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Mechanical-Engineering Based Design of the Transporter: Device Geometry, Drive Systems, Power Requirements, Friction Coefficients R. S. Shaefer MAE-162D Mechanical & Aerospace Engineering Department University of California Los Angeles Winter 2014

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Mech Design of Transporter W2014 (With Slide#)

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  • Mechanical-Engineering BasedDesign of the Transporter:

    Device Geometry, Drive Systems, Power Requirements, Friction Coefficients

    R. S. Shaefer

    MAE-162D

    Mechanical & Aerospace Engineering Department

    University of California Los Angeles

    Winter 2014

  • 1/15/2014 2MAE-162D R. S. Shaefer, W14

    TOPICS

    Machine-shop Training

    Project Updates

    Teams

    Design Concept Report

    Conceptual Design Decisions

    Vehicle Climbing a Ramp

    Wheel Friction Coefficients

    Motor Power Requirements

    Gear Ratio, Battery Life

  • 1/16/2014 3MAE-162D R. S. Shaefer, W14

    Machine-shop Training

    Project Updates

  • 1/15/2014 4MAE-162D R. S. Shaefer, W14

    Project Updates Instead of 5 billiard balls ONLY ONE will be placed in the starting platform.

    Teams have to find and move only one randomly placed billiard ball and transport and deliver it to the collection bin and return to the platform (1

    roundtrip).

    With only one single ball to be transported, the dimensions of the starting platform might not be increased from the current 24 x 24 inches (final

    dimensions will be announced by the next lecture).

    $350 will be deducted from your teams budget if the IO controller board is damaged (fried).

    Water jet use has to be OKd by the TAs or Instructors. In addition $2.50 per minute will be charged for water jet usage.

    Use of On/off switch: If a transporter can achieve automated start/stop, without using the on/off switch

    more than once during the entire trial, the total number of balls delivered will be

    adjusted up by 15%.

  • 1/16/2014 5MAE-162D R. S. Shaefer, W14

    TEAMS

    Formed based on Student Survey

  • 1/15/2014 6MAE-162D R. S. Shaefer, W14

    Group 1

    Chinn, James

    Dashti, Parisa

    Petersen, Daniel

    Ruff, Carlton

    Group 2

    Ahn, Min Sung

    Hruska, Dylan

    Padula, Andrew

    Provinchain, Adam

    Wong, Brian

    Group 3

    Ahn, Christopher

    Godina, Everardo

    Liu, Hsuan-Chen

    Pourati, Pouyan

    Wong, Tsz

    Group 4

    Barnett, Kaleen

    Kampouridis, Christos

    Lee, Jong Hak

    Sakamoto, Ryan

    Zhang, Yuheng

    Group 6

    Chen, Joshua

    Chow, Kevin

    Johnston, Timothy

    Okano, Jillian

    Ruiz, Hector

    Group 5

    Apelacio, John Carlo

    Brett, Bowers

    Calderon, Daniel

    Garg Archit

    Yang, Brandon

    Group 7

    Datta, Sanjeev

    Matsunami, Kameron

    Rechnitz, Jared

    Voyen, Nicole

    Yagi, Yuki

    Group 8

    Dissanayake, Ravisha

    Jimenez, Marlon

    Knox, Allison

    Lloyd, James

    Stromlund, Adam

    Tuesd

    ayMAE-162D/E Team Roster (01/16/14)

  • 1/15/2014 7MAE-162D R. S. Shaefer, W14

    Group 9 (No Downeys)

