optical fibres - dispersion part 2 [group velocity ... - ucy€¦ · ece 455 – lecture 06 6 •...
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ECE 455 – Lecture 06 1
Optical Fibres
- Dispersion Part 2
[Group Velocity Dispersion]
• HMY 445
• Lecture 06
• Fall Semester 2016
Stavros IezekielDepartment of Electrical and
Computer Engineering
University of Cyprus
ECE 455 – Lecture 06
CHROMATIC DISPERSION – WHAT
WE KNOW SO FAR
2
ECE 455 – Lecture 06 3
© U
. of W
ashin
gto
nIf we have a pulse of light which is not monochromatic (it contains a group of
wavelengths), then we will have chromatic dispersion:
Optical fibre
z
Intramodal (chromatic) dispersion
Material dispersion Waveguide dispersion
Due to nonlinear
relationship between
n and λ
Due to refractive
index profile of the
fibre. Changes with
λ.
• Dispersion due to fact that group
velocity changes with wavelength
ECE 455 – Lecture 06 4
dispersion no⇒= pg vv
dispersion⇒≠ pg vv
kvp
ω= Phase velocity
dk
dvg
ω= Group velocity
k
ω
dispersion normal⇒
< pg vv
pg vv =
dispersion anomalous⇒
> pg vv
ECE 455 – Lecture 06
GROUP VELOCITY DISPERSION
5
ECE 455 – Lecture 06 6
• So far we have considered just two, very closely spaced frequencies within the
group emitted by an optical source such as a laser:
Wavepackets
• If we consider the entire spectrum emitted by the source, we still obtain a
modulated waveform, with a group velocity and phase velocity as before.
ω0
Intensity
(arbitrary units)
ω
2 δω
Wave packet –
A short pulse composed of
the sum of waves over a
finite bandwidth.
We now look at the whole
spectrum.
ECE 455 – Lecture 06 7
© U
CS
D
ECE 455 – Lecture 06 8
• We can prove the properties of the wavepacket by using the Fourier transform:
∫∫∞
∞−
∞
∞−
− =↔= dtetfFdeFtftjtj ωω
πωωω )(
2
1)()()(
Time domain Frequency domain
ω0
ωω0 - δω ω0 + δω
F(ω)This represents optical source
spectrum; has a gaussian
profile
peak frequency
(12)
Fourier
ECE 455 – Lecture 06 9
• We can think of F(ω) as being equal to some spectrum G(ω) which is identical in
shape, but centred at ω = 0 instead of ω0:
• By inspection, )()( 0ωωω −=GF
∫∞
∞−
−=− dtetgGtj )(
00)(
2
1)(
ωω
πωω
∫∞
∞−
−= dteetgtjtj ωω
π0)(
2
1∫∞
∞−
=
dtetf
F
tjω
π
ω
)(2
1
)(
ω0ωω0 - δω ω0 + δω
F(ω)G(ω)
0- δω δω
(13)
(14) (15)
ECE 455 – Lecture 06 10
tjetgtf 0)()(
ω−=• Hence:
Corresponds to sinusoid
at optical frequency ω0
Impulse response of:
G(ω)
0
-1,5
-1
-0,5
0
0,5
1
1,5
0 0,5 1 1,5 2
gives:g(t)
0N.B. Fourier transform of a gaussian
pulse is also gaussian in shape
(16)
ECE 455 – Lecture 06 11
• In other words, the impulse response associated with the optical source takes on the
form of a wavepacket:
g(t)
f (t)
t
• This wavepacket represents a pulse of light emitted by the optical source, and it contains
a range of frequencies (i.e. wavelengths).
• We now need to examine what will happen to the group velocity of this pulse as it
propagates along a fibre.
ECE 455 – Lecture 06 12
• Consider an optical pulse launched into a single mode fibre. Due to the spectral width
of the source, this pulse consists of a group of wavelengths which travel at the group
velocity:
optical power
wavelength λ
distance
dk
dvg
ω=
λ0
ECE 455 – Lecture 06 13
• So the time taken for the wavegroup to travel a distance L along the fibre is given by the
group delay τg:
ωτ
d
dkL
v
L
g
g ==
• The phase velocity of the peak wavelength λ0 is given by:
c
nk
n
c
kvp
ωω=⇒==
• Substituting (18) into (17):
+==ω
ωω
τ
d
dnn
cd
dk
L
g 1
(17)
(18)
(19)
ECE 455 – Lecture 06 14
• Eqn. (3) shows that the group delay per unit length depends on both n and dn/dω. It is
also dependent on the frequency ω. However, we prefer to work with wavelength λinstead:
λ
n
• From the inverse relationship between frequency and wavelength (c = fλ = ωλ/2π), we
find that:
−=
+=λ
λω
ωτ
d
dnn
cd
dnn
cL
g 11
ω
n
instead of....
