3 project management project crashing

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  • 7/28/2019 3 Project Management Project Crashing

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    3 1

    33 CHAPTER THREE

    ProjectProjectManagement:Management:

    Project CrashingProject Crashing

    ProjectProjectManagement:Management:

    Project CrashingProject Crashing

    3 2

    A project that your company has undertaken has the followingactivities, which are listed below:

    ActivityPreceding

    ActivityNormal time

    (weeks)Normal cost

    ($)Crash time

    (weeks)Crash cost

    ($)

    ABC

    DEFGHJ

    --

    A

    CB, CD, E

    FE, G

    H

    465

    8108953

    400060004000

    300015006000200060003000

    25-

    47-7--

    60006500

    -

    78003600

    -6000

    --

    The normal costs shown for each activity are the costs to complete eachactivity by working under normal conditions. The crash time represents theshortest time in which the activity can be completed given the use of costlymethods of completion. Assume that it is possible to reduce the normal timeto crash time in steps of one week and that the extra cost will be proportionalto the time saved. In addition, there is a site cost of $1,500 per week.

    Problem

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    1.1. Compute the crash cost per time period.Compute the crash cost per time period.

    Crash costCrash costper periodper period ==

    (Crash cost(Crash cost Normal cost)Normal cost)

    (Normal time(Normal time Crash time)Crash time)

    ActAct AA BB CC DD EE FF GG HH JJ

    CCCC 10001000 500500 -- 12001200 700700 -- 20002000 -- --

    MaxMax 22 11 -- 44 33 -- 22 -- --

    2.2. Using normal activity times, find the criticalUsing normal activity times, find the criticalpath and identify the critical activities.path and identify the critical activities.

    Determine the minimum cost of undertaking this

    project and state its associated time of completion

    3 4

    A

    4

    40

    B

    6

    60

    Start

    0

    00

    C

    5

    94D

    8

    179

    E

    10

    199 F

    8

    2719 G

    9

    3627

    H

    5

    4136J

    3

    4441

    44414136

    36272719199

    19119440

    93

    Critical path:

    A-C-E-F-G-H-J

    Project Duration = 44 weeks

    Total cost = $35,500+(44x1500)=$101,500

    Network Diagram

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    Network Diagram - Crashing

    A1000

    2

    4

    40

    B5001

    6

    60

    Start

    0

    00

    C--5

    94D

    12004

    8

    179

    E7003

    10

    199F--8

    2719G

    20002

    9

    3627

    H--5

    4136J--3

    4441

    44414136

    36272719199

    19119440

    93

    OBJECTIVE minimize totalcost

    One critical path min. crashcost per week on this criticalpath $700 (activity E) thencrash activity E by 2 weekswhy 2 weeks?

    3 6

    Network Diagram - Crashing

    A1000

    2

    4

    40

    B5001

    6

    60

    Start

    0

    00

    C--5

    94D

    12004

    8

    179

    E7001

    8

    179 F--8

    2517 G20002

    9

    3425

    H--5

    3934J--3

    4239

    42393934

    34252517179

    1799440

    93

    Duration: 42

    New Total Cost =101500+(700x2) (2x1500) =$99,900

    Now two critical paths:ACDFGHJ & ACEFGHJ min.crash cost per week for both

    paths$1000 (activity A) thencrash activity A by 2 weeks.

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    4

    3 7

    Network Diagram - Crashing

    A1000

    0

    2

    20

    B5001

    6

    60

    Start

    0

    00

    C--5

    72D

    12004

    8

    157

    E7001

    8

    157F--8

    2315G

    20002

    9

    3223

    H--5

    3732J--3

    4037

    40373732

    32232315157

    1577220

    71

    Duration: 40

    New Total Cost =99,900+(1000x2) (2x1500) =$98,900

    Two critical paths:ACDFGHJ &ACEFGHJSTOPsince min.crash cost per week for both

    paths ($1200+$700) (D & E)greater than $1500site cost.