chapter 11-2 probability and punnett squares...
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Chapter 11-2 Probability and Punnett Squares Notes
Every time Mendel performed a cross with his pea plants, he carefully counted the offspring (over 20,000 plants)
This why he noticed there was a pattern! LARGE NUMBERS
Whenever he crossed 2 plants that were hybrid for stem height (Tt), about ¾ (75%) of the resulting plants were Tall and ¼ (25%) were short (3:1 ratio)
He realized that the principles of probability could be used to explain his results!
Probability
Definition: the likelihood that a particular event will occur
Examples:
Flip a coin: ½ or 50% chance it will come up heads
If you flip a coin 3 times in a row, what is the probability it will come up heads 3 times in a row?
Each coin flip is an independent event therefore it is:
½ x ½ x ½ = 1/8
Past outcomes do not influence future outcomes
The principles of probability can be used to predict the outcomes of genetic crosses
Punnett Squares
The gene combinations that MIGHT result from a genetic cross can be determined by drawing a PunnettSquare
1. The parents go on the outside of the square along the side (male alleles) and top (female alleles
2. The possible outcomes of the cross are on the inside of the square
3. The letters in the Punnett Square represent alleles
Alleles in a Punnett Square
-“T” represents the dominant allele: TALL
-“t” represents the recessive allele: short
Organisms with 2 identical alleles (TT or tt) for a trait are said to be HOMOZYGOUS
Mendel called these: true-breeding
Organisms with 2 different alleles for a particular trait are said to be HETEROZYGOUS
Mendel called these hybrids
Phenotype: the physical characteristics of the organism (what the organism looks like)
Ex: Tall; short
Genotype: the actual genetic makeup of the organism (the 2 alleles the organism inherited)
Ex: TT; Tt: tt
Probabilities Predict Averages
Probabilities predict the outcomes of a LARGEnumber of events
Probabilities cannot predict precise outcomes of an event
-Ex: flip a coin twice you may get 100% heads
-You need to flip the coin many, many times to get close to 50%
Punnett Squares
Tt Tt
Tt Tt
The genes from the female parent go here.
The genes from the male parent go here.
Punnett Squares
T T
t Tt Tt
t Tt Tt
Punnett Squares
T T
t Tt Tt
t Tt Tt
Punnett Squares
T T
t Tt Tt
t Tt Tt
Punnett Squares
T T
t Tt Tt
t Tt Tt
Punnett Squares
T T
t Tt Tt
t Tt Tt
Punnett Squares
T T
t Tt Tt
t Tt Tt
F1 generation
T T
t Tt Tt
t Tt Tt
Interpreting the ResultsThe genotype for all the offspring is Tt.
The genotype ratio is:
Tt – 4:0 = 100%
The phenotype for all the offspring is tall.The phenotype ratio is:
tall – 4:0 = 100%
Punnett Squares
T t
T ?? ??
t ?? ??
Your Turn!!
Punnett Squares
T t
T TT Tt
t Tt tt
F2 generation
Punnett Squares
T t
T TT Tt
t Tt tt
Next, give the genotype and phenotype ratios of the offspring (F2 generation).
Punnett Squares
T t
T TT Tt
t Tt tt
Genotype ratio: TT - 1
Punnett Squares
T t
T TT Tt
t Tt tt
Genotype ratio: TT - 1, Tt - 2
Punnett Squares
T t
T TT Tt
t Tt tt
Genotype ratio: TT - 1, Tt - 2, tt - 1
Genotype ratio: 1: 2: 1
Punnett Squares
T t
T TT Tt
t Tt tt
Genotype ratio: TT - 1, Tt - 2, tt - 1
Phenotype ratio: Tall - 3
Punnett Squares
T t
T TT Tt
t Tt tt
Genotype ratio: TT - 1, Tt - 2, tt - 1
Phenotype ratio: Tall - 3, short - 1
Punnett Squares
T t
T TT Tt
t Tt tt
This is a monohybrid cross. We worked with only onetrait. The height of the plant.
One
Punnett Squares
T t
T TT Tt
t Tt tt
This is a monohybrid cross. We worked with only onetrait. The height of the plant.
Later we will work with a dihybrid cross, using theheight of the plant and either seed color or seedshape.
two
3. What is the expected ratio for this crosses? Assume the first written is from the female….
Tt x tt Female TtM
ale
t
t
T t
t
t
Tt t t
Tt t t
Tt x tt
Genotypic Ratio:
Phenotypic Ratio:
0 TT, 2 Tt, 2 tt = 2 Tt : 2 tt
2 Tall : 2 short or 50% Tall : 50% short
50% Tt : 50% tt
XX and XY
Female XXM
ale
X
Y
XX XX
XY XY
X X
X
Y
XX x XY
Phenotypic Ratio: 50% Females and 50% Males
The Testcross
Homozygous dominant and heterozygous individuals are indistinguishable (phenotypically)
A testcross allows us to determine the genotype of an individual that has the dominant trait.
We cross the parent showing the
dominant trait with a recessive
parent.
-If all (100%) of the offspring are dominant type then we assume the initial parent was homozygous dominant.
-If even one offspring shows the recessive type then we know the initial parent was heterozygous.