hello, my name is professor duitt i’m here to show you the method we require for solving problems!
TRANSCRIPT
Hello, My name is Professor Duitt
I’m here to show you themethod we REQUIRE for
solving problems!
It’s called the
This method will help you with a systematic
approach to solving eventhe most difficult problems.
Let’s look at a very simpleproblem to start with so wecan focus on the different
steps of the format.
How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609m (one mile)?
How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609m (one mile)?
Step#1:Read the problem!
You may want to underline key terms.
How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)?
662 m/s1609 m
How long
How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)?
662 m/s1609 m
How longStep#2:
List the knowns andunknowns in a
COLUMN
How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)?
662 m/s1609 m
How long
t = ?v = 662 m/ss = 1609 m
How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)?
662 m/s1609 m
How long
t = ?v = 662 m/ss = 1609 m
v =st
Step#3: Write the equation needed,
to solve the problem, in the most familiar
form.
Equations as given on the NYS Regents Reference Tables are acceptable as
“the most familiar form”.
How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)?
662 m/s1609 m
How long
t = ?v = 662 m/ss = 1609 m
Step#4: Rearrange the equationsolving for the variable
you are looking for.
v =st
v =
st
t t
v =
s t v v
=
s t v
How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)?
662 m/s1609 m
How long
t = ?v = 662 m/ss = 1609 m
Step#5: Substitute for the known quantities the numerical values along with their
appropriate units.
v =st
v =
st
t t
v =
s t v v
=
s t v
1609 m = t
662 m s
How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)?
662 m/s1609 m
How long
t = ?v = 662 m/ss = 1609 m
Step#6:Solve!
Remember to include units in your answer.
v =st
v =
st
t t
v =
s t v v
=
s t v
1609 m = t
662 m s
t =
2.4 s
Let’s Review.
1. Read the problem.
2. List the knowns and unknowns.
3. Write an equation in the most familiar form.
5. Substitute with numbers and units.
6. Solve and include units in the answer.
4. Rearrange the equation solving for theunknown variable.
Sometimes it helps to draw a simple neat diagram of the problem instead of listing the information
in columnar form.
I’ll demonstrate using a little more complicated problem
how a diagram will help organize the information.
Keep in mind the steps to the
as the problem is solved.
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
1. Read the problem.
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 svo = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
2. List the knowns and unknowns.
a1 = 4 ms2
sT = ?v2 = constant
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
3. Write an equation in the most familiar form.
s1 = vot + at2
2
a1 = 4 ms2
sT = ?v2 = constant
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = vot + at2
2
0
s1 = at2
2
4. Rearrange the equation solving for theunknown variable.
a1 = 4 ms2
sT = ?v2 = constant
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = vot + at2
2
0
s1 = at2
2
s1 = 4 m (3 s)2
2s2
5. Substitute with numbers and units.
a1 = 4 ms2
sT = ?v2 = constant
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = vot + at2
2
0
s1 = at2
2
s1 = 4 m (3 s)2
2s2
s1 = 18 m
6. Solve and include units in the answer.
s1 = 18 m
a1 = 4 ms2
sT = ?v2 = constant
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
3. Write an equation in the most familiar form.
v3 = v0 + a1t
a1 = 4 ms2
sT = ?v2 = constant
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = v0 + a1t0
4. Rearrange the equation solving for theunknown variable.
v3 = a1t
a1 = 4 ms2
sT = ?v2 = constant
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = v0 + a1t0
v3 = a1t
v3 = 4 m (3 s)s2
5. Substitute with numbers and units.
a1 = 4 ms2
sT = ?v2 = constant
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = v0 + a1t0
v3 = a1t
v3 = 4 m (3 s)s2
6. Solve and include units in the answer.
v3 = 12 ms
v23 = 12 ms
a1 = 4 ms2
v3 = 12 ms
v2 = constantbackgroundv2 = 12 mssT = ?
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = 12 ms
v23 = 12 ms
a1 = 4 ms2
3. Write an equation in the most familiar form.
stv =
backgroundv2 = 12 mssT = ?
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = 12 ms
v23 = 12 ms
a1 = 4 ms2
stv =
4. Rearrange the equation solving for theunknown variable.
s = v t
backgroundv2 = 12 mssT = ?
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = 12 ms
v23 = 12 ms
a1 = 4 ms2
stv =
s = v t
5. Substitute with numbers and units.
s = 12 m (20 s)s
backgroundv2 = 12 mssT = ?
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = 12 ms
v23 = 12 ms
a1 = 4 ms2
stv =
s = v t
s = 12 m (20 s)s
s = 240 m
6. Solve and include units in the answer.
s2 = 240 m
backgroundv2 = 12 mssT = ?
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = 12 ms
v23 = 12 ms
a1 = 4 ms2
s2 = 240 m
3. Write an equation in the most familiar form.
stotal = s1 + s2
backgroundv2 = 12 mssT = ?
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = 12 ms
v23 = 12 ms
a1 = 4 ms2
s2 = 240 m
stotal = s1 + s2
4. Rearrange the equation solving for theunknown variable.
backgroundv2 = 12 mssT = ?
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = 12 ms
v23 = 12 ms
a1 = 4 ms2
s2 = 240 m
stotal = s1 + s2
5. Substitute with numbers and units.
stotal = 18 m + 240 m
backgroundv2 = 12 mssT = ?
A car speeding away from a stop sign, accelerates at 4 m/s2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting?
t = 0 s t = 3 s t = 23 sv0 = 0 s v3 = ? v23 = ?
s1 = ? s2 = ?
t2 = 20 s
s1 = 18 m
v3 = 12 ms
v23 = 12 ms
a1 = 4 ms2
s2 = 240 m
stotal = s1 + s2
stotal = 18 m + 240 m
6. Solve and include units in the answer.
stotal = 258 m
WOW!
backgroundv2 = 12 mssT = ?stotal = 258 m
Let’s go over the six steps
Underline key information if needed
Read the problem.
In a column or preferably a diagram.
List the knowns and unknowns.
Write an equation in the most familiar form.
c2 = a2 + b2example
nota = (c2 - b2)
12
Rearrange the equation solving for theunknown variable.
Substitute in the numbers and units.
Solve and include units in the answer.
Draw a box around the answer.