eleg 648 plane waves ii mark mirotznik, ph.d. associate professor the university of delaware email:...

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ELEG 648Plane waves II

Mark Mirotznik, Ph.D.Associate Professor

The University of DelawareEmail: mirotzni@ece.udel.edu

Uniform Plane Waves: Propagation in Any Arbitrary Direction

E

H

y

x

z

zzyyxxo

zyx

zzyyxx

zjyjxjo

EaEaEaE

zayaxar

aaa

eeeErE zyx

ˆˆˆ

ˆˆˆ

ˆˆˆ

)(~

222zyx

222

22

)sin(zyx

yx

22)cos(

yx

y

Uniform Plane Waves: Propagation in Any Arbitrary Direction

E

H

y

x

z

zzyyxxo

zyx

zzyyxx

rjo

EaEaEaE

zayaxar

aaa

eErE

ˆˆˆ

ˆˆˆ

ˆˆˆ

)(~

222zyx

222

22

)sin(zyx

yx

22)cos(

yx

y

Uniform Plane Waves: Propagation in Any Arbitrary Direction

0

)(~

o

rjo

E

eErE

E

H

y

x

z

Since E and are at right anglesfrom each other.

EaEa

EaE

EeE

Eejj

Eej

eEj

Ej

H

rjo

orj

orj

rjo

ˆ1

ˆ

ˆ1

11

11

1~1~

where 222

ˆˆˆˆ

zyx

zzyyxx aaaa

and

Uniform Plane Waves: Propagation in Any Arbitrary Direction

aaa

aaH

aaE

aErtE

trHEarH

aErtEtrEeErE

HE

Ho

Eo

Hoo

o

Eoorj

o

00

00

)cos(),(1

)(~

)cos(),()(~

Observation 1. E, H and vectors are pointing in orthogonal directions.

Summary and Observations:Frequency Domain Time Domain

Observation 2. E and H are in phase with each other, however, H’s magnitude is smaller by the amount of the wave impedance

Uniform Plane Waves: Propagation in 2D

E

H

x

y

22

)sin(

)cos(

)(~

yx

y

x

yjxjo

yx eeErE

Can we write this a bit more compact?

Uniform Plane Waves: Propagation in 2D

E

H

x

y

22

)sin(

)cos(

)(~

yx

y

x

yjxjo

yx eeErE

Can we write this a bit more compact?

yyxxo

yx

yyxx

rjo

EaEaE

yaxar

aa

eErE

ˆˆ

ˆˆ

ˆˆ

)(~

Uniform Plane Waves: Propagation in 2D

E

H

x

y

What about the polarization of E?

yyxxo

yx

yyxx

rjo

EaEaE

yaxar

aa

eErE

ˆˆ

ˆˆ

ˆˆ

)(~

Uniform Plane Waves: Propagation in 2D

E

H

x

y

What about the polarization of E?

0

)(~

o

rjo

E

eErE

yyxxo

yx

yyxx

rjo

EaEaE

yaxar

aa

eErE

ˆˆ

ˆˆ

ˆˆ

)(~

Uniform Plane Waves: Propagation in 2D

E

H

x

y

What about the polarization of E?

0

)(~

o

rjo

E

eErE

yyxxo

yx

yyxx

rjo

EaEaE

yaxar

aa

eErE

ˆˆ

ˆˆ

ˆˆ

)(~

Uniform Plane Waves: Propagation in 2D

E

H

x

y

What about the polarization of E?

)cos(ˆ)sin(ˆ

)(~

oyoxo

rjo

EaEaE

eErE

Two cases

E

H

x

y

Parallel Polarization Perpendicular Polarization

ozo

rjo

EaE

eErE

ˆ

)(~

Uniform Plane Waves: Propagation in 2D

E

H

x

y

What about H?

o

o

o

o

o

o

rjo

rjo

H

H

E

E

H

E

eHrH

eErE

0

0

)(~

)(~

yyxxo

yx

yyxx

rjo

EaEaE

yaxar

aa

eErE

ˆˆ

ˆˆ

ˆˆ

)(~

o

o

o

EH

Uniform Plane Waves: Propagation in 2D

E

H

x

y

What about the polarization of H?

