mechanics lecture 2, slide 1 vectors and 2d-kinematics continued relevant equations how to use them...
TRANSCRIPT
Mechanics Lecture 2, Slide 1
Vectors and 2d-KinematicsContinued
Relevant Equations How to use them Homework Hints
Hyperphysics-Trajectories
Mechanics Lecture 1, Slide 2
http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html
Projectile Motion Quantities
Mechanics Lecture 2, Slide 3
Initial velocityspeed,angle
Maximum Height of trajectory, h=ymax
Range of trajectory, D
Height of trajectory at arbitrary x,t
“Hang Time”Time of Flight, tf
Hyperphysics-Trajectories
Mechanics Lecture 1, Slide 4
Maximum Height of Trajectory
Mechanics Lecture 2, Slide 5
Height of trajectory,h=ymax
g
vyh
g
vyh
g
v
g
vyh
gttvyh
tyh
g
vtvy
gtvtv
y
yy
yyy
y
yyy
yy
2
sin
2
2
1
2
1
)(
0
)(
220
0
20
0
20
20
0
200
0max
0
maxmax
max
max
Time of Flight
Mechanics Lecture 1, Slide 6
Time of Flight, “Hang Time”
Mechanics Lecture 2, Slide 7
g
v
g
vtt
gtvtgttv
gttvyy
yttytt
gttvyty
y
yy
y
y
ff
ffff
ff
ff
sin22;0
02
1
2
12
1
)(2
1)(
00
02
0
2000
0
200
Hyperphysics-Trajectories
Mechanics Lecture 1, Slide 8
Range of trajectory
Mechanics Lecture 2, Slide 9
g
vD
g
v
g
vvD
tvttxD
yttytt
tvxtx
yx
fxf
ff
x
2sin
sincos22
0)(
)(
)(
20
2000
0
0
00
Angle for Maximum Range
Mechanics Lecture 2, Slide 10
0
0
45
902
0)2cos(0)(
)2cos(2)(
)2sin()(
d
dfd
df
f
MAXIMUM range OCCURS AT 450
Will it clear the fence
Mechanics Lecture 1, Slide 11
Height of Trajectory at time t or position x
Mechanics Lecture 2, Slide 12
200 2
1)( gttvyty y
Height of trajectory, y(x)
x
x
v
xxt
tvxx
0
0
00
Height of trajectory, y(t)
2
000
2
000
00
2
0
0
0
000
cos2
1
cossin)(
2
1)(
0;0
2
1)(
v
xg
v
xvxy
v
xg
v
xvxy
yx
v
xxg
v
xxvyxy
xxy
xxy
Projectile Trajectory Equations
Mechanics Lecture 1, Slide 13
2
000 cos2
1
cossin)(
v
xg
v
xvxy
200 2
1)( gttvyty y
Height of trajectory as f(x), y(x)
Height of trajectory as f(t) , y(t)
g
vD
2sin20
g
v
g
vt y
f
sin2200
g
vyh
2
sin220
0
Range of trajectory
Time of Flight (“Hang Time”)
Maximum height
Where will it land?
Mechanics Lecture 1, Slide 14
Launch Velocity-Given R and
Mechanics Lecture 1, Slide 15
Launch Angle
Mechanics Lecture 1, Slide 16
Launch Velocity –Given R and h
Mechanics Lecture 1, Slide 17
Mechanics Lecture 2, Slide 18
Field Goal ExampleA field goal kicker can kick the ball 30 m/s at an angle of 30 degrees w.r.t. the ground. If the crossbar of the goal post is 3m off the ground, from how far away can he kick a field goal?
y-direction
voy = vo sin(30o) = 15 m/s
y = yo + voyt + ½ at 2
3 m = 0 m + (15 m/s) t – ½ (9.8 m/s2) t 2
t = 2.8 s or t = 0.22 s.
