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/centre for analysis, scientific computing and applications Problem Model Linear case Non Linear case Results Applications A systematic impedance model for non-linear Helmholtz resonator liner Deepesh Kumar Singh Mentor: Sjoerd Rienstra CASA DAY April 17, 2013

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  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    A systematic impedance model fornon-linear Helmholtz resonator liner

    Deepesh Kumar Singh

    Mentor: Sjoerd Rienstra

    CASA DAY

    April 17, 2013

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Outline

    1 Problem Definition

    2 The Model

    3 The Linear case

    4 The Non Linear case

    5 Results

    6 Applications

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Outline

    1 Problem Definition

    2 The Model

    3 The Linear case

    4 The Non Linear case

    5 Results

    6 Applications

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Acoustic Liner

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Helmholtz resonator and its ImpedanceMass-spring damper system for attenuating noiseAir in the hole ≡ massAir in the cavity ≡ springViscosity and vortex shading ≡ dampingThe resonator is characterizedby its impedance Z = Z(ω)

    Spatially averaged impedancerelates the pressure andvelocity

    Z(ω) :=p̂

    v̂· n̂Ideally, Z is a wall property and independent of the acoustic fieldIn reality, Z is amplitude dependent for high but relevant amplitudes.

    A good precision in the value of impedance improve the fidelityof the liner optimization by e.g. CAA Solvers

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Aim and Motivation

    Aim

    Systematic solution of non-linear Helmholtz resonator equationfrom first principles to obtain analytic expressions for impedanceclose to resonance with non-linear effects.

    Motivation

    The usual non-linear corrections for a Helmholtz type impedanceare not based on a systematic asymptotic solution of thepertaining equations. All of them are either ad-hoc or by fullyCFD simulation [1] [2] [3].

    example

    Re(Z) = A + BV

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Outline

    1 Problem Definition

    2 The Model

    3 The Linear case

    4 The Non Linear case

    5 Results

    6 Applications

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Model

    SbV p′in

    u′in ' 0

    u′n

    `

    p′exSn

    Sb � Sn - p′ex and u′in are uniformk`� 1 - cavity neck is acoustically compactLine Integral of momentum equation along center streamlineyields:

    ρ0ddt

    ∫ exin

    v′·ds + 12ρ0(u′2ex− u′2in) + (p′ex− p′in) =∫ ex

    inµ∇2v′·ds.

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Model

    With minor friction effects, the velocity integral scales on typicallength and typical velocity∫ ex

    inv′·ds = (`+ 2δ)u′n

    The stress integral depends on Reynolds number, wall heatexchange, turbulence, separation from sharp edges. We takethese effects together in a small factor R.∫ ex

    inµ∇2v′·ds = −Ru′n

    Using the inflow and outflow conditionsInflow: u′ex = 0, u

    ′in = u

    ′n

    Outflow: u′in = 0, u′ex = −u′n

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    ModelMass conservation of volume V

    Vdρ′indt

    = −ρu′nSn ≈ −ρ0u′nSn

    Isentropic relation p′in = c20ρ′in.

    `Vc20Sn

    d2p′indt2

    +V2

    2ρ0c40S2n

    dp′indt

    ∣∣∣∣dp′indt∣∣∣∣+ RVρ0c20Sn dp

    ′in

    dt+ p′in = p

    ′ex

    Resonance frequency ω0 = (c20Sn`V )

    1/2

    Non-dimensionalize the variablesp′ex = 2�

    2ρ0c20(`Sn/V)F p′in = 2�ρ0c

    20(`Sn/V)y

    τ = ω0t R = �ρ0c0(`Sn/V)1/2rd2ydτ 2

    + εdydτ

    ∣∣∣∣ dydτ∣∣∣∣+ εr dydτ + y = εF0 cos(Ωτ) Ω = ωω0 = 1 + ε∆

    Most notorious term harmonic forcing

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Outline

    1 Problem Definition

    2 The Model

    3 The Linear case

    4 The Non Linear case

    5 Results

    6 Applications

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Linear case - away from resonance

    The governing equation:

    d2ydτ 2

    +εdydτ

    ∣∣∣∣ dydτ∣∣∣∣+εr dydτ+y = εF0 cos(Ωτ) Ω = ωω0 = 1+ε∆

    Since 1− Ω2 = O(1), y = O(ε) and εy′|y′| = O(ε3)

    y(τ) = εF0(1− Ω2) cos(Ωτ) + εrΩ sin(Ωτ)

    (1− Ω2)2 + ε2r2Ω2+ . . .

