aoe 5104 class 6
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AOE 5104 Class 6. Online presentations for next class: Equations of Motion 2 Homework 2 Homework 3 (revised this morning) due 9/18 d’Alembert. C. 2D flow over airfoil with =0. Last class. …and their limitations. Integral theorems…. Convective operator…. - PowerPoint PPT PresentationTRANSCRIPT
AOE 5104 Class 6
• Online presentations for next class:– Equations of Motion 2
• Homework 2• Homework 3 (revised this morning) due
9/18• d’Alembert
Last classIntegral theorems…
R S
dSd n
R S
dSd nAA ..
R S
dSd nAA
C
SSd sAnA d..
…and their limitations
2D flow over airfoil with =0
C
.V = change in density in direction of V, multiplied by magnitude of V
Convective operator…
Irrotational and Solenoidal Fields… 0.
0
A
Class Exercise1. Make up the most complex irrotational 3D velocity
field you can.
2223sin /3)2cos( zyxxyxe x kjiV ?
We can generate an irrotational field by taking the gradient of any scalar field, since 0
I got this one by randomly choosing
zyxe x /132sin And computing
kjiVzyx
Acceleration??
2nd Order Integral Theorems• Green’s theorem (1st form)
• Green’s theorem (2nd form)
Volume Rwith Surface S
d
ndS
SR
Sd dn
2
S
RSd d
n-
n22
These are both re-expressions of the divergence theorem.
The Equations of Motion
“Phrase of the Day”
Mutationem motus proportionalem esse vi motrici impressae, & fieri secundum lineam
rectam qua vis illa imprimitur.
Go Hokies?
Supersonic Turbulent Jet Flow and Near Acoustic Field
Freund at al. (1997)Stanford Univ.DNS
Conservation Laws
• Conservation of mass
• Conservation of momentum
• Conservation of energy
0 mass of C. O. R.
ViscousPressureBody of C. O. R. FFFmomentum
QWW Wenergy of C. O. R. ViscousPressureBody
Supersonic Turbulent Jet Flow and Near Acoustic Field
Freund at al. (1997)Stanford Univ.DNS
Conservation Laws
• Conservation of mass
• Conservation of momentum
• Conservation of energy
0 mass of C. O. R.
ViscousPressureBody of C. O. R. FFFmomentum
QWW Wenergy of C. O. R. ViscousPressureBody
Apply to the fluid material (not the space)
Experimental observations
Assumption: Fluid is a homogeneous continuum
flow
x
y
z
x y z r i j k
o o o ox y z r i j k
1 o o, o
2 o o, o
3 o o, o
( , , )
( , , )
( , , )
x f x y z t
y f x y z t
z f x y z t
Position :
1) Lagrangian Method
Kinematics of Continua
1 o o, o
o o, o
2 o o, o 3 o o, o
( , , ) where partial derivative wrt time
holding ( , ) constant
( , , ) ( , , ),
x
y z
Df x y z t Dv
Dt Dtx y z
Df x y z t Df x y z tv v
Dt Dt
Velocity :
DTM
2 2 21 o o, o 2 o o, o 3 o o, o
2 2 2
( , , ) ( , , ) ( , , ), ,
Concept is straightforward, but difficult to implement, often would produce moreinformation than we need or want, and
x y z
D f x y z t D f x y z t D f x y z ta a a
Dt Dt Dt
Acceleration :
doesn't fit the situation usually encounteredin fluid mechanics.
