a systematic impedance model for non-linear helmholtz ...dsingh/images/casa_day.pdf · systematic...
TRANSCRIPT
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
A systematic impedance model fornon-linear Helmholtz resonator liner
Deepesh Kumar Singh
Mentor: Sjoerd Rienstra
CASA DAY
April 17, 2013
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Outline
1 Problem Definition
2 The Model
3 The Linear case
4 The Non Linear case
5 Results
6 Applications
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Outline
1 Problem Definition
2 The Model
3 The Linear case
4 The Non Linear case
5 Results
6 Applications
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Acoustic Liner
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Helmholtz resonator and its ImpedanceMass-spring damper system for attenuating noiseAir in the hole ≡ massAir in the cavity ≡ springViscosity and vortex shading ≡ dampingThe resonator is characterizedby its impedance Z = Z(ω)
Spatially averaged impedancerelates the pressure andvelocity
Z(ω) :=p̂
v̂· n̂Ideally, Z is a wall property and independent of the acoustic fieldIn reality, Z is amplitude dependent for high but relevant amplitudes.
A good precision in the value of impedance improve the fidelityof the liner optimization by e.g. CAA Solvers
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Aim and Motivation
Aim
Systematic solution of non-linear Helmholtz resonator equationfrom first principles to obtain analytic expressions for impedanceclose to resonance with non-linear effects.
Motivation
The usual non-linear corrections for a Helmholtz type impedanceare not based on a systematic asymptotic solution of thepertaining equations. All of them are either ad-hoc or by fullyCFD simulation [1] [2] [3].
example
Re(Z) = A + BV
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Outline
1 Problem Definition
2 The Model
3 The Linear case
4 The Non Linear case
5 Results
6 Applications
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Model
SbV p′in
u′in ' 0
u′n
`
p′exSn
Sb � Sn - p′ex and u′in are uniformk`� 1 - cavity neck is acoustically compactLine Integral of momentum equation along center streamlineyields:
ρ0ddt
∫ exin
v′·ds + 12ρ0(u′2ex− u′2in) + (p′ex− p′in) =∫ ex
inµ∇2v′·ds.
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Model
With minor friction effects, the velocity integral scales on typicallength and typical velocity∫ ex
inv′·ds = (`+ 2δ)u′n
The stress integral depends on Reynolds number, wall heatexchange, turbulence, separation from sharp edges. We takethese effects together in a small factor R.∫ ex
inµ∇2v′·ds = −Ru′n
Using the inflow and outflow conditionsInflow: u′ex = 0, u
′in = u
′n
Outflow: u′in = 0, u′ex = −u′n
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
ModelMass conservation of volume V
Vdρ′indt
= −ρu′nSn ≈ −ρ0u′nSn
Isentropic relation p′in = c20ρ′in.
`Vc20Sn
d2p′indt2
+V2
2ρ0c40S2n
dp′indt
∣∣∣∣dp′indt∣∣∣∣+ RVρ0c20Sn dp
′in
dt+ p′in = p
′ex
Resonance frequency ω0 = (c20Sn`V )
1/2
Non-dimensionalize the variablesp′ex = 2�
2ρ0c20(`Sn/V)F p′in = 2�ρ0c
20(`Sn/V)y
τ = ω0t R = �ρ0c0(`Sn/V)1/2rd2ydτ 2
+ εdydτ
∣∣∣∣ dydτ∣∣∣∣+ εr dydτ + y = εF0 cos(Ωτ) Ω = ωω0 = 1 + ε∆
Most notorious term harmonic forcing
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Outline
1 Problem Definition
2 The Model
3 The Linear case
4 The Non Linear case
5 Results
6 Applications
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Linear case - away from resonance
The governing equation:
d2ydτ 2
+εdydτ
∣∣∣∣ dydτ∣∣∣∣+εr dydτ+y = εF0 cos(Ωτ) Ω = ωω0 = 1+ε∆
Since 1− Ω2 = O(1), y = O(ε) and εy′|y′| = O(ε3)
y(τ) = εF0(1− Ω2) cos(Ωτ) + εrΩ sin(Ωτ)
(1− Ω2)2 + ε2r2Ω2+ . . .
