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Section 3-5 Proving Lines Parallel Wednesday, January 4, 2012

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Page 1: Geometry Section 3-5 1112

Section 3-5Proving Lines Parallel

Wednesday, January 4, 2012

Page 2: Geometry Section 3-5 1112

Essential Questions

• How do you recognize angle pairs tha occur with parallel lines?

• How do you prove that two lines are parallel using angle relationships?

Wednesday, January 4, 2012

Page 3: Geometry Section 3-5 1112

Postulates & Theorems1. Converse of Corresponding Angles Postulate

Wednesday, January 4, 2012

Page 4: Geometry Section 3-5 1112

Postulates & Theorems1. Converse of Corresponding Angles Postulate

If two lines are cut by a transversal so that corresponding angles are congruent, then the lines are

parallel.

Wednesday, January 4, 2012

Page 5: Geometry Section 3-5 1112

Postulates & Theorems2. Parallel Postulate

Wednesday, January 4, 2012

Page 6: Geometry Section 3-5 1112

Postulates & Theorems2. Parallel Postulate

If given a line and a point not on the line, then there exists exactly one line through the point that is parallel

to the given line.

Wednesday, January 4, 2012

Page 7: Geometry Section 3-5 1112

Postulates & Theorems3. Alternate Exterior Angles Converse

Wednesday, January 4, 2012

Page 8: Geometry Section 3-5 1112

Postulates & Theorems3. Alternate Exterior Angles Converse

If two lines in a plane are cut by a transversal so that a pair of alternate exterior angles is congruent, then the

two lines are parallel.

Wednesday, January 4, 2012

Page 9: Geometry Section 3-5 1112

Postulates & Theorems4. Consecutive Interior Angles Converse

Wednesday, January 4, 2012

Page 10: Geometry Section 3-5 1112

Postulates & Theorems4. Consecutive Interior Angles Converse

If two lines in a plane are cut by a transversal so that a pair of consecutive interior angles is supplementary,

then the lines are parallel.

Wednesday, January 4, 2012

Page 11: Geometry Section 3-5 1112

Postulates & Theorems5. Alternate Interior Angles Converse

Wednesday, January 4, 2012

Page 12: Geometry Section 3-5 1112

Postulates & Theorems5. Alternate Interior Angles Converse

If two lines in a plane are cut by a transversal so that a pair of alternate interior angles is congruent, then the

two lines are parallel.

Wednesday, January 4, 2012

Page 13: Geometry Section 3-5 1112

Postulates & Theorems6. Perpendicular Transversal Converse

Wednesday, January 4, 2012

Page 14: Geometry Section 3-5 1112

Postulates & Theorems6. Perpendicular Transversal Converse

In a plane, if two lines are perpendicular to the same line, then they are parallel.

Wednesday, January 4, 2012

Page 15: Geometry Section 3-5 1112

Example 1Given the following information, is it possible to prove that any of the lines shown are parallel? If so, state the

postulate or theorem that justifies your answer.

a. ∠1≅ ∠3

Wednesday, January 4, 2012

Page 16: Geometry Section 3-5 1112

Example 1Given the following information, is it possible to prove that any of the lines shown are parallel? If so, state the

postulate or theorem that justifies your answer.

a. ∠1≅ ∠3

a b since these congruent angles are also corresponding, the Corresponding Angles Converse holds

Wednesday, January 4, 2012

Page 17: Geometry Section 3-5 1112

Example 1Given the following information, is it possible to prove that any of the lines shown are parallel? If so, state the

postulate or theorem that justifies your answer.

b. m∠1=103° and m∠4 =100° ∠1 and ∠4

Wednesday, January 4, 2012

Page 18: Geometry Section 3-5 1112

Example 1Given the following information, is it possible to prove that any of the lines shown are parallel? If so, state the

postulate or theorem that justifies your answer.

b. m∠1=103° and m∠4 =100° ∠1 and ∠4 are alternate interior angles, but not congruent, so a is not parallel to c

Wednesday, January 4, 2012

Page 19: Geometry Section 3-5 1112

Example 2 Find m∠ZYN so that PQ MN.

Wednesday, January 4, 2012

Page 20: Geometry Section 3-5 1112

Example 2 Find m∠ZYN so that PQ MN.

11x − 25 = 7x + 35

Wednesday, January 4, 2012

Page 21: Geometry Section 3-5 1112

Example 2 Find m∠ZYN so that PQ MN.

11x − 25 = 7x + 35

4x = 60

Wednesday, January 4, 2012

Page 22: Geometry Section 3-5 1112

Example 2 Find m∠ZYN so that PQ MN.

11x − 25 = 7x + 35

4x = 60

x =15

Wednesday, January 4, 2012

Page 23: Geometry Section 3-5 1112

Example 2 Find m∠ZYN so that PQ MN.

11x − 25 = 7x + 35

4x = 60

x =15

m∠ZYN = 7(15) + 35

Wednesday, January 4, 2012

Page 24: Geometry Section 3-5 1112

Example 2 Find m∠ZYN so that PQ MN.

11x − 25 = 7x + 35

4x = 60

x =15

m∠ZYN = 7(15) + 35 =105 + 35

Wednesday, January 4, 2012

Page 25: Geometry Section 3-5 1112

Example 2 Find m∠ZYN so that PQ MN.

11x − 25 = 7x + 35

4x = 60

x =15

m∠ZYN = 7(15) + 35 =105 + 35 =140

Wednesday, January 4, 2012

Page 26: Geometry Section 3-5 1112

Example 2 Find m∠ZYN so that PQ MN.

11x − 25 = 7x + 35

4x = 60

x =15

m∠ZYN = 7(15) + 35 =105 + 35 =140

m∠ZYN =140°

Wednesday, January 4, 2012

Page 27: Geometry Section 3-5 1112

Check Your Understanding

Review problems #1-7 on page 208

Wednesday, January 4, 2012

Page 28: Geometry Section 3-5 1112

Problem Set

Wednesday, January 4, 2012

Page 29: Geometry Section 3-5 1112

Problem Set

p. 209 #9-27 odd, 37

“Nothing in life is to be feared. It is only to be understood.” - Marie Curie

Wednesday, January 4, 2012