lecture-2
DESCRIPTION
Mech Design of Transporter W2014 (With Slide#)TRANSCRIPT
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Mechanical-Engineering BasedDesign of the Transporter:
Device Geometry, Drive Systems, Power Requirements, Friction Coefficients
R. S. Shaefer
MAE-162D
Mechanical & Aerospace Engineering Department
University of California Los Angeles
Winter 2014
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1/15/2014 2MAE-162D R. S. Shaefer, W14
TOPICS
Machine-shop Training
Project Updates
Teams
Design Concept Report
Conceptual Design Decisions
Vehicle Climbing a Ramp
Wheel Friction Coefficients
Motor Power Requirements
Gear Ratio, Battery Life
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1/16/2014 3MAE-162D R. S. Shaefer, W14
Machine-shop Training
Project Updates
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1/15/2014 4MAE-162D R. S. Shaefer, W14
Project Updates Instead of 5 billiard balls ONLY ONE will be placed in the starting platform.
Teams have to find and move only one randomly placed billiard ball and transport and deliver it to the collection bin and return to the platform (1
roundtrip).
With only one single ball to be transported, the dimensions of the starting platform might not be increased from the current 24 x 24 inches (final
dimensions will be announced by the next lecture).
$350 will be deducted from your teams budget if the IO controller board is damaged (fried).
Water jet use has to be OKd by the TAs or Instructors. In addition $2.50 per minute will be charged for water jet usage.
Use of On/off switch: If a transporter can achieve automated start/stop, without using the on/off switch
more than once during the entire trial, the total number of balls delivered will be
adjusted up by 15%.
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1/16/2014 5MAE-162D R. S. Shaefer, W14
TEAMS
Formed based on Student Survey
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1/15/2014 6MAE-162D R. S. Shaefer, W14
Group 1
Chinn, James
Dashti, Parisa
Petersen, Daniel
Ruff, Carlton
Group 2
Ahn, Min Sung
Hruska, Dylan
Padula, Andrew
Provinchain, Adam
Wong, Brian
Group 3
Ahn, Christopher
Godina, Everardo
Liu, Hsuan-Chen
Pourati, Pouyan
Wong, Tsz
Group 4
Barnett, Kaleen
Kampouridis, Christos
Lee, Jong Hak
Sakamoto, Ryan
Zhang, Yuheng
Group 6
Chen, Joshua
Chow, Kevin
Johnston, Timothy
Okano, Jillian
Ruiz, Hector
Group 5
Apelacio, John Carlo
Brett, Bowers
Calderon, Daniel
Garg Archit
Yang, Brandon
Group 7
Datta, Sanjeev
Matsunami, Kameron
Rechnitz, Jared
Voyen, Nicole
Yagi, Yuki
Group 8
Dissanayake, Ravisha
Jimenez, Marlon
Knox, Allison
Lloyd, James
Stromlund, Adam
Tuesd
ayMAE-162D/E Team Roster (01/16/14)
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1/15/2014 7MAE-162D R. S. Shaefer, W14
Group 9 (No Downeys)
Chan, Brandon
Hee, Bryan
Kitchener, Bryan
Law, Jonathan
Stern, Brian
Tran, Nina
Group 10
Chiu, Caspar
Downey, Brian
Huang, Wen-Chieh
Meirovitch, Daniel
Shafer, Melissa
Group 11
Hsu, Jonathan
Phan, Tri
Sarabian, Chareena
Sundin, Stephen
Vasko, David
Group 12
Delgado, Kristine
Flynn, Michael
Gloutak, Dasha
Hollins, Asya
Song, James
Group 14
Jones, Luke
Lee, Thomas
McKittrick, Michael
Neff, Samuel
Warwick, Mark
Group 13
Edstrom, Mark
Le, Dai
Liu, Kevin
Tate, Austin
Winters, Zachary
Group 15
Kinoshita, Alan
Lam, Betty
Lee, Joseph
Levin, Cole
Sun, Daniel
Group 16
Chung, Boris
Coleman, Matthew
Dimapasoc, Brando
Holden, Emily
Kurihara, Matthew
Wed
nesd
ay
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1/15/2014 8MAE-162D R. S. Shaefer, W14
Group 17
Chatterjee, Shinjan
Hsu, Eric
Ricciardelli, Albert
Shin, Seung Ryul
Suh, Jungwoo
Group 18
Garcia, Aurora
Nishioka, Crystal
Tang, Yang
Wood, Kevin
Yamayoshi, Itsui
Group 19
Hakobyan, Vardan
Pajuelo Lopez, Paulo
Partusch, Vincent
Ramirez, Ricardo
Tang, Emily
Group 21
Cooper, Andwele
Cooper, Cody
Moore, Danielle
Saad, Hassan
Sheu, Oliver
Group 20
August-Schmidt, Alex
Hwang, Jae Woong