A =εF0√
(1− Ω2)2 + ε2r2Ω2, tan θ =
εrΩ(1− Ω2)2
Invalid close to the resonance, i.e. 1− Ω2 = O(ε) so A = O(1)
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Outline
1 Problem Definition
2 The Model
3 The Linear case
4 The Non Linear case
5 Results
6 Applications
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Non Linear case
Ωτ = τ̃ + θ(ε)absorb Ω into τ̃ to avoid secular terms cos(Ωτ)phase shift θ(ε) to fix the location of the sign change of y′
Ω2d2ydτ̃ 2
+ εΩ2dydτ̃
∣∣∣∣ dydτ̃∣∣∣∣+ εΩr dydτ̃ + y = εF0 cos(τ̃ + θ)
Substitute the assumed Poincaré expansion
y(τ̃ ; ε) = y0(τ̃)+εy1(τ̃)+ε2y2(τ̃)+. . . , and θ(ε) = θ0+εθ1+. . .
and expand
(1+2�∆+�2∆2)(y′′0 +�y′′1 +�
2y′′2 )+(�+2�2∆+�3∆2)(y′0+�y
′1+�
2y′2)∣∣∣(y′0 + �y′1 + �2y′2)∣∣∣
+(�r+�2r∆)(y′0+�y′1+�
2y′2)+(y′0+�y
′1+�
2y′2) = �F0 cos(τ̃+θ0)−�2θ1F0 sin(τ̃+θ0)
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Amplitude calculation
d2y0dτ̃ 2 + y0 = 0, y
′0(Nπ) = 0 with y0(τ̃) = A0 cos(τ̃)
Determine the integration constants A0 and θ0 from next order ε1,d2y1dτ̃ 2
+ y1 = F0 cos(τ̃ + θ0)− 2∆d2y0dτ̃ 2−
dy0dτ̃
∣∣∣∣dy0dτ̃∣∣∣∣− r dy0dτ̃
= F0 cos(τ̃ + θ0) + 2∆A0 cos(τ̃) + A0|A0| sin(τ̃) |sin(τ̃)|+ rA0 sin(τ̃)
Only stationary state→ no sine - cosine excitation
F0 cos θ0 = −2∆A0, F0 sin θ0 =(
83π|A0|+ r
)A0
The next order y1
y1(t) = A1 cos τ̃ +1
4πA0|A0|
[− 89 sin τ̃ +
∞∑n=1
sin(2n + 1)τ̃
n(n + 1)(n2 − 14 )(n +32 )
]
A1 and θ1 determined in a similar way as with y0.
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Amplitude calculationThe full solution is
y(τ ; θ) = A0 cos(τ−θ)+�
A1 cos(τ − θ) + 14π
A0|A0|
− 89 sin(τ − θ) + ∞∑n=1
sin(2n + 1)(τ − θ)n(n + 1)(n2 − 14 )(n +
32 )
(1)
∆ = O(1ε) A0 and θ0 → linear caseAmplitude and Phase (ε0)
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
-4 -2 0 2 4
Am
plitu
de
∆
A0
0
0.5
1
1.5
2
2.5
3
3.5
-4 -2 0 2 4Ph
ase
(rad
ians
)
∆
θ0
Solution of amplitude (A0, A1) and phase (θ0 , θ1) as a function of ∆,for r = 1 and F0 = 1Max amplitude at linear resonance
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Comparison with the numerical solution (R Kiteration)
-0.2
-0.15
-0.1
-0.05
0
0.05
0.1
0.15
0.2
400 402 404 406 408 410 412
y(τ)
arbitrary τ
y0y0 + �y1
numerical solution
Comparison of the amplitude �0 and �1 order with full numerical solution(∆ = 1,� = 0.1)
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Impedance Calculation
In order to comply with the literature, we define Impedance asthe ratio of the Fourier transforms of pressure and velocity at theforcing frequency
Z(η) = −∫∞−∞ p
′exe−iηtdt∫∞
−∞ u′exe−iηtdt
= − p̂′ex(η)
û′ex(η). (2)
Remember
p′ex = 2�2ρ0c20(`Sn/V)F
Vc20
2ερ0c20`Sn/V
Ω
dy(t)dt
= −ρu′nSn and u′ex = u′nSnSb
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Outline
1 Problem Definition
2 The Model
3 The Linear case
4 The Non Linear case
5 Results
6 Applications
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Impedance results
0
20
40
60
80
100
120
140
0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2
Re(
Z)
Ω
100dB110dB120dB130dB
-250
-200
-150
-100
-50
0
50
100
150
200
0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2
Im(Z
)
Ω
100dB110dB120dB130dB
Impedance (Re(Z) and Im(Z) of Helmholtz resonator Vs Ω at differentdriving amplitudes (i.e. ε). Sn/Sb = 0.05, r = 0.2, ω0 = 9086.9 rad/s, L =0.035 m, ` = 0.002 m.