    Chan, Brandon

    Hee, Bryan

    Kitchener, Bryan

    Law, Jonathan

    Stern, Brian

    Tran, Nina

    Group 10

    Chiu, Caspar

    Downey, Brian

    Huang, Wen-Chieh

    Meirovitch, Daniel

    Shafer, Melissa

    Group 11

    Hsu, Jonathan

    Phan, Tri

    Sarabian, Chareena

    Sundin, Stephen

    Vasko, David

    Group 12

    Delgado, Kristine

    Flynn, Michael

    Gloutak, Dasha

    Hollins, Asya

    Song, James

    Group 14

    Jones, Luke

    Lee, Thomas

    McKittrick, Michael

    Neff, Samuel

    Warwick, Mark

    Group 13

    Edstrom, Mark

    Le, Dai

    Liu, Kevin

    Tate, Austin

    Winters, Zachary

    Group 15

    Kinoshita, Alan

    Lam, Betty

    Lee, Joseph

    Levin, Cole

    Sun, Daniel

    Group 16

    Chung, Boris

    Coleman, Matthew

    Dimapasoc, Brando

    Holden, Emily

    Kurihara, Matthew

    Wed

    nesd

    ay

  • 1/15/2014 8MAE-162D R. S. Shaefer, W14

    Group 17

    Chatterjee, Shinjan

    Hsu, Eric

    Ricciardelli, Albert

    Shin, Seung Ryul

    Suh, Jungwoo

    Group 18

    Garcia, Aurora

    Nishioka, Crystal

    Tang, Yang

    Wood, Kevin

    Yamayoshi, Itsui

    Group 19

    Hakobyan, Vardan

    Pajuelo Lopez, Paulo

    Partusch, Vincent

    Ramirez, Ricardo

    Tang, Emily

    Group 21

    Cooper, Andwele

    Cooper, Cody

    Moore, Danielle

    Saad, Hassan

    Sheu, Oliver

    Group 20

    August-Schmidt, Alex

    Hwang, Jae Woong

    Kwak, Wooyoung

    Wong, Jameson

    Friday

  • 9MAE-162D R. S. Shaefer, W14

    Team Structure

    Establish who will be :

    o Project Manager, Mechatronics Engineer, Systems

    Engineer and Cognizant Engineer

    Upload an excel spreadsheet with the following structure by next lecture:

    (template has been uploaded to courseweb)

    Name the excel spreadsheet: Team-YOUR#-Structure.xlsx

    Team #

    Project Manager Name email address

    Mechatronics Engr. Name email address

    Systems Engr. Name email address

    Cognizant Engr. Name email address

    Cognizant Engr. Name email address

    Cognizant Engr. Name email address

  • 1/16/2014 10MAE-162D R. S. Shaefer, W14

    Conceptual Design Report(due next Friday, Jan. 24, 2014)

  • 11MAE-162D R. S. Shaefer, W14

    Conceptual Design Outline

    Report Word-2013 template has been uploaded to courseweb

  • 1/15/2014 12MAE-162D R. S. Shaefer, W14

    Examples of Concept Sketches

  • 1/15/2014 13MAE-162D R. S. Shaefer, W14

    Examples of Acceptable Hand-sketches

    MAE-94 Fall 2013

  • 14MAE-162D R. S. Shaefer, W14

    Developing Design Concepts

    Meet at least two times between now and next Friday and establish team structure

    At this stage you are developing the mechanical portion of your project (the control and feedback will come later)

    Therefore, assume your device has found the ball and you are only concerned with designing a product that will deliver the ball to the drop-off bin.

    Also, do not be concerned about how you will find the entrance to the ramp.

    However, you need to think about how the device will:

    change directions,

    initiate the move up the ramp,

    turns the ramp corners (mechanical aspect only),

    stops in the unloading platform, and

    releases the ball into the bin.

  • 1/15/2014 15MAE-162D R. S. Shaefer, W14

    Design Process

    Need

    Conceptual Design

    Preliminary Design

    Detailed Design

    Product Specifications

  • 1/15/2014 16MAE-162D R. S. Shaefer, W14

    Lecture TOPICS

    Mechanical Engineering Based Design :

    1. Design Concept Overall Geometry ?

    2. Drive System for a Vehicle Climbing

    a Ramp ?

    3. Wheel Friction Coefficients ?

    4. Motor Power Requirements ?

    5. Gear Ratio, Battery Life ?

  • 1/15/2014 17MAE-162D R. S. Shaefer, W14

    Maximize speed of delivery

    Limitations: 5 min

    Budget: $350

    Need to establish

    necessary traction

    force (friction

    coefficient)

    Want to supply sufficient traction force

    at minimum required power

    Need to know

    required power:

    to get the right motor

    Length ?

    Width ?

    Height ?

    Wheelbase & Track ?Wheel size &

    Material?