x-direction
vox = vo cos(30o) = 26 m/s
D = xo + vox t + ½ at 2
= 0 m + (26 m/s)(2.8 s) + 0 m/s2 (2.8 s )2
= 72.8 m
D
3 m
y
x
Illini Kicks 70 yard Field Goal
Homework Hints-Baseball
Mechanics Lecture 1, Slide 19
Homework Hints- Baseball Stadium Wall
Mechanics Lecture 1, Slide 20
Homework Hints – Stadium Wall
Mechanics Lecture 1, Slide 21
Calculate time to reach wall using vx:
cos// 00 vxvxt wallwallwall x
Calculate y position at time to reach wall:
200
20000
200
cos/2
1tan
cos/2
1cos/sin
2
1
vxgxyy
vxgvxvyy
tgtvyy
wallwallwall
wallwallwall
wallwallwall y
Homework Hints-Catch
Mechanics Lecture 1, Slide 22
Homework Hints-Catch
Mechanics Lecture 1, Slide 23
cos00 vvx
sin00 vvx
g
vy
g
vyy y
2
sin
2
)( 20
0
20
0max
g
v
g
vvtvx
g
vt
tvtgtgtv
tgtvyyyy
yx
x
y
yy
y
ff
f
ffff
ffff
sincos22
22
1;
2
10
2
1;
200
0
0
022
0
2000
0
Homework Hints-Catch
Mechanics Lecture 1, Slide 24
20000
0000
0
max1
0
max
/2
1/
cos;sin
)(cos;
)(cos
xjuliejuliejulie vxgvxvyy
vvvv
v
yyv
v
yyv
xy
xy
max2
0max0
20
20
20
max00max2
0
2
cossin
cos;2sin
yyvyygv
vvv
yyvvyygv
Homework Hints-Catch 2
Mechanics Lecture 1, Slide 25
Homework Hints-Catch 2
Mechanics Lecture 1, Slide 26
cos0vvx vVx is constant !
g
vgvtgvttv y
yy ffy
0
00
2)(
g
vt
tvtgtgtv
y
yy
f
ffff
0
022
0
22
1;
2
10
Kinetic energy should be same as when ball was thrown. Y-component of velocity would be downward.
Homework Hints-Catch 2
Mechanics Lecture 1, Slide 27
g
vvtvx yx
x ff
00
0
2
julie
julie
t
xv
x0
Same conditions as before
max2
0max0 2 yyvyygv
20000 /2
1/ xjuliejuliejulie vxgvxvyy
xy
Homework Hints – Soccer Kick & Cannonball
Mechanics Lecture 1, Slide 28
Homework Hints – Soccer Kick & Cannonball
Mechanics Lecture 1, Slide 29
20
200 yx
vvv
x
y
v
v
0
01tan
g
vyy y
2
)( 20
0max
g
vD
2sin2
0
g
vvtvx yx
x ff
00
0
2
Homework Hints – Soccer Kick & Cannonball
Mechanics Lecture 1, Slide 30
)()(
)(;)(
220
00
givenyxgiven
givenxgivengiveny
ttvvttv
vttvtgvttvxy
200 2
1givengivengiven tgtvytty
y
Trigonometric Identity for range equation
Mechanics Lecture 2, Slide 31
)2sin(2
1)sin()sin(
2
1cossin
)sin()sin(2
1cossin
222
1cossin
4cossin
422cossin
2cos
2sin
)()()()(
)()()()(
i
ee
i
ee
i
eeee
i
eeeeeeeeee
i
ee
ee
i
ee
iiii
iiii
iiiiiiiiiiii
ii
ii
http://mathworld.wolfram.com/Cosine.html http://mathworld.wolfram.com/Sine.html
Trigonometric Identities relating sum and products
Mechanics Lecture 2, Slide 32
List of trigonometric identities
cossin2sincoscossin)2sin(
sincoscossin)sin(
Question 2
Mechanics Lecture 2, Slide 33
Question 2
Mechanics Lecture 2, Slide 34
Hyperphysics-Trajectories
Mechanics Lecture 1, Slide 35
http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html