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Solution: Given IP address is class B address. 16 bit is used for subnetting. Number of subnet = 2 n = 2 3 = 8 We want 6 subnet but using three bit, we get 8 subnet. Subnet mask = 255.255. 11100000.0 = 255.255.224.0 Number of subnet: 1 st subnet : 160.11.0.0 2 nd subnet: 160.11.32.0 3 rd subnet : 160.11.64.0 4 th subnet : 160.11.96.0 5 th subnet : 160.11.128.0 6 th subnet: 160.11.160.0 7 th subnet : 160.11. 192.0 8 th subnet : 160.11.224.0

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Page 1: Solution Subnet

Solution: Given IP address is class B address. 16 bit is used for subnetting.

Number of subnet = 2n

= 2 3

= 8

We want 6 subnet but using three bit, we get 8 subnet.

Subnet mask = 255.255. 11100000.0

= 255.255.224.0

Number of subnet:

1st subnet : 160.11.0.0

2nd subnet: 160.11.32.0

3rd subnet : 160.11.64.0

4th subnet : 160.11.96.0

5th subnet : 160.11.128.0

6th subnet: 160.11.160.0

7th subnet : 160.11. 192.0

8th subnet : 160.11.224.0

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