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Comparison with the existing measurements
0
0.2
0.4
0.6
0.8
1
1000 1500 2000 2500 3000 3500
Re(
Z)
f
125dB130dB135dB140dB145dB150dB
Comparison of the resistance of the cavity Re(Z) with the measurements in[3]. 0.2 6 ε 6 0.55
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Comparison of the Impedance obtained from y0 andy0 + εy1
0
20
40
60
80
100
120
140
0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2
Re(
Z)
Ω
ε0 orderε1 order
-250
-200
-150
-100
-50
0
50
100
150
200
0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2
Im(Z
)Ω
ε0 orderε1 order
Comparison of the Impedence of the cavity obtained from the �0 and �1asymptotic analysis for 100dB, 110dB, 120dB and 130dB. 0.1 6 � 6 0.3
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Outline
1 Problem Definition
2 The Model
3 The Linear case
4 The Non Linear case
5 Results
6 Applications
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
N wave forcing
Model N wave ∑∞n=1
sin(nt)n
sin(t)
N-wave modes/shocks produce by fan blade tip at full enginepower take off
-2
-1.5
-1
-0.5
0
0.5
1
1.5
2
0 5 10 15 20
ampl
itude
y
time t
N wave
Shocks from the blade tip at 95% casing height
nwave.wavMedia File (audio/wav)
sine.wavMedia File (audio/wav)
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
Impedance for N wave excitation
(1 + 2ε∆)d2ydτ̃ 2
+ εdydτ̃
∣∣∣∣ dydτ̃∣∣∣∣+ εr dydτ̃ + y = εF0
∞∑n=1
sin n(τ̃ + θ)n
(3)
0
200
400
600
800
1000
1200
1400
1600
1800
1 2 3 4 5 6 7
Rea
l(Z
)
n
Real(Z)
-1000
0
1000
2000
3000
4000
5000
6000
7000
8000
9000
10000
1 2 3 4 5 6 7
Im(Z
)
n
Im(Z)
Impedance at observed frequency η = nω and N wave excitation Ω = 1.
-
/centre for analysis, scientific computing and applications
Problem Model Linear case Non Linear case Results Applications
References
A.W. Guess.Calculation of perforated plate liner parameters from specified acoustic resistance and reactance.Journal of Sound and Vibration, 40(1):119 – 137, 1975.
T.H. Melling.The acoustic impendance of perforates at medium and high sound pressure levels.Journal of Sound and Vibration, 29(1):1 – 65, 1973.
H.H. Hubbard and Acoustical Society of America.Aeroacoustics of Flight Vehicles: Noise sources.Aeroacoustics of Flight Vehicles: Theory and Practice. Volume 1 Noise Sources; Volume 2 Noise Control. Publishedfor the Acoustical Society of America through the American Institute of Physics, 1991.
K.U. Ingard and Massachusetts Institute of Technology. Industrial Liaison Office.On the Theory and Design of Acoustic Resonators.1953.
R.M.M. Mattheij, S.W. Rienstra, and J.H.M.T. Boonkkamp.Partial Differential Equations: Modeling, Analysis, Computation.Society for Industrial and Applied Mathematics, 1987.
C. Bréard, A. Sayma, M. Imregun, A.G. Wilson, and B.J. Tester.A cfd-based non-linear model for the prediction of tone noise in lined ducts.In 7th AIAA/CEAS Aeroacoustics Conference, 2001.AIAA-2001-2181.
Problem DefinitionThe ModelThe Linear caseThe Non Linear caseResultsApplications