(20)
ECE 455 – Lecture 06 15
−=
+=
+=∴
λλ
ωλ
λω
ωω
τ
d
dnn
c
d
d
d
dnn
c
d
dnn
cL
g
1
1
1
Derivation of equation (20):
ωλ
ωπ
ωλ
ωπ
λλλ −=−=⇒=⇒=⇒=2
22 c
d
dc
f
cfc
ECE 455 – Lecture 06 16
Group Refractive Index
n
c
kvp ==
ω
g
gn
c
dk
dv ==
ω
• Imagine we have a fibre with core refractive index n. In this case,
• If we transmit a spread of wavelengths, then we can regard the resulting group as
encountering a group refractive index, and this is defined via:
g
gv
cn =
(21)
(22)
(23)
ECE 455 – Lecture 06 17
λλ
τ
d
dnn
Lcn
g
g −==∴
• n varies with wavelength:
dispersionvvnnd
dngg ⇒≠⇒≠⇒≠ 0
λ
• In fact, ng will also be wavelength dependent:
2
2
λλ
λ d
nd
d
dng −=
(24)
(25)
ECE 455 – Lecture 06 18
λ
n
ng
1.31 µm
Point of inflection
2
2
λλ
λ d
nd
d
dng −=
02
2
=λd
nd
Minimum 0=λd
dng
For silica glass: At 1.31 µm, n has
a point of inflection, ng is
minimum, and the group velocity
is therefore maximum.
ECE 455 – Lecture 06 19
Group velocity dispersion (GVD)
• We know that:
• An optical source emits a spread of wavelengths centred on λ0.
• This can be represented by a wavepacket which travels at the group velocity
and therefore “sees” a group index ng.
• However, ng and thus the group velocity vg and delay τg are all wavelength
dependent.
• Each different spectral component emitted by the source will travel at
different group velocities, and this GVD is the cause of material dispersion.
ECE 455 – Lecture 06 20
λ
=
c
n
L
g
gτ
λ0 λ0 + δλ
)(1
0λτ gL
)(1
0 δλλτ +gL
• Consider the delay difference (per unit length) for a wavelength δλ away from the
central wavelength λ0:
• If the wavelength difference is sufficiently small, we can neglect second-order
terms in a Taylor series expansion to get:
0
)()( 00
λλ
τδλλτδλλτ
d
d
LL
ggg =−+
gτδ
δλ
(26)
ECE 455 – Lecture 06 21
• Consider the delay difference (per unit length) for a wavelength δλ away from the
central wavelength λ0:
0
11
λλ
τ
δλ
δτ
d
d
LL
gg =
−=λ
λτ
d
dnn
cL
g 1
• From (20):
2
21
λλ
δλ
δτ
d
nd
cL
g −=∴
Material
dispersion
Dmat
Units: ps/(nm.km)
(27)
ECE 455 – Lecture 06 22
2
2
λλ
d
nd
cDmat
−=
LDmatmat λσσ =
spread
in time
(ps)
spread in
wavelength (nm)
(11)
Group index, refractive index
and material dispersion for
silica glass (SiO2)
material dispersion
(ps/nm-km)length (km)
ECE 455 – Lecture 06
DISPERSION MANAGEMENT
23
ECE 455 – Lecture 06 24
Dispersion modified fibres
• For conventional single-mode optical fibre:
– minimum attenuation occurs at 1.55 µm
– minimum dispersion occurs at 1.3 µm
• Furthermore, optical amplifiers operate in the 1.55 µm
region
• In response to this, dispersion modified fibres have been
developed to provide minimal dispersion at 1.55 µm
ECE 455 – Lecture 06 25
• Structure dependent losses (waveguide losses) have little
effect on overall attenuation, so changing the refractive
index profile in single-mode fibre will have negligible impact
on attenuation.
– However, changing the refractive index will modify the
waveguide dispersion term, and this can be used to our
advantage.
• In fact, the refractive index profile can be tailored to shift
the dispersion zero to 1.55 µm or to flatten the dispersion
vs. wavelength profile so that dispersion is almost zero
between 1.3 µm and 1.55 µm
ECE 455 – Lecture 06 26
Changing the refractive index profile changes the waveguide
dispersion:
Dispersion
shifted
Dispersion
flattened
ECE 455 – Lecture 06 27
Dispersion
shifted
Dispersion
flattened