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    CHE101 (B.Tech. Chemistry Course)

    Lecture27.28

    Substitution ReactionsSN1 and SN2

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    TWO SUBSTITUTION REACTIONS

    SN1 / SN2

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    RBr + NaOH ROH + NaBr

    In this reaction:

    CH3 Br + CH3 OH + Br-

    20% waterNaOH

    80% ethanol

    1)

    rate = k2 [RBr] [NaOH]

    55oC

    SN2

    primary

    Two similar reactions,

    different kinetics.

    First Case

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    CH3C

    CH3

    CH3

    OH+CH3C

    CH3

    CH3

    Br20% water

    Br-

    +NaOH80% ethanol

    rate = k1 [RBr]

    55oC

    SN1

    tertiary

    2) Second Case

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    Is this difference significant, or is it just a

    mathematical illusion of some kind?

    SN1 SN2

    rate = k1 [RBr] rate = k2 [RBr] [NaOH]

    QUESTION

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    THE WORK OFHUGHES AND INGOLD

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    It was found experimentally that :

    Most primary compounds undergo SN2 reactions

    with second order kinetics.

    Most tertiary compounds undergo SN1 reactionswith first order kinetics.

    Most nucleophilic substitution reactions fit one

    or the other of these two patterns.

    HUGHES AND INGOLD ca. 1940

    Is this significant, or is it just a mathematical

    illusion of some kind?

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    2-BROMOOCTANE

    A STUDY IN STEREOCHEMISTRY

    Lets use an optically-active compound.

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    CH3CH2CH2CH2CH2CH2 CH CH3

    Br

    2-BROMOOCTANE

    *

    R CH CH3

    Brcan react bothSN1 and SN2

    chiral

    secondary

    abbreviation

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    R C

    Br

    H

    CH3

    R C

    OH

    H

    CH3

    R C

    H

    CH3+

    low conc [ OH- ]

    high conc [ OH- ]

    > 1 M

    1) H2O

    2) -H+

    SN1

    SN2

    < 0.1 M

    DIFFERENT KINETICS AT DIFFERENT BASE CONCENTRATIONS

    k2[RBr][OH]

    k1[RBr]

    The two mechanisms

    compete.

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    Total Rate = k1 [RBr] + k2 [RBr] [OH-]

    SN2

    SN1

    [ OH- ]

    [RBr] constant

    Rate

    TOTAL

    k2 [RBr] [OH-]

    k1 [RBr]

    dominates at

    high [OH-]

    dominates at

    low [OH-]

    SN1 SN2

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    2-Bromooctane is chiral .....

    Is the stereohemical result the same in

    each case :

    What if we start with an enantiomerically pure

    compound (one enantiomer only)?

    STEREOCHEMICAL RESULTS

    CH3CH2CH2CH2CH2CH2 CH CH3

    Br

    *

    SN1 and SN2 ?

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    R

    H

    CH3 Br

    R

    H

    HOCH3

    R

    H

    CH3 OH

    R

    H

    HOCH3

    SN2 conditions

    SN1 conditions

    high [OH-]

    low [OH-]

    enantiomers

    racemic mixture

    R-(-)-2-bromooctane

    S-(+)-2-octanol

    complete

    inversion

    complete

    racemization

    STEREOCHEMISTRY CHANGES

    [ ]D = +10.3o

    [ ]D = -36.0o

    [ ]D = 0o

    +

    R

    S

    R S

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    Can we explain the stereochemical results

    with our proposed mechanisms for

    SN1 and SN2 reactions?

    Lets Try .......

    THE MECHANISMS

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    SN1

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    Fastest for tertiary substrates.

    Need a good leaving group.

    Product will be racemic.

    Carbocation intermediate.

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    R

    H

    CH3 Br

    C

    H

    RCH3 O H

    OH

    H

    CH3 R

    OH

    H

    RCH3

    +

    +

    enantiomers

    SN1 MECHANISM

    planar

    carbocation

    sp2

    (S) (R)

    (R)

    50%

    50%

    racemic mixture

    RACEMIZATION

    -

    attacks top

    and bottom

    equally

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    SN2

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    Fastest for primary and methyl substrates.

    Needs a strong nucleophile.

    Leaving group does not need to be primarily good.

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    LIKE POOL OR BILLIARDS

    1) two balls at restand touching2) forceful shot

    directly on axis

    3) straight-on

    collision

    4) momentum

    transfer

    Nu

    Nu

    Nu

    X

    X

    X

    X

    CONCEPTUAL ANALOGY 1

    Similar in concept

    to an attack from

    the back forcingthe nucleophile to

    leave.

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    C

    R

    HCH3

    Br:

    C

    R

    HCH3

    HO :

    C

    HCH3

    R

    BrHO

    H O:..

    ..

    activated complex

    is trigonal planar (sp2 )

    (R)-configuration

    (S)-configuration

    configuration

    is inverted

    Ea

    HO C B

    partial bonding

    2pTHE INVERSION

    PROCESS

    sp3

    sp3

    sp2

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    ACTIVATED COMPLEX FOR SN2

    C

    R

    HCH3

    BrHO

    trigonal planar (sp2)

    5 bonds to Carbon

    breakingforming

    but the bonds to

    Br and OH are only

    half-formed and

    are not full bonds.

    NOT A STABLE SPECIES

    MIDPOINT OF THE REACTION