Kwak, Wooyoung
Wong, Jameson
Friday
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9MAE-162D R. S. Shaefer, W14
Team Structure
Establish who will be :
o Project Manager, Mechatronics Engineer, Systems
Engineer and Cognizant Engineer
Upload an excel spreadsheet with the following structure by next lecture:
(template has been uploaded to courseweb)
Name the excel spreadsheet: Team-YOUR#-Structure.xlsx
Team #
Project Manager Name email address
Mechatronics Engr. Name email address
Systems Engr. Name email address
Cognizant Engr. Name email address
Cognizant Engr. Name email address
Cognizant Engr. Name email address
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1/16/2014 10MAE-162D R. S. Shaefer, W14
Conceptual Design Report(due next Friday, Jan. 24, 2014)
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11MAE-162D R. S. Shaefer, W14
Conceptual Design Outline
Report Word-2013 template has been uploaded to courseweb
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Examples of Concept Sketches
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1/15/2014 13MAE-162D R. S. Shaefer, W14
Examples of Acceptable Hand-sketches
MAE-94 Fall 2013
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14MAE-162D R. S. Shaefer, W14
Developing Design Concepts
Meet at least two times between now and next Friday and establish team structure
At this stage you are developing the mechanical portion of your project (the control and feedback will come later)
Therefore, assume your device has found the ball and you are only concerned with designing a product that will deliver the ball to the drop-off bin.
Also, do not be concerned about how you will find the entrance to the ramp.
However, you need to think about how the device will:
change directions,
initiate the move up the ramp,
turns the ramp corners (mechanical aspect only),
stops in the unloading platform, and
releases the ball into the bin.
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1/15/2014 15MAE-162D R. S. Shaefer, W14
Design Process
Need
Conceptual Design
Preliminary Design
Detailed Design
Product Specifications
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1/15/2014 16MAE-162D R. S. Shaefer, W14
Lecture TOPICS
Mechanical Engineering Based Design :
1. Design Concept Overall Geometry ?
2. Drive System for a Vehicle Climbing
a Ramp ?
3. Wheel Friction Coefficients ?
4. Motor Power Requirements ?
5. Gear Ratio, Battery Life ?
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1/15/2014 17MAE-162D R. S. Shaefer, W14
Maximize speed of delivery
Limitations: 5 min
Budget: $350
Need to establish
necessary traction
force (friction
coefficient)
Want to supply sufficient traction force
at minimum required power
Need to know
required power:
to get the right motor
Length ?
Width ?
Height ?
Wheelbase & Track ?Wheel size &
Material?
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1/15/2014 18MAE-162D R. S. Shaefer, W14
Conceptual Design Decisions
For the conceptual design a number of primary design parameters have to be established:
Overall device dimensions (height, length, width)
Cargo delivery system (mechanism)
Speed and load capacity (device + cargo) (time per run)
Drive system (AWD, FWD, RWD)
Wheel size (diameter)
Wheel position (track & wheel base)
Wheel material (necessary friction to climb)
Motor Power minimum requirements (speed and # of runs)
Gear Ratio (speed/power)
Choice of design parameters must be based on engineering fundamentals (todays lecture)
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1/15/2014 19MAE-162D R. S. Shaefer, W14
Vehicle Climbing an Incline Plane Examine the physics behind wheeled vehicles climbing
slopes for:
Front Wheel Drive (FWD)
Rear Wheel Drive (RWD)
Four Wheel Drive (AWD)
Step (over an obstacle)
Questions:
What is the minimum wheel/surface friction coefficient necessary to avoid slipping, what is the tip-over angle?
What is the minimum Tractional Force necessary to climb?
