me 209 final

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    ME 209GROUP DESIGN

    GROUP 10

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    DESIGN

    REQUIREMENTPick a 5kg box of

    30*30*30cm3 dimensions froma conveyor belt to a trolleywith a high difference of 0.5m

    and angular change of 90o.

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    Design in front viewed

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    NOTATIONS

    D1-piston rod diameter

    D2-cylider inner diameter

    D3-cylinder outer diameterD5-picking solid bar diameter

    D6-pin diameter

    D7-lifting solid bar diameter

    D8-linkage pin diameter

    T3-width of linkage bar(cross section)

    T4-long of linkage bar(cross section)

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    MATERIALSELECTION

    Compound Factor of Safety Material

    Picking cylinder 12 Cast iron

    Pin 14 Steel

    Steel rod 12 Steel

    Spring 12 High carbon steel

    Factor of safety and compound

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    Strenthnesses of Materials

    Ultimate tensileStrength/MPa

    Ultimate ShearStrength/MPa

    Density /kgm-3

    Cast Steel 303 251.5 7650

    Steel 760 456 7840

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    Appearance Clear and Bright

    Density 1027 kg/m3 @ 20oC

    Color Light Amber

    Hydraulic Break oil (E550)(Number 2006)

    Spring

    Modulus 78.6 kN/mm

    2

    Method of manufactureCold Drawing

    Lower Cost SpringAverage Stress application

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    Box and Hard rubber

    (data calculations)

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    Piston Rod Failure

    Due to Shear FailureF1/ (D1

    2/4) Ultimate Shear Stress/Factor of Safety

    Due to Tensile FailureR1 / (D1

    2/4) Ultimate Tensile Stress/Factor of Safety

    D1 =20 mm

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    Specimen Calculation

    Total Liquid Volume = (/4)D22*Total length

    Total Liquid mass = (/4)D22*Total length*

    Cylinder Weight = (/4)(D42- D2

    2)Total length*Total Weight = (Cylinder Weight) * (Liquid

    mass)

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    Cylinder Failure

    Due to Tensile FailureW/(D4

    2-D22)/4 Ultimate Tensile Stress/Factor of Safety

    Due to Tensile FailureD4 - D3 = t

    M / I = / R1 / (D2

    2/4) Ultimate Tensile Stress/Factor of Safety

    D3 =88 mm

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    Solid cast iron rod Failure

    Due to Tensile FailureR1 / (D5

    2/4) Ultimate Tensile Stress/Factor of Safety

    Due to Bending FailureM / I = / Wr / (D5

    2/4) Ultimate Tensile Stress/Factor of Safety

    D5 =60 mm

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    Mode failure of lifting mechanismPin Failure

    Due to Shear FailureW / (D6

    2/4) Ultimate Shear Stress/Factor of Safety

    Due to Compressive FailureW / (D7

    2/4) Ultimate Tensile Stress/Factor of Safety

    Pin is madefrom HarderMaterial

    D6 = 5 mm

    D7 = 5 mm

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    Linkage Failure

    Due to Compressive FailureW / t4 t3 Ultimate Compressive Stress/Factor of Safety

    Instantaneous cantors

    Fixed point

    D2 =80 mm

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    Piston Rod Failure

    Due to Shear FailureW / (D8

    2/4) Ultimate Shear Stress/Factor of Safety

    Due to Bearing FailureW / (D8t4) Ultimate Shear Stress/Factor of Safety

    D8 =4 mmT3 =6 mmT4 =6 mm

    Fixed point

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    High efficiency

    Smooth Pick and Placecan do as we wish

    Reliable

    Some heavy weight

    Initial cost is somemuch high

    Advantages Disadvantages

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