  • 1/15/2014 18MAE-162D R. S. Shaefer, W14

    Conceptual Design Decisions

    For the conceptual design a number of primary design parameters have to be established:

    Overall device dimensions (height, length, width)

    Cargo delivery system (mechanism)

    Speed and load capacity (device + cargo) (time per run)

    Drive system (AWD, FWD, RWD)

    Wheel size (diameter)

    Wheel position (track & wheel base)

    Wheel material (necessary friction to climb)

    Motor Power minimum requirements (speed and # of runs)

    Gear Ratio (speed/power)

    Choice of design parameters must be based on engineering fundamentals (todays lecture)

  • 1/15/2014 19MAE-162D R. S. Shaefer, W14

    Vehicle Climbing an Incline Plane Examine the physics behind wheeled vehicles climbing

    slopes for:

    Front Wheel Drive (FWD)

    Rear Wheel Drive (RWD)

    Four Wheel Drive (AWD)

    Step (over an obstacle)

    Questions:

    What is the minimum wheel/surface friction coefficient necessary to avoid slipping, what is the tip-over angle?

    What is the minimum Tractional Force necessary to climb?

    What is the appropriate drive system: FWD, RWD, or AWD?

    http://hpwizard.com/car-

    performance.html

  • Vehicle Driving Up a Slope

    Fm = gravitational force on the machine

    Nf = normal force of both front wheels

    Nr = normal force of both rear wheels

    Ftf = Nf Tractional force of both FWs, caused by static friction Ftr = Nr Tractional force of both RWs, caused by static friction

    = coefficient of friction, q = angle of incline plane

    x

    L

    LC

    y q

    Ftf

    Ftr

    Nr

    Nf

    Fmhc

    FW

    RW

    L = distance between FW and RW

    Lc = distance between RW & center of mass

    hc = height of the center of mass

    20

  • Front and Rear Wheel Tractive Forces (Ftf, Ftr)

    0 : 0

    0 : 0

    ( )

    :

    y r f m

    r m f m C

    m C mf

    m C mr

    tr r

    tf f

    F N N F cos

    M F h sin N L F L cos

    F L cos F h sinN

    L

    F L L cos F h sinN

    L

    R ear and Front Tractive Forces

    F N

    F N

    q

    q q

    q q

    q q

    Using Free Body Diagram:

    21

  • What happens when Nf zero ?

    x

    L

    LC

    y q

    Ftf

    Ftr

    Nr

    Fmhc

    FW

    RW

    Nf 0

    Nf

    22

  • Tip-over Angle

    When designing your transporter the location of the center of gravity of your system has to be established for the Preliminary Design Report): use SolidWorks to establish the coordinates of the center of gravity of your

    device assign correct materials and include the cargo

    Ramp angles are set the COM (hc, Lc) and L of your transporter can be optimized.

    Write a simple program or use an excel spread-sheet to modify dimensions to optimize dimensions of your design

    max

    0 : 0m C m cf

    C

    F L cos F h sinN

    L

    Lh

    tan

    q q

    q

    tan qmax = Lc / hmax

    Tip-over angle when Nf = 0: q = qmax and maximum COM* height h = hmax

    *COM Center of Mass 23

  • Required Friction Coefficient for AWD, FWD, RWD

    0 : 0

    0 : 0

    0 : 0

    0 : 0

    ( )

    ( )( )

    x r f m

    x r r f f m

    y r f m

    r m f m C

    m C mf

    m C mr

    r f C r

    F N N F sin

    F N N F sin

    F N N F cos

    M F h sin N L F L cos

    F L cos F h sinN

    L

    F L L cos F h sinN

    L

    L sin

    h sin L cos L cos

    T

    q

    q

    q

    q q

    q q

    q q

    q

    q q q

    1

    : ;

    : tan

    Tf f Tr r

    C

    ractive Forces F N F N

    LTipping angle

    h

    q

    f r

    f r

    f r

    FWD set =1 and =0

    RWD set =0 and =1

    AWD set =1 and =1

    Required friction

    coefficient based on

    DRIVE SYSTEM &

    Device dimensions24

  • COEFFICIENT OF FRICTION

    FOR

    AWD, FWD, & RWD

  • Required Tractive Forces

    FTf = Nf Tractional force of both FWsFTr = Nr Tractional force of both RWs

    What is the minimum required (= ?)

