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Chap 12.2 Gas laws

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Page 1: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Chap 12.2

Gas laws

Page 2: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

12.2 Gas Laws• Objectives

• State Boyle’s law, and use it to solve problems involving pressure and volume.

• State Charles’s law, and use it to solve problems involving volume and temperature.

• State Gay-Lussac’s law, and use it to solve problems involving pressure and temperature.

• State Avogadro’s law, and explain its importance in determining the formulas of chemical compounds.

Page 3: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

12.2 Gas Laws• Measurable Properties of Gases

• Gases are described by their measurable properties.

• P = pressure exerted by the gas

• V = total volume occupied by the gas

• T = temperature in kelvins of the gas

• n = number of moles of the gas

Page 4: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

12.2 Gas Laws•T=constant, relationship between V and P

•Volume _____________, Pressure _____________.

Boyle’s Law - 1662

Page 5: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Boyle’s Law

•The inverse relationship between pressure and volume is known as Boyle’s law.

•Boyle’s law states that for a fixed amount of gas at a constant temperature, the volume of the gas increases as the pressure of the gas decreases and the volume of the gas decreases as the pressure of the gas increases.

12.2 Gas Laws

Page 6: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Boyle’s Law, continued

• T= constant, the product of the pressure and volume of a gas is constant.

PV = k

• If the temperature and number of particles are not changed, the PV product remains the same, as shown in the equation below.

P1V1 = P2V2

Chapter 12.2

Page 7: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Volume Versus Pressure for a Gas at Constant Temperature

Chapter 12.2

Page 8: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Solving Pressure-Volume Problems

Sample Problem A given sample of gas occupies 523 mL at 1.00 atm. The pressure is increased to 1.97 atm, while the temperature remains the same. What is the new volume of the gas?

Chapter 12.2

Page 9: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Temperature-Volume Relationships

• Heating a gas makes it expand.

• Cooling a gas makes it contract.

• In 1787, the French physicist Jacques Charles discovered that a gas’s volume is directly proportional to the temperature on the Kelvin scale if the pressure remains the same.

Section 2 The Gas LawsChapter 12

Page 10: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Charles’s Law

• P = Constant, Relationship between temperature and volume - Charles’s law.

• Charles’s law states that for a fixed amount of gas at a constant pressure, the volume of the gas increases as the temperature of the gas increases and the volume of the gas decreases as the temperature of the gas decreases.

Section 2 The Gas LawsChapter 12

Page 11: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Charles’s Law, continued

• If the absolute temperature is reduced by half, then the average kinetic energy is reduced by half, and the particles will strike the walls with half of the energy they had at the higher temperature.

• In that case, the volume of the gas will be reduced to half of the original volume if the pressure remains the same.

Section 2 The Gas LawsChapter 12

Page 12: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Volume Versus Temperature for a Gas at Constant Pressure

Chapter 12 Section 2 The Gas Laws

• V-T graph using the Kelvin scale.

• at 0 K, the gas’s volume becomes zero.

• Before this temperature is reached, the gas becomes a liquid and solid.

Page 13: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Charles’s Law, continued

• At constant pressure, the volume of a sample of gas divided by its absolute temperature is a constant, k.

• Charles’s law can be stated as the following equation.

Section 2 The Gas LawsChapter 12

• If all other conditions are kept constant, V/T will remain the same.

Page 14: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Solving Volume-Temperature Problems

Sample Problem A balloon is inflated to 665 mL volume at 27°C. It is immersed in a dry-ice bath at -78.5°C. What is its volume, assuming the pressure remains constant?

Section 2 The Gas LawsChapter 12

Page 15: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Solving Volume-Temperature Problems, continuedSample Problem C Solution

V1 = 665 mL T1 = 27°C V2 = ? T2 = −78.5°C

T1 = 27°C + 273 = 300 K T2 = −78.5°C + 273 = 194.5 K

Section 2 The Gas LawsChapter 12

Page 16: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Temperature-Pressure Relationships

• Temperature and pressure have a directly proportional relationship.

• The direct relationship between temperature and pressure is known as Gay-Lussac’s law.

• Gay-Lussac’s Law states that the pressure of a gas at a constant volume is directly proportional to the absolute temperature.

Section 2 The Gas LawsChapter 12

Page 17: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Measurable Properties of Gases, continuedTemperature-Pressure Relationships, continued

• Gas pressure is directly proportional to kelvin temperature, at constant volume.

Section 2 The Gas LawsChapter 12

Page 18: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Measurable Properties of Gases, continuedTemperature-Pressure Relationships, continued

• This equation can be rearranged to the following form.

Section 2 The Gas LawsChapter 12

• At constant volume, the following equation applies.

Page 19: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Solving Pressure-Temperature Problems

Sample Problem DAn aerosol can containing gas at 101 kPa and 22°C is heated to 55°C. Calculate the pressure in the heated can.

Section 2 The Gas LawsChapter 12

Page 20: Chap 12.2 Gas laws. 12.2 Gas Laws Objectives State Boyle’s law, and use it to solve problems involving pressure and volume. State Charles’s law, and use

Measurable Properties of Gases, continuedTemperature-Pressure Relationships, continued

Sample Problem D Solution

P1 = 101 kPa T1 = 22°CP2 = ? T2 = 55°C

T1 = 22°C + 273 = 295 K T2 = 55°C + 273 = 328 K

Section 2 The Gas LawsChapter 12