What is the appropriate drive system: FWD, RWD, or AWD?
http://hpwizard.com/car-
performance.html
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Vehicle Driving Up a Slope
Fm = gravitational force on the machine
Nf = normal force of both front wheels
Nr = normal force of both rear wheels
Ftf = Nf Tractional force of both FWs, caused by static friction Ftr = Nr Tractional force of both RWs, caused by static friction
= coefficient of friction, q = angle of incline plane
x
L
LC
y q
Ftf
Ftr
Nr
Nf
Fmhc
FW
RW
L = distance between FW and RW
Lc = distance between RW & center of mass
hc = height of the center of mass
20
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Front and Rear Wheel Tractive Forces (Ftf, Ftr)
0 : 0
0 : 0
( )
:
y r f m
r m f m C
m C mf
m C mr
tr r
tf f
F N N F cos
M F h sin N L F L cos
F L cos F h sinN
L
F L L cos F h sinN
L
R ear and Front Tractive Forces
F N
F N
q
q q
q q
q q
Using Free Body Diagram:
21
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What happens when Nf zero ?
x
L
LC
y q
Ftf
Ftr
Nr
Fmhc
FW
RW
Nf 0
Nf
22
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Tip-over Angle
When designing your transporter the location of the center of gravity of your system has to be established for the Preliminary Design Report): use SolidWorks to establish the coordinates of the center of gravity of your
device assign correct materials and include the cargo
Ramp angles are set the COM (hc, Lc) and L of your transporter can be optimized.
Write a simple program or use an excel spread-sheet to modify dimensions to optimize dimensions of your design
max
0 : 0m C m cf
C
F L cos F h sinN
L
Lh
tan
q q
q
tan qmax = Lc / hmax
Tip-over angle when Nf = 0: q = qmax and maximum COM* height h = hmax
*COM Center of Mass 23
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Required Friction Coefficient for AWD, FWD, RWD
0 : 0
0 : 0
0 : 0
0 : 0
( )
( )( )
x r f m
x r r f f m
y r f m
r m f m C
m C mf
m C mr
r f C r
F N N F sin
F N N F sin
F N N F cos
M F h sin N L F L cos
F L cos F h sinN
L
F L L cos F h sinN
L
L sin
h sin L cos L cos
T
q
q
q
q q
q q
q q
q
q q q
1
: ;
: tan
Tf f Tr r
C
ractive Forces F N F N
LTipping angle
h
q
f r
f r
f r
FWD set =1 and =0
RWD set =0 and =1
AWD set =1 and =1
Required friction
coefficient based on
DRIVE SYSTEM &
Device dimensions24
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COEFFICIENT OF FRICTION
FOR
AWD, FWD, & RWD
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Required Tractive Forces
FTf = Nf Tractional force of both FWsFTr = Nr Tractional force of both RWs
What is the minimum required (= ?)
for a given transporter drive system and ramp slope q
x
L
LC
y q
FTf
FTr
Nr
Nf
Fmhc
FW
RW
26
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Estimate Required Wheel Coefficient of Friction
The necessary static coefficient of friction () depends on powering mode:
Four Wheel Drive 4WD
Front Wheel Drive FWD
Rear Wheel Drive RWD
4 4
4
tr tf m
r WD f WD m
WD
F F F sin
N N F sin
tan
q
q
q
4 Wheel Drive 4WD
Minimize required coefficient of friction depends only on angle?
Decrease by decreasing the incline (cant ramp slope is set !)
(slide 24)
27
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Estimating Necessary Coefficient of Friction
1
f FWD m
FWDC
N F sin
L h
L tan L
q
q
Front Wheel Drive FWD
How can the required coefficient of friction be minimized?
Move the center of gravity forward
Shorten the wheelbase (L)
Lower the height of the center of gravity (hc)
28
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Estimating Necessary Coefficient of Friction
1
r RWD m
RWDC
N F sin
L L h
L tan L
q
q
Rear Wheel Drive RWD
What can be modified to allow for a lower coefficient of friction?
Move the center of gravity towards the RWs (reduce Lc)
Increase the wheelbase (L)
Raise the height (hc) of the center of gravity
29
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Required Coefficient of Friction
Depending on drive-system (FWD or RWD) the required wheel friction coefficient can be
minimized by adjusting device geometry:
L Lc hc4WD NA NA NA
FWD RWD
:
Tf f
Tr r
Tractive Forces
F N
F N
1: tan C
LTipping
hq
30
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Required Coefficient of Friction
The distance of the Center of Gravity from the rear wheels can be chosen such that either RWD and FWDwill require the same minimum coefficient of friction.
