kobject for

iespossibilit

!!

kn

n

k

nP

Page 78: 12X1 T09 03 permutations I (2010)

e.g. (i) From the letters of the word PROBLEMS how many 5

letter words are possible if;

a) there are no restrictions?

Page 79: 12X1 T09 03 permutations I (2010)

e.g. (i) From the letters of the word PROBLEMS how many 5

letter words are possible if;

a) there are no restrictions?

5

8 Words P

Page 80: 12X1 T09 03 permutations I (2010)

e.g. (i) From the letters of the word PROBLEMS how many 5

letter words are possible if;

a) there are no restrictions?

5

8 Words P

6720

Page 81: 12X1 T09 03 permutations I (2010)

e.g. (i) From the letters of the word PROBLEMS how many 5

letter words are possible if;

a) there are no restrictions?

5

8 Words P

6720

b) they must begin with P?

Page 82: 12X1 T09 03 permutations I (2010)

e.g. (i) From the letters of the word PROBLEMS how many 5

letter words are possible if;

a) there are no restrictions?

5

8 Words P

6720

b) they must begin with P?

1 Words

first placed becan

P waysofnumber the

Page 83: 12X1 T09 03 permutations I (2010)

e.g. (i) From the letters of the word PROBLEMS how many 5

letter words are possible if;

a) there are no restrictions?

5

8 Words P

6720

b) they must begin with P?

1 Words

first placed becan

P waysofnumber the

4

7 P ROBLEMS

dsletter wor 4many how

becomes nowQuestion

Page 84: 12X1 T09 03 permutations I (2010)

e.g. (i) From the letters of the word PROBLEMS how many 5

letter words are possible if;

a) there are no restrictions?

5

8 Words P

6720

b) they must begin with P?

1 Words

first placed becan

P waysofnumber the

4

7 P ROBLEMS

dsletter wor 4many how

becomes nowQuestion

840

Page 85: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

Page 86: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

Page 87: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

Page 88: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

Page 89: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.

What is the probability that Bill and Ted are on the left side and

Greg is on the right?

Page 90: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.

What is the probability that Bill and Ted are on the left side and

Greg is on the right?

6

8 ns)restrictio (no Ways P

Page 91: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.

What is the probability that Bill and Ted are on the left side and

Greg is on the right?

6

8 ns)restrictio (no Ways P

20160

Page 92: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.

What is the probability that Bill and Ted are on the left side and

Greg is on the right?

6

8 ns)restrictio (no Ways P

20160

2

4 ons)(restricti Ways P

gocan

Ted & Bill Ways

Page 93: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.

What is the probability that Bill and Ted are on the left side and

Greg is on the right?

6

8 ns)restrictio (no Ways P

20160

2

4 ons)(restricti Ways P

gocan

Ted & Bill Ways

1

4P

gocan

Greg Ways

Page 94: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.

What is the probability that Bill and Ted are on the left side and

Greg is on the right?

6

8 ns)restrictio (no Ways P

20160

2

4 ons)(restricti Ways P

gocan

Ted & Bill Ways

1

4P 3

5P

gocan

Greg Ways

gocan people

remaining Ways

Page 95: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.

What is the probability that Bill and Ted are on the left side and

Greg is on the right?

6

8 ns)restrictio (no Ways P

20160

2

4 ons)(restricti Ways P

gocan

Ted & Bill Ways

1

4P 3

5P

gocan

Greg Ways

gocan people

remaining Ways

2880

Page 96: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.

What is the probability that Bill and Ted are on the left side and

Greg is on the right?

6

8 ns)restrictio (no Ways P

20160

2

4 ons)(restricti Ways P

gocan

Ted & Bill Ways

1

4P 3

5P

gocan

Greg Ways

gocan people

remaining Ways

2880

20160

2880rightG left, T&B P

Page 97: 12X1 T09 03 permutations I (2010)

c) P is included, but not at the beginning, and M is excluded?

4 Words

in placed becan

P positions ofnumber the

4

6 P ROBLES

dsletter wor 4many how

becomes nowQuestion

1440

(ii) Six people are in a boat with eight seats, for on each side.

What is the probability that Bill and Ted are on the left side and

Greg is on the right?

6

8 ns)restrictio (no Ways P

20160

2

4 ons)(restricti Ways P

gocan

Ted & Bill Ways

1

4P 3

5P

gocan

Greg Ways

gocan people

remaining Ways

2880

20160

2880rightG left, T&B P

7

1

Page 98: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

Page 99: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

Page 100: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

Page 101: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

Page 102: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

Page 103: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P

Page 104: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P 20

Page 105: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P

3

5 Towersblock 3 P

20

Page 106: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P

3

5 Towersblock 3 P

20

60

Page 107: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P

3

5 Towersblock 3 P

20

60

4

5 Towersblock 4 P

Page 108: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P

3

5 Towersblock 3 P

20

60

4

5 Towersblock 4 P 120

Page 109: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P

3

5 Towersblock 3 P

20

60

4

5 Towersblock 4 P 120

5

5 Towersblock 5 P

Page 110: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P

3

5 Towersblock 3 P

20

60

4

5 Towersblock 4 P 120

5

5 Towersblock 5 P 120

Page 111: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P

3

5 Towersblock 3 P

20

60

4

5 Towersblock 4 P 120

5

5 Towersblock 5 P 120

320Towers ofnumber Total

Page 112: 12X1 T09 03 permutations I (2010)

Sophia has five coloured blocks: one red, one blue, one green, one

yellow and one white.

She stacks two, three, four or five blocks on top of one another to

form a vertical tower.

2006 Extension 1 HSC Q3c)

(i) How many different towers are there that she could form that are

three blocks high?

3

5 Towers P

60

(ii) How many different towers can she form in total?

2

5 Towersblock 2 P

3

5 Towersblock 3 P

20

60

4

5 Towersblock 4 P 120

5

5 Towersblock 5 P 120

320Towers ofnumber Total

Exercise 10E; odd (not 39)