General 2002

P1 P2

1 2 3 4

5 6 7 8

9 10

Paper 1

General 2002

P1 P2

Paper 2

1 2 3 4

5 6 7 8

9 10 11

General 2002

P1 P2

Paper1 Q1(a)

9.2- 3.71

01 1

.

8

94

1

5

5.49+ 6.471 . 6911

7.29x 8

238572

(b)

.(c)

6 8 7 300 = 6 8 7 100 3 2 29.

6.8732

(d)

33 2

4

3 11

1 4

33

4

18

4

General 2002

P1 P2

Paper1 Q2

( )P yellownumber of favourable outcomes

number of possible outcomes

3

15 1

5

(a)

(b)New total =14

( )P pinknumber of favourable outcomes

number of possible outcomes

6

14 3

7

General 2002

P1 P2

Paper1 Q3

General 2002

P1 P2

Paper1 Q4

30 % of 5 million; 5 000 000

10% = 500 000

30% = 1 500 000

General 2002

P1 P2

Paper1 Q5y

x-2-4-6

2

4

6

2 4 6-2

-4

-6

(a) A (-4,-3)B (3,-1)C (4,4)

(b)

(c)A

B

C

Gradient of AB =

vert

hor

2

7

D

D ( -3,2)

General 2002

P1 P2

Paper1 Q60.404 1

441% 0.04

4

10Change into decimals to compare.

0.250.404 0.41 0.04 0.4

0.25 0.404 0.410.04 0.4

General 2002

P1 P2

Paper1 Q7

O

BCA

AB is a tangent ; 90BCO

26

Triangle AOB is isosceles ; CAO CBO 26

26

So180 90 26COB (Angles in a triangle)

64

General 2002

P1 P2

Paper1 Q8

0

10

20

30

40

50

60

70

80

90

100

10 20 30 40 50 60 70 80 90 100Science marks

Mathematics marks

(c)

Maths mark =

54%(estimate)

General 2002

P1 P2

Paper1 Q9

Week one

Week two

Plant A 29 cm 57 cm

Plant B 46 cm 71 cm

Growth

57 – 29 = 28 cm

71 – 46 = 25 cm

Plant A has grown more by 3 cm .

General 2002

P1 P2

Paper1 Q10

Each tyre spends one fifth of it’s time in the trunk.

So

Each tyre does 420 000

5of miles

14 000

5miles

416 000

5miles

General 2002

P1 P2

Paper2 Q1

• D = • S = • T =

List ;

?76 km/h3 hrs 45 mins

45 mins = 45/60 hrs = 0.75 hrs

= 3.75 hrs

D

S T

D = S x T

= 76 x 3.75

= 285 km

?

General 2002

P1 P2

Paper2 Q2(a)

(b)

VAT = 17.5% of £779

= 17.5/100 x 779

= 136.325

= £ 136.33

Total cost = 779 + 136.33

= £ 915.33

Difference = 915.33 - 900

= £ 15.33

Refund(Double the difference)

= 15.33 x 2 = £ 30.66

General 2002

P1 P2

Paper2 Q3

450 cm

40 cm

(a) From formula sheet; V = r2 h = 3.14 x (20)2 x 450

= 565486.68

= 565 000 cm 3

(b)

5 6 5 0 0 0 = 5.65 x 10 5

General 2002

P1 P2

Paper2 Q41 section 2 sections 3 sections

(a)

(b)

Number of sections(s) 1 2 3 4 12Number of iron bars (b) 8 2215 29

(c)

Number of iron bars = Number of sections x 7 + 1+7 +7 +7

12 x 7+1b = 7s +1

176 = 7s +1

175 = 7s

s = 25 25 sections

85

General 2002

P1 P2

Paper2 Q5

Find 4.5% of £1640

This is for 12 months

Yearly interest =4.5

1640100

73.80

Monthly interest =73.80

126.15

9 months interest = 6.15 9 £ 55.35

General 2002

P1 P2

P

Q

R

S

12 cm

20 cm

In a rhombus, diagonals are bisected at right angles.P

Q

10 cm

6 cm

Paper2 Q6

SOHCAHTOA

O

T A= 1.667

xo = tan –1 (1.67)

= 59 o

tan xo = A

O

10

6

Therefore 2 59PQR 118

General 2002

P1 P2

Paper2 Q7

Bath

Strip of p

lastic

30cm

20 cm

According to Pythagoras:

x2 = 1802 + 1202

= 32400 + 14400

= 46800

x = 46800 = 216.33 cm

180 cm

120 cmx

General 2002

P1 P2

Paper2 Q8(a)

(b)

Scale 1:2

HP (15 cm) 7.5 cm

HT (20 cm) 10 cm

Rod (35 cm) 17.5 cmH P

T

By measuring PT on your drawing you get; 12.5 cm

So

Actual length of PT = 2 x 12.5

= 25 cm

General 2002

P1 P2

Paper2 Q9(a)

(b)

4 ( 3x + 2) = 6812x + 8 = 68

12x = 60x = 5

10y +15 = 5 ( )2y +3

General 2002

P1 P2

Paper2 Q10

A B120 cm

(a)

(b)

Length of curve 2d

120 2

188.5 cmLength of metal edge 188.5 120

308.5 cm

Length of metal

edge needed 308.5 164936 cm49.36 m

50m will be enough!

General 2002

P1 P2

Paper2 Q11Hire purchase price = Deposit + Total instalments

Find these to calculate this

“ The hire purchase price is 22% more than the cash price”

hire purchase price = cash price x 1.22

= 6300 x 1.22

= £ 7686

“….requires a deposit, which is 15% of the cash price”

deposit = 15% of £6300

= 0.15 x 6300

= £945

Total instalments = Hire purchase price - Deposit

= 7686 - 945 = £ 6741

Each instalment =

= £ 112.35

6741 60

General 2002

P1 P2

Paper 1

1 2 3 4

5 6 7 8

9 10