    A =εF0√

    (1− Ω2)2 + ε2r2Ω2, tan θ =

    εrΩ(1− Ω2)2

    Invalid close to the resonance, i.e. 1− Ω2 = O(ε) so A = O(1)

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Outline

    1 Problem Definition

    2 The Model

    3 The Linear case

    4 The Non Linear case

    5 Results

    6 Applications

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Non Linear case

    Ωτ = τ̃ + θ(ε)absorb Ω into τ̃ to avoid secular terms cos(Ωτ)phase shift θ(ε) to fix the location of the sign change of y′

    Ω2d2ydτ̃ 2

    + εΩ2dydτ̃

    ∣∣∣∣ dydτ̃∣∣∣∣+ εΩr dydτ̃ + y = εF0 cos(τ̃ + θ)

    Substitute the assumed Poincaré expansion

    y(τ̃ ; ε) = y0(τ̃)+εy1(τ̃)+ε2y2(τ̃)+. . . , and θ(ε) = θ0+εθ1+. . .

    and expand

    (1+2�∆+�2∆2)(y′′0 +�y′′1 +�

    2y′′2 )+(�+2�2∆+�3∆2)(y′0+�y

    ′1+�

    2y′2)∣∣∣(y′0 + �y′1 + �2y′2)∣∣∣

    +(�r+�2r∆)(y′0+�y′1+�

    2y′2)+(y′0+�y

    ′1+�

    2y′2) = �F0 cos(τ̃+θ0)−�2θ1F0 sin(τ̃+θ0)

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Amplitude calculation

    d2y0dτ̃ 2 + y0 = 0, y

    ′0(Nπ) = 0 with y0(τ̃) = A0 cos(τ̃)

    Determine the integration constants A0 and θ0 from next order ε1,d2y1dτ̃ 2

    + y1 = F0 cos(τ̃ + θ0)− 2∆d2y0dτ̃ 2−

    dy0dτ̃

    ∣∣∣∣dy0dτ̃∣∣∣∣− r dy0dτ̃

    = F0 cos(τ̃ + θ0) + 2∆A0 cos(τ̃) + A0|A0| sin(τ̃) |sin(τ̃)|+ rA0 sin(τ̃)

    Only stationary state→ no sine - cosine excitation

    F0 cos θ0 = −2∆A0, F0 sin θ0 =(

    83π|A0|+ r

    )A0

    The next order y1

    y1(t) = A1 cos τ̃ +1

    4πA0|A0|

    [− 89 sin τ̃ +

    ∞∑n=1

    sin(2n + 1)τ̃

    n(n + 1)(n2 − 14 )(n +32 )

    ]

    A1 and θ1 determined in a similar way as with y0.

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Amplitude calculationThe full solution is

    y(τ ; θ) = A0 cos(τ−θ)+�

    A1 cos(τ − θ) + 14π

    A0|A0|

    − 89 sin(τ − θ) + ∞∑n=1

    sin(2n + 1)(τ − θ)n(n + 1)(n2 − 14 )(n +

    32 )

    (1)

    ∆ = O(1ε) A0 and θ0 → linear caseAmplitude and Phase (ε0)

    0

    0.1

    0.2

    0.3

    0.4

    0.5

    0.6

    0.7

    -4 -2 0 2 4

    Am

    plitu

    de

    A0

    0

    0.5

    1

    1.5

    2

    2.5

    3

    3.5

    -4 -2 0 2 4Ph

    ase

    (rad

    ians

    )

    θ0

    Solution of amplitude (A0, A1) and phase (θ0 , θ1) as a function of ∆,for r = 1 and F0 = 1Max amplitude at linear resonance

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Comparison with the numerical solution (R Kiteration)

    -0.2

    -0.15

    -0.1

    -0.05

    0

    0.05

    0.1

    0.15

    0.2

    400 402 404 406 408 410 412

    y(τ)

    arbitrary τ

    y0y0 + �y1

    numerical solution

    Comparison of the amplitude �0 and �1 order with full numerical solution(∆ = 1,� = 0.1)

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Impedance Calculation

    In order to comply with the literature, we define Impedance asthe ratio of the Fourier transforms of pressure and velocity at theforcing frequency

    Z(η) = −∫∞−∞ p

    ′exe−iηtdt∫∞

    −∞ u′exe−iηtdt

    = − p̂′ex(η)

    û′ex(η). (2)