The Lagrangian Method is always used in solid mechanics :
DTM
P
ox
3 2o o3
6Py x lxEI
3 2o 1 o o o o o 2 o o o 3 o o o( , , , ), 3 ( , , , ), 0 ( , , , )
6P t
x x f x y z t y x lx f x y z t z f x y z tEI
radDDt t
t
Acceleration :v va v vG
1) Lagrangian Method
1 o o, o
2 o o, o
3 o o, o
( , , ) ( , , )
( , , )
x f x y z ty f x y z tz f x y z t
Position :2) Eulerian Method
DTM
Position :
1 o o, o
2 o o, o
3 o o, o
( , , )
( , , )
( , , )
x
y
z
Df x y z tv
DtDf x y z t
vDt
Df x y z tv
Dt
Velocity : ( , , , ) ( , , , )
( , , , )
x
y
z
v x y z tv x y z tv x y z t
Velocity :
solve for position as a function of time and “name”
express the velocity as a function of time and spatial position
denotes the derivative wrt time holding the spatial position fixed, often called the “local” derivative
WOW! big, big difference: velocity as a function of time and spatial position, not velocity as a function of time and particle name
complication: laws governing motion apply to particles (Lagrange), not to positions in space
21 o o, o
2
22 o o, o
2
23 o o, o
2
( , , )
( , , )
( , , )
x
y
z
D f x y z ta
DtD f x y z t
aDt
D f x y z ta
Dt
Acceleration :
skip this step and do not try to find the positions of fluid particles
Giuseppe Lodovico Lagrangia (Joseph-Louis Lagrange)
born 25 January 1736 in Turin, Italydied 10 April 1813 in Paris, France
Leonhard Paul Euler
born 15 April 1707 in Basel, Switzerlanddied 18 September 1783 in St. Petersburg, Russia
DTM
Acceleration in the Eulerian Method:
x
y
z
rdr
A fluid particle, represented as a blue dot in the figure, moves from position to during the time interval .
Its velocity changes from ( , ) to ( , )where be chosen
d dt
t d t dtd dt
a
r r r
v r v r rr MUST v
( , ) ( , )D d t dt tDt dt
v v r r v r
( , ) ( , ) ( , ) ( , ) ( , ) ( , )
( , ) ( , ) = the derivative wrt time at a fixed location
( , ) ( , ) rad change in between two po
D d t dt t d t dt d t d t tDt dt dt
d t dt d tdt t
d t t ddt dt
v v r r v r v r r v r r v r r v ra
v r r v r r v
v r r v r v r vG ints in space at a fixed time
and are independent variables; so we are free to chose them anyway we want. In order
to follow a particle, we must chose : rad
dt
t d
d dtt
rvr v a v vG
.If at a given instant we draw a line with the property that every point on
the line passed through the same reference point at some earlier time, the result is known as a streakline.
It is called a streakline because, if the particles are dyed as they pass through the common reference point, the result will be a line of dyed particles (i.e., a streak) through the flowfield.
If at a given instant the velocity is calculated at all points in the flowfield and then a line is drawn with the property that the velocities of all of the particles lying on that line are tangent to it, the result is known as a streamline.
Streamlines are the velocity field lines. They provide a snapshot of the flowfield, a picture at an instant. The surface formed by all the streamlines that pass through a closed curve in space forms a stream tube.
1 o o, o
2 o o, o
3 o o, o
( , , )( , , )( , , )
x f x y z ty f x y z tz f x y z t
These equations define a line in terms of the parameter, , when are constant.Such a line is called a pathline.
t o o o, ,x y z
PerspectivesEulerian Perspective – the flow as as seen at fixed locations in space, or over fixed volumes of space. (The perspective of most analysis.)
Lagrangian Perspective – the flow as seen by the fluid material. (The perspective of the laws of motion.)
Control volume: finite fixed region of space (Eulerian)
Coordinate: fixed point in space (Eulerian)
Fluid system: finite piece of the fluid material (Lagrangian)
Fluid particle: differentially small finite piece of the fluid material (Lagrangian)
III
II
I
flow
A system moving along in the flow occupies volumes I and II at time t. During the next interval dt some of the system moves out of II into three and some moves out of I into II. The rate of change of an arbitrary property of the system, N, is given by the following:
The Transport Theorem:
in II & III at in I & II at in II at in II at in III at in I at
II II
N t dt N t N t dt N t N t dt N tDNDt dt dt dt
dV dSt
v nthe unit vector normal
to ABC, n
two triangular elements from the family approximating the surface of volume II at time = t
the same two material elements, but now approximating the surface of volume III at time =
material that flowed through the surface of volume II during the interval and now fills volume III:
S dtv dN dt S v n
DTM
A B
C’
C
A’B’
Strategy
• Write down equations of motion for Lagrangian rates of change seen by fluid particle or system
• Derive relationship between Lagrangian and Eulerian rates of change
• Substitute to get Eulerian equations of motion
Conservation of Mass From a Lagrangian Perspective
Law: Rate of Change of Mass of Fluid Material = 0
For a Fluid Particle:
Volume d
Density
0.
0.