    for a given transporter drive system and ramp slope q

    x

    L

    LC

    y q

    FTf

    FTr

    Nr

    Nf

    Fmhc

    FW

    RW

    26

  • Estimate Required Wheel Coefficient of Friction

    The necessary static coefficient of friction () depends on powering mode:

    Four Wheel Drive 4WD

    Front Wheel Drive FWD

    Rear Wheel Drive RWD

    4 4

    4

    tr tf m

    r WD f WD m

    WD

    F F F sin

    N N F sin

    tan

    q

    q

    q

    4 Wheel Drive 4WD

    Minimize required coefficient of friction depends only on angle?

    Decrease by decreasing the incline (cant ramp slope is set !)

    (slide 24)

    27

  • Estimating Necessary Coefficient of Friction

    1

    f FWD m

    FWDC

    N F sin

    L h

    L tan L

    q

    q

    Front Wheel Drive FWD

    How can the required coefficient of friction be minimized?

    Move the center of gravity forward

    Shorten the wheelbase (L)

    Lower the height of the center of gravity (hc)

    28

  • Estimating Necessary Coefficient of Friction

    1

    r RWD m

    RWDC

    N F sin

    L L h

    L tan L

    q

    q

    Rear Wheel Drive RWD

    What can be modified to allow for a lower coefficient of friction?

    Move the center of gravity towards the RWs (reduce Lc)

    Increase the wheelbase (L)

    Raise the height (hc) of the center of gravity

    29

  • Required Coefficient of Friction

    Depending on drive-system (FWD or RWD) the required wheel friction coefficient can be

    minimized by adjusting device geometry:

    L Lc hc4WD NA NA NA

    FWD RWD

    :

    Tf f

    Tr r

    Tractive Forces

    F N

    F N

    1: tan C

    LTipping

    hq

    30

  • Required Coefficient of Friction

    The distance of the Center of Gravity from the rear wheels can be chosen such that either RWD and FWDwill require the same minimum coefficient of friction.

    For equal FWD and RWD minimum coefficient of frictions we can solve for LC-F/RWD :

    Positioning the Center of Gravity at LC-F/RWD provides design flexibility

    / tan2

    FWD RWD

    C F RWD

    LL h

    q

    31

  • Determining Optimum Drive System

    Example:

    Given device dimensions L, h, and slope What would be the best drive

    system: FWD, RWD, or AWD

    Investigate the impact of the distance of the CG from the rear wheels (Lc).

    Dimensions are as follows: Wheel base (L) 12 inch Height of CG (h) 7 inch Angle (theta) 10o

    On the next slide we compare the friction coefficients for FWD, RWD, and AWD

    32

  • 1/15/2014 33MAE-162D R. S. Shaefer, W14

    Minimum Required Friction Coeff. The graph shows that the required friction coefficients -FWD and -RWD are

    equal for an Lc-F/RWD = 7.234 inches from the rear wheels:

    The lowest required minimum coeff. of friction is for AWD (which would require the smallest tractive force (FT) to drive the vehicle up the slope). However the

    additional weight, complexity, and cost of an AWD system has to be considered.

    Device Dims.:

    L = 12 inch

    h = 7 inch

    q = 10o

  • 1/15/2014 34MAE-162D R. S. Shaefer, W14

    For the Preliminary Design Decide on the Best Drive System

    Compare the friction coefficients for FWD, RWD, and AWD and pick the smallest one, which requires the least amount of power to drive the vehicle up the slope.

    Finally, compare the estimated required minimum coefficient of friction with your measured wheel/surface coefficient (-Wheel) to guarantee that the vehicle will not skid backwards.

