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PHYS 532. L6 1
Chapter 5 Summary5.1 Introduction and Definitions
• Definition of Magnetic Flux Density B– To find the “magnetic flux density” B at x, place a
small magnetic dipole µ at x and measure the torqueon it:
N = µ × B(x) (5.1)
– ρ=charge density (coul/m3)
– J=current density (amps/m2)
– The torque tries to turn the dipole in the direction ofB.
• Conservation of charge condition:∂ρ∂t
+ ∇ ⋅J = 0 (5.2)
PHYS 532. L6 2
5.2 Biot-Savart Law
• Force on a volume V:
F = J × B d3x
V∫
N = x × (J × B) d3x
V∫
• Torque on volume V:
• Magnetic force on a point charge q moving at v:
(5.12)
(5.13)
F = qv × B
PHYS 532. L6 3
• Integral form of Biot-Savart Law:
B(x) =µo
4πJ(x' )×
x − x'
x − x' 3∫ d3x' =µo
4π∇ ×
J(x' )x − x'∫ d3x' (5.14)
(5.16)
• Differential equations:– Equation (5.16) obviously implies
∇ ⋅B = 0
– For static conditions (∇⋅J=0), (5.16) implies
∇ × B = µoJ
(5.17)
(5.22)
– Integrating (5.22) over a closed area gives Ampere’slaw:
B ⋅ dlC∫ = µo I
where I is the current threading the closed loop C.
(5.25)
5.3 Differential Equations ofMagnetostatics and Ampere’s Law
where µo=4π×10-7
PHYS 532. L6 4
5.4 Vector Potential
• Since ∇⋅B=0, any magnetic flux density can berepresented in terms of a vector potential:
B = ∇ × A (5.27)
• Integral expression for A:
A(x) =µo
4πJ(x')x - x'∫ d3x' + ∇Ψ(x) (5.28)
PHYS 532. L6 5
5.6 Magnetic Fields of a LocalizedCurrent Distribution
• In (5.28), use an expansion like the one we used toget the multipole expansion in electrostatics:
1x − x'
=1x
+x ⋅ x'
x3 + ...
• First term gives zero (no magnetic monopole).
• Second term gives
(5.28)
A(x) =µo
4πm × x
x 3 (5.55)
where m is the magnetic dipole moment:
m =12
x'∫ × J(x')d3x' (5.54)
If the current is a plane loop, the magnetic momenthas magnitude equal to the current in the loop timesthe area of the loop.
B(x) =µo
4π3x(x ⋅ m) − m
x 3 +8π3
mδ (3)(x)
Looks like E of electric dipole
Extra term tomake integralsright includingorigin
(5.64)
PHYS 532. L6 6
5.7 Force and Torque on and Energy ofa Localized Current Distribution in an
External Magnetic Induction
• Force on a dipole in an external magnetic inductionB:
F = ∇(m ⋅ B) (5.69)
N = m × B (5.71)
Dipole aligned with B is drawn toward the region ofstrong field.
PHYS 532. L6 7
5.8 Macroscopic Equations, BoundaryConditions on B and H
• For materials, define M = magnetic moment perunit volume– The magnetic effect of that continuum of dipoles is
equivalent to a current distribution (calledmagnetization current)
JM = ∇ × M (5.79)
PHYS 532. L6 8
• Define the “magnetic field” H:
• Magnetic Maxwell equations in a medium:– The flux-conservation Maxwell equation, which is
homogeneous, remains the same as in a vacuum:
∇ ⋅B = 0
– For the Ampere’s Law Maxwell equation, split thecurrent into two parts: magnetization current andcurrent carried by free particles:
∇ × B = µo J + ∇ × M( )
(5.75)
(5.80)
Current carried by free charges
H =1
µoB − M (5.81)
• The magnetic field Maxwell equations in a mediumthen become
∇ ⋅B = 0
∇ × H = J(5.82)
• For a linear, isotropic medium, it is convenient towrite
B = µH
where µ is called the “magnetic permeability.”
(5.84)
• For ferromagnetic materials, B is a nonlinearfunction of H.
PHYS 532. L6 9
• Note that∇ ⋅H = − ∇ ⋅M
• If M is specified (as is typically the case forproblems involving ferromagnetic materials), then
∇ × H = 0
and the equations of magnetostatics are equivalentto the equations of electrostatics.
• Among working scientists (as opposed to textbookauthors), there is often confusion about H and B.Plasma physicists usually use the symbol B andavoid H, but they refer to B as the magnetic field,which is politically incorrect.
• Boundary conditions:– The normal component of B is conserved at the
boundary between magnetic materials.
– The tangential component of H is conserved at sucha boundary if the only current flowing on theboundary is magnetization current.
PHYS 532. L6 10
5.15 Faraday’s Law of Induction• Integral form:
E = −k
dF
dt(5.135)
E = E' ⋅dlC∫ (5.134)
where– the EMF in the circuit is defined by
and E’ is the electric field in the rest frame of thecurve C, which may be moving.
– The magnetic flux threading the circuit C is definedby
F = B ⋅ ˆ n daS∫ (5.133)
where S = surface bounded by C.
– In SI units, the constant k is 1. For gaussian units, itis 1/c.
• Differential equation form of Faraday’s Law (SIunits):
∇ × E +∂B∂t
= 0 (5.134)
• Faraday’s Law was an experimental discovery.However, it could almost have been derived fromconsideration of the properties of E and B underGalilean transformation.
E' = E + v × B
B' = B
(5.142)
PHYS 532. L6 11
• Lenz’s Law:– Intuitive way to see the sign of the induced electric
field:
The induced current (and accompanying magneticflux) is in such a direction as to oppose the change offlux through the circuit:
Suppose B is out of page and increasingwith time. Induced E is clockwise. In aconducting wire, it would drive aclockwise current, which, by Biot-Savartlaw, would cause a magnetic field intothe page.
PHYS 532. L6 12
5.16 Energy in the Magnetic Field
• Magnetic fields by themselves don’t change particleenergies, because the magnetic force isperpendicular to the particle velocity.– Therefore, it is not possible to discuss magnetic
energy in the context of magnetostatics.
– However, because time-dependent magnetic fieldsimply electric fields, creation of a magnetic fieldconfiguration requires energy.
• Expressions for change in energy associated withchange in magnetic field:
δW = δA∫ ⋅ J d3x = δB∫ ⋅ H d3x
– In a linear medium, with B proportional to H,
(5.144, 5.147)
W =12
B∫ ⋅H d3x =12
J∫ ⋅ A d3x (5.148, 5.149)