transport no. & kohlrausch law

15
Transport numbers and mobilities Electrolys Electrolys is is Galvanic cell Galvanic cell Electrochemistry

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Page 1: Transport No. & Kohlrausch Law

Transport numbers and mobilities

ElectrolysisElectrolysis

Galvanic cellGalvanic cell

Electrochemistry

Page 2: Transport No. & Kohlrausch Law

Transport numbers and mobilitiesTransport numbers and mobilities

• The definition of transport number t is that current carried by ion B divided by the sum of the current of all the ions in solution, which is also called the transference number of ion B.

cnI Qt

I I Q Q n

vv v

anI Qt

I I Q Q n

vv v

nc and na are the amount of substance of positive ions migrate out from anodic region and that of negative ions migrate out from cathodic region respectively.

Page 3: Transport No. & Kohlrausch Law

Let 4Let 4FF be passed through the cell; be passed through the cell; tt++=3=3tt--

Before electrolysis

On electrolysis

After electrolysis

Page 4: Transport No. & Kohlrausch Law

MobilityMobility

• The transport numbers of ions depend on the properties of ions and solvents, temperature, concentration, electric field strength and the like.

• The mobility uB of an ion B is defined as its velocity in the direction of an electric field E of unit strength.

/B Bu Ev

ut

u u

ut

u u

Page 5: Transport No. & Kohlrausch Law
Page 6: Transport No. & Kohlrausch Law

mobilities of hydrogen and hydroxyl ionsmobilities of hydrogen and hydroxyl ions

• the mobility of hydrogen and hydroxyl ions in aqueous solution is abnormally high.

• This is because both the H3O+ ion and hydroxyl ion are able to transfer a proton to a neighboring water molecule. This is explained by the fact that the H+ and OH- ions need not migrate through a protic solvent, but move through exchange of a proton between neighboring solvent molecules.

• The unit of mobility is m2·V-1·s-1.

Page 7: Transport No. & Kohlrausch Law

measurement of transport numbers by Hittorf methodmeasurement of transport numbers by Hittorf method

The method of Hittorf is based on concentration changes in the anodic region and cathodic region in an electrolytic cell, caused by the passage of current through the electrolyte.

Page 8: Transport No. & Kohlrausch Law

measurement of transport number by the moving boundary methodmeasurement of transport number by the moving boundary method

Suppose the boundary moves a distant x from AA’ to BB’ for the passage of Q coulombs. All the ions, H+, passed through the boundary AA’. The amount of substances transported is then Q/F, of which t+Q/F are carried by the positive ion. If the volume between the boundaries AA’ and BB’ is V, and the concentration of HCl is c, then

/t Q F Vc

FVct

Q

Page 9: Transport No. & Kohlrausch Law

The dependence of molar conductivity on the concentration

Fro strong electrolytes, Kohlrausch observed

that m decreased with concentration according to

the expression

m m A c

Page 10: Transport No. & Kohlrausch Law
Page 11: Transport No. & Kohlrausch Law

conductivities and the concentrations of conductivities and the concentrations of electrolytes electrolytes

Page 12: Transport No. & Kohlrausch Law

Law of the independent migration of ions

Kohlrausch discovered relations between the values

of for different electrolytes. For example m

2 -1(KCl) 0.01499 S m molm

2 -1(LiCl) 0.01150 S m molm

2 -13(KNO ) 0.01450 S m molm

2 -1

3(LiNO ) 0.01101S m molm

The difference in for pairs of salts having common ion is always approximately constant.

Page 13: Transport No. & Kohlrausch Law

2 -13 3(KCl) (LiCl) (KNO ) (LiNO ) 0.00349 S m molm m m m

2 -13 3(KCl) (KNO ) (LiCl) (LiNO ) 0.00049 S m molm m m m

This behavior indicates that ions in an extremely dilute solution migrate independently. There is no interaction between different ions. Therefore

, ,m m m

Page 14: Transport No. & Kohlrausch Law

For example

At 25℃, (NaAc) = 91.0×10-4 S·m2·mol–1 ,

(HCl)=426.2×10-4 S·m2·mol–1 ,

(NaCl)=126.5×10-4 S·m2·mol–1 ,What is the molar conductivity of HAc at 25 ? ℃

m

m

m

Page 15: Transport No. & Kohlrausch Law

Solution + m m m(NaAc) = (Na ) + (Ac )

+ m m m(HCl) = (H ) + (Cl )

+ m m m(NaCl) = (Na ) + (Cl )

+ m m m(HAc) = (H ) + (Ac )

+ + m m m m

+ m m

= (H ) (Cl ) (Na ) (Ac )

(Na ) (Cl )

m m m= (HCl) (NaAc) (NaCl)

=(426.3 +91.0–126.5)×10–4 S·m2·mol–1

=390.7×10–4 S·m2·mol–1