)cos(ˆ)sin(ˆ

)(~

oyoxo

rjo

HaHaH

eHrH

Two cases

E

H

x

y

Parallel Polarization Perpendicular Polarization

ozo

rjo

HaH

eHrH

ˆ

)(~

Reflection and Transmission

Write down the electric fields in the two regions(2 unknowns, R and T)

Reflection and Transmission

Next find the magnetic fields in each region

Reflection and Transmission

Apply boundary conditions

Reflection and Transmission

Reflection and Transmission

Write down the E field in both regions(4 unknowns, R, T, r and t)

Reflection and Transmission

Find the H field in both regions

Reflection and Transmission

Apply boundary conditions

2 equations and 4 unknowns

We need two more equations. How do we get them?

Reflection and Transmission

Reflection and Transmission

Reflection and Transmission

Reflection and Transmission

Reflection and Transmission

Reflection and Transmission

Angle of Incidence, Degrees

Ref

lect

ion

Coe

ffic

ient

Example: Reflection from an Ocean Interface

Reflection and Transmission from Dielectric Slabs

1. Normal Incidence

111

1

11

11,

222

2

22

22 ,

333

3

33

33 ,

z=0 z=d

Region I Region II Region III

Reflection and Transmission from Dielectric Slabs

Region I:

zjoRy

zjoincy

zjo

Rx

zjo

incx

eRE

H

eE

H

eERE

eEE

1

1

1

1

1

1

Region II:

zjzjIIy

zjzjIIx

eAeAH

eAeAE

22

22

212

21

1

Region III:

zjoTy

zjo

Tx

eTE

H

eETE

3

3

3

Boundary Conditions

z=0 z=d

000

000

z

IIyz

Ryz

incy

z

IIxz

Rxz

incx

HHH

EEE

dz

Tydz

IIy

dz

Txdz

IIx

HH

EE

Reflection and Transmission from Dielectric Slabs

Boundary Conditions

z=0 z=d

2

2

2

1

11

21

AAREE

AAREE

oo

oo

djodjdj

djo

djdj

eTE

eAeA

eTEeAeA

322

322

321

2

21

1

Four equations and four unknownsSolution for the Reflection Coefficient:

23

2323

12

1212

22312

22312

2

2

1

dj

dj

e

eR

Reflection and Transmission from Dielectric Slabs

Special Cases

23

2323

12

12122

2312

22312

2

2

1

dj

dj

e

eR

I. Half Wavelength Thickness Slab

""0

1

22

,2,1,0,

231231

2312

2312

2

2

2

2

reflectionnoR

thenif

R

nnn

d

nnd

o

111

1

11

11,

222

2

22

22 ,

z=0 z=2/2

Region I Region II Region III

111

1

11

11,

Reflection and Transmission from Dielectric Slabs

Special Cases

23

2323

12

12122

2312

22312

2

2

1

dj

dj

e

eR

II. Quarter Wavelength Thickness Slab

""0

1

442

2

2312312

2312

2312

2

2

2

2

reflectionnoR

thenif

R

d

d

o

111

1

11

11,

222

132

22 ,

z=0 z=2/4

Region I Region II Region III

333

3

33

33 ,

Reflection and Transmission from Dielectric Slabs: Example

23

2323

12

12122

2312

22312

2

2

1

dj

dj

e

eR

377

,

01

11

o

oo

92

222

132

2

2

10776.5

5.217

3

o

o

z=0 z=m

Region I Region II Region III

67.125

,9

03

33

o

oo

268.05.21767.125

5.21767.125268.0

3775.217

3775.2172312

9

9

2

2

10776.5

10776.5

22312

22312

0716.01

)1(267.0

1

j

j

dj

dj

e

e

e

eR

Reflection and Transmission from Dielectric Slabs: Example

9

9

2

2

10776.5

10776.5

22312

22312

0716.01

)1(267.0

1

j

j

dj

dj

e

e

e

eR

Frequency, MHz

|R|

How do we broaden the bandwidth around the zero reflection point?

