equacoes exponenciais - 2012
TRANSCRIPT
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Questes de Vestibular
EQUAES EXPONENCIAIS
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x
x
x
252
10
1
1
1) Resolva a equao
102 = 25
102
= 255 = 5
25
5 = 5
=
2 = 13 = 1 = 13
= 1 3
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644232
2
x2) Resolva a equao
2. 2 + = 24 64
2. 2+ = 22. 2+ = 22+ = 2
=
2 = 6 42 = 2
= 22 = 1
= 1 = 1
= 1 1
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3) Resolva a equao
xx
9
12
16
93
34 = 129
4
334 = 43
34 = 34
=
2 = 6
3 = 6
= 2
= 2
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4) Resolva a equao27
13.32 xx
3 . 3 = 13
3 . 3 = 33 = 3
3 = 3
3 = 3
= = 3
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5) Resolva a equao 562221 xx
22 2. 2 =56
x1 x+2
22 2 . 4 = 5 6
2 = 2 . 4 = 5 6
2 4 =56
8 =1127 =112
= 1 6 = 2
2 = 162 = 2 = 4
= 4
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6) Resolva a equao 042.5236 xx
2 = 2 2 5. 2 4 = 0
2 = 5 4 = 0= 5 4.1.4 = 9
= 5 92.1 = 5 32 = 14
= 2 = 1 2 = 12 = 2 3 = 0 = 0
= 4 2 = 42 = 2 3 = 2 = 2 3
= 0 , 23
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7) Resolva a equao 32 233 xx 2x
3 33 = 2 3 =
9 = 8 9 = 8
8 9 = 0... = 9 = 1
= 9 3 = 93 = 3 = 2
= 1 3 = 1 | 3 0
= 2
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8) Resolva a equao54
97
2
3
3
21212
xx
23+ 23
+ = 9754
23 . 23 23
23 = 9754
23
= 2
3. 2 3
= 97
54
23 23 = 9754
3 , 3 , 54 = 54
18 18
36 3 6 = 9 736 97 3 6 = 0
..
. = 49 = 94
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8) Resolva a equao54
97
2
3
3
21212
xx
= 49 23 = 49
23
= 2
3
= 23
23 = 23
= 2
= 94 23 = 94
23
= 3
2
= 32
23 = 23
= 2
= 23
= 2 , 2
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9) Resolva a equao 033.4344 xx
3 4 . 3 3 = 03. 4 . 3 3 = 0
3
4 . 3
3 = 0
3 = 4 3 = 0
.
.. = 3 = 1
= 3 3 = 33 = 3 2 = 1 = 1
4 = 1
2
= 1 3 = 13 = 3 2 = 0
= 0 = 0 = 0 , 14
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ISERJ 2012Professora Telma Castro Silva