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Page 1: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Application of Integration (Area)

Bander Almutairi

King Saud University

November 17, 2015

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 1 / 14

Page 2: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

1 Area

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 2 / 14

Page 3: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

If f (x) ≥ 0 and continuous on the interval [a, b],

then the definite integral∫ ba f (x)dx gives the area of the the region under the graph of f from a tob.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 3 / 14

Page 4: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

If f (x) ≥ 0 and continuous on the interval [a, b], then the definite integral∫ ba f (x)dx gives the area of the the region under the graph of f from a tob.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 3 / 14

Page 5: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

If f (x) ≥ 0 and continuous on the interval [a, b], then the definite integral∫ ba f (x)dx gives the area of the the region under the graph of f from a tob.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 3 / 14

Page 6: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Example: Find the area under the graph y = x2 − 4x + 5 from 0 to 5.

Solution:The function y represents a parabola with a vertex at the point(2, 1),

A =

∫ 5

0(x2 − 4x + 5)dx =

50

3.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 4 / 14

Page 7: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Example: Find the area under the graph y = x2 − 4x + 5 from 0 to 5.Solution:

The function y represents a parabola with a vertex at the point(2, 1),

A =

∫ 5

0(x2 − 4x + 5)dx =

50

3.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 4 / 14

Page 8: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Example: Find the area under the graph y = x2 − 4x + 5 from 0 to 5.Solution:The function y represents a parabola with a vertex at the point(2, 1),

A

=

∫ 5

0(x2 − 4x + 5)dx =

50

3.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 4 / 14

Page 9: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Example: Find the area under the graph y = x2 − 4x + 5 from 0 to 5.Solution:The function y represents a parabola with a vertex at the point(2, 1),

A =

∫ 5

0(x2 − 4x + 5)dx =

50

3.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 4 / 14

Page 10: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Note that: If f (x) ≤ 0 for x ∈ [a, b],

then −f (x) ≥ 0, for x ∈ [a, b], sothe area above the graph is

A = −∫ b

af (x)dx

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 5 / 14

Page 11: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Note that: If f (x) ≤ 0 for x ∈ [a, b], then −f (x) ≥ 0, for x ∈ [a, b],

sothe area above the graph is

A = −∫ b

af (x)dx

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 5 / 14

Page 12: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Note that: If f (x) ≤ 0 for x ∈ [a, b], then −f (x) ≥ 0, for x ∈ [a, b], sothe area above the graph is

A = −∫ b

af (x)dx

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 5 / 14

Page 13: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Note that: If f (x) ≤ 0 for x ∈ [a, b], then −f (x) ≥ 0, for x ∈ [a, b], sothe area above the graph is

A = −∫ b

af (x)dx

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 5 / 14

Page 14: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Note that: If f (x) ≤ 0 for x ∈ [a, b], then −f (x) ≥ 0, for x ∈ [a, b], sothe area above the graph is

A = −∫ b

af (x)dx

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 5 / 14

Page 15: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Theorem

If f and g are continuous and f (x) ≥ g(x) for x ∈ [a, b],

then the area Aof the region bounded by the graphs of f , g from x = a to x = b is

A =

∫ b

a[f (x)− g(x)] dx .

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 6 / 14

Page 16: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Theorem

If f and g are continuous and f (x) ≥ g(x) for x ∈ [a, b], then the area Aof the region bounded by the graphs of f , g from x = a to x = b is

A =

∫ b

a[f (x)− g(x)] dx .

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 6 / 14

Page 17: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Theorem

If f and g are continuous and f (x) ≥ g(x) for x ∈ [a, b], then the area Aof the region bounded by the graphs of f , g from x = a to x = b is

A =

∫ b

a[f (x)− g(x)] dx .

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 6 / 14

Page 18: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Exercise: Express the area between the graphs in the following diagram asa definite integral:

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 7 / 14

Page 19: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Example: (1) Sketch the region bounded by graphs y =√x and y = x2,

and find its area.

Solution:The area is

A =

∫ 1

0

[√x − x2

]dx =

1

3.

(2) Find the area of the region bounded by the graphes y − x = 6, y = x3

and 2y + x = 0.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 8 / 14

Page 20: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Example: (1) Sketch the region bounded by graphs y =√x and y = x2,

and find its area.Solution:

The area is

A =

∫ 1

0

[√x − x2

]dx =

1

3.

(2) Find the area of the region bounded by the graphes y − x = 6, y = x3

and 2y + x = 0.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 8 / 14

Page 21: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Example: (1) Sketch the region bounded by graphs y =√x and y = x2,

and find its area.Solution:The area is

A =

∫ 1

0

[√x − x2

]dx =

1

3.

(2) Find the area of the region bounded by the graphes y − x = 6, y = x3

and 2y + x = 0.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 8 / 14

Page 22: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Example: (1) Sketch the region bounded by graphs y =√x and y = x2,

and find its area.Solution:The area is

A =

∫ 1

0

[√x − x2

]dx =

1

3.

(2) Find the area of the region bounded by the graphes y − x = 6, y = x3

and 2y + x = 0.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 8 / 14

Page 23: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Example: (1) Sketch the region bounded by graphs y =√x and y = x2,

and find its area.Solution:The area is

A =

∫ 1

0

[√x − x2

]dx =

1

3.

(2) Find the area of the region bounded by the graphes y − x = 6, y = x3

and 2y + x = 0.

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 8 / 14

Page 24: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

Exercise: Find the shaded area for the following diagrams:[1]

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 9 / 14

Page 25: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

[2]

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 10 / 14

Page 26: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

[3]

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 11 / 14

Page 27: Application of Integration (Area) - KSUfac.ksu.edu.sa/sites/default/files/area_0.pdfApplication of Integration (Area) Bander Almutairi King Saud University November 17, 2015 Bander

Area

[4]

Bander Almutairi (King Saud University) Application of Integration (Area) November 17, 2015 12 / 14