    1. First, measure the coefficient of

    friction (Slide #19) between your

    wheel and the sloped surface:

    -Wheel

    2. Next, determine the coefficient of

    frictions between your vehicle and

    the slope for the drive systems:

    FWD, RWD, AWD

  • MEASURING COEFFICIENT OF

    FRICTION

  • Measure Wheel Coefficient of Friction

    2 2

    cosm mN F F sin

    htan

    L h

    q q

    q

    Coefficient of Friction:

    Perform a simple inclined plane test

    Use hypotenuse length ~ 50 cm

    Raise end of ramp until test car slips

    Measure h and calculate

    Coefficient of friction

    Plywood

    Wheel surface along grain across grain

    Plain 0.45 0.47

    Knurled 0.47 0.48

    Sandpaper covered 0.91 0.92

    36

  • 1/15/2014 37MAE-162D R. S. Shaefer, W14

    Fraction of Weight on Front/Rear Wheels on an Incline

    ( )

    ( )

    m C mf

    f Cf

    m

    m C mr

    Crr

    m

    F L cos F h sinN

    L

    N L cos h sin

    F L

    F L L cos F h sinN

    L

    L L cos h sinN

    F L

    q q

    q q

    q q

    q q

    Dividing the normal forces on the wheels (slide 26)

    by the total weight gives fractional distribution of

    weight (r,f) :

  • 1/15/2014 38MAE-162D R. S. Shaefer, W14

    Measure Wheel Coefficient of Friction

    Assuming you have decided the following for your concept:

    4-wheel drive, 2-wheel rear, or 2-wheel front drive

    Maximum size of the device

    Amount of rice per run

    Approximate time to deliver the load

    You have estimated the minimum coefficient of friction required to go up the plywood ramp

    You can now try different materials and see if they will provide the necessary coefficient of friction

    You can approximate the overall dimension and coordinates of the center of gravity

    And you can now estimated the required total power/torque necessary to deliver the load

    And therefore you can start looking at motors, and decide how many motors you should use.

  • POWER TO MOVE A VEHICLE

  • Required Power to Move a Vehicle & Minimum min

    2

    2 efficiency

    at F vx v at F ma P

    For a machine of mass m to move a distance x under constant

    acceleration a in time t:

    2

    2 2 3

    2 2 2 4

    efficiency

    x x xm mxa v F P

    t t t t

    Solving for the power consumed in terms of m, x, and t: :

    min( )F

    F N F mgmg

    If the percent weight of the vehicle over the drive wheels is , then the minimum coefficient of friction between the drive wheels and the ground is:

    Create an excel spread-sheet to calculate a (m/s2), F (N), min, vmax, P (Watts)40

  • 22 efficiency

    at F vx v at F ma P

    2

    2 2 3

    2 2 2 4

    efficiency

    x x xm mxa v F P

    t t t t

    min( )F

    F N F mgmg

    Excel Spread-sheet to calculate a(m/s2), F(N), min, vmax, P (W)

    Distance to move, x (m) 2.0 m

    Desired move time, t (sec) 3.0 s

    Mass, m (kg) 3.0 kg

    Estimated system efficiency, eta 50% --

    % vehicle weight over drive wheels, beta 50% --

    Power per motor, wm (Watts) 2.0 W

    Acceleration required, a (m/s 2^, g's) 0.44 m/s2 0.05 g's

    Force required, F (N) 1.33 N

    Min. coeff. of friction drive wheels to ground, mu_min 0.09 --

    Maximum velocity (at end of move), v (m/s) 1.33 m/s

    Power required, P (Watts) 3.56 W

    Motors required 2 --

    Enters numbers in BOLD, Results in RED

    Power Required to Move

    To estimate the power to move a mass m a distance x with constant

    41

  • Example: Choosing a Go-Kart Motor

    The challenge:

    Build a Go-Kart that goes up a 30o hill at 4 mph (m = 90 lb, wheel diameter is 10 inch).

    You are given a 9 amp-hour battery to power the Go-Kart.

    For the motor you have two options :

    Motor-1: Electric motor, which draws about 20 A to produce1 Hp with a torque of 60 N-m at 150 rpm. The motor costs $167.99.

    Motor-2: Electric motor that puts out 0.4 Hp at 2500 rpm drawing ~ 5 A. The motor costs $37.59.

    Which motor will you choose and why?42

  • Required Motor Power

    Given: Electric Motor: 0.4 Hp at 2500 rpm

    Hill Slope: 30o

    Design Requirements: Max speed 4 mph (up a hill of 30o)

    Wheel diameter 10 in

    Total Mass 90 lb

    Approach: First determine the necessary POWER needed to move the

    Go-kart up the hill.