For equal FWD and RWD minimum coefficient of frictions we can solve for LC-F/RWD :
Positioning the Center of Gravity at LC-F/RWD provides design flexibility
/ tan2
FWD RWD
C F RWD
LL h
q
31
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Determining Optimum Drive System
Example:
Given device dimensions L, h, and slope What would be the best drive
system: FWD, RWD, or AWD
Investigate the impact of the distance of the CG from the rear wheels (Lc).
Dimensions are as follows: Wheel base (L) 12 inch Height of CG (h) 7 inch Angle (theta) 10o
On the next slide we compare the friction coefficients for FWD, RWD, and AWD
32
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1/15/2014 33MAE-162D R. S. Shaefer, W14
Minimum Required Friction Coeff. The graph shows that the required friction coefficients -FWD and -RWD are
equal for an Lc-F/RWD = 7.234 inches from the rear wheels:
The lowest required minimum coeff. of friction is for AWD (which would require the smallest tractive force (FT) to drive the vehicle up the slope). However the
additional weight, complexity, and cost of an AWD system has to be considered.
Device Dims.:
L = 12 inch
h = 7 inch
q = 10o
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1/15/2014 34MAE-162D R. S. Shaefer, W14
For the Preliminary Design Decide on the Best Drive System
Compare the friction coefficients for FWD, RWD, and AWD and pick the smallest one, which requires the least amount of power to drive the vehicle up the slope.
Finally, compare the estimated required minimum coefficient of friction with your measured wheel/surface coefficient (-Wheel) to guarantee that the vehicle will not skid backwards.
1. First, measure the coefficient of
friction (Slide #19) between your
wheel and the sloped surface:
-Wheel
2. Next, determine the coefficient of
frictions between your vehicle and
the slope for the drive systems:
FWD, RWD, AWD
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MEASURING COEFFICIENT OF
FRICTION
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Measure Wheel Coefficient of Friction
2 2
cosm mN F F sin
htan
L h
q q
q
Coefficient of Friction:
Perform a simple inclined plane test
Use hypotenuse length ~ 50 cm
Raise end of ramp until test car slips
Measure h and calculate
Coefficient of friction
Plywood
Wheel surface along grain across grain
Plain 0.45 0.47
Knurled 0.47 0.48
Sandpaper covered 0.91 0.92
36
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1/15/2014 37MAE-162D R. S. Shaefer, W14
Fraction of Weight on Front/Rear Wheels on an Incline
( )
( )
m C mf
f Cf
m
m C mr
Crr
m
F L cos F h sinN
L
N L cos h sin
F L
F L L cos F h sinN
L
L L cos h sinN
F L
q q
q q
q q
q q
Dividing the normal forces on the wheels (slide 26)
by the total weight gives fractional distribution of
weight (r,f) :
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1/15/2014 38MAE-162D R. S. Shaefer, W14
Measure Wheel Coefficient of Friction
Assuming you have decided the following for your concept:
4-wheel drive, 2-wheel rear, or 2-wheel front drive
Maximum size of the device
Amount of rice per run
Approximate time to deliver the load
You have estimated the minimum coefficient of friction required to go up the plywood ramp
You can now try different materials and see if they will provide the necessary coefficient of friction
You can approximate the overall dimension and coordinates of the center of gravity
And you can now estimated the required total power/torque necessary to deliver the load
And therefore you can start looking at motors, and decide how many motors you should use.
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POWER TO MOVE A VEHICLE
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Required Power to Move a Vehicle & Minimum min
2
2 efficiency
at F vx v at F ma P
For a machine of mass m to move a distance x under constant
acceleration a in time t:
2
2 2 3
2 2 2 4
efficiency
x x xm mxa v F P
t t t t
Solving for the power consumed in terms of m, x, and t: :
min( )F
F N F mgmg
If the percent weight of the vehicle over the drive wheels is , then the minimum coefficient of friction between the drive wheels and the ground is:
Create an excel spread-sheet to calculate a (m/s2), F (N), min, vmax, P (Watts)40
-
22 efficiency
at F vx v at F ma P
2
2 2 3
2 2 2 4
efficiency
x x xm mxa v F P
t t t t
min( )F
F N F mgmg
Excel Spread-sheet to calculate a(m/s2), F(N), min, vmax, P (W)
Distance to move, x (m) 2.0 m
Desired move time, t (sec) 3.0 s
Mass, m (kg) 3.0 kg
Estimated system efficiency, eta 50% --
% vehicle weight over drive wheels, beta 50% --
Power per motor, wm (Watts) 2.0 W
Acceleration required, a (m/s 2^, g's) 0.44 m/s2 0.05 g's
Force required, F (N) 1.33 N
Min. coeff. of friction drive wheels to ground, mu_min 0.09 --
Maximum velocity (at end of move), v (m/s) 1.33 m/s
Power required, P (Watts) 3.56 W
Motors required 2 --
Enters numbers in BOLD, Results in RED
Power Required to Move
To estimate the power to move a mass m a distance x with constant
41
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Example: Choosing a Go-Kart Motor
The challenge:
Build a Go-Kart that goes up a 30o hill at 4 mph (m = 90 lb, wheel diameter is 10 inch).