Frequency, MHz

|R|

One Solution is Multiple Dielectric Layers

111

1

11

11,

222

2

22

22 ,

333

3

33

33 ,

4

4

5

5

6

6

Reflection and Transmission from Dielectric Slabs

1. Oblique Incidence ( Parallel Polarization)

111

1

11

11,

222

2

22

22 ,

333

3

33

33 ,

z=0 z=d

Region I Region II Region III

i

t

r II

II

Reflection and Transmission from Dielectric Slabs

Region I:

])sin(1)cos(1[])sin(1)cos(1[

])sin(1)cos(1[])sin(1)cos(1[

])sin(1)cos(1[

11

11

11

])sin()cos([

)sin(ˆ)cos(ˆ~

)sin(ˆ)cos(ˆ~

ˆ~

ˆ~

yizijyizij

yizijyizij

yizij

ii

eRE

aeRE

aH

eE

aeE

aH

eREaE

eEaE

oizi

oy

R

oizi

oy

inc

oxR

yzjox

inc

Region II:

zy

zyII

yzjyzjIIx

aaeA

aaeA

H

eAeAE

yzj

yzj

ˆ)sin(ˆ)cos(

ˆ)sin(ˆ)cos(~

222

2

222

1

])sin()cos([2

])sin()cos([1

])2sin(2)2cos(2[

])2sin(2)2cos(2[

22222222

Reflection and Transmission from Dielectric Slabs

Region III:

])sin(3)cos(3[])sin(3)cos(3[

])sin(3)cos(3[

33

3

)sin(ˆ)cos(ˆ~

ˆ~

ytztjytztj

ytztj

eTE

aeTE

aH

eTEaE

oiz

oy

T

oxT

Boundary Conditions

z=0 z=d

000

000

z

IIyz

Ryz

incy

z

IIxz

Rxz

incx

HHH

EEE

dz

Tydz

IIy

dz

Txdz

IIx

HH

EE

Phase Matching Conditions

)sin()sin(

)sin()sin(

322

221

t

i

Reflection and Transmission from Dielectric Slabs

Six Equations and Six Unknowns

)sin()sin(

)sin()sin(

322

221

t

i

dtjdjdj

dtjdjdj

eT

EeA

eA

TeEeAeA

AAREE

AAREE

to

o

oo

oo

)cos(3)2cos(2)2cos(2

)cos(3)2cos(2)2cos(2

)cos()cos()cos(

)cos()cos(

32

2

22

2

1

21

22

22

2

1

11

21

Reflection and Transmission from Dielectric Slabs: Solution (parallel polarization)

dj

dj

e

eR

2

2

22312

22312

1

)cos()cos(

)cos()cos(

)cos()cos(

)cos()cos(

))sin((sin

))sin((sin

322

32223

221

22112

23

21

2

112

22

t

t

i

i

t

i

o

*note we have assumed all non-magneticmaterials here

Reflection and Transmission from Dielectric Slabs: Solution (perpendicular polarization)

dj

dj

e

eR

2

2

22312

22312

1

)cos()cos(

)cos()cos(

)cos()cos(

)cos()cos(

))sin((sin

))sin((sin

223

22323

212

21212

23

21

2

112

22

t

t

i

i

t

i

o

*note we have assumed all non-magneticmaterials here

Reflection and Transmission from Dielectric Slabs: Example

377

,

01

11

o

oo

92

222

132

2

2

10776.5

5.217

3

o

o

z=0 z=m

Region I Region IIRegion III

67.125

,9

03

33

o

oo

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