    Next, determine the gear ratio to achieve the necessary torque at the wheels.

    43

  • Estimating Required Power

    Force to move the Go-kart :

    Freq: total required force

    FW : vertical component of weight

    Ff : friction force

    Frol: rolling force

    FInertia: overcome inertia (assume v = 0.25 m/s in 1 s ainertia =0.25 m/s2)

    Estimated the required force using:

    f = 0.35

    rol = 0.015

    Required Power:

    v is steady state velocity

    (vtan = r w; w in rad/s))

    req Inertia W f rolF F F F F

    sin

    cos

    337.00 N

    req Inertia

    f rol

    F ma mg

    mg

    q

    q

    337.00 N 1.79 m/s

    602.56 W

    req reqP F v

    44

  • Estimate Required Torque for Go-Kart & Motor

    Torque Power Relation: P is the motor power

    w is the angular velocity

    Motor produces 0.4 Hp at 2500 rpm*:

    For a 5 inch radius wheel at 4 mph*:

    Necessary torque to drive the cart at 4 mph:

    mm m m m

    m

    PP T Tw

    w

    1.15mT N m

    1.79 /14.08 / 134.45

    0.13

    v m srad s rpm

    r mw

    1 rad/s = (2/60) rpm req mT T

    602.5642.80

    14.08 /

    req

    req

    P WT N m

    rad sw

    *Note that the units actually come out as 1/s (Hz);

    however, radians are a suppressed unit

    with regards to angular velocity

    so we write (rad)/s45

  • Determine the Gear Ratio and Battery Lifetime

    TMotor is less than TRequired

    Requires gearing determine gear ratio (GR):

    1.14 42.80m reqT N m T N m

    46

  • Determine the Gear Ratio and Battery Lifetime

    Tmotor is less than Trequired

    Gear ratio:

    Use a gear ratio of 40

    Battery Lifetime: Motor currents are rated at 5 A and 20 A each:

    1 29 1 48 ; 275

    Motor Motor

    time time

    amp hourB hr min B min

    amp

    42.8037.56

    1.14

    req

    m

    TGR

    T

    1.14 42.80m reqT N m T N m

    47

  • MOTOR SPEED, POWER, AND

    TORQUE

  • Stall Torque and No-Load Speed

    Assuming steady state and no slippage between wheel and ground:

    Torque (T):

    if r is not :

    Stall Torque (ts): The minimum torque needed to completely stop the motor

    shaft from rotating (stalling the motor). Units are ft-lbs or Nm.

    No-Load Speed (wn): The rotational speed of the motor shaft when there is NO

    torque being applied to it. Units are RPM or rad/s

    T r

    F

    (1)T F r

    sin (2)T F r q

    49

  • Motor Torque Speed and Power TRADEOFF

    Using eq. 1 we can define the following :

    The plot of eq. 3 or 4 is calleda torque-speed curve.

    Example: A motor has a no-load speed of 95 RPM and a stall-Torque of 0.6 Nm:

    T r

    F

    (3)

    or in terms of :

    ( ) (4)

    ss

    n

    ns

    s

    TT T

    T TT

    ww

    w

    ww

    Stall Torque ts )

    no-load Speed (wn)

    50

  • Torque -Speed Curves

    If we know the torque applied to the motor shaft we can find how fast the motor will rotate.

    Or if we know how fast we want the motor to spin, we can find how much torque should be applied.

    Stall Torque

    no-load Speed

    Motor Specs.

    often list

    no-load Speed

    Lo

    w P

    ow

    er

    Low Power

    Max Power

    m m m

    mm

    m

    P T

    PT

    w

    w

    51

  • Motor Power

    Recall:

    If we multiply eq. 3 by w or eq. 4 by T we get power as a functions of either torque or velocity:

    These quadratic equations are shown on the next slide:

    (5)P T w

    2

    2

    ( ) (6)

    ( ) (7)

    ss

    n

    nn

    s

    TP T

    P T T TT

    w w ww

    ww

    (3)

    ( ) (4)

    ss

    n

    ns

    s

    TT T

    T TT

    ww

    ww

    52

  • Motor Power as functions of w orT :

    There is a maximum power for a given range of speed and torque.