    Remember

    p′ex = 2�2ρ0c20(`Sn/V)F

    Vc20

    2ερ0c20`Sn/V

    dy(t)dt

    = −ρu′nSn and u′ex = u′nSnSb

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Outline

    1 Problem Definition

    2 The Model

    3 The Linear case

    4 The Non Linear case

    5 Results

    6 Applications

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Impedance results

    0

    20

    40

    60

    80

    100

    120

    140

    0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2

    Re(

    Z)

    100dB110dB120dB130dB

    -250

    -200

    -150

    -100

    -50

    0

    50

    100

    150

    200

    0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2

    Im(Z

    )

    100dB110dB120dB130dB

    Impedance (Re(Z) and Im(Z) of Helmholtz resonator Vs Ω at differentdriving amplitudes (i.e. ε). Sn/Sb = 0.05, r = 0.2, ω0 = 9086.9 rad/s, L =0.035 m, ` = 0.002 m.

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Comparison with the existing measurements

    0

    0.2

    0.4

    0.6

    0.8

    1

    1000 1500 2000 2500 3000 3500

    Re(

    Z)

    f

    125dB130dB135dB140dB145dB150dB

    Comparison of the resistance of the cavity Re(Z) with the measurements in[3]. 0.2 6 ε 6 0.55

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Comparison of the Impedance obtained from y0 andy0 + εy1

    0

    20

    40

    60

    80

    100

    120

    140

    0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2

    Re(

    Z)

    ε0 orderε1 order

    -250

    -200

    -150

    -100

    -50

    0

    50

    100

    150

    200

    0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2

    Im(Z

    )Ω

    ε0 orderε1 order

    Comparison of the Impedence of the cavity obtained from the �0 and �1asymptotic analysis for 100dB, 110dB, 120dB and 130dB. 0.1 6 � 6 0.3

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Outline

    1 Problem Definition

    2 The Model

    3 The Linear case

    4 The Non Linear case

    5 Results

    6 Applications

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    N wave forcing

    Model N wave ∑∞n=1

    sin(nt)n

    sin(t)

    N-wave modes/shocks produce by fan blade tip at full enginepower take off

    -2

    -1.5

    -1

    -0.5

    0

    0.5

    1

    1.5

    2

    0 5 10 15 20

    ampl

    itude

    y

    time t

    N wave

    Shocks from the blade tip at 95% casing height

    nwave.wavMedia File (audio/wav)

    sine.wavMedia File (audio/wav)

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    Impedance for N wave excitation

    (1 + 2ε∆)d2ydτ̃ 2

    + εdydτ̃

    ∣∣∣∣ dydτ̃∣∣∣∣+ εr dydτ̃ + y = εF0

    ∞∑n=1

    sin n(τ̃ + θ)n

    (3)

    0

    200

    400

    600

    800

    1000

    1200

    1400

    1600

    1800

    1 2 3 4 5 6 7

    Rea

    l(Z

    )

    n

    Real(Z)

    -1000

    0

    1000

    2000

    3000

    4000

    5000

    6000

    7000

    8000

    9000

    10000

    1 2 3 4 5 6 7

    Im(Z

    )

    n

    Im(Z)

    Impedance at observed frequency η = nω and N wave excitation Ω = 1.

  • /centre for analysis, scientific computing and applications

    Problem Model Linear case Non Linear case Results Applications

    References

    A.W. Guess.Calculation of perforated plate liner parameters from specified acoustic resistance and reactance.Journal of Sound and Vibration, 40(1):119 – 137, 1975.

    T.H. Melling.The acoustic impendance of perforates at medium and high sound pressure levels.Journal of Sound and Vibration, 29(1):1 – 65, 1973.

    H.H. Hubbard and Acoustical Society of America.Aeroacoustics of Flight Vehicles: Noise sources.Aeroacoustics of Flight Vehicles: Theory and Practice. Volume 1 Noise Sources; Volume 2 Noise Control. Publishedfor the Acoustical Society of America through the American Institute of Physics, 1991.

    K.U. Ingard and Massachusetts Institute of Technology. Industrial Liaison Office.On the Theory and Design of Acoustic Resonators.1953.

    R.M.M. Mattheij, S.W. Rienstra, and J.H.M.T. Boonkkamp.Partial Differential Equations: Modeling, Analysis, Computation.Society for Industrial and Applied Mathematics, 1987.

    C. Bréard, A. Sayma, M. Imregun, A.G. Wilson, and B.J. Tester.A cfd-based non-linear model for the prediction of tone noise in lined ducts.In 7th AIAA/CEAS Aeroacoustics Conference, 2001.AIAA-2001-2181.

    Problem DefinitionThe ModelThe Linear caseThe Non Linear caseResultsApplications