You are given a 9 amp-hour battery to power the Go-Kart.
For the motor you have two options :
Motor-1: Electric motor, which draws about 20 A to produce1 Hp with a torque of 60 N-m at 150 rpm. The motor costs $167.99.
Motor-2: Electric motor that puts out 0.4 Hp at 2500 rpm drawing ~ 5 A. The motor costs $37.59.
Which motor will you choose and why?42
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Required Motor Power
Given: Electric Motor: 0.4 Hp at 2500 rpm
Hill Slope: 30o
Design Requirements: Max speed 4 mph (up a hill of 30o)
Wheel diameter 10 in
Total Mass 90 lb
Approach: First determine the necessary POWER needed to move the
Go-kart up the hill.
Next, determine the gear ratio to achieve the necessary torque at the wheels.
43
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Estimating Required Power
Force to move the Go-kart :
Freq: total required force
FW : vertical component of weight
Ff : friction force
Frol: rolling force
FInertia: overcome inertia (assume v = 0.25 m/s in 1 s ainertia =0.25 m/s2)
Estimated the required force using:
f = 0.35
rol = 0.015
Required Power:
v is steady state velocity
(vtan = r w; w in rad/s))
req Inertia W f rolF F F F F
sin
cos
337.00 N
req Inertia
f rol
F ma mg
mg
q
q
337.00 N 1.79 m/s
602.56 W
req reqP F v
44
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Estimate Required Torque for Go-Kart & Motor
Torque Power Relation: P is the motor power
w is the angular velocity
Motor produces 0.4 Hp at 2500 rpm*:
For a 5 inch radius wheel at 4 mph*:
Necessary torque to drive the cart at 4 mph:
mm m m m
m
PP T Tw
w
1.15mT N m
1.79 /14.08 / 134.45
0.13
v m srad s rpm
r mw
1 rad/s = (2/60) rpm req mT T
602.5642.80
14.08 /
req
req
P WT N m
rad sw
*Note that the units actually come out as 1/s (Hz);
however, radians are a suppressed unit
with regards to angular velocity
so we write (rad)/s45
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Determine the Gear Ratio and Battery Lifetime
TMotor is less than TRequired
Requires gearing determine gear ratio (GR):
1.14 42.80m reqT N m T N m
46
-
Determine the Gear Ratio and Battery Lifetime
Tmotor is less than Trequired
Gear ratio:
Use a gear ratio of 40
Battery Lifetime: Motor currents are rated at 5 A and 20 A each:
1 29 1 48 ; 275
Motor Motor
time time
amp hourB hr min B min
amp
42.8037.56
1.14
req
m
TGR
T
1.14 42.80m reqT N m T N m
47
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MOTOR SPEED, POWER, AND
TORQUE
-
Stall Torque and No-Load Speed
Assuming steady state and no slippage between wheel and ground:
Torque (T):
if r is not :
Stall Torque (ts): The minimum torque needed to completely stop the motor
shaft from rotating (stalling the motor). Units are ft-lbs or Nm.
No-Load Speed (wn): The rotational speed of the motor shaft when there is NO
torque being applied to it. Units are RPM or rad/s
T r
F
(1)T F r
sin (2)T F r q
49
-
Motor Torque Speed and Power TRADEOFF
Using eq. 1 we can define the following :
The plot of eq. 3 or 4 is calleda torque-speed curve.
Example: A motor has a no-load speed of 95 RPM and a stall-Torque of 0.6 Nm:
T r
F
(3)
or in terms of :
( ) (4)
ss
n
ns
s
TT T
T TT
ww
w
ww
Stall Torque ts )
no-load Speed (wn)
50
-
Torque -Speed Curves
If we know the torque applied to the motor shaft we can find how fast the motor will rotate.