    For optimum performance, the motor should be operating at torque and speed corresponding to the maximum power.

    The optimum torque and speed are at about half Ts and wn respectively.

    The maximum power available is (Ts wn )/4 53

  • Maximum Velocity and Torque

    If k (speed-torque slope) is known then relate torque, power, and velocity:

    max

    max

    max

    2

    max

    max

    max smax max

    0 2

    ; 2 2

    P P

    k

    k

    P k

    Pk

    t w t

    t

    w

    t w w t w

    w tw

    w tw t

    54

  • Motor Power

    Given: tmax= 9 N-mm, wmax= 14000 rpm, tw slope (k) = - 0.006 the motor torque and power for w-increments of 200 rpm are:

    0.0

    0.5

    1.0

    1.5

    2.0

    2.5

    3.0

    3.5

    0

    1

    2

    3

    4

    5

    6

    7

    8

    9

    10

    0 2000 4000 6000 8000 10000 12000 14000

    Po

    we

    r (W

    atts)

    To

    rqu

    e (

    N-m

    m)

    Motor Speed (rpm)

    Torque (N-mm)

    Power (Watts)

    Note: max

    power is not

    at maximum

    torque or

    speed

    55

  • Concept Design Procedure

    After you have made the following concept design decisions:

    Drive system (4-wheel, 2-wheel rear, or 2-wheel front)

    Maximum size of the device (height, length, width)

    Cargo weight per run (dont forget weight of the transporter)

    Approximate time to deliver a billiard ball (tmax = 2 4 min ?)

    You can now refine your conceptual design based on the following mechanical engineering fundamentals:

    1. Estimate the minimum coefficient of friction (m) required to climb the

    plywood ramp

    2. Establish candidate wheel materials provide the necessary m

    3. Establish the overall dimension of your device and coordinates of the

    center of gravity (L, LC, h)

    4. Estimate the required power/torque necessary to deliver the load

    5. Research motors, and decide what motor and/or how many you

    should use including gearing requirements (use plot torque-speed

    curves to estimate maximum torque and RPMs)

    6. Approximate battery power consumption (more on this next lecture) 56

  • 1/15/2014 57MAE-162D R. S. Shaefer, W14

    Background Slides

  • 58MAE-162D R. S. Shaefer, W14

    Need for Standards: Inch Converter (Mid 19th Century)

    Hamburgh - Inch divided into 8 parts. 1 inch 23.2 mmAustrian - Inch divided into 8 parts. 1 inch 25.8 mmItallian - Inch divided into 8 parts. 1 inch 28.3 mmBremen - Inch divided into 10 parts. 1 inch 23.7 mmSwedish - Inch divided into 12 parts. 1 inch 24.3 mmTurkish - Inch divided into 12 parts. 1 inch 31.3 mmBavarian - Inch divided into 12 parts. 1 inch 24.0 mmSpanish - Inch divided into 12 parts. 1 inch 23.0 mm

    Portuguese - Inch divided into 12 parts. 1 inch 27.0 mmMoscow - Inch divided into 12 parts. 1 inch 27.7 mmRussian - Vershok divided into 8 parts. 1 vershok 44.1 mmAmsterdam - Inch divided into 12 parts. 1 inch 23.5 mmRhynland - Inch divided into 12 parts. 1 inch 26.1 mmFrench - Inch divided into 12 parts. 1 inch 27.0 mmFr. Metre - Centimetres divided into Millimetres.

    English - Inch divided into 32 parts. 1 inch 25.3 mm

  • The parts of a mill and what they do (1/5)

    Parts of a mill and what they do.

    Variable Speed Control KnobControls motor speed from 0 to 2800 RPM

    HeadstockContains the spindle in two preloaded ball bearings.

    SpindleThe spindle is inside the headstock and is driven with a belt running from the motor pulley to a pulley on the rear end of the

    spindle shaft. The nose of the spindle is treaded on the outside to

    receive chucks and tapered on the inside to receive other

    accessories.

    Drill ChuckUsed to hold drill bits for drilling holes. (Not to be used to hold end mills!)

    Mill TableParts are fixed to the table using a vise, chuck or clamps and moved under the milling cutter using the X- and Y-axis

    handwheels.