01
0
0
DtD
t
ttd
d
td
td
td
part
partpart
partpart
part
V
V
For a Fluid System:
d
Volume R
Density =(x,y,z,t)
whereparttDt
D
is referred to as
the SUBSTANTIAL DERIVATIVE(or total, or material, or Lagrangian…)
‘Seen by the particle’
0
0
R
Rsys
dDtD
dt
AXIOMATA SIVE LEGES MOTUS• Lex I.
– Corpus omne perseverare in statuo suo quiescendi vel movendi uniformiter in directum, nisi quatenus a viribus impressis cogitur statum illum mutare.
• Lex II.– Mutationem motus proportionalem esse vi motrici impressae, &
fieri secundum lineam rectam qua vis illa imprimitur.• Lex III.
– Actioni contrariam semper & æqualem esse reactionem: sive corporum duorum actiones in se mutuo semper esse æquales & in partes contrarias dirigi.
• Corol. I.– Corpus viribus conjunctis diagonalem parallelogrammi eodem
tempore describere, quo latera separatis.
Conservation of Momentum From a Lagrangian Perspective (Fluid Particle)
Law: Rate of Change of Momentum = Fbody+Fpressure+Fviscous
DtDd
td
td
partpart
VVV
ROC of Momentum
Fbody: df
dydx
dzji
kP
Net …density volume dvelocity Vbody force per unit mass f
2dy
yyy
yy
2dz
zzy
zy
2dy
ypp
Elemental Volume, Surface Forces
x, i
y, j
z, k
2dy
ypp
Sides of volume have lengths dx, dy, dz
2dy
yyy
yy
2dz
zzy
zy
• Volume d = dxdydz• Density • Velocity V
2
2dx
y
dxy
xyxy
xyxy
On front and rear faces
y-component
Conservation of Momentum From a Lagrangian Perspective (Fluid Particle)
Law: Rate of Change of Momentum = Fbody+Fpressure+Fviscous
DtDd
td
td
partpart
VVV
ROC of Momentum
Fbody:
Fpressure:
df
dpso
dypdxdzdy
yppdxdzdy
yppcomponenty
pressure
F
jjj 21
21
dydx
dzji
kP
2dy
ypp
P
x, i
y, j
z, k
2dy
ypp
Conservation of Momentum From a Lagrangian Perspective (Fluid Particle)
Law: Rate of Change of Momentum = Fbody+Fpressure+Fviscous
DtDd
td
td
partpart
VVV
ROC of Momentum
Fbody:
Fpressure:
Fviscous:
df
dpso
dypdxdzdy
yppdxdzdy
yppcomponenty
pressure
F
jjj 21
21
dzyx
dxdydzz
dxdydzz
dydzdxx
dydzdxx
dxdzdyy
dxdzdyy
componenty
zyyyxyzyzy
zyzy
xyxy
xyxy
yyyy
yyyy
jjj
jj
jj
21
21
21
21
21
21...
Likewise for x and z
dydx
dzji
kP
2dz
zzy
zy
P
x, i
y, j
z, k
2dy
yyy
yy
2dz
zzy
zy
2dy
yyy
yy
Conservation of Momentum From a Lagrangian Perspective (Fluid Particle)
Law: Rate of Change of Momentum = Fbody+Fpressure+Fviscous
DtDd
td
td
partpart
VVV
ROC of Momentum
Fbody:
Fpressure:
Fviscous:
df
dpso
dypdxdzdy
yppdxdzdy
yppcomponenty
pressure
F
jjj 21
21
dzyx
dxdydzz
dxdydzz
dydzdxx
dydzdxx
dxdzdyy
dxdzdyy
componenty
zyyyxyzyzy
zyzy
xyxy
xyxy
yyyy
yyyy
jjj
jj
jj
21
21
21
21
21
21...
kτjτiτfV ).().().( zyxpDtD
So,
kjiτkjiτkjiτ
zzyzxzz
zyyyxyy
zxyxxxx
where
Likewise for x and z
dydx
dzji
kP
AXIOMS CONCERNING MOTION• Law 1.
– Every body continues in its state of rest or of uniform motion in a straight line, unless it is compelled to change that state by forces impressed upon it.
• Law 2.– Change of motion is proportional to the motive force impressed;
and is in the same direction as the line of the impressed force.• Law 3.
– For every action there is always an opposed equal reaction; or, the mutual actions of two bodies on each other are always equal and directed to opposite parts.
• Corollary 1.– A body, acted on by two forces simultaneously, will describe the
diagonal of a parallelogram in the same time as it would describe the sides by those forces separately.