Or if we know how fast we want the motor to spin, we can find how much torque should be applied.
Stall Torque
no-load Speed
Motor Specs.
often list
no-load Speed
Lo
w P
ow
er
Low Power
Max Power
m m m
mm
m
P T
PT
w
w
51
-
Motor Power
Recall:
If we multiply eq. 3 by w or eq. 4 by T we get power as a functions of either torque or velocity:
These quadratic equations are shown on the next slide:
(5)P T w
2
2
( ) (6)
( ) (7)
ss
n
nn
s
TP T
P T T TT
w w ww
ww
(3)
( ) (4)
ss
n
ns
s
TT T
T TT
ww
ww
52
-
Motor Power as functions of w orT :
There is a maximum power for a given range of speed and torque.
For optimum performance, the motor should be operating at torque and speed corresponding to the maximum power.
The optimum torque and speed are at about half Ts and wn respectively.
The maximum power available is (Ts wn )/4 53
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Maximum Velocity and Torque
If k (speed-torque slope) is known then relate torque, power, and velocity:
max
max
max
2
max
max
max smax max
0 2
; 2 2
P P
k
k
P k
Pk
t w t
t
w
t w w t w
w tw
w tw t
54
-
Motor Power
Given: tmax= 9 N-mm, wmax= 14000 rpm, tw slope (k) = - 0.006 the motor torque and power for w-increments of 200 rpm are:
0.0
0.5
1.0
1.5
2.0
2.5
3.0
3.5
0
1
2
3
4
5
6
7
8
9
10
0 2000 4000 6000 8000 10000 12000 14000
Po
we
r (W
atts)
To
rqu
e (
N-m
m)
Motor Speed (rpm)
Torque (N-mm)
Power (Watts)
Note: max
power is not
at maximum
torque or
speed
55
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Concept Design Procedure
After you have made the following concept design decisions:
Drive system (4-wheel, 2-wheel rear, or 2-wheel front)
Maximum size of the device (height, length, width)
Cargo weight per run (dont forget weight of the transporter)
Approximate time to deliver a billiard ball (tmax = 2 4 min ?)
You can now refine your conceptual design based on the following mechanical engineering fundamentals:
1. Estimate the minimum coefficient of friction (m) required to climb the
plywood ramp
2. Establish candidate wheel materials provide the necessary m
3. Establish the overall dimension of your device and coordinates of the
center of gravity (L, LC, h)
4. Estimate the required power/torque necessary to deliver the load
5. Research motors, and decide what motor and/or how many you
should use including gearing requirements (use plot torque-speed
curves to estimate maximum torque and RPMs)
6. Approximate battery power consumption (more on this next lecture) 56
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1/15/2014 57MAE-162D R. S. Shaefer, W14
Background Slides
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58MAE-162D R. S. Shaefer, W14
Need for Standards: Inch Converter (Mid 19th Century)
Hamburgh - Inch divided into 8 parts. 1 inch 23.2 mmAustrian - Inch divided into 8 parts. 1 inch 25.8 mmItallian - Inch divided into 8 parts. 1 inch 28.3 mmBremen - Inch divided into 10 parts. 1 inch 23.7 mmSwedish - Inch divided into 12 parts. 1 inch 24.3 mmTurkish - Inch divided into 12 parts. 1 inch 31.3 mmBavarian - Inch divided into 12 parts. 1 inch 24.0 mmSpanish - Inch divided into 12 parts. 1 inch 23.0 mm
Portuguese - Inch divided into 12 parts. 1 inch 27.0 mmMoscow - Inch divided into 12 parts. 1 inch 27.7 mmRussian - Vershok divided into 8 parts. 1 vershok 44.1 mmAmsterdam - Inch divided into 12 parts. 1 inch 23.5 mmRhynland - Inch divided into 12 parts. 1 inch 26.1 mmFrench - Inch divided into 12 parts. 1 inch 27.0 mmFr. Metre - Centimetres divided into Millimetres.
English - Inch divided into 32 parts. 1 inch 25.3 mm
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The parts of a mill and what they do (1/5)
Parts of a mill and what they do.
Variable Speed Control KnobControls motor speed from 0 to 2800 RPM
HeadstockContains the spindle in two preloaded ball bearings.
SpindleThe spindle is inside the headstock and is driven with a belt running from the motor pulley to a pulley on the rear end of the
spindle shaft. The nose of the spindle is treaded on the outside to
receive chucks and tapered on the inside to receive other
accessories.
