chapter 2 section 3
DESCRIPTION
Chapter 2 Section 3. Work in Electrical Systems. Objectives. Explain the relationship between work, charge and potential difference (voltage). Calculate electrical charge in a circuit. Define units of electric current. Solve problems in electrical work. Identify effects of electrical work. - PowerPoint PPT PresentationTRANSCRIPT
Chapter 2 Section 3
Work in Electrical Systems
Objectives
• Explain the relationship between work, charge and potential difference (voltage).
• Calculate electrical charge in a circuit.
• Define units of electric current.
• Solve problems in electrical work.
• Identify effects of electrical work.
• Explain efficiency in terms of work in and work out in electrical systems.
Coulombs
• The unit of electric charge is the coulomb (C).
• The fundamental charge on an electron is 1.6 X 10-19 C.
• 1 C = 1/ 1.6 X 10-19 = 6.25 X 1018 electrons or 6,250,000,000,000,000,000 electrons.
Work in electrical systems
• The electric field is given by E = F / q (Sec 1.3). Thus F=Eq.
• Potential difference (voltage) is given by V=Ed (Sec 1.3)
• W = Fd = Eqd• Thus W = Vq
Work - cont
• Thus Work = potential difference X charge moved
• W=Vq
• The work needed to move one coulomb of charge though a potential difference of one volt is one joule.
• 1J = 1 V . C
• 1V = 1 J/C
Electric Charge & Current
• Electric current is the rate at which charge flows through a circuit.
• Current = charge / time; I = q / t
• Current is measured in amperes or amps (A)
• 1 amp = 1 coulomb per second; 1A = 1 C/s
Efficiency
• Efficiency = work out / work in; Wout / Win
• % Efficiency = (Wout / Win) x 100%
• Efficiency can never be equal to or greater than 100%
• Work out will always be less than work in.
Summary
• Electric work is done when a charge is moved through a potential difference.
• W = Vq
• 1 joule = 1 volt X 1 coulomb; 1J = 1V.C
• Current is the rate at which charge flows.
• 1 Amp = 1 coulomb per second; 1A=1C/s.
• % Efficiency = (Wout / Win) x 100%