what goes in the box ? rationalise the denominator of the following expressions: time's up!

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What Goes In The Box ?

Rationalise the denominator of the following expressions:

3

7)1(

6

4)2(

103

14)3(

29

4)4(

37

52)5(

211

36)6(

3

37

3

62 15

107

9

22

21

152 11

63

Time's up!

Rationalising Denominators

Aim: To be able to rationalise denominators of the form √a ;

(1 +/- √a) or (√a +/- √b)

Answer exam questions involving surds and rationalising

denominators

Know the square numbers up to 152

Know the cube numbers up to 63

Difference of 2 squares.

)63)(63( This is a conjugate pair. The brackets are identical apart from the sign in each bracket .

Now observe what happens when the brackets are multiplied out:

)63)(63( = 3 X 3 - 6 3 + 6 3 - 36

= 3 - 36

= -33

When the brackets are multiplied out the surds cancel out and we end up seeing that the expression is rational . This result is used throughout the following slide.

Rationalise the denominator in the expressions below by multiplying top and bottom by the appropriate conjugate:

35

2)1(

)35)(35(

)35(2

)(

)(

9-53+53-5×5

3+52=

)95(

)35(2

2

)35(

)23(

7)2(

)23)(23(

)23(7

)23(

)23(7

)23(7

In both of the above examples the surds have been removed from the denominator as required.

Quick fire square numbers and cube numbers MWB

What Goes In The Box ?Rationalise the denominator in the expressions below :

)27(

5)1(

)23(

3)2(

)452(

7)3(

633

)27(5

2

)25(7

End

Extension• Rationalise

• Hence write a process for rationalising a denominator with three surds.

532

1

Homework

Video&

Quiz

Length and Midpoint of Lines

Have a go

Make mathematical sentences out of the card sets.

See how many you can do?

See how complicated you can make them, but must be correct!

Mathsnet activities

moodle

Surds Activities:

True or false

Exercise Level 2

Make more sentences

Harder Surds

We met surds when solving quadratic equations.e.g. Find the roots of the equation

0122 xx

a

acbbx

2

42

Solution:

Using the formula for :02 cbxax

21x

Simplifying the surd: 22248

2

222x

)1(2

)1)(1(4)2(2 2 x

2

82 x

Harder Surds

We can also surds which are in the denominators of fractions.

2

1e.g.1 Write the expression in the form

p

p

Solution: Multiply the numerator and the denominator by : 2

2

1

2

1

2

2

22

2

2

2

A fraction is simplified if there are no surds in the denominator.

Harder Surds

203

2e.g.2 Simplify the expression

Solution: We first simplify the surd.

203

2

543

2

523

2

5

5

53

1

Multiply the numerator and the denominator by

5

1

1

15

5

Harder Surds

32

1

e.g.3 Write the expression in the form qp

))(( baba

Method: We know that 22 ba

So, )32)(32( 22 )3(2 34

1By multiplying the expression by the surd has disappeared.

)32( )32(

However, if we multiply the denominator by we must multiply the numerator by the same amount.

)32(

Harder Surds

32

1

32

1Solution:

34

32

32

3232

The process of removing surds from the denominator is called rationalising.

Harder Surds

SUMMARY

To rationalise the denominator of a fraction of the form

qp

ba

. . . multiply the numerator and denominator byqp

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