Drill ChuckUsed to hold drill bits for drilling holes. (Not to be used to hold end mills!)
Mill TableParts are fixed to the table using a vise, chuck or clamps and moved under the milling cutter using the X- and Y-axis
handwheels.
Mill SaddleThe mill saddle slides in and out (Y-axis) on the mill base. The mill table moves left and right (X-axis) on top of the
saddle.
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Headstock SaddleThe saddle on the vertical column that moves the headstock (Z-Axis) up and down by means of a leadscrew and handwheel.
Mill ColumnThe steel dovetailed column that is held to the mill column base and supports the Z-axis saddle and headstock.
LeadscrewThe threaded screws that move the table left/right and in/out as well as the vertical axis up and down. They are driven by handwheels
marked in .001" or .01 mm increments.
Leadscrew Locking LeverLocated on the back side of the vertical column, this locking lever locks against the saddle nut to prevent unwanted
movement of the Z-axis during machining operations. Manual machines are
fitted with a standard on/off locking lever. CNC machines are fitted with an
adjustable locking lever that can be used to control backlash in the Z-axis.
This function is available as an option on any manual mill as well. (P/N
4017U inch or 4117U metric)
GibsTapered plastic gibs are used on each dovetailed axis to take up wear as it occurs. They are slightly wedge shaped. As side-to-side "slop"
develops on an axis, the gib lock is loosened and the gib is pushed a little
further into the gap, taking up the play. These allow the machine to always
be kept as tight as the operator desires. If or when they wear out, they are
very inexpensive to replace.
The parts of a mill and what they do (2/5)
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Mill BaseThe solid base that has the dovetail for the saddle to move in and out on and to which the mill column is attached.
DrawboltGoes through the hole in the spindle to draw chucks and other accessories into the headstock taper inside the spindle. A special washer
locates in on center in the spindle hole.
#1 Morse ArborThe arbor screws into the back of the drill chuck so it can be used in the headstock. It is held in place in the #1 Morse taper with the
drawbolt.
Tommy BarsRound steel bars used to tighten and loosen chucks and other spindle accessories. Sometimes called "Spindle Bars."
Y-axis Locking ScrewA thumbscrew on the side of the base that keeps the saddle from moving in and out when tightened.
X-axis Locking ScrewA screw that goes through the barrel lock on the front of the saddle to lock the table in place during machining operations where
movement is not required or desired.
The parts of a mill and what they do (3/5)
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Backlash LocksThe lock works like tightening two nuts against each other on a threaded shaft to reduce play in the threads.
Backlash is the pause in travel when changing direction of rotation of any threaded crew. Because both sides of the thread don't rub on the nut at the
same time (they would quickly wear out), one surface is pulling or pushing the
nut when the screw is turned.
When you stop and change directions, the screw turns a slight amount while the thread picks up the other side and begins to move the nut in the other
direction. The looser the fit of the threads, the more "backlash" occurs.
In essence, it is the amount you can turn the handwheel in the reverse direction before movement occurs on an axis. An adjustment is provided on the X- and
Y-axes to reduce the leadscrew backlash.
Backlash is not a "fault" of a machine, it is simply a physical reality that must be taken into account when machining. You adjust to a known or acceptable
amount using the locks and then remove it from the machining operation by
always approaching your cut from the same direction with the backlash already
eliminated before the cut begins.
The parts of a mill and what they do (4/5)
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Alignment KeyA precision ground key that fits in a slot in the column saddle to keep the headstock aligned straight up and down. A second
slot is also provided to locate the headstock at 90 for horizontal
milling. Removing this key and rotating the headstock allows bevels to
be cut at any angle. An approximate angle scale is laser engraved into
the saddle for reference.
Headstock Spacer BlockMoves the headstock 1.25" further out from the saddle to increase the "throat" distance (distance between
cutter and column). It is optional on 5000-series mills, standard on
5400-series mills and not needed on 2000-series mills because the ram
can be used to adjust this distance.
V-beltA Kevlar-reinforced Urethane belt that drives the spindle through the pulleys.
2-position PulleyThe normal (rear) position gears the motor down about 2:1 for a maximum speed of about 2800 RPM. The "High
Torque" position (closest to the headstock) gears it about 4:1 for lower
speed but more torque when needed for heavy cuts.
The parts of a mill and what they do (5/5)