Isaac Newton1642-1727
Conservation of Energy From a Lagrangian Perspective (Fluid Particle)
Law: Rate of Change of Energy = Wbody+Wpressure+Wviscous+Q
• Total energy is internal energy + kinetic energy = e + V2/2 per unit mass
• Rate of work (power) = force x velocity in direction of force
• Fourier’s law to gives rate of heat added by conduction
DtVeDd
tVed
part
)()( 2212
21
ROC of Energy
Wbody dVf . dydx
dzji
kP
2dy
yvv
2dy
ypp
Elemental Volume, Surface Force Work and Heat Transfer
x, i
y, j
z, k
2dy
ypp
Sides of volume have lengths dx, dy, dz
• Volume d = dxdydz• Density • Velocity V
y-contributions
2dy
yvv
Viscous work requires expansion of v velocity on all six sides
2dy
yyTk
yTk
Velocity components u, v, w
2dy
yyTk
yTk
Conservation of Energy From a Lagrangian Perspective (Fluid Particle)
Law: Rate of Change of Energy = Wbody+Wpressure+Wviscous+Q
DtVeDd
tVed
part
)()( 2212
21
ROC of Energy
Wbody
Wpressure
Wviscous
dVf .
dp ).( V
dwvu zyx )).().().(( τττ
Q:
dTkQso
dyTk
ydxdzdy
yTk
yyTkdxdzdy
yTk
yyTkoncontributiy
).(
21
21
).().().().().(.)( 2
21
TkwvupDt
VeDzyx
τττVVfSo,
Equations for Changes Seen From a Lagrangian Perspective
0 = d DtD
R
S
zyxSRR
dS ).( + ).( + ).( +dS p- d = d DtD knτjnτinτnfV
dS T).k(+dS . + + p- + d . = d )2
V + (eDtD
SSzyx
R
2
R nVknτjnτinτnfV ).().().(
Differential Form (for a particle)
Integral Form (for a system)
V. DtD
kτjτiτfV ).().().( zyxpDtD
).().().().().(.)( 2
21
TkwvupDt
VeDzyx
τττVVf
Conversion from Lagrangian to Eulerian rate of change - Derivative
x
y
z(x(t),y(t),z(t),t)
.Vt
zw
yv
xu
ttz
zty
ytx
xt
DtD
t part
The Substantial Derivative
Time Derivative Convective Derivative
Conversion from Lagrangian to Eulerian rate of change - Integral
x
y
z
The Reynolds Transport Theorem
SR
R
R
R
R
RRRsys
dSdtα
dt
dt
ddDt
DDt
DddDt
D
Dt
d Dd DtD= d
t
nV
V
VV
V
.
).(
..
.
.VtDt
D
Volume RSurface S
Apply Divergence Theorem
Equations for Changes Seen From a Lagrangian Perspective
0 = d DtD
R
S
zyxSRR
dS ).( + ).( + ).( +dS p- d = d DtD knτjnτinτnfV
dS T).k(+dS . + + p- + d . = d )2
V + (eDtD
SSzyx
R
2
R nVknτjnτinτnfV ).().().(
Differential Form (for a particle)
Integral Form (for a system)
V. DtD
kτjτiτfV ).().().( zyxpDtD
).().().().().(.)( 2
21
TkwvupDt
VeDzyx
τττVVf
parttDtD
Equations for Changes Seen From an Eulerian Perspective
Differential Form (for a fixed volume element)
Integral Form (for a system)0 = dSd t SR
nV.
Szyx
SRR
dS ).( + ).( + ).( + dS p- d = dSd t
knτjnτinτnfnVVV ).(
dS T).k(+dS . + + p- + d . =dSV+ ed )t
V+ e
SSzyx
RS
22
R
nVknτjnτinτnfVnV ).().().(.)(
)(212
1
V. DtD
kτjτiτfV ).().().( zyxpDtD
).().().().().(.)( 2
21
TkwvupDt
VeDzyx
τττVVf
.VtDt
D
Equivalence of Integral and Differential Forms
0 = dSd t SR
nV.
d =dSR
S VnV ..
0.
dtR
V
0. V
t0..
VV
t
V. DtD
Cons. of mass (Integral form)
Divergence Theorem
Conservation of mass for any volume R
Then we get or
Cons. of mass (Differential form)