    Mill SaddleThe mill saddle slides in and out (Y-axis) on the mill base. The mill table moves left and right (X-axis) on top of the

    saddle.

  • Headstock SaddleThe saddle on the vertical column that moves the headstock (Z-Axis) up and down by means of a leadscrew and handwheel.

    Mill ColumnThe steel dovetailed column that is held to the mill column base and supports the Z-axis saddle and headstock.

    LeadscrewThe threaded screws that move the table left/right and in/out as well as the vertical axis up and down. They are driven by handwheels

    marked in .001" or .01 mm increments.

    Leadscrew Locking LeverLocated on the back side of the vertical column, this locking lever locks against the saddle nut to prevent unwanted

    movement of the Z-axis during machining operations. Manual machines are

    fitted with a standard on/off locking lever. CNC machines are fitted with an

    adjustable locking lever that can be used to control backlash in the Z-axis.

    This function is available as an option on any manual mill as well. (P/N

    4017U inch or 4117U metric)

    GibsTapered plastic gibs are used on each dovetailed axis to take up wear as it occurs. They are slightly wedge shaped. As side-to-side "slop"

    develops on an axis, the gib lock is loosened and the gib is pushed a little

    further into the gap, taking up the play. These allow the machine to always

    be kept as tight as the operator desires. If or when they wear out, they are

    very inexpensive to replace.

    The parts of a mill and what they do (2/5)

  • Mill BaseThe solid base that has the dovetail for the saddle to move in and out on and to which the mill column is attached.

    DrawboltGoes through the hole in the spindle to draw chucks and other accessories into the headstock taper inside the spindle. A special washer

    locates in on center in the spindle hole.

    #1 Morse ArborThe arbor screws into the back of the drill chuck so it can be used in the headstock. It is held in place in the #1 Morse taper with the

    drawbolt.

    Tommy BarsRound steel bars used to tighten and loosen chucks and other spindle accessories. Sometimes called "Spindle Bars."

    Y-axis Locking ScrewA thumbscrew on the side of the base that keeps the saddle from moving in and out when tightened.

    X-axis Locking ScrewA screw that goes through the barrel lock on the front of the saddle to lock the table in place during machining operations where

    movement is not required or desired.

    The parts of a mill and what they do (3/5)

  • Backlash LocksThe lock works like tightening two nuts against each other on a threaded shaft to reduce play in the threads.

    Backlash is the pause in travel when changing direction of rotation of any threaded crew. Because both sides of the thread don't rub on the nut at the

    same time (they would quickly wear out), one surface is pulling or pushing the

    nut when the screw is turned.

    When you stop and change directions, the screw turns a slight amount while the thread picks up the other side and begins to move the nut in the other

    direction. The looser the fit of the threads, the more "backlash" occurs.

    In essence, it is the amount you can turn the handwheel in the reverse direction before movement occurs on an axis. An adjustment is provided on the X- and

    Y-axes to reduce the leadscrew backlash.

    Backlash is not a "fault" of a machine, it is simply a physical reality that must be taken into account when machining. You adjust to a known or acceptable

    amount using the locks and then remove it from the machining operation by

    always approaching your cut from the same direction with the backlash already

    eliminated before the cut begins.

    The parts of a mill and what they do (4/5)

  • Alignment KeyA precision ground key that fits in a slot in the column saddle to keep the headstock aligned straight up and down. A second

    slot is also provided to locate the headstock at 90 for horizontal

    milling. Removing this key and rotating the headstock allows bevels to

    be cut at any angle. An approximate angle scale is laser engraved into

    the saddle for reference.

    Headstock Spacer BlockMoves the headstock 1.25" further out from the saddle to increase the "throat" distance (distance between

    cutter and column). It is optional on 5000-series mills, standard on

    5400-series mills and not needed on 2000-series mills because the ram

    can be used to adjust this distance.

    V-beltA Kevlar-reinforced Urethane belt that drives the spindle through the pulleys.

    2-position PulleyThe normal (rear) position gears the motor down about 2:1 for a maximum speed of about 2800 RPM. The "High

    Torque" position (closest to the headstock) gears it about 4:1 for lower

    speed but more torque when needed for heavy cuts.

    The parts of a mill and what they do (5/5)